I have a folder directories look somewhat like this:
C:/Documents/A350/a/1.png
/2.png
b/1.png
/B777/a/1.png
/B747/a/1.png
/2.png
b/1.png
c/1.png
d/1.png
/2.png
I want to move all png to the main folder i.e. Documents.
def recur(input_path):
dir_list = os.listdir(input_path)
for directory in dir_list:
path_name = os.path.join(input_path, directory)
p = pathlib.Path(path_name)
if p.is_dir():
input_path = path_name
return recur(input_path)
return input_path
I have some code to get the deepest path inside a folder, but i am not so sure how to use the recursive function to achieve what i wanted.
Any help would be really appreciated, thanks!!
Below program get all files recursively from parent directory and copies files to parent directory.
import os
import glob
import shutil
files_abs_paths = []
def get_all_files(parent_dir):
files_n_folders = glob.glob(f'{parent_dir}/**')
for fl_or_fldr in files_n_folders:
if os.path.isdir(fl_or_fldr):
folder = fl_or_fldr
get_all_files(folder)
else:
file = fl_or_fldr
files_abs_paths.append(file)
parent_dir = r"C:'/Documents"
# get all files recursively in parent dir
get_all_files(parent_dir)
# copies files to parent_dir
for fl in files_abs_paths:
# gets file_name
file_name = os.path.basename(fl)
# create file in parent_dir
new_file_loc = f'{parent_dir}/{file_name}'
if os.path.exists(new_file_loc) is False:
shutil.copyfile(fl, new_file_loc)
You can also get all the files from a folder tree using os.walk:
If you don't mind overwriting files with duplicate names:
from os import walk, rename
from os.path import join
def collect_files(root):
for src_path, _, files in walk(root):
if src_path != root:
for name in files:
rename(join(src_path, name), join(root, name))
If you want to add a number to the end of files with duplicate names:
from os import walk, rename
from os.path import join, splitext, exists
def collect_files(root):
for src_path, _, files in walk(root):
if src_path != root:
for name in files:
dst_name = name
dst_name_parts = splitext(dst_name)
file_num = 1
while exists(join(root, dst_name)):
dst_name = '{}_{:0>3}{}'.format(dst_name_parts[0], file_num, dst_name_parts[1])
file_num += 1
rename(join(src_path, name), join(root, dst_name))
This question's answers are a community effort. Edit existing answers to improve this post. It is not currently accepting new answers or interactions.
How can I find all the files in a directory having the extension .txt in python?
You can use glob:
import glob, os
os.chdir("/mydir")
for file in glob.glob("*.txt"):
print(file)
or simply os.listdir:
import os
for file in os.listdir("/mydir"):
if file.endswith(".txt"):
print(os.path.join("/mydir", file))
or if you want to traverse directory, use os.walk:
import os
for root, dirs, files in os.walk("/mydir"):
for file in files:
if file.endswith(".txt"):
print(os.path.join(root, file))
Use glob.
>>> import glob
>>> glob.glob('./*.txt')
['./outline.txt', './pip-log.txt', './test.txt', './testingvim.txt']
Something like that should do the job
for root, dirs, files in os.walk(directory):
for file in files:
if file.endswith('.txt'):
print(file)
You can simply use pathlibs glob 1:
import pathlib
list(pathlib.Path('your_directory').glob('*.txt'))
or in a loop:
for txt_file in pathlib.Path('your_directory').glob('*.txt'):
# do something with "txt_file"
If you want it recursive you can use .glob('**/*.txt')
1The pathlib module was included in the standard library in python 3.4. But you can install back-ports of that module even on older Python versions (i.e. using conda or pip): pathlib and pathlib2.
