We Keep Coding

LookupError: unknown encoding: utf8r

when I try the code:
f = open("xronia.txt", "r")
for x in f:
print(x)
I always take this Error:Traceback (most recent call last):
File "C:\Users\Desktop\PYTHON\Προγραμματισμός Σταύρος\disekta.py",
line 2, in
lines=fo.readlines() File "C:\Users\AppData\Local\Programs\Python\Python38-32\lib\encodings\cp1253.py",
line 23, in decode
return codecs.charmap_decode(input,self.errors,decoding_table)[0] UnicodeDecodeError: 'charmap' codec can't decode byte 0xff in position
0: character maps to
I have tried to use encoding='utf8' but it didn't work. The file is an excel file formatted as .txt(as I read in a site). I am new to this world, so any help is acceptable..

How to read and understand the .hcc file with Python?

I am having a .hcc file, which I am trying to read but I am getting error.
This is what I am tried:
chardetect 2016.hcc
2016.hcc: windows-1253 with confidence 0.2724130248827703
I have tried the following:
>>> with open("2016.hcc","r",encoding="windows-1253") as f:
... print(f.read())
...
Traceback (most recent call last):
File "<stdin>", line 2, in <module>
File "C:\Python35\lib\encodings\cp1253.py", line 23, in decode
return codecs.charmap_decode(input,self.errors,decoding_table)[0]
UnicodeDecodeError: 'charmap' codec can't decode byte 0x9c in position 232: character maps to <undefined>
then I tried this without using encoding:
>>> with open("2016.hcc","r") as f:
... print(f.read())
...
Traceback (most recent call last):
File "<stdin>", line 2, in <module>
File "C:\Python35\lib\encodings\cp1252.py", line 23, in decode
return codecs.charmap_decode(input,self.errors,decoding_table)[0]
UnicodeDecodeError: 'charmap' codec can't decode byte 0x9d in position 284: character maps to <undefined>
After opening the file in byte mode, I was able to read but none was understandable.
Here is the sample file: 2016.hcc
Please let me know how I can do that.
**UPDATED ATTEMPT: **
>>> with open("2016.hcc","r",encoding="utf-16") as f:
... print(f.read())
...
Traceback (most recent call last):
File "<stdin>", line 2, in <module>
File "C:\Python35\lib\codecs.py", line 321, in decode
(result, consumed) = self._buffer_decode(data, self.errors, final)
File "C:\Python35\lib\encodings\utf_16.py", line 61, in _buffer_decode
codecs.utf_16_ex_decode(input, errors, 0, final)
UnicodeDecodeError: 'utf-16-le' codec can't decode bytes in position 15390-15391: illegal encoding

Python - cannot decode html (urllib)

I'm trying to write html from webpage to file, but I have problem with decode characters:
import urllib.request
response = urllib.request.urlopen("https://www.google.com")
charset = response.info().get_content_charset()
print(response.read().decode(charset))
Last line causes error:
Traceback (most recent call last):
File "script.py", line 7, in <module>
print(response.read().decode(charset))
UnicodeEncodeError: 'ascii' codec can't encode character '\u015b' in
position 6079: ordinal not in range(128)
response.info().get_content_charset() returns iso-8859-2, but if i check content of response without decoding (print(resposne.read())) there is "utf-8" encoding as html metatag. If i use "utf-8" in decode function there is also similar problem:
Traceback (most recent call last):
File "script.py", line 7, in <module>
print(response.read().decode("utf-8"))
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xb6 in position
6111: invalid start byte
What's going on?

You can ignore invalid characters using
response.read().decode("utf-8", 'ignore')
Instead of ignore there are other options, e.g. replace
https://www.tutorialspoint.com/python/string_encode.htm
https://docs.python.org/3/howto/unicode.html#the-string-type
(There is also str.encode(encoding='UTF-8',errors='strict') for strings.)

Resolving ascii codec can't decode byte in position ordinal not in range

I've seen all of the other posts and done quite a bit of research but I am still scratching my head.
Here is the problem:
$ python
Python 2.7.6 (default, Mar 22 2014, 22:59:56)
[GCC 4.8.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> a=u'My Mate\u2019s'
>>> b='\xe2\x80\x99s BBQ'
>>> print a
My Mate’s
>>> print b
’s BBQ
So, the variables are finely printed themselves, but printing a concatenation:
>>> print a+b
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe2 in position 0: ordinal not in range(128)
gives a decode error. So, I try to decode the string:
>>> print a.decode('utf-8')+b.decode('utf-8')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/encodings/utf_8.py", line 16, in decode
return codecs.utf_8_decode(input, errors, True)
UnicodeEncodeError: 'ascii' codec can't encode character u'\u2019' in position 7: ordinal not in range(128)
The error changes into an encode error. So, I try a couple of ways to inform the encoding:
>>> print a.decode('utf-8').encode('utf-8')+b.decode('utf-8').encode('utf-8')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/encodings/utf_8.py", line 16, in decode
return codecs.utf_8_decode(input, errors, True)
UnicodeEncodeError: 'ascii' codec can't encode character u'\u2019' in position 7: ordinal not in range(128)
>>> print a.decode('ascii','ignore')+b.decode('ascii','ignore')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
UnicodeEncodeError: 'ascii' codec can't encode character u'\u2019' in position 7: ordinal not in range(128)
>>> print a.decode('utf-8').encode('ascii','ignore') +b.decode('utf-8').encode('ascii','ignore')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/encodings/utf_8.py", line 16, in decode
return codecs.utf_8_decode(input, errors, True)
UnicodeEncodeError: 'ascii' codec can't encode character u'\u2019' in position 7: ordinal not in range(128)
>>>
The error persists no matter what I try.
I suppose the problem might be very simple. I'd appreciate someone helping with an explanation of what's going on, and how to resolve this.
I have python 2.7 on ubuntu.

