I'm trying to insert text into a textbox using Tkinter. I'm trying to insert information retrieved from a file but I've boiled it down to something simpler which exhibits the same problem:
class Main(Frame):
def __init__(self, parent):
Frame.__init__(self, parent)
self.parent = parent
self.init_ui()
def helloCallBack(self):
self.txt.insert("lol")
def init_ui(self):
self.txt = Text(root, width=24, height = 10).grid(column=0, row = 0)
load_button = Button(root, text="Load Wave Data", command = self.helloCallBack).grid(column=1, row = 0, sticky="E")
def main():
ex = Main(root)
root.geometry("300x250+300+300")
root.mainloop()
What I want it to do is whenever I press the button it inserts lol into the text box but I get the error
AttributeError: 'NoneType' object has no attribute 'insert'
How do I fix this?
You need to call grid in separated line. Because the method return None; causing the self.txt to reference None instead of Text widget object.
def init_ui(self):
self.txt = Text(root, width=24, height=10)
self.txt.grid(column=0, row=0)
load_button = Button(root, text="Load Wave Data", command=self.helloCallBack)
load_button.grid(column=1, row=0, sticky="E")
You need to specify where to insert the text.
def helloCallBack(self):
self.txt.insert(END, "lol")
To insert you need to indicate where you want to start inserting text:
self.txt.insert(0, "lol")
Related
I'm building a desktop application that lets you insert some data into a form and then the data is displayed in a series (3) of Treeview widgets.
This is the form that I'm using to enter new data:
It's in a Toplevel widget. When the Add button is pressed the new data is stored in a file and it also should insert the new data in the corresponding Treeview Widget.
This is the root window:
It's comprised of 3 Treeview widgets. The purpose of the application is to give the user the opportunity to sort candidates into the right Treeview widget.
The issue that I'm facing is that when the Add button is pressed the new data is not shown in the Treeview widget and no errors are given. I think it may be an issue of class instantiation. This is an excerpt from my app, please see below a Minimal, Complete and Verifiable example
class MainApp(tk.Tk):
def __init__(self, *args, **kwargs):
...
# frame and menu classes are instantiated here
self.FrameList = {ViableCandidates: ViableCandidates(self),
NotViableCandidates: NotViableCandidates(self),
InProgressCandidates: InProgressCandidates(self)}
...
def InstanceLinker(self, frame):
link = self.FrameList[frame]
return link
class GUIMenu(tk.Menu):
def __init__(self, parent):
...
# menu code is here
addcandidates.add_command(label='Quick Add', command=lambda: QuickAdd(parent))
class QuickAdd(tk.Toplevel):
def __init__(self, parent):
...
# code for the small Toplevel window
...
# this is the code that I use to add the new item to Treeview when the Add button is pressed
if CandidateInfo['status'] == 'Viable':
app.InstanceLinker(ViableCandidates).AddtoList()
elif CandidateInfo['status'] == 'Not Viable':
app.InstanceLinker(NotViableCandidates).AddtoList()
else:
app.InstanceLinker(InProgressCandidates).AddtoList()
# ViableCandidates, NotViableCandidates, InProgressCandidates are created with the same pattern
class InProgressCandidates(tk.Frame):
def __init__(self, parent):
global Counter
tk.Frame.__init__(self, parent)
self.columnconfigure(0, weight=1)
self.rowconfigure(1, weight=1)
title = tk.Label(self, text="Candidates In Progress", font="Verdana 10 bold")
title.grid(row=0, column=0, sticky='nesw')
self.tree = ttk.Treeview(self)
self.tree.grid(row=1, column=0, sticky='nesw')
scrollbar = ttk.Scrollbar(self, orient='vertical', command=self.tree.yview)
scrollbar.grid(row=1, column=1, sticky='nws')
self.tree.config(columns=('Name', 'Date'), selectmode='browse', height=20, yscrollcommand=scrollbar.set)
self.tree.column('#0', width=20, minwidth=10, stretch=tk.YES)
self.tree.column('Name', width=150, minwidth=10, stretch=tk.YES)
self.tree.column('Date', width=80, minwidth=10, stretch=tk.YES)
self.tree.heading('#0', text='#', anchor=tk.W)
self.tree.heading('Name', text='Name', anchor=tk.W)
self.tree.heading('Date', text='Date', anchor=tk.W)
if Counter < 4:
Counter += 1
self.PopulateList()
def PopulateList(self):
selection = Database().SelectFromDB('name, date', "status = 'In progress'")
for i in range(len(selection)):
name = list(selection[i])[0]
date = adjusttotimezone(list(selection[i])[1])
self.tree.insert("", i, name, text=i + 1)
self.tree.set(name, 'Name', name)
self.tree.set(name, 'Date', date)
CandidateCounter['InProgressCandidates'] = i
def AddtoList(self):
CandidateCounter['InProgressCandidates'] += 1
print('I was here')
self.tree.insert("", CandidateCounter['InProgressCandidates'], CandidateInfo['name'],
text=CandidateCounter['InProgressCandidates'])
self.tree.set(CandidateInfo['name'], 'Name', CandidateInfo['name'])
selection = Database().SelectFromDB('date', "name = '" + CandidateInfo['name'] + "'")
date = adjusttotimezone(list(selection[0])[0])
self.tree.set(CandidateInfo['name'], 'Date', date)
app = MainApp()
app.mainloop()
When the "Add" button is pressed there are no errors and "I was here" is printed so the AddtoList method is instantiated, but there are no new items added to Treeview. I did check if the variables that I'm using to create the new Treeview item hold the correct data and they do.
