We Keep Coding

Trouble with webscraping, how to NA when no results?

I have several URLs which link to Hotel pages and I would like to scrape some data from it.
I'm using the following this script, but I would like to update it:
data=[]
for i in range(0,10):
url = final_list[i]
driver2 = webdriver.Chrome()
driver2.get(url)
sleep(randint(10,20))
soup = BeautifulSoup(driver2.page_source, 'html.parser')
my_table2 = soup.find_all(class_=['title-2', 'rating-score body-3'])
review=soup.find_all(class_='reviews')[-1]
try:
price=soup.find_all('span', attrs={'class':'price'})[-1]
except:
price=soup.find_all('span', attrs={'class':'price'})
for tag in my_table2:
data.append(tag.text.strip())
for p in price:
data.append(p)
for r in review:
data.append(r)
But here's the problem, tag.text.strip() scrape rating numbers like here :
It will strip the number rating into alone value but some hotels don't have the same amout of ratings. Here's a hotel with 7 ratings, the default number is 8. Some have seven ratings, other six, and so on. So in the end, my dataframe is quite screwed. If the hotel doesn't have 8 ratings, the value will be shifted.
My question is : How to tell the script "if there is a value in this tag.text.strip(i) so put the value but if there isn't put None. And of course made that for the eight value.
I tried several things like :
for tag in my_table2:
for i in tag.text.strip()[i]:
if i:
data.append(i)
else:
data.append(None)
But unfortunately, that goes nowhere, so if you could help to figure out the answer, it would be awesome :)
If that could help you, I put link on Hotel that I'm scraping :
https://www.hostelworld.com/pwa/hosteldetails.php/Itaca-Hostel/Barcelona/1279?from=2020-11-21&to=2020-11-22&guests=1
The number ratings are at the end
Thank you.

A few suggestions:
Put your data in a dictionary. You don't have to assume that all tags are present and the order of the tags doesn't matter. You can get the labels and the corresponding ratings with
rating_labels = soup.find_all(class_=['rating-label body-3'])
rating_scores = soup.find_all(class_=['rating-score body-3'])
and then iterate over both lists with zip
move your driver outside of the loop, opening it once is enough
don't use wait but you use Selenium's wait functions. You can wait for a particular element to be present or populated with WebDriverWait(driver, 10).until(EC.presence_of_element_located(your_element)
https://selenium-python.readthedocs.io/waits.html
Cache your scraped HTML code to a file. It's faster for you and politer to the website you are scraping
import selenium
import selenium.webdriver
import time
import random
import os
from bs4 import BeautifulSoup
data = []
final_list = [
'https://www.hostelworld.com/pwa/hosteldetails.php/Itaca-Hostel/Barcelona/1279?from=2020-11-21&to=2020-11-22&guests=1',
'https://www.hostelworld.com/pwa/hosteldetails.php/Be-Ramblas-Hostel/Barcelona/435?from=2020-11-27&to=2020-11-28&guests=1'
]
# load your driver only once to save time
driver = selenium.webdriver.Chrome()
for url in final_list:
data.append({})
# cache the HTML code to the filesystem
# generate a filename from the URL where all non-alphanumeric characters (e.g. :/) are replaced with underscores _
filename = ''.join([s if s.isalnum() else '_' for s in url])
if not os.path.isfile(filename):
driver.get(url)
# better use selenium's wait functions here
time.sleep(random.randint(10, 20))
source = driver.page_source
with open(filename, 'w', encoding='utf-8') as f:
f.write(source)
else:
with open(filename, 'r', encoding='utf-8') as f:
source = f.read()
soup = BeautifulSoup(source, 'html.parser')
review = soup.find_all(class_='reviews')[-1]
try:
price = soup.find_all('span', attrs={'class':'price'})[-1]
except:
price = soup.find_all('span', attrs={'class':'price'})
data[-1]['name'] = soup.find_all(class_=['title-2'])[0].text.strip()
rating_labels = soup.find_all(class_=['rating-label body-3'])
rating_scores = soup.find_all(class_=['rating-score body-3'])
assert len(rating_labels) == len(rating_scores)
for label, score in zip(rating_labels, rating_scores):
data[-1][label.text.strip()] = score.text.strip()
data[-1]['price'] = price.text.strip()
data[-1]['review'] = review.text.strip()
The data can then be easily put in a nicely formatted table using Pandas
import pandas as pd
df = pd.DataFrame(data)
df
If some data is missing/incomplete, Pandas will replace it with 'NaN'
data.append(data[0].copy())
del(data[-1]['Staff'])
data[-1]['name'] = 'Incomplete Hostel'
pd.DataFrame(data)

