how to update model in django by adding new primary key field? - python

How to replace default primary key in Django model with custom primary key field?
I have a model with no primary key defined at first since django automatically adds an id field by default as primary field.
#models.py
from django.db import models
class Event(models.Model):
title = models.CharField(max_length=50, unique=True)
description = models.CharField(max_length=150)
I added some objects into it from django shell.
>>e = Event('meeting', 'Contents about meeting')
>>e.save()
>>e = Event('party', 'Contents about party')
>>e.save()
Then I require to add custom character field as primary into this model.
class Event(models.Model):
event-id = models.CharField(max_length=50, primary_key=True)
...
Running makemigrations:
$ python manage.py makemigrations
You are trying to add a non-nullable field 'event-id' to event without a default; we can't do that (the database needs something to populate existing rows).
Please select a fix:
1) Provide a one-off default now (will be set on all existing rows)
2) Quit, and let me add a default in models.py
Select an option: 1
Please enter the default value now, as valid Python
The datetime and `django.utils.timezone modules` are available, so you can do e.g. timezone.now()
>>> 'meetings'
Migrations for 'blog':
0002_auto_20141201_0301.py:
- Remove field id from event
- Add field event-id to event
But while running migrate it threw an error:
.virtualenvs/env/local/lib/python2.7/site-packages/django/db/backends/sqlite3/base.py", line 485, in execute
return Database.Cursor.execute(self, query, params)
django.db.utils.IntegrityError: UNIQUE constraint failed: blog_event__new.event-id

In my experience (using Django 1.8.* here), I've seen similar situations when trying to update the PK field for models that already exist, have a Foreign Key relationship to another model, and have associated data in the back-end table.
You didn't specify if this model is being used in a FK relation, but it seems this is the case.
In this case, the error message you're getting is because the data that already exists needs to be made consistent with the changes you're requesting --i.e. a new field will be the PK. This implies that the current PK must be dropped for django to 'replace' them. (Django only supports a single PK field per model, as per docs[1].)
Providing a default value that matches currently existing data in the related table should work.
For example:
class Organization(models.Model):
# assume former PK field no longer here; name is the new PK
name = models.CharField(primary_key=True)
class Product(models.Model):
name = models.CharField(primary_key=True)
organization = models.ForeignKey(Organization)
If you're updating the Organization model and products already exist, then existing product rows must be updated to refer to a valid Organization PK value. During the migration, you'd want to choose one of the existing Organization PKs (e.g. 'R&D') to update the existing products.
[1] https://docs.djangoproject.com/en/1.8/topics/db/models/#automatic-primary-key-fields

Django has already established an auto incrementing integer id as primary key in your backend as and when u made the previous model.
When u were trying to run the new model , An attempt was made to recreate a new primary key column that failed.
Another reason is,When u made the field,Django was expecting a unique value be explicitly defined for each new row which it couldn't found,hence the reason.
As told in previous answer you can re-create the migration and then try doing it again.It should work.. cheers :-)

The problem is that you made the field unique, then attempted to use the same value for all the rows in the table. I'm not sure if there's a way to programmatically provide the key, but you could do the following:
Delete the migration
Remove the primary_key attribute from the field
Make a new migration
Apply it
Fill in the value for all your rows
Add the primary_key attribute to the field
Make a new migration
Apply it
It's bruteforce-ish, but should work well enough.
Best of luck!

Related

Why do I get an error when I try to add a new object?

