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How to get out of a while loop with a specific key

I am trying to make an auto clicker but when i try to make my code exit it doesnt
here is my code
import mouse
import keyboard
import time
import os
os.system('cls')
def Config():
print("Click every")
hour = int(input("Hour: "))
minute = int(input("Minute: "))
second = int(input("Second: "))
total_time = hour*3600 + minute*60 + second
print("f6 to start and f10 to stop")
keyboard.wait('f6')
while True:
time.sleep(total_time)
mouse.click()
#def Fastest():
print(" Auto clicker!!!")
print(" By ze")
print("-------------------------")
print("Auto click on desired time or Fastest?")
choose = int(input("""
1. Config (No milliseconds)
2. Fastest
"""))
if choose == 1:
Config()
# elif choose == 2:
# Fastest()
#TODO:
# use mouse.click
# make it click with time
# make function fastest start with f1 and stops with f2
# create back up file
i tried an if statement with keyboard.is_pressed('key') thinking it would work but it doesnt my results are that the code exits (if key is pressed then exit)

You need to check if the key is pressed in your infinite loop. If it is pressed, you need to exit
while True:
time.sleep(total_time)
mouse.click()
if keyboard.is_pressed("f10"):
break
But this waits for the sleep function , so you'll need to hold f10 for total_time seconds.
You should use a loop to check for the key, rather than sleeping
import datetime
...
clicking = True
while clicking:
mouse.click()
s = datetime.datetime.now()
while ((datetime.datetime.now()-s).total_seconds() < total_time):
# This runs while the difference in time since you started the loop is less than the time you want to wait
if keyboard.is_pressed("f10"):
clicking = False
break

Use one thread to handle user input and another thread to do the clicking:
from threading import Thread
from msvcrt import getwch
import mouse
done = False
def auto_click():
print("Press \"q\" to quit")
global done
while True:
if getwch() == "q":
done = True
break
Thread( target = auto_click, daemon = True ).start()
while not done: # you can add whatever logic you want including a time gate here
mouse.click()

Python Script Infinite Loop untill specific Keypress

I am a total newbie at coding but I made a simple script:
import time
import keyboard
while True:
try:
if keyboard.is_pressed('F3'):
time.sleep(1)
keyboard.press('enter')
continue
except:
break
When I press F3, the script makes the computer press the Enter key. The problem is it only does it once until you press F3 again.
How can I make it go forever until I press F3 to stop it?

I hope that I understand the question correctly. In order to stop pressing enter when F3 is pressed you should move these lines:
time.sleep(1)
keyboard.press('enter')
outside of the if-statement. Like this:
import time
import keyboard
while True:
try:
if keyboard.is_pressed('F3'):
break
time.sleep(1)
keyboard.press('enter')
except:
break
Also, the continue is not needed here. And because the program sleeps for 1 second after checking for the keypress, you will have to hold the F3-key for at least 1 second.
To start the loop by pressing a key, you could start the function with the following:
while not keyboard.is_pressed('F3'):
pass
time.sleep(0.1)
Now the function will wait until the F3-key is pressed. The small delay is needed because otherwise the keyboard function will think the F3-key is pressed when it enters the second loop. I found that a 100 ms delay works fine.
If you choose another key then the F3-key, this delay will not be needed.

I modified the code so it starts with the F3 and stops with the F4 keys. Here it is for anyone reading !
import time
import keyboard
from random import randint
def main():
x = 0
while x == 0:
try:
if keyboard.is_pressed('F3'):
x = 1
except:
x = 0
while x == 1:
if keyboard.is_pressed('F4'):
break
try:
time.sleep(randint(2,3))
keyboard.press('enter')
except:
break
main()

PYTHON: How to make a program to stop if some seconds have passed?

So I'm making a little speed game. A random letter is going to be generated by a function, right after that, I want the program to wait some seconds. If nothing is pressed, you will lose and your record will be displayed If you press the right key, another random letter is going to be displayed. I used the time function and simulated a cronometer that lasts in a range (0,2). This is what I have so far. It works, the thing is, it displays the first letter, if you press it wrong you lose (good) but even if you press it right, the cronometer obviously keeps running, so it gets to 2 and you lose. I want it to stop and reset after I hit the key, but I have no idea of how to do it. Im new in programming so I'm sorry if you don't get something.
import string
import random
import msvcrt
import time
def generarletra():
string.ascii_lowercase
letra = random.choice(string.ascii_lowercase)
return letra
def getchar():
s = ''
return msvcrt.getch().decode('utf-8')
print("\nWelcome to Key Pop It!")
opcion = int(input("\n Press 1 to play OR\n Press 2 for instructions"))
if(opcion == 1):
acum=0
while True:
letra2 = generarletra()
print(letra2)
key = getchar()
for s in range (0,2):
print("Segundos ", s)
time.sleep(2)
acum = acum + 1
if((key is not letra2) or (s == 2)):
print("su record fue de, ", acum)
break
elif(opcion == 2):
print("\n\nWelcome to key pop it!\nThe game is simple, the machine is going to generate a
random\nletter and you have to press it on your keyboard, if you take too\nlong or press the wrong
letter, you will lose.")
else:
print("Invalid option!")
PD: You need to run it with a console simulation in your IDE or directly from the console. msvcrt library won't work inside an IDE for some reason.

