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How can I get a PyInstaller executable to create a file in the same directory?

I found the answer
So it looks like PyInstaller actually runs in a temp directory, not your own, which explains my issue. This is an explanation for that. I guess I will keep this up incase people in the future have problems.
Original question
I am trying to use PyInstaller to create an executable of a simple python script called test.py that just creates a text file and adds numbers to it, as a test of PyInstaller. This file works correctly when run normally.
from os.path import dirname, abspath
def main():
txtfile = dirname(abspath(__file__)) + '/text.txt'
with open(txtfile, 'w') as f:
for num in range(101):
f.write(str(num) + '\n')
if __name__ == '__main__':
main()
print('script executed')
When I use:
pyinstaller test.py --onefile in the same directory as test.py it successfully creates the dist file with the binary file test inside of it.
when I cd dist and do ./test to execute the file inside dist it successfully prints out main called and script executed but it doesn't actually create the file. So, main is being called and the script is being executed, but the file isn't created at all, and I am quite confused about what I'm doing wrong..I must be getting file paths messed up? But I have specified the exact full path with os.path, so it doesn't make sense to me.
The system exit code is 0, and there are no errors raised when I call ./test

I found this that shows that PyInstaller will save to a temp file. I created this script below to check if the script is being executed directly or via PyInstaller.
import os
import sys
def create_file(path):
with open(path + '/test.txt', 'w') as f:
for num in range(101):
f.write(str(num) + '\n')
def check_using_pyinstaller():
if getattr(sys, 'frozen', False):
application_path = os.path.dirname(sys.executable)
return application_path
return os.path.dirname(os.path.abspath(__file__))
def main():
path = check_using_pyinstaller()
os.chdir(path)
create_file(path)
if __name__ == '__main__':
main()

Python script violates the command-line character limit

I am using a Python script to batch convert many images in different folders into single pdfs (with https://pypi.org/project/img2pdf/):
import os
import subprocess
import img2pdf
from shutil import copyfile
def main():
folders = [name for name in os.listdir(".") if os.path.isdir(name)]
for f in folders:
files = [f for f in os.listdir(f)]
p = ""
for ffile in files:
p += f+'\\' + ffile + " "
os.system("py -m img2pdf *.pn* " + p + " --output " + f + "\combined.pdf")
if __name__ == '__main__':
main()
However, despite running the command via Powershell on Windows 10, and despite using very short filenames, when the number of images is very high (eg over 600 or so), Powershell gives me the error "The command line is too long" and it does not create the pdf. I know there is a command-line string limitation (https://learn.microsoft.com/en-us/troubleshoot/windows-client/shell-experience/command-line-string-limitation), but I also know that for powershell this limit is higher (Powershell to avoid cmd 8191 character limit), and I can't figure out how to fix the script. I would like to ask you if you could help me fix the script to avoid violating the character limit. Thank you
PS: I use the script after inserting it in the parent folder that contains the folders with the images; then in each subfolder the output pdf file is created.

Using img2pdf library you can use this script:
import img2pdf
import os
for r, _, f in os.walk("."):
imgs = []
for fname in f:
if fname.endswith(".jpg") or fname.endswith(".png"):
imgs.append(os.path.join(r, fname))
if len(imgs) > 0:
with open(r+"\output.pdf","wb") as f:
f.write(img2pdf.convert(imgs))

Python script won't print when called from another python script

I have two scripts. The first script outputs to a file a list of folders and files, then it calls a second python script to read that file and print it to screen. The second script is called but nothing ever prints to the screen and I'm not sure why. No error message is thrown.
First Script:
#!/bin/python
from subprocess import call
import os.path
import os
def main():
userRequest=raw_input("""Type the path and folder name that you'd like to list all files for.
The format should begin with a slash '/' and not have an ending slash '/'
Example (/var/log) *Remember capital vs. lower case does matter* :""")
userInputCheck(userRequest)
def userInputCheck(userRequest):
lastCharacter=userRequest[-1:]
if lastCharacter=="/":
userRequest=userRequest[:-1]
folderCheck=os.path.isdir(userRequest)
if folderCheck != True:
print("\nSorry, '"+userRequest+"' does not exist, please try again.\n")
requestUserInput()
else:
extractFileList(userRequest)
def extractFileList(userRequest):
fileList=open('/tmp/fileList.txt', 'a')
for folderName, subFolderName, listFiles in os.walk(userRequest):
fileList.write(folderName+":\n")
for fileName in listFiles:
fileList.write(fileName+"\n")
fileList.write("\n")
fileList.close
os.system("readFile.py /tmp/fileList.txt")
if os.path.isfile("/tmp/fileList.txt"):
os.remove("/tmp/fileList.txt")
if __name__ == "__main__":
main()
Second Script:
#!/bin/python
import sys
userFile=sys.argv[1]
f = open(userFile, 'r')
fileInfo=f.read()
sys.stdout.write(fileInfo)
sys.stdout.flush()
f.close

