I have to create a program that lets the user enter a string and then, using range, the program outputs that same string backwards. I entered this into python, but it goes me an error, in the 4th line, it says 'int' object has no attribute '__getitem__'.
Can someone please help me correct it? (Using range)
user=raw_input("Please enter a string: ")
user1=len(user)-1
for user in range(user1,-1,-1):
user2=user[user1]
print user2
I think you have a mistake because you keep using the same words to describe very different data types. I would use a more descriptive naming scheme:
user = raw_input("Please enter a string: ")
user_length = len(user)
for string_index in range(user_length - 1, -1, -1):
character = user[string_index]
print(character)
For example, if the user input was foo, it would output:
o
o
f
You are overwriting the user string with your for-loop, fix it by changing the for-loop variable
Fix:
for ind in range(user1,-1,-1):
user2 = user[ind]
print (user2)
Alternative (without for-loop):
print user[::-1]
This is because you are overwriting the string user with an int in the line for user in range(...)
Perhaps you'd be better off with:
user=raw_input("Please enter a string: ")
for user1 in range(len(user)-1,-1,-1):
user2=user[user1]
print user2
your user has been overwrited in your for loop. Take this(Use range)
user=raw_input("Please enter a string: ")
print ''.join([user[i] for i in range(len(user)-1, -1, -1)])
Python 3 solution:
user=input("Please enter a string: ")
for ind in range(1,len(user)+1):
char = user[-ind]
print(char)
And another non for loop solution is:
''.join(reversed(user))
Related
I have a txt file with names of people.
I open it and want to get only the names with the length the user entered, using the filter and lambda functions.
The problem is that the list I get is empty [].
names_file = open('names.txt').read().split()
user_choice = input("Enter name length: ")
print(list(filter(lambda c : len(c) == user_choice, names_file)))
What is the problem ?
See this line
user_choice = input("Enter name length: ")
You are taking a string input. If you want to take an integer input you need to write int(input()). I hope this will solve the problem.
user_choice = int(input("Enter name length: "))
should fix it.
This question already has answers here:
Asking the user for input until they give a valid response
(22 answers)
Closed 3 years ago.
I'm attempting to accept user input and check the string for non-alphabet values. My problem is if they enter a bad value, how do I query them again and start the loop over? See below
name = str(input("Enter name:"))
for i in name:
if not i.isalpha():
name = str(input("Enter name:")
**line to start iterating from the beginning with new entry.**
Just trying to verify users only enter letters. If the check fails they enter the name again and it starts over. Thanks in advance!
You can do something like this:
correct = False
while correct == False:
name = str(input("Enter name:"))
for i in name:
if not i.isalpha():
correct = False
break
else:
correct = True
You can see below an example code:
while True:
number_found = False
name = str(input("Enter name:"))
for i in name:
print("Check {} character".format(i))
if i.isdigit():
print("{} is number. Try again.".format(i))
number_found = True
break # Break the for loop when you find the first non-alpha. You can reduce the run-time with this solution.
if not number_found:
break
print("Correct input {}".format(name))
Output:
>>> python3 test.py # Success case
Enter name:test
Check t character
Check e character
Check s character
Check t character
Correct input test
>>> python3 test.py # Failed case
Enter name:test555
Check t character
Check e character
Check s character
Check t character
Check 5 character
5 is number. Try again.
Enter name:
My task is to have the user input an unlimited amount of words while using enter.
Example:
(this is where the program asks the user to input names)
Please input names one by one.
Input END after you've entered the last name.
(this is where the user would input the names)
Sarah
Tyler
Matthew
END
(by pressing enter, they are entering the names into a list until they enter END)
I'm not sure where the coding for this will be. I assume I would use a while loop but I'm not sure how. Thanks.
