Can I create model in Django without automatic ID? - python

I need a table without a primary key (in Django it was created automatically). So my question is: Can I create a model without an ID/primary key?
I'm using Django 1.7.

You can create a model without an auto-incrementing key, but you cannot create one without a primary key.
From the Django Documentation:
If Django sees you’ve explicitly set Field.primary_key, it won’t add the automatic id column.
Each model requires exactly one field to have primary_key=True (either explicitly declared or automatically added).

No, you can't. Excerpt from the documentation:
Each model requires exactly one field to have primary_key=True (either explicitly declared or automatically added).

I've found the solution.
Since django need Primary Key (either it's composite or single-field ID) so, I've tried to set primary_key=True in every fields in its composite-key combination, and add those fields in Meta and groups in unique_together
class ReportPvUv(models.Model):
report_id = models.ForeignKey(Reports, primary_key=True)
rdate = models.DateField(primary_key=True)
fdate = models.DateTimeField(primary_key=True)
ga_pv = models.BigIntegerField()
ga_uv = models.BigIntegerField()
ur_pv = models.BigIntegerField()
ur_uv = models.BigIntegerField()
da_pv = models.BigIntegerField()
da_uv = models.BigIntegerField()
class Meta:
db_table = 'report_pv_uv'
unique_together = ('report_id', 'rdate', 'fdate')
and when I run makemigrations, there are no ID field in it's migrations script :D
thanks everybody

Related

How to allow boolean True on just one model in table in Django?

I've got a model where I would like there to be able to have one set as the 'app default'.
In this model I added a field named is_app_default in order to help accommodate this.
class TreeLevel(models.Model):
id = models.BigAutoField(primary_key=True)
short_description = models.CharField(max_length=200)
long_description = models.TextField()
is_app_default = models.BooleanField(default=False)
class Meta:
verbose_name = "Tree Level"
verbose_name_plural = "Tree Levels"
class Layer(models.Model):
id = models.BigAutoField(primary_key=True)
tree_levels = models.ManyToManyField(TreeLevel)
description = models.TextField()
class Meta:
verbose_name = "Layer"
verbose_name_plural = "Layers"
The Layer model links to TreeLevel with an m2m. Ultimately I would like the is_app_default TreeLevel automatically added to every Layer m2m relationship - which is why there can only be one TreeLevel with is_app_default set as True.
My potential solution(s):
Users with admin may be creating new TreeLevel objects - so I need to make sure they aren't setting that Boolean in any new models. I think I can override the save() method on TreeLevel to check the DB to see if another with that boolean as True exists - if so? Don't save the 'new' one and return an error. But I think this hits the database - causing unnecessary queries potentially?
Then additionally, I would also need to override the save() method on Layer and add the 'default' TreeLevel to that many2many at that time.
Is there a good way to 'automatically' handle this with these relationships?
My ultimate goal:
Have a default TreeLevel that is automatically added to every Layer many to many relationship whenever a Layer is created.
Questions:
Would my proposed solution work?
I've tried looking into Djangos Unique Constraints, but I think those are more on a row level, as opposed to a Table level.

Django models: set default IntegerField to number of instances

I would like to set the "order" IntegerField of my Achievement model to the current count of objects in Achievement. The order field is used to order achievements, and users can change it. For now I have 1 as default.
class Achievement(models.Model):
title = models.CharField(max_length=50, blank=True)
description = models.TextField()
order = models.IntegerField(default=1) #Get the number of achievement objects
class Meta:
db_table = 'achievement'
ordering = ['order', 'id']
For example, if I already have one achievement in my database with whatever order the next one should get order=2 by default.
As far as I understood, you want to have a default value of 1 to the order integer field and increment it with each entry of Achievment (same functionality as the id), but also allow users change it.
For this purpose you can use Django's AutoField:
An IntegerField that automatically increments according to available IDs. You usually won’t need to use this directly; a primary key field will automatically be added to your model if you don’t specify otherwise.
Like this:
class Achievement(models.Model):
...
order = models.AutoField(default=1, primary_key=False)
# Also specify that this autofield is *not* a ^ primary key
class Meta:
ordering = ['order', 'id']