b is encoded as UTF-8 so you have to .decode it to Unicode.
print a + b.decode('utf-8')
Tested in Python 2.7.6 on Ubuntu.
If you want both in UTF-8 you can do:
print a.encode('utf-8') + b
I'll explain why each one of your attempts doesn't work:
a + b # the default decoding is ascii which cannot decode UTF-8
a.decode('utf-8')+b.decode('utf-8') # you don't need to decode Unicode
Again you don't need to decode Unicode.
a.decode('utf-8').encode('utf-8')+b.decode('utf-8').encode('utf-8')
You keep trying to decode Unicode. What you should do instead is to encode it, or to decode b.
a.decode('ascii','ignore')+b.decode('ascii','ignore')
And finally you again try to decode Unicode. The point to be made here is that UTF-8 is an encoding. You decode from UTF-8 to Unicode.
a.decode('utf-8').encode('ascii','ignore') +b.decode('utf-8').encode('ascii','ignore')

Error while using urllib.request.urlopen in Python

What's wrong with this code?
>>> from urllib.request import urlopen
>>> for line in urlopen("http://google.com/"):
print(line.decode("utf-8"))
<!doctype html><html><head><meta http-equiv="content-type" content="text/html; charset=windows-1251"><title>Google</title><script>window.google={kEI:"XMECT7XyDcGn0AWFk7ywAQ",getEI:function(a){var b;while(a&&!(a.getAttribute&&(b=a.getAttribute("eid"))))a=a.parentNode;return b||google.kEI},https:function(){return window.location.protocol=="https:"},kEXPI:"33492,35300",kCSI:{e:"33492,35300",ei:"XMECT7XyDcGn0AWFk7ywAQ"},authuser:0,
ml:function(){},kHL:"uk",time:function(){return(new Date).getTime()},log:function(a,b,c,e){var d=new Image,g=google,h=g.lc,f=g.li,j="";d.onerror=(d.onload=(d.onabort=function(){delete h[f]}));h[f]=d;if(!c&&b.search("&ei=")==-1)j="&ei="+google.getEI(e);var i=c||"/gen_204?atyp=i&ct="+a+"&cad="+b+j+"&zx="+google.time(),k=/^http:/i;if(k.test(i)&&google.https()){google.ml(new Error("GLMM"),false,{src:i});
delete h[f];return}d.src=i;g.li=f+1},lc:[],li:0,Toolbelt:{},y:{},x:function(a,b){google.y[a.id]=
[a,b];return false}};
window.google.sn="webhp";window.google.timers={};window.google.startTick=function(a,b){window.google.timers[a]={t:{start:(new Date).getTime()},bfr:!(!b)}};window.google.tick=function(a,b,c){if(!window.google.timers[a])google.startTick(a);window.google.timers[a].t[b]=c||(new Date).getTime()};google.startTick("load",true);try{}catch(u){}
var _gjwl=location;function _gjuc(){var e=_gjwl.href.indexOf("#");if(e>=0){var a=_gjwl.href.substring(e);if(a.indexOf("&q=")>0||a.indexOf("#q=")>=0){a=a.substring(1);if(a.indexOf("#")==-1){for(var c=0;c<a.length;){var d=c;if(a.charAt(d)=="&")++d;var b=a.indexOf("&",d);if(b==-1)b=a.length;var f=a.substring(d,b);if(f.indexOf("fp=")==0){a=a.substring(0,c)+a.substring(b,a.length);b=c}else if(f=="cad=h")return 0;c=b}_gjwl.href="/search?"+a+"&cad=h";return 1}}}return 0}function _gjp(){!(window._gjwl.hash&&
window._gjuc())&&setTimeout(_gjp,500)};
Traceback (most recent call last):
File "<pyshell#109>", line 2, in <module>
print(line.decode("utf-8"))
UnicodeDecodeError: 'utf8' codec can't decode byte 0xc2 in position 2364: invalid continuation byte

Google sends you text in windows-1251 encoding, it says it in meta tag. This will work:
>>> from urllib.request import urlopen
>>> for line in urlopen("http://google.com/"):
print(line.decode("cp1251"))

That's your failing line (last part of it):
>>> line
b'<a class=gb1 href="http://www.google.es/imghp?hl=es&tab=wi">Im\xe1genes</a>'
>>> line.decode()
Traceback (most recent call last):
File "<pyshell#12>", line 1, in <module>
line.decode()
UnicodeDecodeError: 'utf8' codec can't decode byte 0xe1 in position 62: invalid continuation byte
The failing code is from a spanish word that has accent:
>>> bite = 0xe1
>>> bite
225
>>> chr(225)
'á'
You will be ok with latins decoding accordingly:
>>> line.decode('latin-1')
'<a class=gb1 href="http://www.google.es/imghp?hl=es&tab=wi">Imágenes</a>'
btw, Imágenes is spanish images