I'm using the following python code to connect to a jsonrpc server and nick some song information. However, I can't work out how to get the current title in to a variable to print elsewhere. Here is the code:
TracksInfo = []
for song in playingSongs:
data = { "id":1,
"method":"slim.request",
"params":[ "",
["songinfo",0,100, "track_id:%s" % song, "tags:GPASIediqtymkovrfijnCYXRTIuwxN"]
]
}
params = json.dumps(data, sort_keys=True, indent=4)
conn.request("POST", "/jsonrpc.js", params)
httpResponse = conn.getresponse()
data = httpResponse.read()
responce = json.loads(data)
print json.dumps(responce, sort_keys=True, indent=4)
TrackInfo = responce['result']["songinfo_loop"][0]
TracksInfo.append(TrackInfo)
This brings me back the data in json format and the print json.dump brings back:
pi#raspberrypi ~/pithon $ sudo python tom3.py
{
"id": 1,
"method": "slim.request",
"params": [
"",
[
"songinfo",
"0",
100,
"track_id:-140501481178464",
"tags:GPASIediqtymkovrfijnCYXRTIuwxN"
]
],
"result": {
"songinfo_loop": [
{
"id": "-140501481178464"
},
{
"title": "Witchcraft"
},
{
"artist": "Pendulum"
},
{
"duration": "253"
},
{
"tracknum": "1"
},
{
"type": "Ogg Vorbis (Spotify)"
},
{
"bitrate": "320k VBR"
},
{
"coverart": "0"
},
{
"url": "spotify:track:2A7ZZ1tjaluKYMlT3ItSfN"
},
{
"remote": 1
}
]
}
}
What i'm trying to get is result.songinfoloop.title (but I tried that!)
The songinfo_loop structure is.. peculiar. It is a list of dictionaries each with just one key.
Loop through it until you have one with a title:
TrackInfo = next(d['title'] for d in responce['result']["songinfo_loop"] if 'title' in d)
TracksInfo.append(TrackInfo)
A better option would be to 'collapse' all those dictionaries into one:
songinfo = reduce(lambda d, p: d.update(p) or d,
responce['result']["songinfo_loop"], {})
TracksInfo.append(songinfo['title'])
songinfo_loop is a list not a dict. That means you need to call it by position, or loop through it and find the dict with a key value of "title"
positional:
responce["result"]["songinfo_loop"][1]["title"]
loop:
for info in responce["result"]["songinfo_loop"]:
if "title" in info.keys():
print info["title"]
break
else:
print "no song title found"
Really, it seems like you would want to have the songinfo_loop be a dict, not a list. But if you need to leave it as a list, this is how you would pull the title.
The result is really a standard python dict, so you can use
responce["result"]["songinfoloop"]["title"]
which should work
Related
resp = {
"Name": "test",
"os": "windows",
"Agent": {
"id": "2",
"status": [
{
"code": "123",
"level": "Info",
"displayStatus": "Ready",
"message": "running",
"time": "2022-01-18T09:51:08+00:00"
}
]
}
I am trying to get the time value from the JSON.
I tried the below code but faced error with dict
resp1 = json.loads(resp)
resp2 = resp1.values()
creation_time = resp2.get("Agent").get("status")
val= creation_time["time"]
print(val) ## Thrwoing error as dict_values has no 'get'
Any suggestion on python how to take this time values
Few problems I noticed
You are trying to load a Dict type using the json's loads function which is supposed to get a string in json format (ex: '{ "name":"John", "age":30, "city":"New York"}')
You tried to access resp2 before declaration (I guessed you meant "resp1?")
You're using resp3 without declaration.
You are missing }
You don't need the .value() function because it will return a list.
Also creation time is a list with one object, so you need to access it too.
