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How to get sender mailbox from email.message.Message object?

First I connect to my own mailbox using such code:
import email
import imaplib
imap_server = imaplib.IMAP4_SSL('imap.gmail.com', 993)
imap_server.login("myemail", "mypassword")
imap_server.select('inbox')
Then I get the last email on it in the way like:
_, data = imap_server.search(None, 'ALL')
id_list = data[0].split()
_, data = imap_server.fetch(id_list[-1], '(RFC822)')
rawmail = data[0][1]
prev_mail = email.message_from_bytes(rawmail)
And after that, I need to get sender email from prev_mail variable.
I tried it myself a little bit, and figured out that prev_mail['From'] is usually sth like this: "John Snow" <johnsnow#gmail.com>, so that means I can just grab the <*> part and use it.
But the question is: will it always be like this so I could use my method? And are there any better ways to do this rather than mine?
EDIT:
There are multiple variants of From: headers. Python 3.8 has a good parser for this in the email.header module. But perhaps the Return-Path: header would actually be closer to what you really want? - tripleee
Thank you very much, tripleee, that's exactly what I needed!

how to sign request tokens?

I am currently trying to write a script to send off a request token, I have the header, and the claimset, but I don't understand the signature! OAuth requires my private key to be encrypted with SHA256withRSA (also known as RSASSA-PKCS1-V1_5-SIGN with the SHA-256 hash function), but the closest I could find was RSAES-PKCS1-v1_5 (has RSA, and the SHA-256 hash). I followed the example, and tweaked it, so I could get it set, but heres my dillema:
signature = ""
h = SHA.new (signature)
key = RSA.importKey(open('C:\Users\Documents\Library\KEY\My Project 905320c6324f.json').read())
cipher = PKCS1_v1_5.new(key)
ciphertext = cipher.encrypt(message+h.digest())
print(ciphertext)
I'm a bit lost, the JSON file I was given has both public key, and private, do I copy and paste the private key into the signature variable (it gave me a invalid syntax)? Or do I past the directory again? I am so lost, and way over my head haha. I am currently running Python 3.4, with pyCrypto for the signature.

Based on what you've said below about wanting to write a command system using gmail, I wrote a simple script to do this using IMAP. I think this is probably simpler than trying to use Google APIs for a single user, unless you were wanting to do that simply for the exercise.
import imaplib, logging
from time import sleep
USERNAME = 'YOUR_USERNAME_HERE' # For gmail, this is your full email address.
PASSWORD = 'YOUR_PASSWORD_HERE'
CHECK_DELAY = 60 # In seconds
LOGGING_FORMAT = '%(asctime)s %(message)s'
logging.basicConfig(filename='imapTest.log', format=LOGGING_FORMAT, level=logging.INFO)
logging.info("Connecting to IMAP server...")
imap = imaplib.IMAP4_SSL('imap.gmail.com')
imap.login(USERNAME, PASSWORD)
logging.info("Connected to IMAP server.")
def get_command_messages():
logging.info("Checking for new commands.")
imap.check()
# Search the inbox (server-side) for messages containing the subject 'COMMAND' and which are from you.
# Substitute USERNAME below for the sending email address if it differs.
typ, data = imap.search(None, '(FROM "%s" SUBJECT "COMMAND")' %(USERNAME))
return data[0]
def delete_messages(message_nums):
logging.info("Deleting old commands.")
for message in message_nums.split():
imap.store(message, '+FLAGS', '\\DELETED')
imap.expunge()
# Select the inbox
imap.select()
# Delete any messages left over that match commands, so we are starting 'clean'.
# This probably isn't the nicest way to do this, but saves checking the DATE header.
message_nums = get_command_messages()
delete_messages(message_nums)
try:
while True:
sleep(CHECK_DELAY)
# Get the message body and sent time. Use BODY.PEEK instead of BODY if you don't want to mark the message as read, but we're deleting it anyway below.
message_nums = get_command_messages()
if message_nums:
# search returns space-separated message IDs, but we need them comma-separated for fetch.
typ, messages = imap.fetch(message_nums.replace(' ', ','), '(BODY[TEXT])')
logging.info("Found %d commands" %(len(messages[0])))
for message in messages[0]:
# You now have the message body in the message variable.
# From here, you can check against it to perform commands, e.g:
if 'shutdown' in message:
print("I got a shutdown command!")
# Do stuff
delete_messages(message_nums)
finally:
try:
imap.close()
except:
pass
imap.logout()
If you're set on using the Gmail API, though, Google strongly encourage you to use their existing Python library rather than attempt to do full authentication etc. yourself as you appear to be. With that, it should - more or less - be a case of replacing the imap calls above with the relevant Gmail API ones.

How can I login into an email account, and check the subject of recently delivered emails using Ruby (or Python)?

Basically, I am try to write a program where I need to login into my email account and check the header of recently delivered emails.
I am a complete novice in terms of this type of stuff and would prefer to do the programming in Ruby. I also have some skill in Python if this would make the task easier. Thanks in advance!

The documentation for Python's imaplib library includes an example that does pretty much that:
import getpass, imaplib
M = imaplib.IMAP4()
M.login(getpass.getuser(), getpass.getpass())
M.select()
typ, data = M.search(None, 'ALL')
for num in data[0].split():
typ, data = M.fetch(num, '(RFC822)')
print 'Message %s\n%s\n' % (num, data[0][1])
M.close()
M.logout()
You can modify the search string from 'ALL' to e.g. (since "24-May-2012"). I don't think IMAP supports searching by times; you'll probably have to do that filtering yourself.

