How to print this pattern? I have done regular patterns but I am unable to get odd stars.
You could use a simple list comprehension:
n = 5
print("\n".join((a := [("* "*i).center(n*2 + 1) for i in range(1, n + 1) if i&1]) + a[::-1][1:]))
*
* * *
* * * * *
* * *
*
You can change n to anything you want
This is my code which i wrote in python
n = 5
row = 2 * n - 2
for i in range(n,-1,-1):
for j in range(row):
print(end="")
row -=2
for k in range(i+1):
print('*',end=" ")
print()
The output what is get is this
* * * * *
* * * *
* * *
* *
*
i want to print this start from left to right order for example
The expected output is :-
* * * * *
* * * *
* * *
* *
*
if it's any possible way to print the elements from left to right because in most of my program i need that logic i'm searching for it please help me and even i used reversed function for loop it will reverse the loop but i'm not getting what i expect
n = 5
print(*[' '.join(' '*i + '*'*(n-i)) for i in range(n)], sep='\n')
Output:
* * * * *
* * * *
* * *
* *
*
Explanation:
for i in range(n):
chars = ' '*i + '*'*(n-i) # creating list of (i) spaces followed
# by (n-i) stars to finish a line of n elements
print(' '.join(chars)) # join prepared values with spaces
Here is a simple solution not using list comprehension:
n = 5
for i in range(n+1):
for j in range(i):
print(" ", end="")
for j in range(i+1, n+1):
print("* ", end="")
print()
Output:
* * * * *
* * * *
* * *
* *
*
My solution - I'm new to python as well:
n = 5
c = 0
for i in range(n, 0, -1):
print(" " * c + "*" * i)
c += 1
or
n = 5
c = 0
while n >= 0:
print(" " * c + "*" * n)
n -= 1
c += 1
The problem is that print itself cannot print right-justified text. But you can print a right-justified string instead of using multiple calls to print.
Here's your original code, using join instead of an inner loop:
n = 5
row = 2 * n - 2
for i in range(n,-1,-1):
for j in range(row):
print(end="")
row -=2
row_str = " ".join(["*"] * i)
print(row_str)
And here's the modified code to make the output right-justified:
n = 5
row = 2 * n - 2
whole = row + 1
for i in range(n,-1,-1):
for j in range(row):
print(end="")
row -=2
row_str = " ".join(["*"] * i).rjust(whole)
print(row_str)
This question already has answers here:
How to recreate pyramid triangle?
(3 answers)
Closed 5 years ago.
I am trying to print a triangle made of asterisk (*) separated by spaces.
If n = 4, it should look like:
*
* *
* * *
* * * *
This is the code I have:
n = 4
for i in range(1, n + 1):
for j in range(i):
print("*")
This is the result I get:
*
*
*
*
*
*
*
*
*
*
I would very appreciate what is wrong with my code...
print() adds a newline to your string each time.
It is easier to multiply the * with the number of times you would like to see it:
n = 4
for i in range(1, n + 1):
print("* " * i)
Output:
*
* *
* * *
* * * *
You could use the built-in "end" parameter:
n = 4
for i in range(1, n + 1):
for j in range(i):
print("*", end=" ")
print()
n = 4
for i in range(1, n + 1):
lvl = ""
for j in range(i):
lvl += "* "
print(lvl)
You need to aggregate the level of the triangle to print.
edit :
if you don't want spaces at the end of the line :-/
n = 4
for i in range(1, n+1):
print( " ".join([c for c in '*' * i]))
Write a program to prompt the user to enter 2 numbers: one for number of columns and one for number of rows and outputs a grid of asterisks with the specified number of rows and columns
Hint: You will need to use one loop nested inside another.
For example, given width = 3 and height = 4, the program should output the following grid:
* * *
* * *
* * *
* * *
This is what I have so far:
width = int(input("Please enter a width for your grid:"))
rows = int(input("Please enter the amount of rows in your grid:"))
for width in range (5,0,-1):
print(width * ' ' + (5 - width) * '*')
Just a snippet:
w = 5
h = 4
for i in range(h):
print ' *' * w + ' '
output:
* * * * *
* * * * *
* * * * *
* * * * *
Since you're being asked to use nested loops, you'll want to print asterisks separated by spaces in the inner loop, and move to the next line at the end of that loop:
for x in range(rows):
for y in range(width):
print('*',end = ' ')
print()
My goal is to create a hollow diamond using python.
Sample input:
Input an odd Integer:
9
Sample output:
*
* *
* *
* *
* *
* *
* *
* *
*
But so far, I have the following code that is not working right. Please help me to modify the code to achieve the goal above:
a=int(input("Input an odd integer: "))
k=1
c=1
r=a
while k<=r:
while c<=r:
print "*"
c+=1
r-=1
c=1
while c<=2*k-1:
print "*"
c+=1
print "\n"
k+=1
r=1
k=1
c=1
while k<=a-1:
while c<=r:
print " "
c+=1
r+=1
c=1
while c<= 2*(a-k)-1:
print ("*")
c+=1
print "\n"
k+=1
The code above return a result that is very far from my goal.
Input an odd integer: 7
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
I am actually converting the code from this post: http://www.programmingsimplified.com/c/source-code/c-program-print-diamond-pattern written in C language and will modify later for the hollow one but I can't get it... There is something wrong with my conversion..