I added a field that is a foreign key called user in a model but I initially received an error that said:
It is impossible to add a non-nullable field 'user' to bid without specifying a default.
So I made the default the string 'user'. However, instead I have been receiving the error:
ValueError: invalid literal for int() with base 10: 'user' when I try to migrate the changes I have made (python3 manage.py migrate).
And when I try to add a new bid, I get an error in the web page:
OperationalError: no such column: auctions_listing.user_id
How do I fix this?
models.py:
class Bid(models.Model):
item = models.ForeignKey(Listing, on_delete=models.CASCADE)
price = models.FloatField()
user = models.ForeignKey(User, on_delete=models.CASCADE)
The fundamental reason you're getting the error is because you have provided a string to an IntegerField.
The real reason you have a problem is because you have tried to run migrations with a new non-nullable field without providing Django with a suitable default value.
When you run the migrations, Django needs to populate the new fields on existing objects with something as it can't enter null. It probably asked you in the terminal whether you would like to provide a default - you entered 'user' when what it wanted was a user_id integer (1, 2, 3, etc.).
This may not be the option you want as you would end up assigning all of the existing items to one particular user. Your fix would be to:
Remove the migration you have tried to apply
Allow the field to be nullable in your code
Re-run the migrations
Assign your desired users to each existing object
Remove the null=True from the field
Run another migration
If it doesn't matter that a particular user would be temporarily allocated all the objects then you can skip the nullable step and just pass a default ID when asked and change them after the migration has been run. You might not want to do this if it will affect current users of your application.
first error:
It is impossible to add a non-nullable field 'user' to bid without
specifying a default.
You faced This error because you already have some records in your database and they didn't have this new field/column 'user', so when you tried to add 'user' field to this table without having null=Ture for it, something like:
user = models.ForeignKey(User, null=True, Blank=True, on_delete=models.CASCADE)
what will happen to the old records? because they didn't have that column already and you didn't provide that new field/column as an unrequired field/column so you should provide a default value for the old record in migrating flow.
second error:
ValueError: invalid literal for int() with base 10: 'user
The Django ORM by default uses integer type for id/pk field of tables, so when you are creating a foreign key in your tables because it refers to a integer field so it should be integer as same as id/pk, (you can set custom type for your foreign keys in Django tables if you want)
Because you provide an string as default for existing records so you entered corrupted data in your table
third error:
OperationalError: no such column: auctions_listing.user_id
This happened because you migration flow faced issues and Django couldn't create new migration for your table
What should you do:
if existed data is not important to you:
truncate your database/table
remove your app migrations
create migrations again
else:
find the existed rows that you create a wrong default value for them
update them with existed users ids (integer value) or add a default integer value in your model field that refers to the your target user, like
user = models.ForeignKey(User, default=1, on_delete=models.CASCADE)

How to make a username as a foreign key of another model in django

I am very new to Django. I want to link a model which has 2 field 'username' and 'password'. I want to make 'username' field as as Foreign in another model. But as per Django we can only pass the whole Model Object, who is referring to as it's foreign key.
am I wrong somewhere? please give me any solution regarding this basic problem.
No you can link to any unique field of a Django model. So if your models look like:
class Target(models.Model):
name = models.CharField(max_length=128, unique=True)
class SourceModel(models.Model):
target = models.ForeignKey(Target, to_field='name', on_delete=models.CASCADE)
You can assign the value of the target column to the target_id then. So for example:
Target.objects.create(name='target1')
SourceModel.objects.create(target_id='target1')
So you do not need to pass a Target object itself. You can use the …_id "twin" field to use the target column value. The database will normally enforce referential integrity, and thus will prevent passing a non-existing value to the foreign key column.

Django. Create composite primary key

I want create composite promary key like {id, project_id}. I remove old tables(all). when i do:
python manage.py makemigrations
I have a mistake:
AssertionError: Model mdm.Group can't have more than one AutoField.
change my model:
id = models.AutoField(db_index=True, primary_key=False)
and add composite primary key as
constraints = [
models.UniqueConstraint(
fields=['id', 'project_id'], name='unique_group_project'
)
]
From docs:
By default, Django gives each model the following field:
id = models.AutoField(primary_key=True)
This is an auto-incrementing primary key.
If you’d like to specify a custom primary key, just specify primary_key=True on one of your fields. If Django sees you’ve explicitly set Field.primary_key, it won’t add the automatic id column.
Each model requires exactly one field to have primary_key=True (either explicitly declared or automatically added).
I just don't understand the problem. If I add AutoField, It's necessarily must PK. How I can resolve problem with Autofield id and composite PK (id, project_id)?

Forked django-oscar app with custom model unable to migrate

I am using django-oscar and forked some of the apps to use a custom model.
Specifically with the catalogue model. By default there are products, product types and product categories. I am trying to extent the model to have a collections table, and to have each product be associated with a collection.
I want to make the relationship so that when a collection is deleted all associated products are deleted, but so that deleting a product does not delete a collection.
Aside from adding a new collection table, I extent the product table to have a multiplier field (which will contain an integer used to multiply the wholesale price...if there is a better way to do this please inform) and a foreign key to the collections table.
Based on my understanding everything looks good. This is my models.py from the forked catalogue app:
from django.db import models
class Collection(models.Model):
name = models.CharField(max_length=50)
prod_category = models.CharField(max_length=50)
description = models.TextField()
manufacturer = models.TextField()
num_products = models.IntegerField()
image_url = models.URLField()
from oscar.apps.catalogue.abstract_models import AbstractProduct
class Product(AbstractProduct):
collection = models.ForeignKey(Collection, on_delete=models.CASCADE)
multiplier = models.DecimalField(max_digits=2, decimal_places=1)
from oscar.apps.catalogue.models import *
When I do makemigrations via manage.py, after asking for default values (something I will deal with later) it seems fine.
When running migrate however, I get the following error output:
Running migrations:
Applying catalogue.0014_auto_20181211_1617...Traceback (most recent call last):
File "/home/mysite/lib/python3.7/Django-2.1.3-py3.7.egg/django/db/backends/utils.py", line 85, in _execute
return self.cursor.execute(sql, params)
psycopg2.IntegrityError: insert or update on table "catalogue_product" violates foreign key constraint "catalogue_product_collection_id_e8789e0b_fk_catalogue"
DETAIL: Key (collection_id)=(1) is not present in table "catalogue_collection".
Is this because I need to add a field collection_id?
The problem is that you have specified a default value that doesn't exist. I am guessing that when asked to specify default values for the migration, you entered 1 for the collection. The problem is that there is no Collection object with such an ID in the database, which is why the migration fails.
You either need to:
Create a Collection object with the default ID you specified before attempting to add the overridden product model.
Make the foreign key to Collection nullable, so that you don't need a default value.

