I have a dataset with 1400 obs and 19 columns. The Target variable has values 1 (value that I am most interested in) and 0. The distribution of classes shows imbalance (70:30).
Using the code below I am getting weird values (all 1s). I am not figuring out if this is due to a problem of overfitting/imbalance data or to feature selection (I used Pearson correlation since all values are numeric/boolean).
I am thinking that the steps followed are wrong.
import numpy as np
import math
import sklearn.metrics as metrics
from sklearn.metrics import f1_score
y = df['Label']
X = df.drop('Label',axis=1)
def create_cv(X,y):
if type(X)!=np.ndarray:
X=X.values
y=y.values
test_size=1/5
proportion_of_true=y[y==1].shape[0]/y.shape[0]
num_test_samples=math.ceil(y.shape[0]*test_size)
num_test_true_labels=math.floor(num_test_samples*proportion_of_true)
num_test_false_labels=math.floor(num_test_samples-num_test_true_labels)
y_test=np.concatenate([y[y==0][:num_test_false_labels],y[y==1][:num_test_true_labels]])
y_train=np.concatenate([y[y==0][num_test_false_labels:],y[y==1][num_test_true_labels:]])
X_test=np.concatenate([X[y==0][:num_test_false_labels] ,X[y==1][:num_test_true_labels]],axis=0)
X_train=np.concatenate([X[y==0][num_test_false_labels:],X[y==1][num_test_true_labels:]],axis=0)
return X_train,X_test,y_train,y_test
X_train,X_test,y_train,y_test=create_cv(X,y)
X_train,X_crossv,y_train,y_crossv=create_cv(X_train,y_train)
tree = DecisionTreeClassifier(max_depth = 5)
tree.fit(X_train, y_train)
y_predict_test = tree.predict(X_test)
print(classification_report(y_test, y_predict_test))
f1_score(y_test, y_predict_test)
Output:
precision recall f1-score support
0 1.00 1.00 1.00 24
1 1.00 1.00 1.00 70
accuracy 1.00 94
macro avg 1.00 1.00 1.00 94
weighted avg 1.00 1.00 1.00 94
Has anyone experienced similar issues in building a classifier when data has imbalance, using CV and/or under sampling? Happy to share the whole dataset, in case you might want to replicate the output.
What I would like to ask you for some clear answer to follow that can show me the steps and what I am doing wrong.
I know that, to reduce overfitting and work with balance data, there are some methods such as random sampling (over/under), SMOTE, CV. My idea is
Split the data on train/test taking into account imbalance
Perform CV on trains set
Apply undersampling only on a test fold
After the model has been chosen with the help of CV, undersample the train set and train the classifier
Estimate the performance on the untouched test set
(f1-score)
as also outlined in this question: CV and under sampling on a test fold .
I think the steps above should make sense, but happy to receive any feedback that you might have on this.
When you have imbalanced data you have to perform stratification. The usual way is to oversample the class that has less values.
Another option is to train your algorithm with less data. If you have a good dataset that should not be a problem. In this case you grab first the samples from the less represented class use the size of the set to compute how many samples to get from the other class:
This code may help you split your dataset that way:
def split_dataset(dataset: pd.DataFrame, train_share=0.8):
"""Splits the dataset into training and test sets"""
all_idx = range(len(dataset))
train_count = int(len(all_idx) * train_share)
train_idx = random.sample(all_idx, train_count)
test_idx = list(set(all_idx).difference(set(train_idx)))
train = dataset.iloc[train_idx]
test = dataset.iloc[test_idx]
return train, test
def split_dataset_stratified(dataset, target_attr, positive_class, train_share=0.8):
"""Splits the dataset as in `split_dataset` but with stratification"""
data_pos = dataset[dataset[target_attr] == positive_class]
data_neg = dataset[dataset[target_attr] != positive_class]
if len(data_pos) < len(data_neg):
train_pos, test_pos = split_dataset(data_pos, train_share)
train_neg, test_neg = split_dataset(data_neg, len(train_pos)/len(data_neg))
# set.difference makes the test set larger
test_neg = test_neg.iloc[0:len(test_pos)]
else:
train_neg, test_neg = split_dataset(data_neg, train_share)
train_pos, test_pos = split_dataset(data_pos, len(train_neg)/len(data_pos))
# set.difference makes the test set larger
test_pos = test_pos.iloc[0:len(test_neg)]
return train_pos.append(train_neg).sample(frac = 1).reset_index(drop = True), \
test_pos.append(test_neg).sample(frac = 1).reset_index(drop = True)
Usage:
train_ds, test_ds = split_dataset_stratified(data, target_attr, positive_class)
You can now perform cross validation on train_ds and evaluate your model in test_ds.
