Output every nth byte of stdin - python

What's the easiest efficient way to read from stdin and output every nth byte?
I'd like a command-line utility that works on OS X, and would prefer to avoid compiled languages.
This Python script is fairly slow (25s for a 3GB file when n=100000000):
#!/usr/bin/env python
import sys
n = int(sys.argv[1])
while True:
chunk = sys.stdin.read(n)
if not chunk:
break
sys.stdout.write(chunk[0])
Unfortunately we can't use sys.stdin.seek to avoid reading the entire file.
Edit: I'd like to optimize for the case when n is a significant fraction of the file size. For example, I often use this utility to sample 500 bytes at equally-spaced locations from a large file.

NOTE: OP change the example n from 100 to 100000000 which effectively render my code slower than his, normally i would just delete my answer since it is no longer better than the original example, but my answer gotten a vote so i will just leave it as it is.
the only way that i can think of to make it faster is to read everything at once and use slice
#!/usr/bin/env python
import sys
n = int(sys.argv[1])
data = sys.stdin.read()
print(data[::n])
although, trying to fit a 3GB file into the ram might be a very bad idea

Related

Python difflib with long diff blocks

I was using Python's difflib to create comprehensive differential logs between rather long files. Everything was running smoothly, until I encountered problem of never-ending diffs. After digging around, it turned out that difflib cannot handle long sequences of semi-matching lines.
Here is a (somewhat minimal) example:
import sys
import random
import difflib
def make_file(fname, dlines):
with open(fname, 'w') as f:
f.write("This is a small file with a long sequence of different lines\n")
f.write("Some of the starting lines could differ {}\n".format(random.random()))
f.write("...\n")
f.write("...\n")
f.write("...\n")
f.write("...\n")
for i in range(dlines):
f.write("{}\t{}\t{}\t{}\n".format(i, i+random.random()/100, i+random.random()/10000, i+random.random()/1000000))
make_file("a.txt", 125)
make_file("b.txt", 125)
with open("a.txt") as ff:
fromlines = ff.readlines()
with open("b.txt") as tf:
tolines = tf.readlines()
diff = difflib.ndiff(fromlines, tolines)
sys.stdout.writelines(diff)
Even for the 125 lines in the example, it took Python over 4 seconds to compute and print the diff, while for GNU Diff it took literally a few milliseconds. And I'm facing problems, where the number of lines is approx. 100 times larger.
Is there a sensible solution to the issue? I hoped for using difflib, as it produces rather nice HTML diffs, but I am open to suggestions. I need a portable solution, that would work on as many platforms as possible, although I am already considering porting GNU Diff for the matter :). Hacking into difflib is also possible as long as I wouldn't have to literally rewrite the whole library.
PS. The files might have variable-length prefixes, so splitting them into parts without aligning diff context might not be the best idea.

python limit must be integer

I'm trying to run the following code but for some reason I get the following error: "TypeError: limit must be an integer".
Reading csv data file
import sys
import csv
maxInt = sys.maxsize
decrement = True
while decrement:
decrement = False
try:
**csv.field_size_limit(maxInt)**
except OverflowError:
maxInt = int(maxInt/10)
decrement = True
with open("Data.csv", 'rb') as textfile:
text = csv.reader(textfile, delimiter=" ", quotechar='|')
for line in text:
print ' '.join(line)
The error occurs in the starred line. I have only added the extra bit above the csv read statement as the file was too large to read normally. Alternatively, I could change the file to a text file from csv but I'm not sure whether this will corrupt the data further I can't actually see any of the data as the file is >2GB and hence costly to open.
Any ideas? I'm fairly new to Python but I'd really like to learn a lot more.
I'm not sure whether this qualifies as an answer or not, but here are a few things:
First, the csv reader automatically buffers per line of the CSV, so the file size shouldn't matter too much, 2KB or 2GB, whatever.
What might matter is the number of columns or amount of data inside the fields themselves. If this CSV contains War and Peace in each column, then yeah, you're going to have an issue reading it.
Some ways to potentially debug are to run print sys.maxsize, and to just open up a python interpreter, import sys, csv and then run csv.field_size_limit(sys.maxsize). If you are getting some terribly small number or an exception, you may have a bad install of Python. Otherwise, try to take a simpler version of your file. Maybe the first line, or the first several lines and just 1 column. See if you can reproduce the smallest possible case and remove the variability of your system and the file size.
On Windows 7 64bit with Python 2.6, maxInt = sys.maxsize returns 9223372036854775807L which consequently results in a TypeError: limit must be an integer when calling csv.field_size_limit(maxInt). Interestingly, using maxInt = int(sys.maxsize) does not change this. A crude workaround is to simlpy use csv.field_size_limit(2147483647) which of course cause issues on other platforms. In my case this was adquat to identify the broken value in the CSV, fix the export options in the other application and remove the need for csv.field_size_limit().
-- originally posted by user roskakori on this related question

