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Expected an indented block, python

Hello can someone fix it I tried to find solution online but nothing work.
Python Version: 3.7.9
if engine == "example1":
search = example1(engine)
request = partial(search.search_for, string)
all = p.map(request, pages)
elif engine == "example2":
filepath = "list.txt"
with open(filepath) as fp:
line = fp.readline()
count = 1
while line:
search = example2(engine)
request = partial(search.search_for, line.strip())
all = p.map(request, pages)
line = fp.readline()
count += 1
input(" press close to exit ")

It appears that the biggest issue is with lines immediately following your with statement. Those should be indented to be part of the context manager scope.
elif engine == "example2":
filepath = "list.txt"
with open(filepath) as fp:
line = fp.readline() # <--- note indent
count = 1 # <--- note indent
while line:
search = example2(engine)
request = partial(search.search_for, line.strip())
all = p.map(request, pages)
line = fp.readline()
count += 1

Here you have 2 intent mistakes.copy this code and try it
if engine == "example1":
search = example1(engine)
request = partial(search.search_for, string)
all = p.map(request, pages)
1. In elif there is one space before the line
elif engine == "example2":
filepath = "list.txt"
2.After the next line With open you need to leave 4 spaces
with open(filepath) as fp:
line = fp.readline()
count = 1
while line:
search = example2(engine)
request = partial(search.search_for, line.strip())
all = p.map(request, pages)
line = fp.readline()
count += 1
input(" press close to exit ")

When I open a text file, it only reads the last line

Say customPassFile.txt has two lines in it. First line is "123testing" and the second line is "testing321". If passwordCracking = "123testing", then the output would be that "123testing" was not found in the file (or something similar). If passwordCracking = "testing321", then the output would be that "testing321" was found in the file. I think that the for loop I have is only reading the last line of the text file. Any solutions to fix this?
import time
import linecache
def solution_one(passwordCracking):
print("Running Solution #1 # " + time.strftime("%Y-%m-%d %H:%M:%S",time.localtime()))
startingTimeSeconds = time.time()
currentLine = 1
attempt = 1
passwordFound = False
wordListFile = open("customPassFile.txt", encoding="utf8")
num_lines = sum(1 for line in open('customPassFile.txt'))
while(passwordFound == False):
for i, line in enumerate(wordListFile):
if(i == currentLine):
line = line
passwordChecking = line
if(passwordChecking == passwordCracking):
passwordFound = True
endingTimeSeconds = time.time()
overallTimeSeconds = endingTimeSeconds - startingTimeSeconds
print("~~~~~~~~~~~~~~~~~")
print("Password Found: {}".format(passwordChecking))
print("ATTEMPTS: {}".format(attempt))
print("TIME TO FIND: {} seconds".format(overallTimeSeconds))
wordListFile.close()
break
elif(currentLine == num_lines):
print("~~~~~~~~~~~~~~~~~")
print("Stopping Solution #1 # " + time.strftime("%Y-%m-%d %H:%M:%S", time.localtime()))
print("REASON: Password could not be cracked")
print("ATTEMPTS: {}".format(attempt))
break
else:
attempt = attempt + 1
currentLine = currentLine + 1
continue

The main problem with your code is that you open the file and you read it multiple times. The first time the file object position goes to the end and stays there. Next time you read the file nothing happens, since you are already at the end of the file.
Example
Sometimes an example is worth more than lots of words.
Take the file test_file.txt with the following lines:
line1
line2
Now open the file and read it twice:
f = open('./test_file.txt')
f.tell()
>>> 0
for l in f:
print(l, end='')
else:
print('nothing')
>>> line1
>>> line2
>>> nothing
f.tell()
>>> 12
for l in f:
print(l, end='')
else:
print('nothing')
>>> nothing
f.close()
The second time nothing happen, as the file object is already at the end.
Solution
Here you have two options:
you read the file only once and save all the lines in a list and then use the list in your code. It should be enough to replace
wordListFile = open("customPassFile.txt", encoding="utf8")
num_lines = sum(1 for line in open('customPassFile.txt'))
with
with open("customPassFile.txt", encoding="utf8") as f:
wordListFile = f.readlines()
num_lines = len(wordListFile)
you reset the file object position after you read the file using seek. It would be something along the line:
for i, line in enumerate(wordListFile):
if(i == currentLine):
line = line
wordListFile.seek(0)
I would go with option 1., unless you have memory constraint (e.g. the file is bigger than memory)
Notes
I have a few extra notes:
python starts counters with 0 (like c/c++) and not 1 (like fortran). So probably you want to set:
currentLine = 0
when you read a file, the new line character \n is not stripped, so you have to do it (with strip) or account for it when comparing strings (using e.g. startswith). As example:
passwordChecking == passwordCracking
will likely always return False as passwordChecking contains \n and passwordCracking very likely doesn't.
Disclamer
I haven't tried the code, nor my suggestions, so there might be other bugs lurking around.

**I will delete this answer after OP understands the problem in indentation of I understand his intention of his code.*
for i, line in enumerate(wordListFile):
if(i == currentLine):
line = line
passwordChecking = line
#rest of the code.
Here your code is outside of for loop so only last line is cached.
for i, line in enumerate(wordListFile):
if(i == currentLine):
line = line
passwordChecking = line
#rest of the code.