There is another solution that is in the model-level - using models that support weights of samples, such as Gradient Boosted Trees. Of those, CatBoost is usually the best as its training method leads to less leakage (as described in their article).
Example code:
from catboost import CatBoostClassifier
y = df['Label']
X = df.drop('Label',axis=1)
label_ratio = (y==1).sum() / (y==0).sum()
model = CatBoostClassifier(scale_pos_weight = label_ratio)
model.fit(X, y)
And so forth.
This works because Catboost treats each sample with a weight, so you can determine class weights in advance (scale_pos_weight).
This is better than downsampling, and is technically equal to oversampling (but requires less memory).
Also, a major part of treating imbalanced data, is making sure your metrics are weighted as well, or at least well-defined, as you might want equal performance (or skewed performance) on these metrics.
And if you want a more visual output than sklearn's classification_report, you can use one of the Deepchecks built-in checks (disclosure - I'm one of the maintainers):
from deepchecks.checks import PerformanceReport
from deepchecks import Dataset
PerformanceReport().run(Dataset(train_df, label='Label'), Dataset(test_df, label='Label'), model)
your implementation of stratified train/test creation is not optimal, as it lacks randomness. Very often data comes in batches, so it is not a good practice to take sequences of data as is, without shuffling.
as #sturgemeister mentioned, classes ratio 3:7 is not critical, so you should not worry too much of class imbalance. When you artificially change data balance in training you will need to compensate it by multiplication by prior for some algorithms.
as for your "perfect" results either your model overtrained or the model is indeed classifies the data perfectly. Use different train/test split to check this.
another point: your test set is only 94 data points. It is definitely not 1/5 of 1400. Check your numbers.
to get realistic estimates, you need lots of test data. This is the reason why you need to apply Cross Validation strategy.
as for general strategy for 5-fold CV I suggest following:
split your data to 5 folds with respect to labels (this is called stratified split and you can use StratifiedShuffleSplit function)
take 4 splits and train your model. If you want to use under/oversampling, modify the data in those 4 training splits.
apply the model to the remaining part. Do not under/over sample data in the test part. This way you get realistic performance estimate. Save the results.
repeat 2. and 3. for all test splits (totally 5 times obviously). Important: do not change parameters (e.g. tree depth) of the model when training - they should be the same for all splits.
now you have all your data points tested without being trained on them. This is the core idea of cross validation. Concatenate all the saved results, and estimate the performance .
Cross-validation or held-out set
First of all, you are not doing cross-validation. You are splitting your data in a train/validation/test set, which is good, and often sufficient when the number of training samples is large (say, >2e4). However, when the number of samples is small, which is your case, cross-validation becomes useful.
It is explained in depth in scikit-learn's documentation. You will start by taking out a test set from your data, as your create_cv function does. Then, you split the rest of the training data in e.g. 3 splits. Then, you do, for i in {1, 2, 3}: train on data j != i, evaluate on data i. The documentation explains it with prettier and colorful figures, you should have a look! It can be quite cumbersome to implement, but hopefully scikit does it out of the box.
As for the dataset being unbalanced, it is a very good idea to keep the same ratio of labels in each set. But again, you can let scikit handle it for you!
Purpose
Also, the purpose of cross-validation is to choose the right values for the hyper-parameters. You want the right amount of regularization, not too big (under-fitting) nor too small (over-fitting). If you're using a decision tree, the maximum depth (or the minimum number of samples per leaf) is the right metric to consider to estimate the regularization of your method.
Conclusion
Simply use GridSearchCV. You will have cross-validation and label balance done for you.
from sklearn.model_selection import train_test_split
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=1/5, stratified=True)
tree = DecisionTreeClassifier()
parameters = {'min_samples_leaf': [1, 5, 10]}
clf = GridSearchCV(svc, parameters, cv=5) # Specifying cv does StratifiedShuffleSplit, see documentation
clf.fit(iris.data, iris.target)
sorted(clf.cv_results_.keys())
You can also replace the cv variable by a fancier shuffler, such as StratifiedGroupKFold (no intersection between groups).