Python: Read huge number of lines from stdin

I'm trying to read a huge amount of lines from standard input with python.
more hugefile.txt | python readstdin.py
The problem is that the program freezes as soon as i've read just a single line.
print sys.stdin.read(8)
exit(1)
This prints the first 8 bytes but then i expect it to terminate but it never does. I think it's not really just reading the first bytes but trying to read the whole file into memory.
Same problem with sys.stdin.readline()
What i really want to do is of course to read all the lines but with a buffer so i don't run out of memory.
I'm using python 2.6
This should work efficiently in a modern Python:
import sys
for line in sys.stdin:
# do something...
print line,
You can then run the script like this:
python readstdin.py < hugefile.txt
Back in the day, you had to use xreadlines to get efficient huge line-at-a-time IO -- and the docs now ask that you use for line in file.
Of course, this is of assistance only if you're actually working on the lines one at a time. If you're just reading big binary blobs to pass onto something else, then your other mechanism might be as efficient.

Reading an entire binary file into Python

I need to import a binary file from Python -- the contents are signed 16-bit integers, big endian.
The following Stack Overflow questions suggest how to pull in several bytes at a time, but is this the way to scale up to read in a whole file?
Reading some binary file in Python
Receiving 16-bit integers in Python
I thought to create a function like:
from numpy import *
import os
def readmyfile(filename, bytes=2, endian='>h'):
totalBytes = os.path.getsize(filename)
values = empty(totalBytes/bytes)
with open(filename, 'rb') as f:
for i in range(len(values)):
values[i] = struct.unpack(endian, f.read(bytes))[0]
return values
filecontents = readmyfile('filename')
But this is quite slow (the file is 165924350 bytes). Is there a better way?
Use numpy.fromfile.
I would directly read until EOF (it means checking for receiving an empty string), removing then the need to use range() and getsize.
Alternatively, using xrange (instead of range) should improve things, especially for memory usage.
Moreover, as Falmarri suggested, reading more data at the same time would improve performance quite a lot.
That said, I would not expect miracles, also because I am not sure a list is the most efficient way to store all that amount of data.
What about using NumPy's Array, and its facilities to read/write binary files? In this link there is a section about reading raw binary files, using numpyio.fread. I believe this should be exactly what you need.
Note: personally, I have never used NumPy; however, its main raison d'etre is exactly handling of big sets of data - and this is what you are doing in your question.
You're reading and unpacking 2 bytes at a time
values[i] = struct.unpack(endian,f.read(bytes))[0]
Why don't you read like, 1024 bytes at a time?
I have had the same kind of problem, although in my particular case I have had to convert a very strange binary format (500 MB) file with interlaced blocks of 166 elements that were 3-bytes signed integers; so I've had also the problem of converting from 24-bit to 32-bit signed integers that slow things down a little.