Considering all this, you can change it as follows:
import json
resp = '{ "Name": "test", "os": "windows","Agent": {"id": "2","status": [{"code": "123","level": "Info","displayStatus": "Ready","message": "running","time": "2022-01-18T09:51:08+00:00"}]}}'
resp1 = json.loads(resp)
creation_time = resp1.get("Agent").get("status")
val= creation_time[0]["time"]
print(val)
You just need to access the dicts using [] like so:
resp = {"Name": "test", "os": "windows", "Agent": {"id": "2","status": [{"code": "123","level": "Info","displayStatus": "Ready","message": "running","time": "2022-01-18T09:51:08+00:00"}]}}
creation_time = resp["Agent"]["status"]
val= creation_time[0]["time"]
print(val)
Output:
2022-01-18T09:51:08+00:00
I have a dictionary below:
event = {
"body-json": {},
"params": {
"path": {
"matchphrase": "term"
},
"querystring": {
"dataproduct.keyword": "health"
},
"header": {
"Accept": "application/json"
}
},
"resource-path": "/{matchphrase}"
}
I would like to access the above event dictionary keys & values and frame a new dictionary as follows:
{"query": {"term" : {"dataproduct.keyword": "health"}}}
Here is the code what I tried:
a = event['params']['path']['matchphrase'] #term
b = list(event['params']['querystring'].keys())[0] #dataproduct.keyword
c = list(event['params']['querystring'].values())[0] #health
body=f"{query: {{a} : {{b}: {c}}}}"
print(body)
Am I missing something ?
This should work :
body = {"query":{str(a):{str(b):str(c)}}}
print(body)
The escaping is wrong.
Try this instead:
body = f'{{"query": {{{a!r}: {{{b!r}: {c!r}}}}}}}'
I've also added !r which will return the real representation (repr) of the object (so you don't need to artificially add quotes).
you can create a dictionary and then get a string version of it using json.dumps.
import json
event = {
"body-json": {},
"params": {
"path": {"matchphrase": "term"},
"querystring": {"dataproduct.keyword": "health"},
"header": {"Accept": "application/json"},
},
"resource-path": {"matchphrase}"},
}
a = event["params"]["path"]["matchphrase"] # term
b = list(event["params"]["querystring"].keys())[0] # dataproduct.keyword
c = list(event["params"]["querystring"].values())[0] # health
result = {"query": {a: {b: c}}}
print(json.dumps(result))
Output:
{"query": {"term": {"dataproduct.keyword": "health"}}}
I am attempting to parse a json response that looks like this:
{
"links": {
"next": "http://www.neowsapp.com/rest/v1/feed?start_date=2015-09-08&end_date=2015-09-09&detailed=false&api_key=xxx",
"prev": "http://www.neowsapp.com/rest/v1/feed?start_date=2015-09-06&end_date=2015-09-07&detailed=false&api_key=xxx",
"self": "http://www.neowsapp.com/rest/v1/feed?start_date=2015-09-07&end_date=2015-09-08&detailed=false&api_key=xxx"
},
"element_count": 22,
"near_earth_objects": {
"2015-09-08": [
{
"links": {
"self": "http://www.neowsapp.com/rest/v1/neo/3726710?api_key=xxx"
},
"id": "3726710",
"neo_reference_id": "3726710",
"name": "(2015 RC)",
"nasa_jpl_url": "http://ssd.jpl.nasa.gov/sbdb.cgi?sstr=3726710",
"absolute_magnitude_h": 24.3,
"estimated_diameter": {
"kilometers": {
"estimated_diameter_min": 0.0366906138,
"estimated_diameter_max": 0.0820427065
},
"meters": {
"estimated_diameter_min": 36.6906137531,
"estimated_diameter_max": 82.0427064882
},
"miles": {
"estimated_diameter_min": 0.0227984834,
"estimated_diameter_max": 0.0509789586
},
"feet": {
"estimated_diameter_min": 120.3760332259,
"estimated_diameter_max": 269.1689931548
}
},
"is_potentially_hazardous_asteroid": false,
"close_approach_data": [
{
"close_approach_date": "2015-09-08",
"close_approach_date_full": "2015-Sep-08 09:45",
"epoch_date_close_approach": 1441705500000,
"relative_velocity": {
"kilometers_per_second": "19.4850295284",
"kilometers_per_hour": "70146.106302123",
"miles_per_hour": "43586.0625520053"
},
"miss_distance": {
"astronomical": "0.0269230459",
"lunar": "10.4730648551",
"kilometers": "4027630.320552233",
"miles": "2502653.4316094954"
},
"orbiting_body": "Earth"
}
],
"is_sentry_object": false
},
}
I am trying to figure out how to parse through to get "miss_distance" dictionary values ? I am unable to wrap my head around it.