I would also advise looking towards random trees, which are less interpretable but said to have better performances in practice.
Just wanted to add thresholding and cost sensitive learning to the list of possible approaches mentioned by the others. The former is well described here and consists in finding a new threshold for classifying positive vs negative classes (generally is 0.5 but it can be treated as an hyper parameter). The latter consists on weighting the classes to cope with their unbalancedness. This article was really useful to me to understand how to deal with unbalanced data sets. In it, you can find also cost sensitive learning with a specific explanation using decision tree as a model. Also all other approaches are really nicely reviewed including: Adaptive Synthetic Sampling, informed undersampling etc.
So as a part of my assignment I'm applying linear and lasso regressions, and here's Question 7.
Based on the scores from question 6, what gamma value corresponds to a
model that is underfitting (and has the worst test set accuracy)? What
gamma value corresponds to a model that is overfitting (and has the
worst test set accuracy)? What choice of gamma would be the best
choice for a model with good generalization performance on this
dataset (high accuracy on both training and test set)?
Hint: Try plotting the scores from question 6 to visualize the
relationship between gamma and accuracy. Remember to comment out the
import matplotlib line before submission.
This function should return one tuple with the degree values in this order: (Underfitting, Overfitting, Good_Generalization) Please note there is only one correct solution.
I really need help, I can't really think of any way to solve this last question. What code should I use to determine (Underfitting, Overfitting, Good_Generalization) and why???
Thanks,
Data set: http://archive.ics.uci.edu/ml/datasets/Mushroom?ref=datanews.io
Here's my code from question 6:
from sklearn.svm import SVC
from sklearn.model_selection import validation_curve
def answer_six():
# SVC requires kernel='rbf', C=1, random_state=0 as instructed
# C: Penalty parameter C of the error term
# random_state: The seed of the pseudo random number generator
# used when shuffling the data for probability estimates
# e radial basis function kernel, or RBF kernel, is a popular
# kernel function used in various kernelized learning algorithms,
# In particular, it is commonly used in support vector machine
# classification
model = SVC(kernel='rbf', C=1, random_state=0)
# Return numpy array numbers spaced evenly on a log scale (start,
# stop, num=50, endpoint=True, base=10.0, dtype=None, axis=0)
gamma = np.logspace(-4,1,6)
# Create a Validation Curve for model and subsets.
# Create parameter name and range regarding gamma. Test Scoring
# requires accuracy.
# Validation curve requires X and y.
train_scores, test_scores = validation_curve(model, X_subset, y_subset, param_name='gamma', param_range=gamma, scoring ='accuracy')
# Determine mean for scores and tests along columns (axis=1)
sc = (train_scores.mean(axis=1), test_scores.mean(axis=1))
return sc
answer_six()
Well, make yourself familiar with overfitting. You are supposed to produce something like this: Article on this topic
On the left you have underfitting, on the right overfitting... Where both errors are low you have good generalisation.
And these things are a function of gamma (the regularizor)
Overfitting = your model false
if model false
scatter it
change linear to poly or suport vector with working kernel...
Underfitting = your dataset false
add new data ideal correleated ...
check by nubers
score / accuracy of test and train if test and train high and no big difference you are doiing good ...
if test low or train low then you facing overfitting / underfitting
hope explained you ...
I have a classification problem where I need to predict a class of (0,1) given a data. Basically I have a dataset with more than 300 features (including a target value for prediction) and more than 2000 rows (samples). I applied different classifiers as follows:
1. DecisionTreeClassifier()
2. RandomForestClassifier()
3. GradientBoostingClassifier()
4. KNeighborsClassifier()
Almost all the classifiers gave me similar results around 0.50 AUC value except Random forest around 0.28. I would like to know that whether it is correct if I inverse the RandomForest result like:
1-0.28= 0.72
And report it as the AUC? Is it correct?
Your intuition is not wrong: if a binary classifier performs indeed worse than random (i.e. AUC < 0.5), a valid strategy is to simply invert its predictions, i.e. report a 0 whenever the classifier predicts a 1, and vice versa); from the relevant Wikipedia entry (emphasis added):
The diagonal divides the ROC space. Points above the diagonal represent good classification results (better than random); points below the line represent bad results (worse than random). Note that the output of a consistently bad predictor could simply be inverted to obtain a good predictor.