Why should I set default value of foreign key, django

For example, we have this code:
class Foo(models.Model):
a = models.CharField(max_length=10)
class Bar(models.Model):
b = models.CharField(max_length=10)
a = models.ForeignKey(Foo)
And when I run makemigrations, i see that I need set default of a(Bar)
Can anyone explain me, why should I do it?
Thanks!
It seems that you already have some data in your database (or you have made a migration before adding the ForeignKey field). In order for the migration to work you will need to "tell" Django what data should be in the a column of the Bar table for rows that already exist.
Either delete your whole database/earlier migrations, or provide a default value of your choice:
a = models.ForeignKey(Foo, default=None) # or any other default value

Django create_or_update(), unique_together, unique, and primary

I'm still trying to fully understand Django models, let's say I have the following model:
class Manufacturer(models.Model):
name = models.CharField(amx_length=255, unique=True)
class Car(models.Model):
name = models.CharField(max_length=255)
color = models.CharField(max_length=255)
manufacturer = models.ForeignKey(Manufacturer)
unique_together = ('manufacturer', 'name')
And I run the following commands:
honda = Manufacturer.objects.get(name='Honda') #Let's assume this object already exists
car = Car.objects.get_or_create(name='Honda Accord', color='Red', manufacturer=honda)
car = Car.objects.get_or_create(name='Honda Accord', color='Green', manufacturer=honda)
Will Django simply update the existing car to change the color from Red to Green? Or will issues arise because I don't have a primary_key set?
Also, does it matter if I use primary_key or unique or are they the same? I'm using a mySQL backend if it matters.
Django automatically sets a primary key field called id unless you specify one yourself. So your Car model will already have an id field. It's on the base model class that your model inherits.
In your example, you haven't specified the defaults argument of the get_or_create() method, so Django will only attempt to retrieve an object with the values you've passed in via a get call: https://docs.djangoproject.com/en/1.7/ref/models/querysets/#django.db.models.query.QuerySet.get_or_create
unique constraints can be specified on a field regardless if it's an AutoField or not. See: https://docs.djangoproject.com/en/1.7/ref/models/fields/#unique for more specific information.

How to use unique_together method in django views

class Model1(models.Model):
username = models.CharField(max_length=100,null=False,blank=False,unique=True)
password = models.CharField(max_length=100,null=False,blank=False)
class Model2(models.Model):
name = models.ForeignKey(Model1, null=True)
unique_str = models.CharField(max_length=50,null=False,blank=False,unique=True)
city = models.CharField(max_length=100,null=False,blank=False)
class Meta:
unique_together = (('name', 'unique_str'),)
I've already filled 3 sample username-password in Model1 through django-admin page
In my views I'm getting this list as
userlist = Model1.objects.all()
#print userlist[0].username, userlist[0].password
for user in userlist:
#here I want to get or create model2 object by uniqueness defined in meta class.
#I mean unique_str can belong to multiple user so I'm making name and str together as a unique key but I dont know how to use it here with get_or_create method.
#right now (without using unique_together) I'm doing this (but I dont know if this by default include unique_together functionality )
a,b = Model2.objects.get_or_create(unique_str='f3h6y67')
a.name = user
a.city = "acity"
a.save()
What I think you're saying is that your logical key is a combination of name and unique_together, and that you what to use that as the basis for calls to get_or_create().
First, understand the unique_together creates a database constraint. There's no way to use it, and Django doesn't do anything special with this information.
Also, at this time Django cannot use composite natural primary keys, so your models by default will have an auto-incrementing integer primary key. But you can still use name and unique_str as a key.
Looking at your code, it seems you want to do this:
a, _ = Model2.objects.get_or_create(unique_str='f3h6y67',
name=user.username)
a.city = 'acity'
a.save()
On Django 1.7 you can use update_or_create():
a, _ = Model2.objects.update_or_create(unique_str='f3h6y67',
name=user.username,
defaults={'city': 'acity'})
In either case, the key point is that the keyword arguments to _or_create are used for looking up the object, and defaults is used to provide additional data in the case of a create or update. See the documentation.
In sum, to "use" the unique_together constraint you simply use the two fields together whenever you want to uniquely specify an instance.

Categories