msvcrt.getch() is blocking, so you don't actually measure the time it took the user to press the key. The for loop starts after the user already pressed it.
also, time.sleep() is blocking, so the user will have to wait the sleep time even if he already pressed the key.
To solve the first problem you can use msvcrt.kbhit() to check if the user pressed on some key, and call msvcrt.getch() only if he did. This way msvcrt.getch() will return immediately after you call it.
To solve the second problem you can just use time.time() to get the start time of the round, and compare it to current time inside a loop. You can print how much time passed inside the loop also.
Here is the final code (with some extra naming and formatting changes):
import string
import random
import msvcrt
import time
MAX_TIME = 2
def get_random_char():
return random.choice(string.ascii_lowercase)
def get_user_char():
return msvcrt.getch().decode('utf-8')
print("\nWelcome to Key Pop It!")
option = input("\n Press 1 to play OR\n Press 2 for instructions\n")
if option == "1":
score=0
while True:
char = get_random_char()
print("\n" + char)
start_time = time.time()
while not msvcrt.kbhit():
seconds_passed = time.time() - start_time
print("seconds passed: {0:.1f}".format(seconds_passed), end="\r")
if seconds_passed >= MAX_TIME:
key = None
break
else:
key = get_user_char()
if key != char:
break
score = score + 1
print("\nsu record fue de, ", score)
elif option == "2":
print("""
Welcome to key pop it!
The game is simple, the machine is going to generate a random
letter and you have to press it on your keyboard, if you take too
long or press the wrong letter, you will lose.""")
else:
print("Invalid option!")

Timestamp-solution:
from time import time, sleep
start = time() # start time measuring by creating timestamp
def time_passed(start, duration):
"""tests if an amount of time has passed
Args:
start(float): timestamp of time()
duration(int): seconds that need to pass
Returns:
bool: are 'duration' seconds over since 'start'
"""
return start + duration <= time()
# Use as condition for while
while not time_passed(start, 5):
sleep(1)
# ... or if statements or <younameit>
if time_passed(start, 5):
print("Do something if 5 seconds are over")

Pause and resume a running script in Python 3.42 in Windows

I'm new to Python and have been googling for a couple of days and read all I can find on this forum. Might be that I don't understand it all but I haven't found a solution to my problem yet. Ask for forgiveness already if there's an answer already to my problem, then I haven't understood it.
I want to make a Pause function for my program Tennismatch. The program will when it's being run print the score of a tennis match like this: "15-0, 15-15 etc ongoing till the match ends. It will print the score line by line.
I want the user to be able to pause after x number of balls, games, etc. So I don't know when the user wants to pause and after the user has paused I want the user to be able to resume the tennismatch where it was.
Have seen the time.sleep() but as I have understood it you must know when you want to pause to use this and it also ain't an indefinetie pause like I want. With input() it's the same.
Am going to make a GUI later on when the code is finished. Happy for anything that leads me to solving my problem.
I use Windows and Python 3.42 and run the program in Shell.
A piece of the code (haven't written it all yet, it's more of a general situation when something is being printed line after line for some time and want to be able do pause in the CIL:
#self.__points = [0,0]
def playGame(self):
if self.server == True: #self.server is either True or False when someone calls playGame()
server = self.player_1.get_win_serve() #self.player_1 = an object of a class Player():
else:
server = self.player_2.get_win_serve() #get_win_serve() method returns the probability to win his serv (1-0)
while (0 < self.__points[0] - self.__points[1] >= 2 or 0 < self.__points[1] - self.__points[0] >= 2) and (self.__points[1] >= 4 or self.__points[0] >= 4):
x = random.uniform(0,1)
if x > 0 and x < server:
self.__points[0] += 1
else:
self.__points[1] += 1
# print('The score, by calling a score() function that I haven't written yet')