I've resolved it using NumPy's memmap (it's just a handy way of using Python's memmap) and struct.unpack on large chunk of the file.
With this solution I'm able to convert (read, do stuff, and write to disk) the entire file in about 90 seconds (timed with time.clock()).
I could upload part of the code.
I think the bottleneck you have here is twofold.
Depending on your OS and disc controller, the calls to f.read(2) with f being a bigish file are usually efficiently buffered -- usually. In other words, the OS will read one or two sectors (with disc sectors usually several KB) off disc into memory because this is not a lot more expensive than reading 2 bytes from that file. The extra bytes are cached efficiently in memory ready for the next call to read that file. Don't rely on that behavior -- it might be your bottleneck -- but I think there are other issues here.
I am more concerned about the single byte conversions to a short and single calls to numpy. These are not cached at all. You can keep all the shorts in a Python list of ints and convert the whole list to numpy when (and if) needed. You can also make a single call struct.unpack_from to convert everything in a buffer vs one short at a time.
Consider:
#!/usr/bin/python
import random
import os
import struct
import numpy
import ctypes
def read_wopper(filename,bytes=2,endian='>h'):
buf_size=1024*2
buf=ctypes.create_string_buffer(buf_size)
new_buf=[]
with open(filename,'rb') as f:
while True:
st=f.read(buf_size)
l=len(st)
if l==0:
break
fmt=endian[0]+str(l/bytes)+endian[1]
new_buf+=(struct.unpack_from(fmt,st))
na=numpy.array(new_buf)
return na
fn='bigintfile'
def createmyfile(filename):
bytes=165924350
endian='>h'
f=open(filename,"wb")
count=0
try:
for int in range(0,bytes/2):
# The first 32,767 values are [0,1,2..0x7FFF]
# to allow testing the read values with new_buf[value<0x7FFF]
value=count if count<0x7FFF else random.randint(-32767,32767)
count+=1
f.write(struct.pack(endian,value&0x7FFF))
except IOError:
print "file error"
finally:
f.close()
if not os.path.exists(fn):
print "creating file, don't count this..."
createmyfile(fn)
else:
read_wopper(fn)
print "Done!"
I created a file of random shorts signed ints of 165,924,350 bytes (158.24 MB) which comports to 82,962,175 signed 2 byte shorts. With this file, I ran the read_wopper function above and it ran in:
real 0m15.846s
user 0m12.416s
sys 0m3.426s
If you don't need the shorts to be numpy, this function runs in 6 seconds. All this on OS X, python 2.6.1 64 bit, 2.93 gHz Core i7, 8 GB ram. If you change buf_size=1024*2 in read_wopper to buf_size=2**16 the run time is:
real 0m10.810s
user 0m10.156s
sys 0m0.651s
So your main bottle neck, I think, is the single byte calls to unpack -- not your 2 byte reads from disc. You might want to make sure that your data files are not fragmented and if you are using OS X that your free disc space (and here) is not fragmented.
Edit I posted the full code to create then read a binary file of ints. On my iMac, I consistently get < 15 secs to read the file of random ints. It takes about 1:23 to create since the creation is one short at a time.