Something like this will work:
>>> import os
>>> path = '/usr/share/cups/charmaps'
>>> text_files = [f for f in os.listdir(path) if f.endswith('.txt')]
>>> text_files
['euc-cn.txt', 'euc-jp.txt', 'euc-kr.txt', 'euc-tw.txt', ... 'windows-950.txt']
import os
path = 'mypath/path'
files = os.listdir(path)
files_txt = [i for i in files if i.endswith('.txt')]
I like os.walk():
import os
for root, dirs, files in os.walk(dir):
for f in files:
if os.path.splitext(f)[1] == '.txt':
fullpath = os.path.join(root, f)
print(fullpath)
Or with generators:
import os
fileiter = (os.path.join(root, f)
for root, _, files in os.walk(dir)
for f in files)
txtfileiter = (f for f in fileiter if os.path.splitext(f)[1] == '.txt')
for txt in txtfileiter:
print(txt)
Here's more versions of the same that produce slightly different results:
glob.iglob()
import glob
for f in glob.iglob("/mydir/*/*.txt"): # generator, search immediate subdirectories
print f
glob.glob1()
print glob.glob1("/mydir", "*.tx?") # literal_directory, basename_pattern
fnmatch.filter()
import fnmatch, os
print fnmatch.filter(os.listdir("/mydir"), "*.tx?") # include dot-files
Try this this will find all your files recursively:
import glob, os
os.chdir("H:\\wallpaper")# use whatever directory you want
#double\\ no single \
for file in glob.glob("**/*.txt", recursive = True):
print(file)
Python v3.5+
Fast method using os.scandir in a recursive function. Searches for all files with a specified extension in folder and sub-folders. It is fast, even for finding 10,000s of files.
I have also included a function to convert the output to a Pandas Dataframe.
import os
import re
import pandas as pd
import numpy as np
def findFilesInFolderYield(path, extension, containsTxt='', subFolders = True, excludeText = ''):
""" Recursive function to find all files of an extension type in a folder (and optionally in all subfolders too)
path: Base directory to find files
extension: File extension to find. e.g. 'txt'. Regular expression. Or 'ls\d' to match ls1, ls2, ls3 etc
containsTxt: List of Strings, only finds file if it contains this text. Ignore if '' (or blank)
subFolders: Bool. If True, find files in all subfolders under path. If False, only searches files in the specified folder
excludeText: Text string. Ignore if ''. Will exclude if text string is in path.
"""
if type(containsTxt) == str: # if a string and not in a list
containsTxt = [containsTxt]
myregexobj = re.compile('\.' + extension + '$') # Makes sure the file extension is at the end and is preceded by a .
try: # Trapping a OSError or FileNotFoundError: File permissions problem I believe
for entry in os.scandir(path):
if entry.is_file() and myregexobj.search(entry.path): #
bools = [True for txt in containsTxt if txt in entry.path and (excludeText == '' or excludeText not in entry.path)]
if len(bools)== len(containsTxt):
yield entry.stat().st_size, entry.stat().st_atime_ns, entry.stat().st_mtime_ns, entry.stat().st_ctime_ns, entry.path
elif entry.is_dir() and subFolders: # if its a directory, then repeat process as a nested function
yield from findFilesInFolderYield(entry.path, extension, containsTxt, subFolders)
except OSError as ose:
print('Cannot access ' + path +'. Probably a permissions error ', ose)
except FileNotFoundError as fnf:
print(path +' not found ', fnf)
def findFilesInFolderYieldandGetDf(path, extension, containsTxt, subFolders = True, excludeText = ''):
""" Converts returned data from findFilesInFolderYield and creates and Pandas Dataframe.
Recursive function to find all files of an extension type in a folder (and optionally in all subfolders too)
path: Base directory to find files
extension: File extension to find. e.g. 'txt'. Regular expression. Or 'ls\d' to match ls1, ls2, ls3 etc
containsTxt: List of Strings, only finds file if it contains this text. Ignore if '' (or blank)
subFolders: Bool. If True, find files in all subfolders under path. If False, only searches files in the specified folder
excludeText: Text string. Ignore if ''. Will exclude if text string is in path.