For dealing with events in main loop you need to make a separated thread which capture input or any other event.
import sys
from sys import stdin
from time import sleep
from threading import Thread
from Queue import Queue, Empty
def do_something():
sleep(1)
print 42
def enqueue_output(queue):
while True:
# reading line from stdin and pushing to shared queue
input = stdin.readline()
print "got input ", input
queue.put(input)
queue = Queue()
t = Thread(target=enqueue_output, args=(queue,))
t.daemon = True
t.start()
pause = False
try:
while True:
try:
command = queue.get_nowait().strip()
print 'got from queue ', command
except Empty:
print "queue is empty"
command = None
if command:
if command == 'p':
pause = True
if command == 'u':
pause = False
if not pause:
print pause
do_something()
except KeyboardInterrupt:
sys.exit(0)

I came up with the following.
while True:
try:
## Keep doing something here
## your regular code
print '.',
except KeyboardInterrupt:
## write or call pause function which could be time.sleep()
print '\nPausing... (Hit ENTER to continue, type quit to exit.)'
try:
response = raw_input()
if response.lower() == 'quit':
break
print 'Quitting...'
except KeyboardInterrupt:
print 'Resuming...'
continue

The Event loop might as well be the code I wrote with.
I don't see any user input so I assume that x emulates it. To pause the game if x < 0.1 and to unpause(/resume) it if x > 0.9, you could:
while your_condition(self.__points):
x = random.random()
if x < 0.1: # pause
self.pause()
elif x > 0.9: # resume
self.resume()
if self.is_paused:
continue # do nothing else only wait for input (`x`)
# assume your_condition() has no side-effects
# here's what the resumed version does:
print("...")
# change self.__points, etc
where pause(), resume(), is_paused() methods could be implemented as:
def __init__(self):
self.is_paused = False
def pause(self):
self.is_paused = True
def resume(self):
self.is_paused = False
as you can see the implementation is very simple.

How to set time limit on raw_input

in python, is there a way to, while waiting for a user input, count time so that after, say 30 seconds, the raw_input() function is automatically skipped?

The signal.alarm function, on which #jer's recommended solution is based, is unfortunately Unix-only. If you need a cross-platform or Windows-specific solution, you can base it on threading.Timer instead, using thread.interrupt_main to send a KeyboardInterrupt to the main thread from the timer thread. I.e.:
import thread
import threading
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
timer = threading.Timer(timeout, thread.interrupt_main)
astring = None
try:
timer.start()
astring = input(prompt)
except KeyboardInterrupt:
pass
timer.cancel()
return astring
this will return None whether the 30 seconds time out or the user explicitly decides to hit control-C to give up on inputting anything, but it seems OK to treat the two cases in the same way (if you need to distinguish, you could use for the timer a function of your own that, before interrupting the main thread, records somewhere the fact that a timeout has happened, and in your handler for KeyboardInterrupt access that "somewhere" to discriminate which of the two cases occurred).
Edit: I could have sworn this was working but I must have been wrong -- the code above omits the obviously-needed timer.start(), and even with it I can't make it work any more. select.select would be the obvious other thing to try but it won't work on a "normal file" (including stdin) in Windows -- in Unix it works on all files, in Windows, only on sockets.
So I don't know how to do a cross-platform "raw input with timeout". A windows-specific one can be constructed with a tight loop polling msvcrt.kbhit, performing a msvcrt.getche (and checking if it's a return to indicate the output's done, in which case it breaks out of the loop, otherwise accumulates and keeps waiting) and checking the time to time out if needed. I cannot test because I have no Windows machine (they're all Macs and Linux ones), but here the untested code I would suggest:
import msvcrt
import time
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
finishat = time.time() + timeout
result = []
while True:
if msvcrt.kbhit():
result.append(msvcrt.getche())
if result[-1] == '\r': # or \n, whatever Win returns;-)
return ''.join(result)
time.sleep(0.1) # just to yield to other processes/threads
else:
if time.time() > finishat:
return None
The OP in a comment says he does not want to return None upon timeout, but what's the alternative? Raising an exception? Returning a different default value? Whatever alternative he wants he can clearly put it in place of my return None;-).
If you don't want to time out just because the user is typing slowly (as opposed to, not typing at all!-), you could recompute finishat after every successful character input.

I found a solution to this problem in a blog post. Here's the code from that blog post:
import signal
class AlarmException(Exception):
pass
def alarmHandler(signum, frame):
raise AlarmException
def nonBlockingRawInput(prompt='', timeout=20):
signal.signal(signal.SIGALRM, alarmHandler)
signal.alarm(timeout)
try:
text = raw_input(prompt)
signal.alarm(0)
return text
except AlarmException:
print '\nPrompt timeout. Continuing...'
signal.signal(signal.SIGALRM, signal.SIG_IGN)
return ''
Please note: this code will only work on *nix OSs.

