I have a narrow Python 2.7.6 build on Windows. I also have a string containing both "narrow" (< 0x10000) and "wide" (> 0xFFFF) Unicode code points.
>>> wide1 = u'\U0002b740'
>>> wide2 = u'\ud86d\udf40'
>>> wide1 == wide2
True
>>> narrow = u'\ud86d'
>>> s = wide1 + narrow
But when I iterate over the string, it doesn't recognize wide code points:
>>> for c in s:
>>> c
u'\ud86d'
u'\udf40'
u'\ud86d'
And it becomes impossible to find out whether a char was a narrow code point or it was a part of a wide code point.
You cannot. High Unicode codepoints are internally represented as UTF-16 surrogates.
The U+D86D and U+DF40 codepoints are such surrogates, you should never see this in normal Unicode text usage anyway. Quoting from the Wikipedia article on UTF-16:
The Unicode standard permanently reserves these code point values for UTF-16 encoding of the lead and trail surrogates, and they will never be assigned a character, so there should be no reason to encode them. The official Unicode standard says that no UTF forms, including UTF-16, can encode these code points.
As such the U+D800 to U+DFFF codepoints should not be treated as narrow points; they are one half of a wide codepoint, that is their purpose.
Related
I've been working on a project where I'm encoding numbers as characters. Being used to C++, I assumed I could just use any 8bit number and cast it to a character. However, python's chr() function is returning Unicode characters, which aren't 8-bit, so that will not work.
I am new to Python and, from what I've read, previous versions used to have 2 separate functions: chr() for ASCII characters and unichr() for Unicode characters.
I am also limited to what I can get in the standard python library for windows (we are not allowed to install modules with pip).
This might usually be okay, but here's an example of when this can mess with my program:
If I'm encoding the integer 143:
# this is not taken from my actual code
num = 143
c = chr(143)
print(c)
I would expect this to print the ASCII character (a capital A with a little circle above it). Instead, I get the unicode \x8f, which represents "SS3" (Single Shift 3).
TL;DR: I'm converting 8-bit numbers to characters, but chr() converts to Unicode and I REALLY need a way to convert to ASCII instead, but I can't seem to find it in the standard library.
I know that this is such a simple problem and it's extremely frustrating to be stuck on this of all things.
Thanks a lot in advance!
Have a nice day!
- Vlad
"A with a little circle above it" is not an ASCII character, and 143 is outside the ASCII range (0-127).
It seems you are thinking in terms of the encoded bytes rather than unicode codepoints (which Python3 uses to represent string values). See here for 8 bit encodings where b'\x8f' represents 'Å'.
You probably want to do something like this:
import sys
c = 143
# Convert to byte
b = c.to_bytes(1, sys.byteorder)
# Decode to unicode (str) and print
print(b.decode('cp437'))
Å
You could also take a look at the struct package in the standard library, which deals with bytes and chars in a more "C-like" fashion.
When I parse this XML with p = xml.parsers.expat.ParserCreate():
<name>Fortuna Düsseldorf</name>
The character parsing event handler includes u'\xfc'.
How can u'\xfc' be turned into u'ü'?
This is the main question in this post, the rest just shows further (ranting) thoughts about it
Isn't Python unicode broken since u'\xfc' shall yield u'ü' and nothing else?
u'\xfc' is already a unicode string, so converting it to unicode again doesn't work!
Converting it to ASCII as well doesn't work.
The only thing that I found works is: (This cannot be intended, right?)
exec( 'print u\'' + 'Fortuna D\xfcsseldorf'.decode('8859') + u'\'')
Replacing 8859 with utf-8 fails! What is the point of that?
Also what is the point of the Python unicode HOWTO? - it only gives examples of fails instead of showing how to do the conversions one (especially the houndreds of ppl who ask similar questions here) actually use in real world practice.
Unicode is no magic - why do so many ppl here have issues?
The underlying problem of unicode conversion is dirt simple:
One bidirectional lookup table '\xFC' <-> u'ü'
unicode( 'Fortuna D\xfcsseldorf' )
What is the reason why the creators of Python think it is better to show an error instead of simply producing this: u'Fortuna Düsseldorf'?
