i'm trying to comunicate with a webserver with python. I'm using the suds library. Actually i'm pretty new with this.
Usually, to comunicate with this WebServer a send a xml message and i get a response. So this is what i would like to do with python.
Here's the code i wrote:
from suds.client import Client
with open("PATH","r") as f:
file=f.read()
url='URL'
client = Client(url)
httpHeaders = {'Content-Type': 'text/xml', 'SOAPAction': 'ACTION'}
client.set_options(headers=httpHeaders)
Now i don't know how to make the request. I tried this:
print client.service.test(__inject={'msg': file})
But i got the error:
Exception: No services defined
The problem seems clear, but i don't know haw to procede. Any suggestion ?
Related
I am using a zeep client to consume a web service that is supposed to return me a file in base64binary format. I am using the following code.
try:
client = Client('https://host.com/xmlpserver/services/v2/CatalogService?wsdl')
response = client.service.downloadObject('/~fin_impl/INVITEM20.xdo','username','password')
print(response)
except zeepExceptions.Fault as fault:
print(fault.detail)
However, I am not sure what format is this response in and how to decode it.
b'PK\x03\x04\x14\x00\x08\x08\x08\x00o\xb8\x9cP\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x0b\x00\x00\x00_report.xdo\x8dT\xcbN\xdc0\x14\xdd\xf3\x15V6\xacH\x02tQ\x01\x03*/i\xa4\x99\x01\r\x94v\x87\x8cs\x87\xb1\xf0K\xf65\xc9t\xd1o\xefu^\xa2\x14\xaaI\x94\x85\x8f\x8f}\xcf\xb99\xf6\xc9Y\xa3\x15{\x05\x1f\xa45l\xc2v\xf7\xf3r\x97\x81\x11\xb6\x92\xe69\x01\x11W{_w\xcfNwN<8\xeb\x91\xd1\x02\x13&\xd9\x1a\xd1\x1d\x15E;\xca\xad\xe7BA.\xac.l\xe3\x12\xe8\xb2\x8ex\xd4\x84j$\xd7\xf4\xe4\xf5!\xd1\x9f\x8b\x83\xb2\xdc/~\xcegwb\r\x9ag\x83\x86Iv\x90\x97\x19\xab8\xf2\xb9\xad#M2\xf4\x112\x16\x03\x9cKw\xcb=\xd7\x80D\x1dp\xe7m\x15\x05\xf8\x05\xe1\x93l%\xcd\x1e}\xdc\x08\xc9\xd5\x85\xd5\xda\x1a\xa2\x0c\x8b\x1en:\xd6\x1b\xe8\x9e\x87\x97ke\xeb\x04\x8a\x18\xd0\xeaK\xaa|a\rz\xabZ\x90\x93\xbe[\xf0\xdf\x03\xf8\xa1f\x8b\xddi\xeeq\t+\x0faM\x85\xb9\n\xc3L\xa2\xbe\x9b8\xdda\x8c\x9d\x8c\xa6X\xf4\xb4y\xf1\xfbz\xbax\x9c\xceog\xc5t\xf10\xbd\xbf\x9a\xe7M\xa5\xb3\xa2\'C\x10^:\xa4\x9e\xf4\x08Yu\xe0q\xc3L\xeb"\xacm\xdd\x0b\r\xd4>\xae"\xf4\x02?\xe6[\xa3\xa4\x81\xad\x98\x0e\xccL\x9a\x97\xa9Y#\xfdC\x9a\xca\xd6\xdb,\xe3\x11\xed2\x9a\x91\xdaY\xff\x98\xdb6\xea\xd2\x8a\xa8\xc1\xe06\x9b\'\xb7\xcb6\x80I\xd9V\x86y\xd8\x18\xb1\xf6\xd6\xd8\x18\xb6\xd5\xe5\xbc\xb4^\xe2f$\x1b\xeb5W\xffu\x11=O\x7fi\\rX~F\xef\xfe\x16T\xe7\x9b\xab\x06\xbf9\xf7\x89\xa41\xe4]N)}\xe49m\x9c\xb1\x80\x1b\x95d\x0e\x94\x99\x15m\xf1#\n\xfe\x9a\x94\xff\xa2\x12\\\x1dSa\xedp\x9c\x0c\xb2\x82\xe3a{\x04\xed\x14G\x08\xac\x82\x15\x8f\n\'Y\x1f\xbf\xc7\x83\x92\xde\xfd\xb2\xfc\xd2\x05\xf6-\x9b)\xfe\x94N\xe3\xbf\xd4.\xcco\xf1\x04\xe7MJ%n\x1c\xa9\x85F\x80\xca\x98\x8d\xe8"^\xa7\x86\xe2\x08\xf6\x1a\xde\xa1\x8a\x94\'\x9f#]\xadd\xe0O\n\xe6<\xa4\xf3\xda\xcb\x19\x8e"\x17(_\xc7\xd1\xab\x84\xfa\xa6\x8d\xf9\xdf\xc1(F\xcft\x8d\x15\xdd=v\xba\xf3\x07PK\x07\x08\xe8\xc9\xba\xb2-\x02\x00\x00\xfc\x04\x00\x00PK\x03\x04\x14\x00\x08\x08\x08\x00o\xb8\x9cP\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x18\x00\x00\x00INVITEM_20201004.xls.png\x03\x00PK\x07\x08\x00\x00\x00\x00\x02\x00\x00\x00\x00\x00\x00\x00PK\x03\x04\x14\x00\x08\x08\x08\x00o\xb8\x9cP\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x17\x00\x00\x00INVITEM_20201004_en.xls\xed]\x07\\SI ........'