EDIT: This is a Minimal, Complete and Verifiable example:
import tkinter as tk
from tkinter import ttk
Bigbadtext = ''
Counter = 0
class MainApp(tk.Tk):
def __init__(self, *args, **kwargs):
self.MainWindow = tk.Tk.__init__(self, *args, **kwargs)
menu = GUIMenu(self)
self.config(menu=menu)
frame = InProgressCandidates(self)
frame.grid(row=0, column=1, sticky='nesw')
self.FrameList = {InProgressCandidates:InProgressCandidates(self)}
def InstanceLinker(self, frame):
link = self.FrameList[frame]
return link
class GUIMenu(tk.Menu):
def __init__(self, parent):
tk.Menu.__init__(self, parent)
addcandidates = tk.Menu(self, tearoff=0)
self.add_cascade(label='Add Candidates', menu=addcandidates)
addcandidates.add_command(label='Quick Add', command=lambda: QuickAdd(parent))
class QuickAdd(tk.Toplevel):
def __init__(self, parent):
tk.Toplevel.__init__(self, parent)
saysomething = tk.Entry(self)
saysomething.grid(row=1, column=0)
def addbutton():
global Bigbadtext
Bigbadtext = saysomething.get()
app.InstanceLinker(InProgressCandidates).AddtoList()
okbutton = ttk.Button(self, text='Add', command=addbutton)
okbutton.grid(row=2, column=0)
class InProgressCandidates(tk.Frame):
def __init__(self, parent):
tk.Frame.__init__(self, parent)
self.tree = ttk.Treeview(self)
self.tree.grid(row=1, column=0, sticky='nesw')
scrollbar = ttk.Scrollbar(self, orient='vertical', command=self.tree.yview)
scrollbar.grid(row=1, column=1, sticky='nws')
self.tree.config(columns='something', selectmode='browse', height=20, yscrollcommand=scrollbar.set)
self.tree.column('#0', width=20, minwidth=10, stretch=tk.YES)
self.tree.column('something', width=150, minwidth=10, stretch=tk.YES)
self.tree.heading('#0', text='#', anchor=tk.W)
self.tree.heading('something', text='Say something', anchor=tk.W)
def AddtoList(self):
global Counter
Counter += 1
print('I was here')
self.tree.insert("", Counter, Bigbadtext, text=Counter)
self.tree.set(Bigbadtext, 'something', Bigbadtext)
app = MainApp()
app.mainloop()
The problem is that you are creating two treeview widgets, and then adding items to the one that is invisible.
You create one here:
frame = InProgressCandidates(self)
Then you create another one here:
self.FrameList = {InProgressCandidates:InProgressCandidates(self)}
Since you've already created one, the one you created should be what goes in self.FrameList:
self.FrameList = {InProgressCandidates:frame}
It is not really an answer but I up voted the question because it solved me a problem. I wanted to add items to the widget but did not want to show it to the user until I finished to populate the tree. But each insert showed right away. Now I create 2 identical widgets, one visible and the other is not, and once it is populated I change between them. Thus even a mistake can have a benefit.