Also why did they made it not reversible?:
>>> u'Fortuna Düsseldorf'.encode('utf-8')
'Fortuna D\xc3\xbcsseldorf'
>>> unicode('Fortuna D\xc3\xbcsseldorf','utf-8')
u'Fortuna D\xfcsseldorf'
You already have the value. Python simply tries to make debugging easier by giving you a representation that is ASCII friendly. Echoing values in the interpreter gives you the result of calling repr() on the result.
In other words, you are confusing the representation of the value with the value itself. The representation is designed to be safely copied and pasted around, without worry about how other systems might handle non-ASCII codepoints. As such the Python string literal syntax is used, with any non-printable and non-ASCII characters replaced by \xhh and \uhhhh escape sequences. Pasting those strings back into a Python string or interactive Python session will reproduce the exact same value.
As such ü has been replaced by \xfc, because that's the Unicode codepoint for the U+00FC LATIN SMALL LETTER U WITH DIAERESIS codepoint.
If your terminal is configured correctly, you can just use print and Python will encode the Unicode value to your terminal codec, resulting in your terminal display giving you the non-ASCII glyphs:
>>> u'Fortuna Düsseldorf'
u'Fortuna D\xfcsseldorf'
>>> print u'Fortuna Düsseldorf'
Fortuna Düsseldorf
If your terminal is configured for UTF-8, you can also write the UTF-8 bytes directly to your terminal, after encoding explicitly:
>>> u'Fortuna Düsseldorf'.encode('utf8')
'Fortuna D\xc3\xbcsseldorf'
>>> print u'Fortuna Düsseldorf'.encode('utf8')
Fortuna Düsseldorf
The alternative is for you upgrade to Python 3; there repr() only uses escape sequences for codepoints that have no printable glyphs (control codes, reserved codepoints, surrogates, etc; if the codepoint is not a space but falls in a C* or Z* general category, it is escaped). The new ascii() function gives you the Python 2 repr() behaviour still.
I'm making a virtual machine in RPython using PyPy. The problem is, when I tried to add unicode support I found an unusual problem. I'll use the letter "á" in my examples.
# The char in the example is á
print len(char)
OUTPUT:
2
I understand how the letter "á" takes two bytes, hence the length of 2. But the problem is when I use this example below I am faced with the problem.
# In this example instr = "á" (including the quotes)
for char in instr:
print hex(int(ord(char)))
OUTPUT:
0x22
0xc3
0xa1
0x22
As you can there are 4 numbers. For 0x22 are for the quotes, but there is only 1 letter in between the quotes but there are two numbers. My question is, some machines I tested this script on produced this output:
OUTPUT:
0x22
0xe1
0x22
Is there anyway to make the output the same on both machines? The script is exactly the same on each.
The program is not being given the same input on the two machines:
In [154]: '\xe1'.decode('cp1252').encode('utf_8') == '\xc3\xa1'
Out[154]: True
When you type á in a console, you may see the glyph á, but the console is translating that into bytes. The particular bytes it translates that into depends on the encoding used by the console. On a Windows machine, that may be cp1252, while on a Unix machine it is likely to be utf-8.
So you may see the input as the same, but the console (and thus the program) receives different input.
If your program were to decode the bytes with the appropriate encoding, and then work with unicode, then both programs will operate the same after that point. If you are receiving the bytes from sys.stdin, then sys.stdin.encoding will be the encoding Python detects the console is using.
You have this question tagged "Python-3.x" -- is it possible that some machines are running Python 2.x, and others are running Python 3.x?
The character á is in fact U+00E1, so on a Python 3.x system, I would expect to see your second output. Since strings are Unicode in Python3 by default, len(char) will be 3 (including the quotes).
In Python 2.x, that same character in a string will be two bytes long, and (depending on your input method) will be represented in UTF-8 as \xc3\xa1. On that system, len(char) will be 4, and you would see your first output.
The issue is that you use bytestrings to work with a text data. You should use Unicode instead.
It implies that you need to know the character encoding of your input data -- There Ain't No Such Thing As Plain Text.
If you know the character encoding then it is easy to convert a bytestring to Unicode e.g.:
unicode_text = bytestring.decode(encoding)
It should resolve your initial issue.