Moving to an arbitrary position in a file in Python

Let's say that I routinely have to work with files with an unknown, but large, number of lines. Each line contains a set of integers (space, comma, semicolon, or some non-numeric character is the delimiter) in the closed interval [0, R], where R can be arbitrarily large. The number of integers on each line can be variable. Often times I get the same number of integers on each line, but occasionally I have lines with unequal sets of numbers.
Suppose I want to go to Nth line in the file and retrieve the Kth number on that line (and assume that the inputs N and K are valid --- that is, I am not worried about bad inputs). How do I go about doing this efficiently in Python 3.1.2 for Windows?
I do not want to traverse the file line by line.
I tried using mmap, but while poking around here on SO, I learned that that's probably not the best solution on a 32-bit build because of the 4GB limit. And in truth, I couldn't really figure out how to simply move N lines away from my current position. If I can at least just "jump" to the Nth line then I can use .split() and grab the Kth integer that way.
The nuance here is that I don't just need to grab one line from the file. I will need to grab several lines: they are not necessarily all near each other, the order in which I get them matters, and the order is not always based on some deterministic function.
Any ideas? I hope this is enough information.
Thanks!
Python's seek goes to a byte offset in a file, not to a line offset, simply because that's the way modern operating systems and their filesystems work -- the OS/FS just don't record or remember "line offsets" in any way whatsoever, and there's no way for Python (or any other language) to just magically guess them. Any operation purporting to "go to a line" will inevitably need to "walk through the file" (under the covers) to make the association between line numbers and byte offsets.
If you're OK with that and just want it hidden from your sight, then the solution is the standard library module linecache -- but performance won't be any better than that of code you could write yourself.
If you need to read from the same large file multiple times, a large optimization would be to run once on that large file a script that builds and saves to disk the line number - to - byte offset correspondence (technically an "index" auxiliary file); then, all your successive runs (until the large file changes) could very speedily use the index file to navigate with very high performance through the large file. Is this your use case...?
Edit: since apparently this may apply -- here's the general idea (net of careful testing, error checking, or optimization;-). To make the index, use makeindex.py, as follows:
import array
import sys
BLOCKSIZE = 1024 * 1024
def reader(f):
blockstart = 0
while True:
block = f.read(BLOCKSIZE)
if not block: break
inblock = 0
while True:
nextnl = block.find(b'\n', inblock)
if nextnl < 0:
blockstart += len(block)
break
yield nextnl + blockstart
inblock = nextnl + 1
def doindex(fn):
with open(fn, 'rb') as f:
# result format: x[0] is tot # of lines,
# x[N] is byte offset of END of line N (1+)
result = array.array('L', [0])
result.extend(reader(f))
result[0] = len(result) - 1
return result
def main():
for fn in sys.argv[1:]:
index = doindex(fn)
with open(fn + '.indx', 'wb') as p:
print('File', fn, 'has', index[0], 'lines')
index.tofile(p)
main()
and then to use it, for example, the following useindex.py:
import array
import sys
def readline(n, f, findex):
f.seek(findex[n] + 1)
bytes = f.read(findex[n+1] - findex[n])
return bytes.decode('utf8')
def main():
fn = sys.argv[1]
with open(fn + '.indx', 'rb') as f:
findex = array.array('l')
findex.fromfile(f, 1)
findex.fromfile(f, findex[0])
findex[0] = -1
with open(fn, 'rb') as f:
for n in sys.argv[2:]:
print(n, repr(readline(int(n), f, findex)))
main()
Here's an example (on my slow laptop):
$ time py3 makeindex.py kjv10.txt
File kjv10.txt has 100117 lines
real 0m0.235s
user 0m0.184s
sys 0m0.035s
$ time py3 useindex.py kjv10.txt 12345 98765 33448
12345 '\r\n'
98765 '2:6 But this thou hast, that thou hatest the deeds of the\r\n'
33448 'the priest appointed officers over the house of the LORD.\r\n'
real 0m0.049s
user 0m0.028s
sys 0m0.020s
$
The sample file is a plain text file of King James' Bible:
$ wc kjv10.txt
100117 823156 4445260 kjv10.txt
100K lines, 4.4 MB, as you can see; this takes about a quarter second to index and 50 milliseconds to read and print out three random-y lines (no doubt this can be vastly accelerated with more careful optimization and a better machine). The index in memory (and on disk too) takes 4 bytes per line of the textfile being indexed, and performance should scale in a perfectly linear way, so if you had about 100 million lines, 4.4 GB, I would expect about 4-5 minutes to build the index, a minute to extract and print out three arbitrary lines (and the 400 MB of RAM taken for the index should not inconvenience even a small machine -- even my tiny slow laptop has 2GB after all;-).
You can also see that (for speed and convenience) I treat the file as binary (and assume utf8 encoding -- works with any subset like ASCII too of course, eg that KJ text file is ASCII) and don't bother collapsing \r\n into a single character if that's what the file has as line terminator (it's pretty trivial to do that after reading each line if you want).
The problem is that since your lines are not of fixed length, you have to pay attention to line end markers to do your seeking, and that effectively becomes "traversing the file line by line". Thus, any viable approach is still going to be traversing the file, it's merely a matter of what can traverse it fastest.
Another solution, if the file is potentially going to change a lot, is to go full-way to a proper database. The database engine will create and maintain the indexes for you so you can do very fast searches/queries.
This may be an overkill though.

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