"""
fileSizes, accessTimes, modificationTimes, creationTimes , paths = zip(*findFilesInFolderYield(path, extension, containsTxt, subFolders))
df = pd.DataFrame({
'FLS_File_Size':fileSizes,
'FLS_File_Access_Date':accessTimes,
'FLS_File_Modification_Date':np.array(modificationTimes).astype('timedelta64[ns]'),
'FLS_File_Creation_Date':creationTimes,
'FLS_File_PathName':paths,
})
df['FLS_File_Modification_Date'] = pd.to_datetime(df['FLS_File_Modification_Date'],infer_datetime_format=True)
df['FLS_File_Creation_Date'] = pd.to_datetime(df['FLS_File_Creation_Date'],infer_datetime_format=True)
df['FLS_File_Access_Date'] = pd.to_datetime(df['FLS_File_Access_Date'],infer_datetime_format=True)
return df
ext = 'txt' # regular expression
containsTxt=[]
path = 'C:\myFolder'
df = findFilesInFolderYieldandGetDf(path, ext, containsTxt, subFolders = True)
path.py is another alternative: https://github.com/jaraco/path.py
from path import path
p = path('/path/to/the/directory')
for f in p.files(pattern='*.txt'):
print f
To get all '.txt' file names inside 'dataPath' folder as a list in a Pythonic way:
from os import listdir
from os.path import isfile, join
path = "/dataPath/"
onlyTxtFiles = [f for f in listdir(path) if isfile(join(path, f)) and f.endswith(".txt")]
print onlyTxtFiles
Python has all tools to do this:
import os
the_dir = 'the_dir_that_want_to_search_in'
all_txt_files = filter(lambda x: x.endswith('.txt'), os.listdir(the_dir))
I did a test (Python 3.6.4, W7x64) to see which solution is the fastest for one folder, no subdirectories, to get a list of complete file paths for files with a specific extension.
To make it short, for this task os.listdir() is the fastest and is 1.7x as fast as the next best: os.walk() (with a break!), 2.7x as fast as pathlib, 3.2x faster than os.scandir() and 3.3x faster than glob.
Please keep in mind, that those results will change when you need recursive results. If you copy/paste one method below, please add a .lower() otherwise .EXT would not be found when searching for .ext.
import os
import pathlib
import timeit
import glob
def a():
path = pathlib.Path().cwd()
list_sqlite_files = [str(f) for f in path.glob("*.sqlite")]
def b():
path = os.getcwd()
list_sqlite_files = [f.path for f in os.scandir(path) if os.path.splitext(f)[1] == ".sqlite"]
def c():
path = os.getcwd()
list_sqlite_files = [os.path.join(path, f) for f in os.listdir(path) if f.endswith(".sqlite")]
def d():
path = os.getcwd()
os.chdir(path)
list_sqlite_files = [os.path.join(path, f) for f in glob.glob("*.sqlite")]
def e():
path = os.getcwd()
list_sqlite_files = [os.path.join(path, f) for f in glob.glob1(str(path), "*.sqlite")]
def f():
path = os.getcwd()
list_sqlite_files = []
for root, dirs, files in os.walk(path):
for file in files:
if file.endswith(".sqlite"):
list_sqlite_files.append( os.path.join(root, file) )
break
print(timeit.timeit(a, number=1000))
print(timeit.timeit(b, number=1000))
print(timeit.timeit(c, number=1000))
print(timeit.timeit(d, number=1000))
print(timeit.timeit(e, number=1000))
print(timeit.timeit(f, number=1000))
Results:
# Python 3.6.4
0.431
0.515
0.161
0.548
0.537
0.274
import os
import sys
if len(sys.argv)==2:
print('no params')
sys.exit(1)
dir = sys.argv[1]
mask= sys.argv[2]
files = os.listdir(dir);
res = filter(lambda x: x.endswith(mask), files);
print res
To get an array of ".txt" file names from a folder called "data" in the same directory I usually use this simple line of code:
import os
fileNames = [fileName for fileName in os.listdir("data") if fileName.endswith(".txt")]
This code makes my life simpler.