I'm really really new to programming and I'm really lost. This is what I have so far:
def main() :
name = []
print("Please input names one-by-one for validation.")
diffPasswords = input("Input END after you've entered the last name.")
while True :
if
Try using the below while loop:
l = []
while 'END' not in l:
l.append(input('Name: '))
l.pop()
print(l)
Output:
Name: Sarah
Name: Tyler
Name: Matthew
Name: END
['Sarah', 'Tyler', 'Matthew']
it's simply done with a while loop.
name_list=[]
while True:
i = input('enter').rstrip()
if i == 'END':
break
name_list.append(i)
Basically keep on getting a new line but if it equals END\n then stop. The \n is from the enter. Otherwise add it to the list but make sure to omit the last character because that is the newline character(\n) from the enter.
import sys
list = []
while True:
c = sys.stdin.readline()
if c == "END\n":
break
else:
list.append(c[0:-1])
print(list)
I'm a technical writer learning python. I wanted to write a program for validating the Name field input,as a practise, restricting the the user entries to alphabets.I saw a similar code for validating number (Age)field here, and adopted it for alphabets as below:
import string
import re
r = re.compile(r'[a-zA-Z]+')
print "WELCOME FOR NAME VERIFICATION. TYPE ALPHABETS ONLY!"
print raw_input("Your Name:")
x = r
if x == r:
print x
elif x != r:
print "Come on,'", x,"' can't be your name"
print raw_input("Your Name:")
if 5<=len(x)<=10:
print "Hi,", x, "!"
elif len(x)>10:
print "Mmm,Your name is too long!"
elif len(x)<5:
print "Alas, your name is too short!"
raw_input("Press 'Enter' to exit!")
I intend this code block to do two things. Namely, display the input prompt until the user inputs alphabets only as 'Name'. Then, if that happens, process the length of that input and display messages as coded. But, I get two problems that I could not solve even after a lot of attempts. Either, even the correct entries are rejected by exception code or wrong entries are also accepted and their length is processed.
Please help me to debug my code. And, is it possible to do it without using the reg exp?
If you're using Python, you don't need regular expressions for this--there are included libraries which include functions which might help you. From this page on String methods, you can call isalpha():
Return true if all characters in the string are alphabetic and there is at least one character, false otherwise.
I would suggest using isalpha() in your if-statement instead of x==r.
I don't understand what you're trying to do with
x = r
if x == r:
etc
That condition will obviously always be true.
With your current code you were never saving the input, just printing it straight out.
You also had no loop, it would only ask for the name twice, even if it was wrong both times it would continue.
I think what you tried to do is this:
import string
import re
r = re.compile(r'[a-zA-Z]+')
print "WELCOME FOR NAME VERIFICATION. TYPE ALPHABETS ONLY!"
x = raw_input("Your Name:")
while not r.match(x):
print "Come on,'", x,"' can't be your name"
x = raw_input("Your Name:")
if 5<=len(x)<=10:
print "Hi,", x, "!"
elif len(x)>10:
print "Mmm,Your name is too long!"
elif len(x)<5:
print "Alas, your name is too short!"
raw_input("Press 'Enter' to exit!")
Also, I would not use regex for this, try
while not x.isalpha():
One way to do this would be to do the following:
namefield = raw_input("Your Name: ")
if not namefield.isalpha():
print "Please use only alpha charactors"
elif not 4<=len(namefield)<=10:
print "Name must be more than 4 characters and less than 10"
else:
print "hello" + namefield
isalpha will check to see if the whole string is only alpha characters. If it is, it will return True.
I am very new to Python programming (15 minutes) I wanted to make a simple program that would take an input and then print it back out. This is how my code looks.
Number = raw_input("Enter a number")
print Number
How can I make it so a new line follows. I read about using \n but when I tried:
Number = raw_input("Enter a number")\n
print Number
It didn't work.
Put it inside of the quotes:
Number = raw_input("Enter a number\n")
\n is a control character, sort of like a key on the keyboard that you cannot press.
You could also use triple quotes and make a multi-line string:
Number = raw_input("""Enter a number
""")
If you want the input to be on its own line then you could also just
print "Enter a number"
Number = raw_input()
I do this:
print("What is your name?")
name = input("")
print("Hello" , name + "!")
So when I run it and type Bob the whole thing would look like:
What is your name?
Bob
Hello Bob!
# use the print function to ask the question:
print("What is your name?")
# assign the variable name to the input function. It will show in a new line.
your_name = input("")
# repeat for any other variables as needed
It will also work with: your_name = input("What is your name?\n")
in python 3:
#!/usr/bin/python3.7
'''
Read list of numbers and print it
'''
def enter_num():
i = input("Enter the numbers \n")
for a in range(len(i)):
print i[a]
if __name__ == "__main__":
enter_num()
In the python3 this is the following way to take input from user:
For the string:
s=input()
For the integer:
x=int(input())
Taking more than one integer value in the same line (like array):
a=list(map(int,input().split()))