Python text processing/finding data

I am trying to parse/process some information from a text file using Python. This file contains names, employee numbers and other data. I do not know the names or employee numbers ahead of time. I do know that after the names there is the text: "Per End" and before the employee number there is the text: "File:". I can find these items using the .find() method. But, how do I ask Python to look at the information that comes before or after "Per End" and "File:"? In this specific case the output should be the name and employee number.
The text looks like this:
SMITH, John
Per End: 12/10/2016
File:
002013
Dept:
000400
Rate:10384 60
My code is thus:
file = open("Register.txt", "rt")
lines = file.readlines()
file.close()
countPer = 0
for line in lines:
line = line.strip()
print (line)
if line.find('Per End') != -1:
countPer += 1
print ("Per End #'s: ", countPer)

file = open("Register.txt", "rt")
lines = file.readlines()
file.close()
for indx, line in enumerate(lines):
line = line.strip()
print (line)
if line.find('Per End') != -1:
print lines[indx-1].strip()
if line.find('File:') != -1:
print lines[indx+1].strip()
enumerate(lines) gives access to indices and line as well, there by you can access previous and next lines as well
here is my stdout directly ran in python shell:
>>> file = open("r.txt", "rt")
>>> lines = file.readlines()
>>> file.close()
>>> lines
['SMITH, John\n', 'Per End: 12/10/2016\n', 'File:\n', '002013\n', 'Dept:\n', '000400\n', 'Rate:10384 60\n']
>>> for indx, line in enumerate(lines):
... line = line.strip()
... if line.find('Per End') != -1:
... print lines[indx-1].strip()
... if line.find('File:') != -1:
... print lines[indx+1].strip()
SMITH, John
002013

Here is how I would do it.
First, some test data.
test = """SMITH, John\n
Per End: 12/10/2016\n
File:\n
002013\n
Dept:\n
000400\n
Rate:10384 60\n"""
text = [line for line in test.splitlines(keepends=False) if line != ""]
Now for the real answer.
count_per, count_num = 0, 0
Using enumerate on an iterable gives you an index automagically.
for idx, line in enumerate(text):
# Just test whether what you're looking for is in the `str`
if 'Per End' in line:
print(text[idx - 1]) # access the full set of lines with idx
count_per += 1
if 'File:' in line:
print(text[idx + 1])
count_num += 1
print("Per Ends = {}".format(count_per))
print("Files = {}".format(count_num))
yields for me:
SMITH, John
002013
Per Ends = 1
Files = 1

How do I count the number of lines that are full-line comments in python?

I'm trying to create a function that accepts a file as input and prints the number of lines that are full-line comments (i.e. the line begins with #followed by some comments).
For example a file that contains say the following lines should print the result 2:
abc
#some random comment
cde
fgh
#another random comment
So far I tried along the lines of but just not picking up the hash symbol:
infile = open("code.py", "r")
line = infile.readline()
def countHashedLines(filename) :
while line != "" :
hashes = '#'
value = line
print(value) #here you will get all
#if(value == hashes): tried this but just wasn't working
# print("hi")
for line in value:
line = line.split('#', 1)[1]
line = line.rstrip()
print(value)
line = infile.readline()
return()
Thanks in advance,
Jemma

I re-worded a few statements for ease of use (subjective) but this will give you the desired output.
def countHashedLines(lines):
tally = 0
for line in lines:
if line.startswith('#'): tally += 1
return tally
infile = open('code.py', 'r')
all_lines = infile.readlines()
num_hash_nums = countHashedLines(all_lines) # <- 2
infile.close()
...or if you want a compact and clean version of the function...
def countHashedLines(lines):
return len([line for line in lines if line.startswith('#')])

I would pass the file through standard input
import sys
count = 0
for line in sys.stdin: """ Note: you could also open the file and iterate through it"""
if line[0] == '#': """ Every time a line begins with # """
count += 1 """ Increment """
print(count)

Here is another solution that uses regular expressions and will detect comments that have white space in front.
import re
def countFullLineComments(infile) :
count = 0
p = re.compile(r"^\s*#.*$")
for line in infile.readlines():
m = p.match(line)
if m:
count += 1
print(m.group(0))
return count
infile = open("code.py", "r")
print(countFullLineComments(infile))

Split large text file using keyword delimiter

I'm trying to split a large text files into smaller text files by using a word delimiter. I tried searching but I've only seen posts to break apart files after x lines. I'm fairly new to programming but I've given it a start. I want to go through all the lines, and if it starts with hello, it will put all of those lines into one file until it reaches the next hello. The first word in the file is hello. Ultimately, I'm trying to get the text into R, but I think it would be easier if I split it up like this first. Any help is appreciated, thanks.
text_file = open("myfile.txt","r")
lines = text_file.readlines()
print len(lines)
for line in lines :
print line
if line[0:5] == "hello":

If you are finding for a very simple logic, Try this.
text_file = open("myfile.txt","r")
lines = text_file.readlines()
print len(lines)
target = open ("filename.txt", 'a') ## a will append, w will over-write
hello1Found = False
hello2Found = False
for line in lines :
if hello1Found == True :
if line[0:5] == "hello":
hello2Found = True
hello1Found = False
break ## When second hello is found looping/saving to file is stopped
##(though using break is not a good practice here it suffice your simple requirement
else:
print line #write the line to new file
target.write(line)
if hello1Found == False:
if line[0:5] == "hello": ##find first occurrence of hello
hello1Found = True
print line
target.write(line) ##if hello is found for the first time write the
##line/subsequent lines to new file till the occurrence of second hello

I am new to Python. I just finished a Python for Geographic Information Systems class at Northeastern University. This is what I came up with.
import os
import sys
import arcpy
def files():
n = 0
while True:
n += 1
yield open('/output/dir/%d.txt' % n, 'w')
pattern = 'hello'
fs = files()
outfile = next(fs)
filename = r'C:\output\dir\filename.txt'
with open(filename) as infile:
for line in infile:
if pattern not in line:
outfile.write(line)
else:
items = line.split(pattern)
outfile.write
(items[0])
for item in items:
outfile = next(fs)
outfile.write(item)
filename.close();outfile.close();