import os
fnames = ([file for root, dirs, files in os.walk(dir)
for file in files
if file.endswith('.txt') #or file.endswith('.png') or file.endswith('.pdf')
])
for fname in fnames: print(fname)
Use fnmatch: https://docs.python.org/2/library/fnmatch.html
import fnmatch
import os
for file in os.listdir('.'):
if fnmatch.fnmatch(file, '*.txt'):
print file
A copy-pastable solution similar to the one of ghostdog:
def get_all_filepaths(root_path, ext):
"""
Search all files which have a given extension within root_path.
This ignores the case of the extension and searches subdirectories, too.
Parameters
----------
root_path : str
ext : str
Returns
-------
list of str
Examples
--------
>>> get_all_filepaths('/run', '.lock')
['/run/unattended-upgrades.lock',
'/run/mlocate.daily.lock',
'/run/xtables.lock',
'/run/mysqld/mysqld.sock.lock',
'/run/postgresql/.s.PGSQL.5432.lock',
'/run/network/.ifstate.lock',
'/run/lock/asound.state.lock']
"""
import os
all_files = []
for root, dirs, files in os.walk(root_path):
for filename in files:
if filename.lower().endswith(ext):
all_files.append(os.path.join(root, filename))
return all_files
You can also use yield to create a generator and thus avoid assembling the complete list:
def get_all_filepaths(root_path, ext):
import os
for root, dirs, files in os.walk(root_path):
for filename in files:
if filename.lower().endswith(ext):
yield os.path.join(root, filename)
I suggest you to use fnmatch and the upper method. In this way you can find any of the following:
Name.txt;
Name.TXT;
Name.Txt
.
import fnmatch
import os
for file in os.listdir("/Users/Johnny/Desktop/MyTXTfolder"):
if fnmatch.fnmatch(file.upper(), '*.TXT'):
print(file)
Here's one with extend()
types = ('*.jpg', '*.png')
images_list = []
for files in types:
images_list.extend(glob.glob(os.path.join(path, files)))
Functional solution with sub-directories:
from fnmatch import filter
from functools import partial
from itertools import chain
from os import path, walk
print(*chain(*(map(partial(path.join, root), filter(filenames, "*.txt")) for root, _, filenames in walk("mydir"))))
In case the folder contains a lot of files or memory is an constraint, consider using generators:
def yield_files_with_extensions(folder_path, file_extension):
for _, _, files in os.walk(folder_path):
for file in files:
if file.endswith(file_extension):
yield file
Option A: Iterate
for f in yield_files_with_extensions('.', '.txt'):
print(f)
Option B: Get all
files = [f for f in yield_files_with_extensions('.', '.txt')]
use Python OS module to find files with specific extension.
the simple example is here :
import os
# This is the path where you want to search
path = r'd:'
# this is extension you want to detect
extension = '.txt' # this can be : .jpg .png .xls .log .....
for root, dirs_list, files_list in os.walk(path):
for file_name in files_list:
if os.path.splitext(file_name)[-1] == extension:
file_name_path = os.path.join(root, file_name)
print file_name
print file_name_path # This is the full path of the filter file
Many users have replied with os.walk answers, which includes all files but also all directories and subdirectories and their files.
import os
def files_in_dir(path, extension=''):
"""
Generator: yields all of the files in <path> ending with
<extension>
\param path Absolute or relative path to inspect,
\param extension [optional] Only yield files matching this,
\yield [filenames]
"""
for _, dirs, files in os.walk(path):
dirs[:] = [] # do not recurse directories.
yield from [f for f in files if f.endswith(extension)]
# Example: print all the .py files in './python'
for filename in files_in_dir('./python', '*.py'):
print("-", filename)
Or for a one off where you don't need a generator:
path, ext = "./python", ext = ".py"
for _, _, dirfiles in os.walk(path):
matches = (f for f in dirfiles if f.endswith(ext))
break
for filename in matches:
print("-", filename)
If you are going to use matches for something else, you may want to make it a list rather than a generator expression:
matches = [f for f in dirfiles if f.endswith(ext)]
I'm trying to organize some data before processing it.