Nevertheless, the formally correct AUC for this inverted classifier, would be to first invert the individual probabilistic predictions prob of your model:
prob_invert = 1 - prob
and then calculate the AUC using these predictions prob_invert (arguably the process should give similar results with the naive approach you describe of simply subtracting the AUC from 1, but I'm not quire sure of the exact result - see also this Quora answer).
Needless to say, all this is based on the assumption that your whole process is correct, i.e. you don't have any modeling or coding errors (constructing a worse-than-random classifier is not exactly trivial).
I have a dataframe X which is comprised of 60 features and ~ 450k outcomes. My response variable y is categorical (survival, no survival).
I would like to use RFECV to reduce the number of significant features for my estimator (right now, logistic regression) on Xtrain, which I would like to score of accuracy under an ROC Curve. "Features Selected" is a list of all features.
from sklearn.cross_validation import StratifiedKFold
from sklearn.feature_selection import RFECV
import sklearn.linear_model as lm
# Create train and test datasets to evaluate each model
Xtrain, Xtest, ytrain, ytest = train_test_split(X,y,train_size = 0.70)
# Use RFECV to reduce features
# Create a logistic regression estimator
logreg = lm.LogisticRegression()
# Use RFECV to pick best features, using Stratified Kfold
rfecv = RFECV(estimator=logreg, cv=StratifiedKFold(ytrain, 10), scoring='roc_auc')
# Fit the features to the response variable
X_new = rfecv.fit_transform(Xtrain[features_selected], ytrain)
I have a few questions:
a) X_new returns different features when run on separate occasions (one time it returned 5 features, another run it returned 9. One is not a subset of the other). Why would this be?
b) Does this imply an unstable solution? While using the same seed for StratifiedKFold should solve this problem, does this mean I need to reconsider the approach in totality?
c) IN general, how do I approach tuning? e.g., features are selected BEFORE tuning in my current implementation. Would tuning affect the significance of certain features? Or should I tune simultaneously?
In k-fold cross-validation, the original sample is randomly partitioned into k equal size sub-samples. Therefore, it's not surprising to get different results every time you execute the algorithm. Source
There is an approach, so-called Pearson's correlation coefficient. By using this method, you can calculate the a correlation coefficient between each two features, and aim for removing features with a high correlation. This method could be considered as a stable solution to such a problem. Source
I am training my dataset using linearsvm in scikit. Can I calculate/get the probability with which a sample is classified under a given label?
For example, using SGDClassifier(loss="log") to fit the data, enables the predict_proba method, which gives a vector of probability estimates P(y|x) per sample x:
>>> clf = SGDClassifier(loss="log").fit(X, y)
>>> clf.predict_proba([[1., 1.]])
Output:
array([[ 0.0000005, 0.9999995]])
Is there any similar function which I can use to calculate the prediction probability while using svm.LinearSVC (multi-class classification). I know there is a method decision_function to predict the confidence scores for samples in this case. But, is there any way I can calculate probability estimates for the samples using this decision function?
No, LinearSVC will not compute probabilities because it's not trained to do so. Use sklearn.linear_model.LogisticRegression, which uses the same algorithm as LinearSVC but with the log loss. It uses the standard logistic function for probability estimates:
1. / (1 + exp(-decision_function(X)))
(For the same reason, SGDClassifier will only output probabilities when loss="log", not using its default loss function which causes it to learn a linear SVM.)
Multi class classification is a one-vs-all classification. For a SGDClassifier, as a distance to hyperplane corresponding to to particular class is returned, probability is calculated as
clip(decision_function(X), -1, 1) + 1) / 2
Refer to code for details.
You can implement similar function, it seems being reasonable to me for LinearSVC, althrough that probably needs some justification. Refer to paper mentioned in docs
Zadrozny and Elkan, “Transforming classifier scores into multiclass probability estimates”, SIGKDD‘02, http://www.research.ibm.com/people/z/zadrozny/kdd2002-Transf.pdf
P.s. A comment from "Is there 'predict_proba' for LinearSVC?":
if you want probabilities, you should either use Logistic regression or SVC. both can predict probsbilities, but in very diferent ways.