I am trying to create a GUI for an auto-complete prototype and am new to tkinter. I want to get the entire input when Space is pressed but I am unable to do so. The idea is to get all the entries in the text box so that I can do some analysis inside a function call.
This is the code:
def kp(event):
app.create_widgets(1)
import random
def getFromScript(text):
#########THIS IS A PLACE HOLDER FOR ACTUAL IMPLEMENTATION
i= random.randint(1,100)
return ['hello'+str(i),'helou'+text]
from tkinter import *
class Application(Frame):
def __init__(self, master=None):
Frame.__init__(self, master)
self.pack()
self.create_widgets(0)
# Create main GUI window
def create_widgets(self,i):
self.search_var = StringVar()
self.search_var.trace("w", lambda name, index, mode: self.update_list(i))
self.lbox = Listbox(self, width=45, height=15)
if i==0:
self.entry = Entry(self, textvariable=self.search_var, width=13)
self.entry.grid(row=0, column=0, padx=10, pady=3)
self.lbox.grid(row=1, column=0, padx=10, pady=3)
# Function for updating the list/doing the search.
# It needs to be called here to populate the listbox.
self.update_list(i)
def update_list(self,i):
search_term = self.search_var.get()#### THIS LINE SHOULD READ THE TEXT
# Just a generic list to populate the listbox
if(i==0):
lbox_list = ['Excellent','Very Good','Shabby', 'Unpolite']
if(i==1):
lbox_list = getFromScript(search_term)####### PASS TEXT HERE
self.lbox.delete(0, END)
for item in lbox_list:
if search_term.lower() in item.lower():
self.lbox.insert(END, item)
root = Tk()
root.title('Filter Listbox Test')
root.bind_all('<space>', kp)
app = Application(master=root)
app.mainloop()
Any kind of help is highly appreciable. Thanks in advance
Problem is you are creating a new StringVar on each create_widgets call.
Create StringVar in your __init__.
class Application(Frame):
def __init__(self, master=None):
...
self.search_var = StringVar()
...
How do I place the QUIT button in below code to the extreme right of the Frame?
I tried several things like:
padx
and
self.pack(side="top", anchor="e")
but after trying some 15 times both buttons are coming close to each other. Maybe Some help from anyone would be really appreciated. I need one button on extreme right and other on extreme left
import tkinter as tk
from tkinter.ttk import *
class Application(tk.Frame):
def __init__(self, master=None):
tk.Frame.__init__(self, master)
self.pack()
self.createWidgets()
self.master.title("Log Parser")
def createWidgets(self):
self.Run_Main = tk.Button(self)
self.Run_Main["text"] = "Browse.."
# self.Run_Main["fg"] = "blue"
self.Run_Main["command"] = self.Sayhello
self.Run_Main.pack(side='left')
self.Label = tk.Label(self)
self.Label["text"] = 'Processing...'
self.progressbar = Progressbar(mode="indeterminate", maximum=20)
self.QUIT = tk.Button(self)
self.QUIT["text"] = "Quit!"
self.QUIT["command"] = self.quit
self.QUIT.pack(anchor='e')
self.pack(side="top", anchor="w")
def Sayhello(self):
print("Hello")
# scroll text inside application frame
class scrollTxtArea:
def __init__(self, root):
frame = tk.Frame(root)
frame.pack()
self.textPad(frame)
return
def textPad(self, frame):
# add a frame and put a text area into it
textPad = tk.Frame(frame)
self.text = tk.Text(textPad, height=18, width=60)
self.text.config()
# add a vertical scroll bar to the text area
scroll = tk.Scrollbar(textPad)
self.text.configure(yscrollcommand=scroll.set,background="black", foreground="green")
# pack everything
self.text.pack(side=tk.LEFT, pady=2)
scroll.pack(side=tk.RIGHT, fill=tk.Y)
textPad.pack(side=tk.TOP)
return
root = tk.Tk()
root.resizable(width=False, height=False)
root.option_add('*font', ('verdana', 9, 'bold'))
app = Application(master=root)
scrollFrame = scrollTxtArea(root)
app.mainloop()
You have several problems here.
First, you're using the wrong geometry manager. The pack geometry manager, as the name implies, packs the widgets as close together as possible. That's not what you want. The grid geometry manager lets you put the widgets into a table-like layout with rows and columns. If you put the Browse button into the first column and the Quit button into the last column, you'll be a step closer.
