I am trying to send an email in Python using SMTP, with a From address, To address, BCC address, subject, and message. I have the email sending, and it even sends to the BCC as it should, the only issue is that the message of the email says:
To: example#gmail.com
Subject: Subject goes here
this is the email that I’m sending
when I only want the message itself to show where the message belongs, and the subject of the email isn't set, so there's a blank subject. Here is how I have it set up:
def sendEmail(fromAddress, toAddress, bccAddress, appName, message):
subject = "Subject goes here"
BODY = string.join((
"From: %s\r\n" % fromAddress,
"To: %s\r\n" % toAddress,
"Subject: %s\r\n" % subject,
"\r\n",
message
), "\r\n")
#im using arbitrary values here, when I run it I use actual login info
username = 'example#gmail.com'
password = 'password'
server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.login(username,password)
toList = []
bccList = []
toList.append(toAddress)
bccList.append(bccAddress)
server.sendmail(fromAddress, toList + bccList, BODY)
server.quit()
Use the email package (docs).
from email.mime.text import MIMEText
def send_mail(to, from_addr, subject, text):
msg = MIMEText(text)
msg['Subject'] = subject
msg['From'] = from_addr
msg['To'] = to
s = smtplib.SMTP_SSL("smtp.gmail.com")
s.login(smtp_user, smtp_pass)
# for Python 3
s.send_message(msg)
# OR
# for Python 2 (or 3, will still work)
s.sendmail(from_addr, [to], msg.as_string())
s.quit()
Related
I used server.sendmail(fromaddr, toaddrs, msg) to send automated emails using python.
How can I add an email subject to the mail?
I tried to look in SMTP documentation and didn't find any documentation for that.
From How to send an email with Gmail as provider using Python? :
def send_email(user, pwd, recipient, subject, body):
import smtplib
gmail_user = user
gmail_pwd = pwd
FROM = user
TO = recipient if type(recipient) is list else [recipient]
SUBJECT = subject
TEXT = body
# Prepare actual message
message = """From: %s\nTo: %s\nSubject: %s\n\n%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
try:
server = smtplib.SMTP("smtp.gmail.com", 587)
server.ehlo()
server.starttls()
server.login(gmail_user, gmail_pwd)
server.sendmail(FROM, TO, message)
server.close()
print 'successfully sent the mail'
except:
print "failed to send mail"
I'm using Gmail SMTP to send emails in Python, however sometimes the application may stay idle for an extended period of time.
How do I make sure that the session hasn't expired? Here's my code:
def send_email(user, pwd, recipient, subject, body):
import smtplib
gmail_user = user
gmail_pwd = pwd
FROM = user
TO = recipient if type(recipient) is list else [recipient]
SUBJECT = subject
TEXT = body
# Prepare actual message
message = """\From: %s\nTo: %s\nSubject: %s\n\n%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
try:
server = smtplib.SMTP("smtp.gmail.com", 587)
server.ehlo()
server.starttls()
server.login(gmail_user, gmail_pwd)
server.sendmail(FROM, TO, message)
server.close()
print 'successfully sent the mail'
except:
print "failed to send mail"
Can I always reuse the server session, or can it expire after let's say 5 hours?
I recently wrote a script that sent me an email if a website I wanted to monitor had changed using smtplib. The program works, and I get the email but when I look at the sent email (as I am sending myself the email from the same account), it says that there is no recipient or 'To:' address, only a Bcc with the address I want the email to be sent to. Is this a feature of smtplib -- that it doesn't actually add a 'To:' address, only Bcc addresses? code is as follows:
if (old_source != new_source):
# now we create a mesasge to send via email
fromAddr = "example#gmail.com"
toAddr = "example#gmail.com"
msg = ""
# smtp login
username = "example#gmail.com"
pswd = "password"
# create server object and login to the gmail smtp
server = smtplib.SMTP_SSL("smtp.gmail.com", 465)
server.login(username, pswd)
server.sendmail(fromAddr, toAddr, msg)
server.quit()
Updating your code as follows will do the trick:
if (old_source != new_source):
# now we create a mesasge to send via email
fromAddr = "example#gmail.com"
toAddr = "example#gmail.com"
msg = ""
# smtp login
username = "example#gmail.com"
pswd = "password"
# create server object and login to the gmail smtp
server = smtplib.SMTP_SSL("smtp.gmail.com", 465)
header = 'To:' + toAddr + '\n' + 'From: ' + fromAddr + '\n' + 'Subject:testing \n'
msg = header + msg
server.login(username, pswd)
server.sendmail(fromAddr, toAddr, msg)
server.quit()
Try manually adding any headers to your message, separated from the body by a blank line e.g.:
...