Django ForeignKey which does not require referential integrity?

I'd like to set up a ForeignKey field in a django model which points to another table some of the time. But I want it to be okay to insert an id into this field which refers to an entry in the other table which might not be there. So if the row exists in the other table, I'd like to get all the benefits of the ForeignKey relationship. But if not, I'd like this treated as just a number.
Is this possible? Is this what Generic relations are for?
This question was asked a long time ago, but for newcomers there is now a built in way to handle this by setting db_constraint=False on your ForeignKey:
https://docs.djangoproject.com/en/dev/ref/models/fields/#django.db.models.ForeignKey.db_constraint
customer = models.ForeignKey('Customer', db_constraint=False)
or if you want to to be nullable as well as not enforcing referential integrity:
customer = models.ForeignKey('Customer', null=True, blank=True, db_constraint=False)
We use this in cases where we cannot guarantee that the relations will get created in the right order.
EDIT: update link
I'm new to Django, so I don't now if it provides what you want out-of-the-box. I thought of something like this:
from django.db import models
class YourModel(models.Model):
my_fk = models.PositiveIntegerField()
def set_fk_obj(self, obj):
my_fk = obj.id
def get_fk_obj(self):
if my_fk == None:
return None
try:
obj = YourFkModel.objects.get(pk = self.my_fk)
return obj
except YourFkModel.DoesNotExist:
return None
I don't know if you use the contrib admin app. Using PositiveIntegerField instead of ForeignKey the field would be rendered with a text field on the admin site.
This is probably as simple as declaring a ForeignKey and creating the column without actually declaring it as a FOREIGN KEY. That way, you'll get o.obj_id, o.obj will work if the object exists, and--I think--raise an exception if you try to load an object that doesn't actually exist (probably DoesNotExist).
However, I don't think there's any way to make syncdb do this for you. I found syncdb to be limiting to the point of being useless, so I bypass it entirely and create the schema with my own code. You can use syncdb to create the database, then alter the table directly, eg. ALTER TABLE tablename DROP CONSTRAINT fk_constraint_name.
You also inherently lose ON DELETE CASCADE and all referential integrity checking, of course.
To do the solution by #Glenn Maynard via South, generate an empty South migration:
python manage.py schemamigration myapp name_of_migration --empty
Edit the migration file then run it:
def forwards(self, orm):
db.delete_foreign_key('table_name', 'field_name')
def backwards(self, orm):
sql = db.foreign_key_sql('table_name', 'field_name', 'foreign_table_name', 'foreign_field_name')
db.execute(sql)
Source article
(Note: It might help if you explain why you want this. There might be a better way to approach the underlying problem.)
Is this possible?
Not with ForeignKey alone, because you're overloading the column values with two different meanings, without a reliable way of distinguishing them. (For example, what would happen if a new entry in the target table is created with a primary key matching old entries in the referencing table? What would happen to these old referencing entries when the new target entry is deleted?)
The usual ad hoc solution to this problem is to define a "type" or "tag" column alongside the foreign key, to distinguish the different meanings (but see below).
Is this what Generic relations are for?
Yes, partly.
GenericForeignKey is just a Django convenience helper for the pattern above; it pairs a foreign key with a type tag that identifies which table/model it refers to (using the model's associated ContentType; see contenttypes)
Example:
class Foo(models.Model):
other_type = models.ForeignKey('contenttypes.ContentType', null=True)
other_id = models.PositiveIntegerField()
# Optional accessor, not a stored column
other = generic.GenericForeignKey('other_type', 'other_id')
This will allow you use other like a ForeignKey, to refer to instances of your other model. (In the background, GenericForeignKey gets and sets other_type and other_id for you.)
To represent a number that isn't a reference, you would set other_type to None, and just use other_id directly. In this case, trying to access other will always return None, instead of raising DoesNotExist (or returning an unintended object, due to id collision).
tablename= columnname.ForeignKey('table', null=True, blank=True, db_constraint=False)
use this in your program

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