Second, your Application window contains three child widgets and you're only putting two of them into a geometry manager. How that is going to mess you up I don't even want to think about. So I put the label into column 1, the Quit button into column 2, and the Browse button into column 0. The Quit button I gave a "sticky" value of "e" so it will be attached to the east (right) side of its allocated space.
Third, all the geometry managers try to compact the widgets as much as possible unless you specifically tell it to do otherwise. I told the grid manager to expand column 2 so that the extra space gets assigned to the cell that holds the Quit button.
Fourth, you need to tell the pack manager to expand the top widget so that it spans the entire window. The directive for that is fill="x".
Fifth, you have a redundant call to the pack manager at the end of your createWidgets function.
import tkinter as tk
from tkinter.ttk import *
class Application(tk.Frame):
def __init__(self, master=None):
tk.Frame.__init__(self, master)
self.pack(fill="x")
self.createWidgets()
self.master.title("Log Parser")
def createWidgets(self):
self.Run_Main = tk.Button(self)
self.Run_Main["text"] = "Browse.."
# self.Run_Main["fg"] = "blue"
self.Run_Main["command"] = self.Sayhello
self.Label = tk.Label(self)
self.Label["text"] = 'Processing...'
self.progressbar = Progressbar(mode="indeterminate", maximum=20)
self.QUIT = tk.Button(self)
self.QUIT["text"] = "Quit!"
self.QUIT["command"] = self.quit
self.Label.grid(row=0, column=1)
self.Run_Main.grid(row=0, column=0, sticky="w")
self.QUIT.grid(row=0, column=2, sticky="e")
self.columnconfigure(2, weight=1)
def Sayhello(self):
print("Hello")
# scroll text inside application frame
class scrollTxtArea:
def __init__(self, root):
frame = tk.Frame(root)
frame.pack()
self.textPad(frame)
return
def textPad(self, frame):
# add a frame and put a text area into it
textPad = tk.Frame(frame)
self.text = tk.Text(textPad, height=18, width=60)
self.text.config()
# add a vertical scroll bar to the text area
scroll = tk.Scrollbar(textPad)
self.text.configure(yscrollcommand=scroll.set,background="black", foreground="green")
# pack everything
self.text.pack(side=tk.LEFT, pady=2)
scroll.pack(side=tk.RIGHT, fill=tk.Y)
textPad.pack(side=tk.TOP)
return
root = tk.Tk()
root.resizable(width=False, height=False)
root.option_add('*font', ('verdana', 9, 'bold'))
app = Application(master=root)
scrollFrame = scrollTxtArea(root)
app.mainloop()
These link, link helped. The other option would be to use tkinter's grid manager, it will be more intuitive and keep you more organized in the future.
import tkinter as tk
from tkinter.ttk import *
class Application(tk.Frame):
def __init__(self, master=None):
tk.Frame.__init__(self, master)
self.pack()
self.createWidgets()
self.master.title("Log Parser")
def createWidgets(self):
self.Run_Main = tk.Button(self)
self.Run_Main["text"] = "Browse.."
# self.Run_Main["fg"] = "blue"
self.Run_Main["command"] = self.Sayhello
self.Run_Main.pack(side='left')
self.Label = tk.Label(self)
self.Label["text"] = 'Processing...'
self.Label.pack(side='left')
self.progressbar = Progressbar(mode="indeterminate", maximum=20)
self.QUIT = tk.Button(self)
self.QUIT["text"] = "Quit!"
self.QUIT["command"] = self.quit
self.QUIT.pack(side='right')
self.pack(side="top", fill=tk.BOTH) # changes here
def Sayhello(self):
print("Hello")
# scroll text inside application frame
class scrollTxtArea:
def __init__(self, root):
frame = tk.Frame(root)
frame.pack()
self.textPad(frame)
return
def textPad(self, frame):
# add a frame and put a text area into it
textPad = tk.Frame(frame)
self.text = tk.Text(textPad, height=18, width=60)
self.text.config()
# add a vertical scroll bar to the text area
scroll = tk.Scrollbar(textPad)
self.text.configure(yscrollcommand=scroll.set,background="black", foreground="green")
# pack everything
self.text.pack(side=tk.LEFT, pady=2)
scroll.pack(side=tk.RIGHT, fill=tk.Y)
textPad.pack(side=tk.TOP)
return
root = tk.Tk()
root.resizable(width=False, height=False)
root.option_add('*font', ('verdana', 9, 'bold'))
app = Application(master=root)
scrollFrame = scrollTxtArea(root)
app.mainloop()
There are two simple fixes you can make in order to get the behavior you want.