msg="""From: sender#domain.org
To: recipient#otherdomain.org
Subject: Test mail
Mail body, ..."""
...
Try this, seems to work for me.
#!/usr/bin/python
#from smtplib import SMTP # Standard connection
from smtplib import SMTP_SSL as SMTP #SSL connection
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
sender = 'example#gmail.com'
receivers = ['example#gmail.com']
msg = MIMEMultipart()
msg['From'] = 'example#gmail.com'
msg['To'] = 'example#gmail.com'
msg['Subject'] = 'simple email via python test 1'
message = 'This is the body of the email line 1\nLine 2\nEnd'
msg.attach(MIMEText(message))
ServerConnect = False
try:
smtp_server = SMTP('smtp.gmail.com','465')
smtp_server.login('######gmail.com', '############')
ServerConnect = True
except SMTPHeloError as e:
print "Server did not reply"
except SMTPAuthenticationError as e:
print "Incorrect username/password combination"
except SMTPException as e:
print "Authentication failed"
if ServerConnect == True:
try:
smtp_server.sendmail(sender, receivers, msg.as_string())
print "Successfully sent email"
except SMTPException as e:
print "Error: unable to send email", e
finally:
smtp_server.close()
Just throwing it out there: please try yagmail. Disclaimer: I'm the maintainer, but I feel like it can help everyone out!
It really provides a lot of defaults: I'm quite sure you'll be able to send an email directly with:
import yagmail
yag = yagmail.SMTP(username, password)
yag.send(to_addrs, contents = msg)
Which will also set the headers :)
You'll have to install yagmail first with either:
pip install yagmail # python 2
pip3 install yagmail # python 3
Once you will want to also embed html/images or add attachments, you'll really love the package!
It will also make it a lot safer by preventing you from having to have your password in the code.
So yesterday I had this bit of code written out and it worked perfectly fine, but today it's not sending e-mails anymore. Can someone explain why?
import smtplib
SERVER = 'owa.server.com'
FROM = 'noreply#server.com'
TO = ['person#gmail.com', '1112223344#vtext.com']
name = 'Mr. Man'
SUBJECT = 'Recent Information for: %s' % (name)
TEXT = "Dear " +name+ ",\n\nHello.\n\nSincerely,\nOur Guys Here"
message = """From: %s\r\nTo: %s\r\nSubject: %s\r\n\
%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
server = smtplib.SMTP(SERVER, 587)
server.ehlo()
server.starttls()
server.ehlo
server.login('noreply#server.com', 'password')
server.sendmail(FROM, TO, message)
server.quit()
This code is a working snippet. I wasn't getting the e-mails in my personal gmail account because gmail was sending it to the spam folder. I checked to see if it works at my office account, and it did just fine.
import smtplib
# Specifying the from and to addresses
fromaddr = 'fromuser#gmail.com'
toaddrs = 'to#gmail.com'
# Writing the message (this message will appear in the email)
msg = 'Enter you message here'
# Gmail Login
username = 'username'
password = 'password'
# Sending the mail
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(username,password)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()
Above standard smtp send works with gmail,
thus it must be your server(whatever you're using) configuration that is at fault.
I am successfully able to send email using the smtplib module. But when the emial is sent, it does not include the subject in the email sent.
import smtplib
SERVER = <localhost>
FROM = <from-address>
TO = [<to-addres>]
SUBJECT = "Hello!"
message = "Test"
TEXT = "This message was sent with Python's smtplib."