Please suggest, Thanks
from suds.client import Client
url = r'http://*********?singleWsdl'
c = Client(url)
The requests work fine till here, but when I execute the below statement, I get the error message shown at the end. Please help.
c.service.Method_Name('parameter1', 'parameter2')
The Error message is :
Exception: (415, u'Cannot process the message because the content type
\'text/xml; charset=utf-8\' was not the expected type
\'multipart/related; type="application/xop+xml"\'.')
A Content-Type header of multipart/related; type="application/xop+xml" is the type used by MTOM, a message format used to efficiently send attachments to/from web services.
I'm not sure why the error claims to be expecting it, because the solution I found for my situation was the override the Content-Type header to 'application/soap+xml;charset=UTF-8'.
Example:
soap_client.set_options(headers = {'Content-Type': 'application/soap+xml;charset=UTF-8'})
If you are able, you could also trying checking for MTOM encoding in the web service's configuration and changing it.
I have to work with an API that has multiple services. All of which require the JSESSION cookie from the authentication one below. When I call the next service however, it doesn't keep the cookie and so rejects them.
from suds.client import Client
url = 'http://example/ws/Authenticate?wsdl'
client = Client(url)
result = client.service.connect(username='admin', password='admin')
print client.options.transport.cookiejar
>>> <cookielib.CookieJar[<Cookie JSESSIONID=XXXXXXXXXX for localhost.local/Service/>]>
I believe that the way to get it to keep this cookie is to extract it, then provide it as a custom header in the format: -
url = 'http://example/ws/dostuffnowloggedin?wsdl'
client2 = Client(url, headers= { 'Cookie': 'JSESSIONID=value'})
But I can't figure out how to do it. I've reviewed the SUDS Docs, URL2LIB and Cookiejar python docs, looked over stack & asked on Reddit. This is the first question I've asked on Stack, I've tried to make it meaningful and specific, but if I've commited a faux par, tell me and I'll do my best to correct it.
Try this.
from suds.client import Client
url = 'http://example/ws/Authenticate?wsdl'
client = Client(url)
result = client.service.connect(username='admin', password='admin')
url2='url of second service'
client2=Client(url2)
client2.options.transport.cookiejar=client.options.transport.cookiejar
I'm currently working on a automated way to interface with a database website that has RESTful webservices installed. I am having issues with figure out the proper formatting of how to properly send the requests listed in the following site using python.
https://neesws.neeshub.org:9443/nees.html
Particular example is this:
POST https://neesws.neeshub.org:9443/REST/Project/731/Experiment/1706/Organization
<Organization id="167"/>
The biggest problem is that I do not know where to put the XML formatted part of the above. I want to send the above as a python HTTPS request and so far I've been trying something of the following structure.
>>>import httplib
>>>conn = httplib.HTTPSConnection("neesws.neeshub.org:9443")
>>>conn.request("POST", "/REST/Project/731/Experiment/1706/Organization")
>>>conn.send('<Organization id="167"/>')
But this appears to be completely wrong. I've never actually done python when it comes to webservices interfaces so my primary question is how exactly am I supposed to use httplib to send the POST Request, particularly the XML formatted part of it? Any help is appreciated.
You need to set some request headers before sending data. For example, content-type to 'text/xml'. Checkout the few examples,
Post-XML-Python-1
Which has this code as example:
import sys, httplib
HOST = www.example.com
API_URL = /your/api/url
def do_request(xml_location):
"""HTTP XML Post requeste"""
request = open(xml_location,"r").read()
webservice = httplib.HTTP(HOST)
webservice.putrequest("POST", API_URL)
webservice.putheader("Host", HOST)
webservice.putheader("User-Agent","Python post")
webservice.putheader("Content-type", "text/xml; charset=\"UTF-8\"")
webservice.putheader("Content-length", "%d" % len(request))
webservice.endheaders()
webservice.send(request)
statuscode, statusmessage, header = webservice.getreply()
result = webservice.getfile().read()
print statuscode, statusmessage, header
print result
do_request("myfile.xml")
Post-XML-Python-2
You may get some idea.
I'm trying to use the Zimbra SOAP API from Python to programmatically modify & cleanup my contacts but I'm having trouble getting started.
What I have so far is:
from SOAPpy import SOAPProxy
url = 'https://zimbra/service/soap'
auth = {"account": "xxxxx", "password": "xxxxx"}
zimbra = SOAPProxy(url, 'urn:zimbra')
zimbraAuth = SOAPProxy(url, "urn:zimbraAccount")
zimbraMail = SOAPProxy(url, "urn:zimbraMail")
response = zimbraAuth.AuthRequest(**auth)
authToken = response.authToken
I've logged in successfully, but can't pass this authToken in further requests.
My understanding is that any zimbraMail requests need to have a header in the urn:zimbra namespace with the authToken set there, but being new to SOAP I have no idea how to do so.
I'm not married to using SOAPpy so any example code for another library would be well appreciated.
I'd like to nod in the direction of Python-Zimbra, a python library for Zimbra, which does all that for you.
There is also an higher level, and pythonic library: zimsoap.
Using raw SOAP or python-zimbra or zimsoap depends realy on what level of flexibility/ease you need (although I will not suggest using SOAP directly, as python-zimbra can issue any possible SOAP request to zimbra.