There are also Unicode normalization forms e.g.:
import unicodedata
norm_text = unicodedata.normalize('NFC', unicode_text)
If I don't change the encoding in the program how can I output unicode characters for example?
You might mean that you have a sequence of bytes e.g., '\xc3\xa1' (two bytes) that can be interpreted as text using some character encoding e.g., it is U+00E1 Unicode codepoint in utf-8. It may be something different in a different character encoding. Please, read the link I've provided above The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!).
Unless by accident your terminal uses the same character encoding as data in your input file; you need to be able to convert from one character encoding to another. Otherwise the output will be corrupted e.g., instead of á you might get ├б on the screen.
In ordinary Python, you could use bytes.decode, unicode.encode methods (or codecs module directly). I don't know whether it is possible in RPython.
I have begun to look through the Python Standard Library: (http://docs.python.org/3/library/functions.html)
In an attempt to further familiarise myself with basic python. When it comes to the explanation on the ascii( ) function, I'm not finding it clear.
Is someone able to supply a concise explanation giving examples of useful situations in which one may use the ascii( ) function please?
ascii() is a function that encodes the output of repr() to use escape sequences for any codepoint in the output produced by repr() that is not within the ASCII range.
So a Latin 1 codepoint like ë is represented by the Python escape sequence \xeb instead.
This was the standard representation in Python 2; Python 3 repr() leaves most Unicode codepoints as their actual value in the output, as long as it is a printable character:
>>> print(repr('ë'))
'ë'
>>> print(ascii('ë'))
'\xeb'
Both outputs are valid Python string literals, but the latter uses just ASCII characters, while the former requires a Unicode-compatible encoding.
For unicode codepoints between U+0100 and U+FFFF \uxxxx escape code sequences are used, for anything over that the \Uxxxxxxxx form is used. See the available escape code syntax for Python string literals.
Like repr(), ascii() is a very helpful debugging tool, especially when it comes to exact contents of a string. Unlike repr(), the ascii() output makes many Unicode gotchas much more visible.
Take de-normalised codepoints for example; The ë character can be represented in two ways, as the U+00EB codepoint, or as an ASCII e plus combining diaeresis ¨ (codepoint U+0308):
>>> import unicodedata
>>> one, two = 'ë', unicodedata.normalize('NFD', 'ë')
>>> print(one, two)
ë ë
>>> print(repr(one), repr(two))
'ë' 'ë'
>>> print(ascii(one), ascii(two))
'\xeb' 'e\u0308'
Only with ascii() is it clear that two consists of two distinct codepoints.
ascii() can be useful for finding out exactly what is in a string. If a string has whitespace or unprintable characters, or if the terminal is turning the string into mojibake because of a character-encoding mismatch, it is useful to look at the ascii representation of the string since it provides a visible and unambiguous representation for those otherwise unreadable characters which will print the same way on everyone's terminals.
There are frequent questions on Stackoverflow regarding incorrectly printed strings, and sometimes it is hard to tell what's going on because the question only shows the mojibake and not an unambiguous representation of the string. When the questioner shows the ascii representation (or the repr in Python 2) then the situation becomes much clearer.
CPython stores unicode strings as either utf-16 or utf-32 internally depending on compile options. In utf-16 builds of Python string slicing, iteration, and len seem to work on code units, not code points, so that multibyte characters behave strangely.
E.g., on CPython 2.6 with sys.maxunicode = 65535:
>>> char = u'\U0001D49E'
>>> len(char)
2
>>> char[0:1]
u'\uu835'
>>> char[1:2]
u'\udc9e'
According to the Python documentation, sys.maxunicode is "An integer giving the largest supported code point for a Unicode character."
Does this mean that unicode operations aren't guranteed to work on code points beyond sys.maxunicode? If I want to work with characters outside the BMP I either have to use a utf-32 build or write my own portable unicode operations?
I came across this problem in How to iterate over Unicode characters in Python 3?
Characters beyond sys.maxunicode=65535 are stored internally using UTF-16 surrogates. Yes you have to deal with this yourself or use a wide build. Even with a wide build you also may have to deal with single characters represented by a combination of code points. For example:
>>> print('a\u0301')
á
>>> print('\xe1')
á
The first uses a combining accent character and the second doesn't. Both print the same. You can use unicodedata.normalize to convert the forms.