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
How should I write "server.sendmail" to include the SUBJECT as well in the email sent.
If I use, server.sendmail(FROM, TO, message, SUBJECT), it gives error about "smtplib.SMTPSenderRefused"
Attach it as a header:
message = 'Subject: {}\n\n{}'.format(SUBJECT, TEXT)
and then:
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
Also consider using standard Python module email - it will help you a lot while composing emails. Using it would look like this:
from email.message import EmailMessage
msg = EmailMessage()
msg['Subject'] = SUBJECT
msg['From'] = FROM
msg['To'] = TO
msg.set_content(TEXT)
server.send_message(msg)
This will work with Gmail and Python 3.6+ using the new "EmailMessage" object:
import smtplib
from email.message import EmailMessage
msg = EmailMessage()
msg.set_content('This is my message')
msg['Subject'] = 'Subject'
msg['From'] = "me#gmail.com"
msg['To'] = "you#gmail.com"
# Send the message via our own SMTP server.
server = smtplib.SMTP_SSL('smtp.gmail.com', 465)
server.login("me#gmail.com", "password")
server.send_message(msg)
server.quit()
try this:
import smtplib
from email.mime.multipart import MIMEMultipart
msg = MIMEMultipart()
msg['From'] = 'sender_address'
msg['To'] = 'reciver_address'
msg['Subject'] = 'your_subject'
server = smtplib.SMTP('localhost')
server.sendmail('from_addr','to_addr',msg.as_string())
You should probably modify your code to something like this:
from smtplib import SMTP as smtp
from email.mime.text import MIMEText as text
s = smtp(server)
s.login(<mail-user>, <mail-pass>)
m = text(message)
m['Subject'] = 'Hello!'
m['From'] = <from-address>
m['To'] = <to-address>
s.sendmail(<from-address>, <to-address>, m.as_string())
Obviously, the <> variables need to be actual string values, or valid variables, I just filled them in as place holders. This works for me when sending messages with subjects.
See the note at the bottom of smtplib's documentation:
In general, you will want to use the email package’s features to construct an email message, which you can then convert to a string and send via sendmail(); see email: Examples.
Here's the link to the examples section of email's documentation, which indeed shows the creation of a message with a subject line. https://docs.python.org/3/library/email.examples.html
It appears that smtplib doesn't support subject addition directly and expects the msg to already be formatted with a subject, etc. That's where the email module comes in.
import smtplib
# creates SMTP session
List item
s = smtplib.SMTP('smtp.gmail.com', 587)
# start TLS for security
s.starttls()
# Authentication
s.login("login mail ID", "password")
# message to be sent
SUBJECT = "Subject"
TEXT = "Message body"
message = 'Subject: {}\n\n{}'.format(SUBJECT, TEXT)
# sending the mail
s.sendmail("from", "to", message)
# terminating the session
s.quit()
I think you have to include it in the message:
import smtplib
message = """From: From Person <from#fromdomain.com>
To: To Person <to#todomain.com>
MIME-Version: 1.0
Content-type: text/html
Subject: SMTP HTML e-mail test
This is an e-mail message to be sent in HTML format
<b>This is HTML message.</b>
<h1>This is headline.</h1>
"""
try:
smtpObj = smtplib.SMTP('localhost')
smtpObj.sendmail(sender, receivers, message)
print "Successfully sent email"
except SMTPException:
print "Error: unable to send email"
code from: http://www.tutorialspoint.com/python/python_sending_email.htm
In case of wrapping it in a function, this should work as a template.
def send_email(login, password, destinations, subject, message):
server = smtplib.SMTP_SSL("smtp.gmail.com", 465)
server.login(login, password)
message = 'Subject: {}\n\n{}'.format(subject, message)
for destination in destinations:
print("Sending email to:", destination)
server.sendmail(login, destinations, message)
server.quit()
try this out :
from = "myemail#site.com"
to= "someemail#site.com"
subject = "Hello there!"
body = "Have a good day."
message = "Subject:" + subject + "\n" + body
server.sendmail(from, , message)
server.quit()