Python extract and append data into data frame

I've scraped the website for my research but I couldn't find the right way to extract it into data frame. I believe that my problem is related with list objects that are between lines 36 and 38.
The print line has worked very nice that I can see the final version of data frame in the Python console.
The solution can be really easy but I couldn't figure it out. Thanks in advance for all help.
from time import sleep
from bs4 import BeautifulSoup, SoupStrainer
import requests
import pandas as pd
# Insert the hisghest page number for website
highest_number = 12
def total_page_number(url):
all_webpage_links = []
all_webpage_links.insert(0, url)
pages = [str(each_number) for each_number in range(2, highest_number)]
for page in pages:
link = ''.join(url + '&page=' + page)
all_webpage_links.append(link)
return all_webpage_links
# Use total_page_number function to create page list for website
All_page = total_page_number(
'https://www.imdb.com/search/title?countries=tr&languages=tr&locations=Turkey&count=250&view=simple')
def clean_text(text):
""" Removes white-spaces before, after, and between characters
:param text: the string to remove clean
:return: a "cleaned" string with no more than one white space between
characters
"""
return ' '.join(text.split())
# Create list objects for data
# Problem occurs in this line !!!!!!
actor_names = []
titles = []
dates = []
def get_cast_from_link(movie_link):
""" Go to the IMDb Movie page in link, and find the cast overview list.
Prints tab-separated movie_title, actor_name, and character_played to
stdout as a result. Nothing returned
:param movie_link: string of the link to IMDb movie page (http://imdb.com
...)
:return: void
"""
movie_page = requests.get(movie_link)
# Use SoupStrainer to strain the cast_list table from the movie_page
# This can save some time in bigger scraping projects
cast_strainer = SoupStrainer('table', class_='cast_list')
movie_soup = BeautifulSoup(movie_page.content, 'html.parser', parse_only=cast_strainer)
# Iterate through rows and extract the name and character
# Remember that some rows might not be a row of interest (e.g., a blank
# row for spacing the layout). Therefore, we need to use a try-except
# block to make sure we capture only the rows we want, without python
# complaining.
for row in movie_soup.find_all('tr'):
try:
actor = clean_text(row.find(itemprop='name').text)
actor_names.append(actor)
titles.append(movie_title)
dates.append(movie_date)
print('\t'.join([movie_title, actor, movie_date]))
except AttributeError:
pass
# Export data frame
# Problem occurs in this line !!!!!!
tsd_df = pd.DataFrame({'Actor_Names': actor_names,
'Movie_Title': titles,
'Movie_Date': dates})
tsd_df.to_csv('/Users/ea/Desktop/movie_df.tsv', encoding='utf-8')
for each in All_page:
# Use requests.get('url') to load the page you want
web_page = requests.get(each)
# https://www.imdb.com/search/title?countries=tr&languages=tr&count=250&view=simple&page=2
# Prepare the SoupStrainer to strain just the tbody containing the list of movies
list_strainer = SoupStrainer('div', class_='lister-list')
# Parse the html content of the web page with BeautifulSoup
soup = BeautifulSoup(web_page.content, 'html.parser', parse_only=list_strainer)
# Generate a list of the "Rank & Title" column of each row and iterate
movie_list = soup.find_all('span', class_='lister-item-header')
for movie in movie_list:
movie_title = movie.a.text
movie_date = movie.find('span', class_='lister-item-year text-muted unbold').text
# get the link to the movie's own IMDb page, and jump over
link = 'http://imdb.com' + movie.a.get('href')
get_cast_from_link(link)
# remember to be nice, and sleep a while between requests!
sleep(15)

How do I web scrape the sub-headers from this link?