What I have is a folder of raw tiff files (they're raster bands from a drone sensor).
I want to move these files into new, individual folders. e.g., IMG_001_1, IMG_001_2, IMG_001_3, IMG_001_4 and IMG_001_5 are all moved into a new folder titled IMG_001. I am ok with changing the naming structure of the files in order to make the code simpler.
An additional issue is that there are a few images missing from the folder. The current files are IMG0016 - IMG0054 (no IMG0055), IMG0056 - IMG0086 (no IMG0087), and IMG0087 - IMG0161. This is why I think it would be simpler to just rename the new image folders from 1-143.
My main problem is actually moving the files into the new folders - creating the folders is fairly simple.
Played around a little and this script came out, which should do what you want:
import os
import shutil
import re
UNORG = "C:\\Users\joshuarb\Desktop\Unorganized_Images\\"
ORG = "C:\\Users\joshuarb\Desktop\Organized_Images\\"
def main():
file_names = [os.path.join(UNORG, i) for i in get_files_of(UNORG)]
for count in range(0, 143):
current_dir = "{}IMG_{:04d}".format(ORG, count)
os.makedirs(current_dir)
move_files = get_files_to_move(file_names, count)
print move_files
for i in move_files:
shutil.move(i, os.path.join(current_dir, os.path.basename(i)))
def get_files_to_move(file_names, count):
return [i for i in file_names if re.match('.*IMG{}_.*'.format(count), i)]
def get_files_of(mypath):
(dirpath, dirnames, filenames) = os.walk(mypath).next()
return filenames
if __name__ == '__main__':
main()
As you see, the code is not commented. But feel free to ask if something is unclear;)
Problem solved!
import os
import shutil
srcpath = "C:\Users\joshuarb\Desktop\Python_Test\UnorganizedImages"
srcfiles = os.listdir(srcpath)
destpath = "C:\Users\joshuarb\Desktop\Python_Test\OrganizedImages"
# extract the three letters from filenames and filter out duplicates
destdirs = list(set([filename[0:8] for filename in srcfiles]))
def create(dirname, destpath):
full_path = os.path.join(destpath, dirname)
os.mkdir(full_path)
return full_path
def move(filename, dirpath):
shutil.move(os.path.join(srcpath, filename)
,dirpath)
# create destination directories and store their names along with full paths
targets = [
(folder, create(folder, destpath)) for folder in destdirs
]
for dirname, full_path in targets:
for filename in srcfiles:
if dirname == filename[0:8]:
move(filename, full_path)
I'm looking for a way to include/exclude files patterns and exclude directories from a os.walk() call.
Here's what I'm doing by now:
import fnmatch
import os
includes = ['*.doc', '*.odt']
excludes = ['/home/paulo-freitas/Documents']
def _filter(paths):
for path in paths:
if os.path.isdir(path) and not path in excludes:
yield path
for pattern in (includes + excludes):
if not os.path.isdir(path) and fnmatch.fnmatch(path, pattern):
yield path
for root, dirs, files in os.walk('/home/paulo-freitas'):
dirs[:] = _filter(map(lambda d: os.path.join(root, d), dirs))
files[:] = _filter(map(lambda f: os.path.join(root, f), files))
for filename in files:
filename = os.path.join(root, filename)
print(filename)
Is there a better way to do this? How?