First, you need to pack Application so that it fills the window:
class Application(...):
def __init__(...):
...
self.pack(fill="x")
Next, simply pack the quick button on the right side of the window:
self.QUIT.pack(side="right", anchor='e')
Even though the above is all you need to do in this specific example, there are additional things you can do to make your job much easier.
I would recommend creating a frame specifically for the buttons. You can pack it at the top. Then, put the buttons inside this frame, and pack them either on the left or right. You'll get the same results, but you'll find it easier to add additional buttons later.
I also find that it makes the code much easier to read, write, maintain, and visualize when you separate widget creation from widget layout.
class Application(...):
...
def createWidgets(self):
toolbar = tk.Frame(self)
toolbar.pack(side="top", fill="x")
self.Run_Main = tk.Button(toolbar)
self.Label = tk.Label(toolbar)
self.QUIT = tk.Button(toolbar)
...
self.Run_Main.pack(side="left")
self.Label.pack(side="left", fill="x")
self.QUIT.pack(side="right")
...
from tkinter import *
import random
root = Tk()
name = StringVar()
class Window(Frame):
def __init__(self, master = None):
Frame.__init__(self, master)
self.master = master
self.init_window()
def init_window(self):
self.master.title("Are you smart enough?")
self.pack(fill=BOTH, expand="no")
self.entry = Entry(root,textvariable=name)
self.entry.pack()
enterButton = Button(self, text="Enter", command=self.client_enter)
enterButton.pack(side="top", fill="none", expand="True", anchor = "s")
def client_enter(self):
text = name.get()
textlabel = Label(self, text=name).pack()
app = Window(root)
root.geometry("1200x600")
root.mainloop()
For some reason, when I input a name and press the "Enter" button, nothing shows up.
How can I make it say ("Welcome", name) on Tkinter?
It seems like the variable text contains the right value, but you are displaying the name (which is a StringVar) instead.
Replace this:
textlabel = Label(self, text=name).pack()
By this:
textlabel = Label(self, text=text).pack()
To make it say "Welcome, name", change the definition of text as such:
text = "Welcome, {}".format(name.get())
Also, textlabel becomes useless if you put .pack() in its definition. You should be doing it like this:
textlabel = Label(self, text=text)
textlabel.pack()
Or like this if you don't need to store it in a variable:
Label(self, text=text).pack()
I am having difficulty updating a python Tkinter frame. I draw the frame with
some labels and text fields, when a person presses a button, I want to do some
calculations and update the labels and text fields. I can print the data to my
stdout, but I cannot get the Tk screen to update. How can I get the countFld to display an updated value?
class Application(Frame):
def __init__(self):
self.root = Tk()
Frame.__init__(self, self.root)
self.count = 0
self.createWidgets()
def createWidgets(self):
self.countFrame = Frame(self, bd=2, relief=RIDGE)
Label(self.countFrame, text='Count:').pack(side=LEFT, padx=5)
self.countFld = IntVar()
Label(self.countFrame, text=str(self.count)).pack(side=RIGHT, padx=5)
self.countFld.set(self.count)
self.countFrame.pack(expand=1, fill=X, pady=10, padx=5)
self.CNTBTN = Button(self)
self.CNTBTN["text"] = "UPDATE"
self.CNTBTN["fg"] = "red"
self.CNTBTN["command"] = self.update_count
self.CNTBTN.pack({"side": "left"})
def update_count(self):
self.count = self.count + 1
print "Count = %" % self.count #prints correct value
self.countFld.set(self.count) #Does not update display
Your problem is that you do not attach the Variable to the widget. In addition you need to use a StringVar, as the Label Widget operates on Strings and not Ints.
Try something like:
self.countStr = StringVar()
self.countStr.set(str(self.count))
Label(self.countFrame, textvariable=self.countStr).pack(side=RIGHT, padx=5)
Tk updates the display when the eventloop is idle. So you need to re-enter the event loop after you set the new value.
You should try destroying the label itself and making it again in the code with the updated text and use self.root.update()