I've made a web scraper that scrapes data from pages that look like this (it scrapes the tables): https://www.techpowerup.com/gpudb/2/
The problem is that my program, for some reason, is only scraping the values, and not the subheaders. For instance, (click on the link), it only scrapes the "R420", "130nm", "160 million", etc. but not the "GPU Name", "Process Size", "Transistors" etc.
What do I add to the code to get it to scrape the subheaders? Here's my code:
import csv
import requests
import bs4
url = "https://www.techpowerup.com/gpudb/2"
#obtain HTML and parse through it
response = requests.get(url)
html = response.content
import sys
reload(sys)
sys.setdefaultencoding('utf-8')
soup = bs4.BeautifulSoup(html, "lxml")
tables = soup.findAll("table")
#reading every value in every row in each table and making a matrix
tableMatrix = []
for table in tables:
list_of_rows = []
for row in table.findAll('tr'):
list_of_cells = []
for cell in row.findAll('td'):
text = cell.text.replace(' ', '')
list_of_cells.append(text)
list_of_rows.append(list_of_cells)
tableMatrix.append((list_of_rows, list_of_cells))
#(YOU CAN PROBABLY IGNORE THIS)placeHolder used to avoid duplicate data from appearing in list
placeHolder = 0
excelTable = []
for table in tableMatrix:
for row in table:
if placeHolder == 0:
for entry in row:
excelTable.append(entry)
placeHolder = 1
else:
placeHolder = 0
excelTable.append('\n')
for value in excelTable:
print value
print '\n'
#create excel file and write the values into a csv
fl = open(str(count) + '.csv', 'w')
writer = csv.writer(fl)
for values in excelTable:
writer.writerow(values)
fl.close()

if you check the page source, those cells are header cells. So they are not using TD tags but TH tags. you may want to update your loop to include TH cells alongside TD cells.

How to save the string, one word per column in Python?

I'm scraping the names of massage therapists along with their addresses from a directory. The addresses are all being saved into the CSV in one column for the whole string, but the title/name of each therapist is being saved one word per column over 2 or 3 columns.
What do I need to do in order to get the string that's being extracted to save in one column, like the addresses are being saved? (The top two lines of code are example html from the page, the next set of code is the extract from the script targeting this element)
<span class="name">
<img src="/images/famt-placeholder-sm.jpg" class="thumb" alt="Tiffani D Abraham"> Tiffani D Abraham</span>
import mechanize
from lxml import html
import csv
import io
from time import sleep
def save_products (products, writer):
for product in products:
for price in product['prices']:
writer.writerow([ product["title"].encode('utf-8') ])
writer.writerow([ price["contact"].encode('utf-8') ])
writer.writerow([ price["services"].encode('utf-8') ])
f_out = open('mtResult.csv', 'wb')
writer = csv.writer(f_out)
links = ["https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY","https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY&PageIndex=2&PageSize=10","https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY&PageIndex=3&PageSize=10","https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY&PageIndex=4&PageSize=10","https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY&PageIndex=5&PageSize=10","https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY&PageIndex=6&PageSize=10","https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY&PageIndex=7&PageSize=10", "https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY&PageIndex=8&PageSize=10", "https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY&PageIndex=9&PageSize=10", "https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY&PageIndex=10&PageSize=10" ]
br = mechanize.Browser()
for link in links:
print(link)
r = br.open(link)
content = r.read()
products = []
tree = html.fromstring(content)
product_nodes = tree.xpath('//ul[#class="famt-results"]/li')
for product_node in product_nodes:
product = {}
price_nodes = product_node.xpath('.//a')
product['prices'] = []
for price_node in price_nodes:
price = {}
try:
product['title'] = product_node.xpath('.//span[1]/text()')[0]
except:
product['title'] = ""
try:
price['services'] = price_node.xpath('./span[2]/text()')[0]
except:
price['services'] = ""
try:
price['contact'] = price_node.xpath('./span[3]/text()')[0]
except:
price['contact'] = ""
product['prices'].append(price)
products.append(product)
save_products(products, writer)
f_out.close()