Python: Trying to put the contents of a folder into a text file:

I'm in the process of writing a python script that takes two arguments that will allow me to output the contents of a folder to a text file for me to use for another process. The snippet of I have is below:
#!/usr/bin/python
import cv2
import numpy as np
import random
import sys
import os
import fileinput
#Variables:
img_path= str(sys.argv[1])
file_path = str(sys.argv[2])
print img_path
print file_path
cmd = 'find ' + img_path + '/*.png | sed -e "s/^/\"/g;s/$/\"/g" >' + file_path + '/desc.txt'
print "command: ", cmd
#Generate desc.txt file:
os.system(cmd)
When I try and run that from my command line, I get the following output, and I have no idea how to fix it.
sh: 1: s/$//g: not found
I tested the command I am using by running the following command in a fresh terminal instance, and it works out fine:
images/*.png | sed -e "s/^/\"/g;s/$/\"/g" > desc.txt
Can anyone see why my snippet isn't working? When I run it, I get an empty file...
Thanks in advance!

its not sending the full text for your regular expression through to bash because of how python processes and escapes string content, so the best quickest solution would be to just manually escape the back slashes in the string, because python thinks they currently are escape codes. so change this line:
cmd = 'find ' + img_path + '/*.png | sed -e "s/^/\"/g;s/$/\"/g" >' + file_path + '/desc.txt'
to this:
cmd = 'find ' + img_path + '/*.png | sed -e "s/^/\\"/g;s/$/\\"/g" >' + file_path + '/desc.txt'
and that should work for you.
although, the comment on your question has a great point, you could totally just do it from python, something like:
import os
import sys
def main():
# variables
img_path= str(sys.argv[1])
file_path = str(sys.argv[2])
with open(file_path,'w') as f:
f.writelines(['{}\n'.format(line) for line in os.listdir(img_path) if line.endswith('*.png')])
if __name__ == "__main__":
main()

I fully agree with Kyle. My recommendation is to do using only python code better than call bash commands from your code. Here it is my recommended code, it is longer and not as optimal than the aforementioned one, but IMHO it is a more easy to understand solution.
#!/usr/bin/python
import glob
import sys
import os
# Taking arguments
img_path = str(sys.argv[1])
file_path = str(sys.argv[2])
# lets put the target filename in a variable (it is better than hardcoding it)
file_name = 'desc.txt'
# folder_separator is used to define how your operating system separates folders (unix / and windows \)
folder_separator = '\\' # Windows folders
# folder_separator = '/' # Unix folders
# better if you make sure that the target folder exists
if not os.path.exists(file_path):
# if it does not exist, you create it
os.makedirs(file_path)
# Create the target file (write mode).
outfile = open(file_path + '/' + file_name, 'w')
# loop over folder contents
for fname in glob.iglob("%s/*" % img_path):
# for every file found you take only the name (assuming that structure is folder/file.ext)
file_name_in_imgPath = fname.split('\\')[1]
# we want to avoid to write 'folders' in the target file
if os.path.isfile(file_name_in_imgPath):
# write filename in the target file
outfile.write(str(file_name_in_imgPath) + '\n')
outfile.close()

Trying to access a file located on a flashdrive

I have made a simple test code in python that reads from a text file, and then preforms an action if the text file contains a line "on".
My code works fine if i run the script on my hardive with the text file in the same folder. Example, (C:\Python27\my_file.txt, and C:\Python27\my_scipt.py).
However, if I try this code while my text file is located on my flashdrive and my script is still on my hardrive it won't work even though I have the correct path specified. Example, (G:\flashdrive_folder\flashdrive_file.txt, and C:\Python27\my_scipt.py).
Here is the code I have written out.
def locatedrive():
file = open("G:\flashdrive_folder\flashdrive_file.txt", "r")
flashdrive_file = file.read()
file.close()
if flashdrive_file == "on":
print "working"
else:
print"fail"
while True:
print "trying"
try:
locatedrive()
break
except:
pass
break

The backslash character does double duty. Windows uses it as a path separator, and Python uses it to introduce escape sequences.
You need to escape the backslash (using a backslash!), or use one of the other techniques below:
file = open("G:\\flashdrive_folder\\flashdrive_file.txt", "r")
or
file = open(r"G:\flashdrive_folder\flashdrive_file.txt", "r")
or
file = open("G:/flashdrive_folder/flashdrive_file.txt", "r")

cd /media/usb0
import os
path = "/media/usb0"
#!/usr/bin/python
import os
path = "/usr/tmp"
# Check current working directory.
retval = os.getcwd()
print "Current working directory %s" % retval
# Now change the directory
os.chdir( path )
# Check current working directory.
retval = os.getcwd()
print "Directory changed successfully %s" % retval

Use:
import os
os.chdir(path_to_flashdrive)