This solution uses fnmatch.translate to convert glob patterns to regular expressions (it assumes the includes only is used for files):
import fnmatch
import os
import os.path
import re
includes = ['*.doc', '*.odt'] # for files only
excludes = ['/home/paulo-freitas/Documents'] # for dirs and files
# transform glob patterns to regular expressions
includes = r'|'.join([fnmatch.translate(x) for x in includes])
excludes = r'|'.join([fnmatch.translate(x) for x in excludes]) or r'$.'
for root, dirs, files in os.walk('/home/paulo-freitas'):
# exclude dirs
dirs[:] = [os.path.join(root, d) for d in dirs]
dirs[:] = [d for d in dirs if not re.match(excludes, d)]
# exclude/include files
files = [os.path.join(root, f) for f in files]
files = [f for f in files if not re.match(excludes, f)]
files = [f for f in files if re.match(includes, f)]
for fname in files:
print fname
From docs.python.org:
os.walk(top[, topdown=True[, onerror=None[, followlinks=False]]])
When topdown is True, the caller can modify the dirnames list in-place … this can be used to prune the search …
for root, dirs, files in os.walk('/home/paulo-freitas', topdown=True):
# excludes can be done with fnmatch.filter and complementary set,
# but it's more annoying to read.
dirs[:] = [d for d in dirs if d not in excludes]
for pat in includes:
for f in fnmatch.filter(files, pat):
print os.path.join(root, f)
I should point out that the above code assumes excludes is a pattern, not a full path. You would need to adjust the list comprehension to filter if os.path.join(root, d) not in excludes to match the OP case.
why fnmatch?
import os
excludes=....
for ROOT,DIR,FILES in os.walk("/path"):
for file in FILES:
if file.endswith(('doc','odt')):
print file
for directory in DIR:
if not directory in excludes :
print directory
not exhaustively tested
dirtools is perfect for your use-case:
from dirtools import Dir
print(Dir('.', exclude_file='.gitignore').files())
Here is one way to do that
import fnmatch
import os
excludes = ['/home/paulo-freitas/Documents']
matches = []
for path, dirs, files in os.walk(os.getcwd()):
for eachpath in excludes:
if eachpath in path:
continue
else:
for result in [os.path.abspath(os.path.join(path, filename)) for
filename in files if fnmatch.fnmatch(filename,'*.doc') or fnmatch.fnmatch(filename,'*.odt')]:
matches.append(result)
print matches
import os
includes = ['*.doc', '*.odt']
excludes = ['/home/paulo-freitas/Documents']
def file_search(path, exe):
for x,y,z in os.walk(path):
for a in z:
if a[-4:] == exe:
print os.path.join(x,a)
for x in includes:
file_search(excludes[0],x)
This is an example of excluding directories and files with os.walk():
ignoreDirPatterns=[".git"]
ignoreFilePatterns=[".php"]
def copyTree(src, dest, onerror=None):
src = os.path.abspath(src)
src_prefix = len(src) + len(os.path.sep)
for root, dirs, files in os.walk(src, onerror=onerror):
for pattern in ignoreDirPatterns:
if pattern in root:
break
else:
#If the above break didn't work, this part will be executed
for file in files:
for pattern in ignoreFilePatterns:
if pattern in file:
break
else:
#If the above break didn't work, this part will be executed
dirpath = os.path.join(dest, root[src_prefix:])
try:
os.makedirs(dirpath,exist_ok=True)
except OSError as e:
if onerror is not None:
onerror(e)
filepath=os.path.join(root,file)
shutil.copy(filepath,dirpath)
continue;#If the above else didn't executed, this will be reached
continue;#If the above else didn't executed, this will be reached
python >=3.2 due to exist_ok in makedirs
The above methods had not worked for me.
So, This is what I came up with an expansion of my original answer to another question.
What worked for me was:
if (not (str(root) + '/').startswith(tuple(exclude_foldr)))
which compiled a path and excluded the tuple of my listed folders.
This gave me the exact result I was looking for.
My goal for this was to keep my mac organized.