Get sender email address with Python IMAP

I have this python IMAP script, but my problem is that, every time I want to get the sender's email address, (From), I always get the sender's first name followed by their email address:
Example:
Souleiman Benhida <souleb#gmail.com>
How can i just extract the email address (souleb#gmail.com)
I did this before, in PHP:
$headerinfo = imap_headerinfo($connection, $count)
or die("Couldn't get header for message " . $count . " : " . imap_last_error());
$from = $headerinfo->fromaddress;
But, in python I can only get the full name w/address, how can I get the address alone? I currently use this:
typ, data = M.fetch(num, '(RFC822)')
mail = email.message_from_string(data[0][1])
headers = HeaderParser().parsestr(data[0][1])
message = parse_message(mail) #body
org = headers['From']
Thanks!

Just one more step, using email.utils:
email.utils.parseaddr(address)
Parse address – which should be the value of some address-containing field such as To or Cc – into its constituent realname and email address parts. Returns a tuple of that information, unless the parse fails, in which case a 2-tuple of ('', '') is returned.
Note: originally referenced rfc822, which is now deprecated.

to = email.utils.parseaddr(msg['cc'])
This works for me.

My external lib https://github.com/ikvk/imap_tools
let you work with mail instead read IMAP specifications.
from imap_tools import MailBox, A
# get all emails from INBOX folder
with MailBox('imap.mail.com').login('test#mail.com', 'pwd', 'INBOX') as mailbox:
for msg in mailbox.fetch(A(all=True)):
print(msg.date, msg.from_, msg.to, len(msg.text or msg.html))
msg.from_, msg.to - parsed addresses, like: 'Sender#ya.ru'

I didn't like the existing solutions so I decided to make a sister library for my email sender called Red Box.
Here is how to search and process emails including getting the from address:
from redbox import EmailBox
# Create email box instance
box = EmailBox(
host="imap.example.com",
port=993,
username="me#example.com",
password="<PASSWORD>"
)
# Select an email folder
inbox = box["INBOX"]
# Search and process messages
for msg in inbox.search(unseen=True):
# Process the message
print(msg.from_)
print(msg.to)
print(msg.subject)
print(msg.text_body)
print(msg.html_body)
# Flag the email as read/seen
msg.read()
I also wrote extensive documentation for it. It also has query language that fully supports nested logical operations.

How to receive mail using python

I would like to receive email using python. So far I have been able to get the subject but not the body. Here is the code I have been using:
import poplib
from email import parser
pop_conn = poplib.POP3_SSL('pop.gmail.com')
pop_conn.user('myusername')
pop_conn.pass_('mypassword')
#Get messages from server:
messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
# Concat message pieces:
messages = ["\n".join(mssg[1]) for mssg in messages]
#Parse message intom an email object:
messages = [parser.Parser().parsestr(mssg) for mssg in messages]
for message in messages:
print message['subject']
print message['body']
pop_conn.quit()
My issue is that when I run this code it properly returns the Subject but not the body. So if I send an email with the subject "Tester" and the body "This is a test message" it looks like this in IDLE.
>>>>Tester >>>>None
So it appears to be accurately assessing the subject but not the body, I think it is in the parsing method right? The issue is that I don't know enough about these libraries to figure out how to change it so that it returns both a subject and a body.

The object message does not have a body, you will need to parse the multiple parts, like this:
for part in message.walk():
if part.get_content_type():
body = part.get_payload(decode=True)
The walk() function iterates depth-first through the parts of the email, and you are looking for the parts that have a content-type. The content types can be either text/plain or text/html, and sometimes one e-mail can contain both (if the message content_type is set to multipart/alternative).

The email parser returns an email.message.Message object, which does not contain a body key, as you'll see if you run
print message.keys()
What you want is the get_payload() method:
for message in messages:
print message['subject']
print message.get_payload()
pop_conn.quit()
But this gets complicated when it comes to multi-part messages; get_payload() returns a list of parts, each of which is a Message object. You can get a particular part of the multipart message by using get_payload(i), which returns the ith part, raises an IndexError if i is out of range, or raises a TypeError if the message is not multipart.
As Gustavo Costa De Oliveir points out, you can use the walk() method to get the parts in order -- it does a depth-first traversal of the parts and subparts of the message.
There's more about the email.parser module at http://docs.python.org/library/email.message.html#email.message.Message.

it also good return data in correct encoding in message contains some multilingual content
charset = part.get_content_charset()
content = part.get_payload(decode=True)
content = content.decode(charset).encode('utf-8')

Here is how I solved the problem using python 3 new capabilities:
import imaplib
import email
mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login(username, password)
mail.select(readonly=True) # refresh inbox
status, message_ids = mail.search(None, 'ALL') # get all emails
for message_id in message_ids[0].split(): # returns all message ids
# for every id get the actual email
status, message_data = mail.fetch(message_id, '(RFC822)')
actual_message = email.message_from_bytes(message_data[0][1])
# extract the needed fields
email_date = actual_message["Date"]
subject = actual_message["Subject"]
message_body = get_message_body(actual_message)
Now get_message_body is actually pretty tricky due to MIME format. I used the function suggested in this answer.
This particular example works with Gmail, but IMAP is a standard protocol, so it should work for other email providers as well, possibly with minor changes.

if u want to use IMAP4. Use outlook python library, download here : https://github.com/awangga/outlook
to retrieve unread email from your inbox :
import outlook
mail = outlook.Outlook()
mail.login('emailaccount#live.com','yourpassword')
mail.inbox()
print mail.unread()
to retrive email element :
print mail.mailbody()
print mail.mailsubject()
print mail.mailfrom()
print mail.mailto()