Here is what I have been able to do so far:
After I get a Response object from request.get()
response = request.get(url
I convert the response object to json object
data = response.json() #this returns dictionary object
I try to parse the first level of the dictionary:
for i in data:
if i == "near_earth_objects":
dataset1 = data["near_earth_objects"]["2015-09-08"]
#this returns the next object which is of type list
Please someone can explain me :
1. How to decipher this response in the first place.
2. How can I move forward in parsing the response object and get to miss_distance dictionary ?
Please any pointers/help is appreciated.
Thank you
Your data will will have multiple dictionaries for the each date, near earth object, and close approach:
near_earth_objects = data['near_earth_objects']
for date in near_earth_objects:
objects = near_earth_objects[date]
for object in objects:
close_approach_data = object['close_approach_data']
for close_approach in close_approach_data:
print(close_approach['miss_distance'])
The code below gives you a table of date, miss_distances for every object for every date
import json
raw_json = '''
{
"near_earth_objects": {
"2015-09-08": [
{
"close_approach_data": [
{
"miss_distance": {
"astronomical": "0.0269230459",
"lunar": "10.4730648551",
"kilometers": "4027630.320552233",
"miles": "2502653.4316094954"
},
"orbiting_body": "Earth"
}
]
}
]
}
}
'''
if __name__ == "__main__":
parsed = json.loads(raw_json)
# assuming this json includes more than one near_earch_object spread across dates
near_objects = []
for date, near_objs in parsed['near_earth_objects'].items():
for obj in near_objs:
for appr in obj['close_approach_data']:
o = {
'date': date,
'miss_distances': appr['miss_distance']
}
near_objects.append(o)
print(near_objects)
output:
[
{'date': '2015-09-08',
'miss_distances': {
'astronomical': '0.0269230459',
'lunar': '10.4730648551',
'kilometers': '4027630.320552233',
'miles': '2502653.4316094954'
}
}
]
I'm in over my head, trying to parse JSON for my first time and dealing with a multi dimensional array.
{
"secret": "[Hidden]",
"minutes": 20,
"link": "http:\/\/www.1.com",
"bookmark_collection": {
"free_link": {
"name": "#free_link#",
"bookmarks": [
{
"name": "1",
"link": "http:\/\/www.1.com"
},
{
"name": "2",
"link": "http:\/\/2.dk"
},
{
"name": "3",
"link": "http:\/\/www.3.in"
}
]
},
"boarding_pass": {
"name": "Boarding Pass",
"bookmarks": [
{
"name": "1",
"link": "http:\/\/www.1.com\/"
},
{
"name": "2",
"link": "http:\/\/www.2.com\/"
},
{
"name": "3",
"link": "http:\/\/www.3.hk"
}
]
},
"sublinks": {
"name": "sublinks",
"link": [
"http:\/\/www.1.com",
"http:\/\/www.2.com",
"http:\/\/www.3.com"
]
}
}
}
This is divided into 3 parts, the static data on my first dimension (secret, minutes, link) Which i need to get as seperate strings.
Then I need a dictionary per "bookmark collection" which does not have fixed names, so I need the name of them and the links/names of each bookmark.