I'm not positive if this solves the issue you were having, but either way there are a few improvements and modifications you might be interested in.
For example, since each link varies by a page index you can loop through the links easily rather than copying all 50 down to a list. Each therapist per page also has their own index, so you can also loop through the xpaths for each therapist's information.
#import modules
import mechanize
from lxml import html
import csv
import io
#open browser
br = mechanize.Browser()
#create file headers
titles = ["NAME"]
services = ["TECHNIQUE(S)"]
contacts = ["CONTACT INFO"]
#loop through all 50 webpages for therapist data
for link_index in range(1,50):
link = "https://www.amtamassage.org/findamassage/results.html?match=exact&l=NY&PageIndex=" + str(link_index) + "&PageSize=10"
r = br.open(link)
page = r.read()
tree = html.fromstring(page)
#loop through therapist data for each therapist per page
for therapist_index in range(1,10):
#store names
title = tree.xpath('//*[#id="content"]/div[2]/ul[1]/li[' + str(therapist_index) + ']/a/span[1]/text()')
titles.append(" ".join(title))
#store techniques and convert to unicode
service = tree.xpath('//*[#id="content"]/div[2]/ul[1]/li[' + str(therapist_index) + ']/a/span[2]/text()')
try:
services.append(service[0].encode("utf-8"))
except:
services.append(" ")
#store contact info and convert to unicode
contact = tree.xpath('//*[#id="content"]/div[2]/ul[1]/li[' + str(therapist_index) + ']/a/span[3]/text()')
try:
contacts.append(contact[0].encode("utf-8"))
except:
contacts.append(" ")
#open file to write to
f_out = open('mtResult.csv', 'wb')
writer = csv.writer(f_out)
#get rows in correct format
rows = zip(titles, services, contacts)
#write csv line by line
for row in rows:
writer.writerow(row)
f_out.close()
The script loops through all 50 links on the provided webpage, and seems to be scraping all relevant information for each therapist if provided. Finally, it prints all the data to a csv with all data stored under respective columns for 'Name', 'Technique(s)', and 'Contact Info' if this is what you were originally struggling with.
Hope this helps!

How to extract data from all urls, not just the first

This script is generating a csv with the data from only one of the urls fed into it. There are meant to be 98 sets of results, however the for loop isn't getting past the first url.
I've been working on this for 12hrs+ today, what am I missing in order get the correct results?
import requests
import re
from bs4 import BeautifulSoup
import csv
#Read csv
csvfile = open("gyms4.csv")
csvfilelist = csvfile.read()
def get_page_data(urls):
for url in urls:
r = requests.get(url.strip())
soup = BeautifulSoup(r.text, 'html.parser')
yield soup # N.B. use yield instead of return
print r.text
with open("gyms4.csv") as url_file:
for page in get_page_data(url_file):
name = page.find("span",{"class":"wlt_shortcode_TITLE"}).text
address = page.find("span",{"class":"wlt_shortcode_map_location"}).text
phoneNum = page.find("span",{"class":"wlt_shortcode_phoneNum"}).text
email = page.find("span",{"class":"wlt_shortcode_EMAIL"}).text
th = pages.find('b',text="Category")
td = th.findNext()
for link in td.findAll('a',href=True):
match = re.search(r'http://(\w+).(\w+).(\w+)', link.text)
if match:
web_address = link.text
gyms = [name,address,phoneNum,email,web_address]
gyms.append(gyms)
#Saving specific listing data to csv
with open ("xgyms.csv", "w") as file:
writer = csv.writer(file)
for row in gyms:
writer.writerow([row])

You have 3 for-loops in your code and do not specifiy which one causes problem. I assume it is the one in get_page_date() function.
You leave the looop exactly in the first run with the return assignemt. That is why you never get to the second url.
There are at least two possible solutions:
Append every parsed line of url to a list and return that list.
Move you processing code in the loops and append the parsed data to gyms in the loop.

As Alex.S said, get_page_data() returns on the first iteration, hence subsequent URLs are never accessed. Furthermore, the code that extracts data from the page needs to be executed for each page downloaded, so it needs to be in a loop too. You could turn get_page_data() into a generator and then iterate over the pages like this:
def get_page_data(urls):
for url in urls:
r = requests.get(url.strip())
soup = BeautifulSoup(r.text, 'html.parser')
yield soup # N.B. use yield instead of return
with open("gyms4.csv") as url_file:
for page in get_page_data(url_file):
name = page.find("span",{"class":"wlt_shortcode_TITLE"}).text
address = page.find("span",{"class":"wlt_shortcode_map_location"}).text
phoneNum = page.find("span",{"class":"wlt_shortcode_phoneNum"}).text
email = page.find("span",{"class":"wlt_shortcode_EMAIL"}).text
# etc. etc.
You can write the data to the CSV file as each page is downloaded and processed, or you can accumulate the data into a list and write it in one for with csv.writer.writerows().
Also you should pass the URL list to get_page_data() rather than accessing it from a global variable.