I can Search any folder by path, locate & move specific file.types, ignore subfolders and i preemptively prompt the user if they want to move the files.
NOTE: the Prompt is only one time per run and is NOT per file
By Default the prompt defaults to NO when you hit enter instead of [y/N], and will just list the Potential files to be moved.
This is only a snippet of my GitHub Please visit for the total script.
HINT: Read the script below as I added info per line as to what I had done.
#!/usr/bin/env python3
# =============================================================================
# Created On : MAC OSX High Sierra 10.13.6 (17G65)
# Created On : Python 3.7.0
# Created By : Jeromie Kirchoff
# =============================================================================
"""THE MODULE HAS BEEN BUILD FOR KEEPING YOUR FILES ORGANIZED."""
# =============================================================================
from os import walk
from os import path
from shutil import move
import getpass
import click
mac_username = getpass.getuser()
includes_file_extensn = ([".jpg", ".gif", ".png", ".jpeg", ])
search_dir = path.dirname('/Users/' + mac_username + '/Documents/')
target_foldr = path.dirname('/Users/' + mac_username + '/Pictures/Archive/')
exclude_foldr = set([target_foldr,
path.dirname('/Users/' + mac_username +
'/Documents/GitHub/'),
path.dirname('/Users/' + mac_username +
'/Documents/Random/'),
path.dirname('/Users/' + mac_username +
'/Documents/Stupid_Folder/'),
])
if click.confirm("Would you like to move files?",
default=False):
question_moving = True
else:
question_moving = False
def organize_files():
"""THE MODULE HAS BEEN BUILD FOR KEEPING YOUR FILES ORGANIZED."""
# topdown=True required for filtering.
# "Root" had all info i needed to filter folders not dir...
for root, dir, files in walk(search_dir, topdown=True):
for file in files:
# creating a directory to str and excluding folders that start with
if (not (str(root) + '/').startswith(tuple(exclude_foldr))):
# showcase only the file types looking for
if (file.endswith(tuple(includes_file_extensn))):
# using path.normpath as i found an issue with double //
# in file paths.
filetomove = path.normpath(str(root) + '/' +
str(file))
# forward slash required for both to split
movingfileto = path.normpath(str(target_foldr) + '/' +
str(file))
# Answering "NO" this only prints the files "TO BE Moved"
print('Files To Move: ' + str(filetomove))
# This is using the prompt you answered at the beginning
if question_moving is True:
print('Moving File: ' + str(filetomove) +
"\n To:" + str(movingfileto))
# This is the command that moves the file
move(filetomove, movingfileto)
pass
# The rest is ignoring explicitly and continuing
else:
pass
pass
else:
pass
else:
pass
if __name__ == '__main__':
organize_files()
Example of running my script from terminal:
$ python3 organize_files.py
Exclude list: {'/Users/jkirchoff/Pictures/Archive', '/Users/jkirchoff/Documents/Stupid_Folder', '/Users/jkirchoff/Documents/Random', '/Users/jkirchoff/Documents/GitHub'}
Files found will be moved to this folder:/Users/jkirchoff/Pictures/Archive
Would you like to move files?
No? This will just list the files.
Yes? This will Move your files to the target folder.
[y/N]:
Example of listing files:
Files To Move: /Users/jkirchoff/Documents/Archive/JayWork/1.custom-award-768x512.jpg
Files To Move: /Users/jkirchoff/Documents/Archive/JayWork/10351458_318162838331056_9023492155204267542_n.jpg
...etc
Example of moving files:
Moving File: /Users/jkirchoff/Documents/Archive/JayWork/1.custom-award-768x512.jpg
To: /Users/jkirchoff/Pictures/Archive/1.custom-award-768x512.jpg
Moving File: /Users/jkirchoff/Documents/Archive/JayWork/10351458_318162838331056_9023492155204267542_n.jpg
To: /Users/jkirchoff/Pictures/Archive/10351458_318162838331056_9023492155204267542_n.jpg
...