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Is there a function in Python 3 that would allow me to find a substring in any order in a larger string? For example:
ant in Gnat returns True
flat in plat returns False
cooler in polomacear returns True
Here's something I whipped up that will do it. There might be something easier, but it passes tests!
def check(sub, full):
full_list = list(full)
for char in sub:
if char in full_list:
full_list.remove(char)
else:
return False
return True
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So I want to convert strings to shapes after being given a certain string by the user.
e.g "I love squares" = square shape.
what about just looking for the word to convert to in the string? something like this:
userstring = "I love squares"
if not userstring.find('squares') == -1:
create_square()
if not userstring.find('circle') == -1:
create_circle()
#etc etc
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I want to check if the char in string is English alphabetic or not. I mean, the method is.alpha() will return True if I put Hebrew letter, but I want only English letter.
Check if it is letter and if it is ascii character
def isEnglish(s):
return s.isascii() and s.isalpha()
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Below is my list,
['pending/', 'pending/2021-08-01/', 'pending/2021-06-01/', 'pending/2021-06-18/']
And I need to sort the list and filter it to a below format. Please suggest a quicker way to achieve it
['pending/2021-06-01/', 'pending/2021-06-18/', 'pending/2021-08-01/']
When your format is fixed and always starts with "pending" you can use the normal sorted function and count the / in a list comprehension.
>>> values = ['pending/', 'pending/2021-08-01/', 'pending/2021-06-01/', 'pending/2021-06-18/']
>>> sorted(x for x in values if x.count('/') == 2)
['pending/2021-06-01/', 'pending/2021-06-18/', 'pending/2021-08-01/']
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answer=input(print('What s the capital',country,'?'))
RETURN
What s the capital of South Africa ?
None
And I have to put my answer just after the 'none'
You are printing inside the input function and print returns None.
You should do something like this:
country = "Italy"
answer = input(f"What's the capital of {country}? ")
print(answer)
Read the documentation here.
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I have a list output:
['Go497f9te(40RAAC34)\n','G0THDU433(40RAAC33)\n']
and I want to clean it up in order to output:
[40RAAC34,40RAAC33]
If you have a string:
'hello (world)'
and want the text between the brackets, you can either use a regex:
import re
re.findall('\((.*?)\)', s)[0]
#'world'
or, if you are sure that there is only one set of brackets (i.e. no leading ) chars) then you can just use slicing:
s[s.index('(')+1:s.index(')')]
#'world'
So then you just need to throw this into a list-comprehension or similar.
l = ['Go497f9te(40RAAC34)\n','G0THDU433(40RAAC33)\n']
[s[s.index('(')+1:s.index(')')] for s in l]
#['40RAAC34', '40RAAC33']