Then there is the seperate sublinks which is always the same, where I need all the links in a seperate dictionary.
I'm reading about parsing JSON but most of the stuff I find is a simple array put into 1 dictionary.
Does anyone have any good techniques to do this ?
After you parse the JSON, you will end up with a Python dict. So, suppose the above JSON is in a string named input_data:
import json
# This converts from JSON to a python dict
parsed_input = json.loads(input_data)
# Now, all of your static variables are referenceable as keys:
secret = parsed_input['secret']
minutes = parsed_input['minutes']
link = parsed_input['link']
# Plus, you can get your bookmark collection as:
bookmark_collection = parsed_input['bookmark_collection']
# Print a list of names of the bookmark collections...
print bookmark_collection.keys() # Note this contains sublinks, so remove it if needed
# Get the name of the Boarding Pass bookmark:
print bookmark_collection['boarding_pass']['name']
# Print out a list of all bookmark links as:
# Boarding Pass
# * 1: http://www.1.com/
# * 2: http://www.2.com/
# ...
for bookmark_definition in bookmark_collection.values():
# Skip sublinks...
if bookmark_definition['name'] == 'sublinks':
continue
print bookmark_definition['name']
for bookmark in bookmark_definition['bookmarks']:
print " * %(name)s: %(link)s" % bookmark
# Get the sublink definition:
sublinks = parsed_input['bookmark_collection']['sublinks']
# .. and print them
print sublinks['name']
for link in sublinks['link']:
print ' *', link
Hmm, doesn't json.loads do the trick?
For example, if your data is in a file,
import json
text = open('/tmp/mydata.json').read()
d = json.loads(text)
# first level fields
print d['minutes'] # or 'secret' or 'link'
# the names of each of bookmark_collections's items
print d['bookmark_collection'].keys()
# the sublinks section, as a dict
print d['bookmark_collection']['sublinks']
The output of this code (given your sample input above) is:
20
[u'sublinks', u'free_link', u'boarding_pass']
{u'link': [u'http://www.1.com', u'http://www.2.com', u'http://www.3.com'], u'name': u'sublinks'}
Which, I think, gets you what you need?
I'm reading in a JSON string which is littered with u'string' style strings. Example:
[
{
"!\/award\/award_honor\/honored_for": {
"award": {
"id": "\/en\/spiel_des_jahres"
},
"year": {
"value": "1996"
}
},
"guid": "#9202a8c04000641f80000000003a0ee6",
"type": "\/games\/game",
"id": "\/en\/el_grande",
"name": "El Grande"
},
{
"!\/award\/award_honor\/honored_for": {
"award": {
"id": "\/en\/spiel_des_jahres"
},
"year": {
"value": "1995"
}
},
"guid": "#9202a8c04000641f80000000000495ec",
"type": "\/games\/game",
"id": "\/en\/settlers_of_catan",
"name": "Settlers of Catan"
}
]
If I assign name = result.name. Then when I log of pass that value to a Django template, it displays as u'Dominion'
How do I format it to display as Dominion?
++ UPDATE ++
I think the problem has to do with printing values from a list or dictionary. For example:
result = freebase.mqlread(query)
games = {}
count = 0
r = result[0]
name = r.name
games["name"] = name,
self.response.out.write(games["name"])
self.response.out.write(name)
This displays as:
(u'Dominion',) // saved response to dictionary, and then printed
Dominion // when calling the value directly from the response
I need to iterate through an array of JSON items and the values are being shown with the unicode. Why?
The comma at the end of games["name"] = name, makes it a 1-tuple. Remove it.
>>> # example
>>> s = u"Jägermütze"
>>> s.encode("utf-8")
'J\xc3\xa4germ\xc3\xbctze'
>>> print s.encode("utf-8") # on a utf-8 terminal
Jägermütze
Don't know much about Django, but not accepting snicode strings seems unpythonic to me.
You can use str(your string) to do this.