The input() function is designed to wait for the user to enter something (at least the [Enter] key).
If you are not dead set to use input(), below is a much lighter solution using tkinter. In tkinter, dialog boxes (and any widget) can be destroyed after a given time.
Here is an example :
import tkinter as tk
def W_Input (label='Input dialog box', timeout=5000):
w = tk.Tk()
w.title(label)
W_Input.data=''
wFrame = tk.Frame(w, background="light yellow", padx=20, pady=20)
wFrame.pack()
wEntryBox = tk.Entry(wFrame, background="white", width=100)
wEntryBox.focus_force()
wEntryBox.pack()
def fin():
W_Input.data = str(wEntryBox.get())
w.destroy()
wSubmitButton = tk.Button(w, text='OK', command=fin, default='active')
wSubmitButton.pack()
# --- optionnal extra code in order to have a stroke on "Return" equivalent to a mouse click on the OK button
def fin_R(event): fin()
w.bind("<Return>", fin_R)
# --- END extra code ---
w.after(timeout, w.destroy) # This is the KEY INSTRUCTION that destroys the dialog box after the given timeout in millisecondsd
w.mainloop()
W_Input() # can be called with 2 parameter, the window title (string), and the timeout duration in miliseconds
if W_Input.data : print('\nYou entered this : ', W_Input.data, end=2*'\n')
else : print('\nNothing was entered \n')

from threading import Timer
def input_with_timeout(x):
def time_up():
answer= None
print('time up...')
t = Timer(x,time_up) # x is amount of time in seconds
t.start()
try:
answer = input("enter answer : ")
except Exception:
print('pass\n')
answer = None
if answer != True: # it means if variable have somthing
t.cancel() # time_up will not execute(so, no skip)
input_with_timeout(5) # try this for five seconds
As it is self defined... run it in command line prompt , I hope you will get the answer
read this python doc you will be crystal clear what just happened in this code!!

A curses example which takes for a timed math test
#!/usr/bin/env python3
import curses
import curses.ascii
import time
#stdscr = curses.initscr() - Using curses.wrapper instead
def main(stdscr):
hd = 100 #Timeout in tenths of a second
answer = ''
stdscr.addstr('5+3=') #Your prompt text
s = time.time() #Timing function to show that solution is working properly
while True:
#curses.echo(False)
curses.halfdelay(hd)
start = time.time()
c = stdscr.getch()
if c == curses.ascii.NL: #Enter Press
break
elif c == -1: #Return on timer complete
break
elif c == curses.ascii.DEL: #Backspace key for corrections. Could add additional hooks for cursor movement
answer = answer[:-1]
y, x = curses.getsyx()
stdscr.delch(y, x-1)
elif curses.ascii.isdigit(c): #Filter because I only wanted digits accepted
answer += chr(c)
stdscr.addstr(chr(c))
hd -= int((time.time() - start) * 10) #Sets the new time on getch based on the time already used
stdscr.addstr('\n')
stdscr.addstr('Elapsed Time: %i\n'%(time.time() - s))
stdscr.addstr('This is the answer: %s\n'%answer)
#stdscr.refresh() ##implied with the call to getch
stdscr.addstr('Press any key to exit...')
curses.wrapper(main)

under linux one could use curses and getch function, its non blocking.
see getch()
https://docs.python.org/2/library/curses.html
function that waits for keyboard input for x seconds (you have to initialize a curses window (win1) first!
import time
def tastaturabfrage():
inittime = int(time.time()) # time now
waitingtime = 2.00 # time to wait in seconds
while inittime+waitingtime>int(time.time()):
key = win1.getch() #check if keyboard entry or screen resize
if key == curses.KEY_RESIZE:
empty()
resize()
key=0
if key == 118:
p(4,'KEY V Pressed')
yourfunction();
if key == 107:
p(4,'KEY K Pressed')
yourfunction();
if key == 99:
p(4,'KEY c Pressed')
yourfunction();
if key == 120:
p(4,'KEY x Pressed')
yourfunction();
else:
yourfunction
key=0

This is for newer python versions, but I believe it will still answer the question. What this does is it creates a message to the user that the time is up, then ends the code. I'm sure there's a way to make it skip the input rather than completely end the code, but either way, this should at least help...
import sys
import time
from threading import Thread
import pyautogui as pag
#imports the needed modules
xyz = 1 #for a reference call
choice1 = None #sets the starting status
def check():
time.sleep(15)#the time limit set on the message
global xyz
if choice1 != None: # if choice1 has input in it, than the time will not expire
return
if xyz == 1: # if no input has been made within the time limit, then this message
# will display
pag.confirm(text = 'Time is up!', title = 'Time is up!!!!!!!!!')
sys.exit()
Thread(target = check).start()#starts the timer
choice1 = input("Please Enter your choice: ")