A Hollow diamond is the solution to the equation
|x|+|y| = N
on an integer grid. So Hollow diamond as a 1-liner:
In [22]: N = 9//2; print('\n'.join([''.join([('*' if abs(x)+abs(y) == N else ' ') for x in range(-N, N+1)]) for y in range(-N, N+1)]))
*
* *
* *
* *
* *
* *
* *
* *
*
Your problem is that you keep using print. The print statement (and the function in Python 3) will add a line-break after what you printed, unless you explicitely tell it not to. You can do that in Python 2 like this:
print '*', # note the trailing comma
Or in Python 3 (with the print function) like this:
print('*', end='')
My solution
I took my own take at the problem and came up with this solution:
# The diamond size
l = 9
# Initialize first row; this will create a list with a
# single element, the first row containing a single star
rows = ['*']
# Add half of the rows; we loop over the odd numbers from
# 1 to l, and then append a star followed by `i` spaces and
# again a star. Note that range will not include `l` itself.
for i in range(1, l, 2):
rows.append('*' + ' ' * i + '*')
# Mirror the rows and append; we get all but the last row
# (the middle row) from the list, and inverse it (using
# `[::-1]`) and add that to the original list. Now we have
# all the rows we need. Print it to see what's inside.
rows += rows[:-1][::-1]
# center-align each row, and join them
# We first define a function that does nothing else than
# centering whatever it gets to `l` characters. This will
# add the spaces we need around the stars
align = lambda x: ('{:^%s}' % l).format(x)
# And then we apply that function to all rows using `map`
# and then join the rows by a line break.
diamond = '\n'.join(map(align, rows))
# and print
print(diamond)
def diamond(n, c='*'):
for i in range(n):
spc = i * 2 - 1
if spc >= n - 1:
spc = n - spc % n - 4
if spc < 1:
print(c.center(n))
else:
print((c + spc * ' ' + c).center(n))
if __name__ == '__main__':
diamond(int(input("Input an odd integer: ")))
this is not pretty, but its a function that does what you want:
def make_diamond(size):
if not size%2:
raise ValueError('odd number required')
r = [' ' * space + '*' + ' ' * (size-2-(space*2)) + '*' + ' ' * space for space in xrange((size-1)/2)]
r.append(' ' * ((size-1)/2) + '*' + ' ' * ((size-1)/2))
return '\n'.join(r[-1:0:-1] + r)
first i check to make sure its an odd number,
then i create a list of the lines from the center downwards.
then i create the last point.
then i return them as as a string, with a mirror of the bottom on top without the center line.
output:
>>> print make_diamond(5)
*
* *
* *
* *
*
>>> print make_diamond(9)
*
* *
* *
* *
* *
* *
* *
* *
*
Made it in one single loop ;)
x = input("enter no of odd lines : ") #e.g. x=5
i = int(math.fabs(x/2)) # i=2 (loop for spaces before first star)
j = int(x-2) #j=3 # y & j carry loops for spaces in between
y = int(x-3) #y=2
print ( " " * i + "*" )
i = i-1 #i=1
while math.fabs(i) <= math.fabs((x/2)-1): # i <= 1
b = int(j- math.fabs(y)) # b = (1, 3, 1) no of spaces in between stars
a = int(math.fabs(i)) # a = (1, 0, 1) no of spaces before first star
print (" "* a + "*" + " "*b + "*")
y = y-2 # 2,0,-2
i = i-1 # 1,0,-1, -2 (loop wont run for -2)
i = int(math.fabs(i)) # i = -2
print ( " " * i + "*")
The previous answer has got two corrections, which've been done here :
import math
x = int(input("enter no of odd lines : ")) #e.g. x=5
i = int(math.fabs(x/2)) # i=2 (loop for spaces before first star)
j = int(x-2) #j=3 # y & j carry loops for spaces in between
y = int(x-3) #y=2
print ( " " * i + "*" )
i = i-1 #i=1
while math.fabs(i) <= math.fabs((x/2)-1): # i <= 1
b = int(j- math.fabs(y)) # b = (1, 3, 1) no of spaces in between stars
a = int(math.fabs(i)) # a = (1, 0, 1) no of spaces before first star
print (" "* a + "*" + " "*b + "*")
y = y-2 # 2,0,-2
i = i-1 # 1,0,-1, -2 (loop wont run for -2)
i = int(math.fabs(i)) # i = -2
print ( " " * i + "*")
Note : Now this works for both python 2.5x and python 3.x
If you wish to know the difference in the two answers, then google it!
sizeChoice = 13
N = sizeChoice//2
for column in range (-N, N + 1):
for row in range (-N, N + 1):
if abs(column) + abs(row) == N:
print ("*", end = " ")
else:
print(" ", end = " ")
print ( )
this code works perfectly to print a hollow diamond where you can set diagonal length upto user requirement
n=int(input('Enter Odd Diagonal length :'))-1
j=n-1
print(' '*(n)+'*')
for i in range(1, 2*n):
if i>n:
print(' '*(i-n)+'*'+' '*(2*j-1)+'*')
j-=1
else:
print(' '*(n-i)+'*'+' '*(2*i-1)+'*')
if n>1:
print(' '*n+'*')
Hallow Diamond in Python using only print function
for i in range(1,6):
print(' '*(5-i) + '*'*1 + ' '*(i-1) + ' '*max((i-2),0) + '*'*(1%i) )
for j in range(4,0,-1):
print(' '*(5-j) + '*'*1 + ' '*(j-1) + ' '*max((j-2),0) + '*'*(1%j) )