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Form Problems - Setting Initial Value

I am trying to set the initial value of a field on a form. The field is not part of the model, but when I try and set it to a value the field is blank. From my research it could be because the form is "bound" which makes some sense to me, but in this case the field is not part of the model.
My form:
#Form for editing profile
class CatForm(forms.ModelForm):
pictureid = forms.CharField()
class Meta:
model = Cat
fields = ['name']
def __init__(self, *args, **kwargs):
picid = kwargs.pop("pictureid")
print(picid)
super(CatForm, self).__init__(*args, **kwargs)
self.fields['pictureid'] = forms.CharField(initial=picid, required=False)
The model:
class Cat(models.Model):
name = models.CharField(max_length=34,null=False)
From the view it is called like this:
catform = CatForm(request.POST, pictureid=instance.id)
I was expecting it to set the field to the value of the initial attribute, but it doesn't. I have tried testing it by directly adding a string, but doesn't set.
This is what seems to be working for me:
class CatForm(forms.ModelForm):
class Meta:
model = Cat
fields = ['name']
def __init__(self, *args, **kwargs):
picid = kwargs.pop("pictureid")
super(CatForm, self).__init__(*args, **kwargs)
self.fields['pictureid'] = forms.CharField(initial=picid)
I also needed to drop the "request.POST" from the call to this when initiating the form.

If you want to render the pictureid in GET request, then you can try like this:
catform = CatForm(initial={'pictureid': instance.id})
For GET request, you don't need to override the __init__ method.
But, if you want to use the Catform in POST request, to use the value of pictureid somewhere else(lets say in save method), then you will need to override __init__ method here.
class CatForm(forms.ModelForm):
pictureid = forms.CharField()
class Meta:
model = Cat
fields = ['name']
def __init__(self, *args, **kwargs):
picid = kwargs.pop("pictureid")
print(picid)
super(CatForm, self).__init__(*args, **kwargs)
self.pictureid = picid
def save(self, *args, **kwargs):
print(self.pictureid) # if you want to use it in save method
return super().save(*args, **kwargs)

django application with postgresql error value too long for type character varying(1)

I have a problem with django app and POSTGRESQL database with the slug field.
Error:
value too long for type character varying(1)
I test my app with sqlite database and everything works fine, but my app does not work in postgresql database. Any ideas why this is the case?
Test 1:
class MyModel(models.Model):
name = models.CharField(max_length=254)
slug_name = models.SlugField(max_length=254)
def save(self, *args, **kwargs):
self.slug_name = slugify(self.name)
super(MyModel, self).save(*args, **kwargs)
Test 2:
class MyModel(models.Model):
name = models.TextField(max_length=500)
slug_name = models.SlugField(max_length=500)
def save(self, *args, **kwargs):
self.slug_name = slugify(self.name)
super(MyModel, self).save(*args, **kwargs)
Test 3:
class MyModel(models.Model):
name = models.TextField()
slug_name = models.SlugField()
def save(self, *args, **kwargs):
self.slug_name = slugify(self.name)
super(MyModel, self).save(*args, **kwargs)

You're trying to insert a value with more that one character into a field specified as character varying(1). SQLite3 will allow this (see https://sqlite.org/datatype3.html) but PostgreSQL will give an error - i.e., it enforces that you have specified the maximum length as 1.

how to i can change wagtail cms page tag before save

How can I change wagtail page tag before saving?
I can change the title by overriding save() like this-
class ProductPageTag(TaggedItemBase):
content_object = ParentalKey('product.ProductPage',related_name='tagged_items')
class ProductPage(Page):
body = StreamField(BodyStreamBlock)
tags = ClusterTaggableManager(through=ProductPageTag, blank=True)
def save(self, *args, **kwargs):
self.title = "my title" # work
self.tags = "test,test2,test3" #not work
super(ProductPage, self).save()
but I don't know how to change the tag list.

I Found the Answer :D
just need change
self.tags = "test,test2,test3"
to
self.tags.add('test',"test2","test3")
final code
class ProductPageTag(TaggedItemBase):
content_object =ParentalKey('product.ProductPage',related_name='tagged_items')
class ProductPage(Page):
body = StreamField(BodyStreamBlock)
tags = ClusterTaggableManager(through=ProductPageTag, blank=True)
def save(self, *args, **kwargs):
self.title = "my title" # work
self.tags.add('test',"test2","test3") #work
super().save(*args, **kwargs)
(Or, when working with the old Python 2.7, super(ProductPage, self).save(*args, **kwargs))

Overriding save method to create second auto incrementing field in Django

I am trying to override the save method on a model in order to generate a unique, second auto-incrementing id.
I create my class and override the save() method, but for some reason it is erroring out with the following error:
TypeError: %d format: a number is required, not NoneType
Here's the code:
class Person(models.Model):
target = models.OneToOneField(Target)
person = models.OneToOneField(User)
gender = models.CharField(max_length=1)
gender_name = models.CharField(max_length=100)
person_id = models.CharField(max_length=100)
def save(self, *args, **kwargs):
self.person_id = "%07d" % self.id
super(Person, self).save(*args, **kwargs)
Is it because I didn't pass an id parameter and it hasn't saved yet? Is there anyway to generate a value from the id?

Safest and easiest way to achieve what you want is to use a post_save signal because it is fired right after save is called, but before the transaction is committed to the database.
from django.dispatch import receiver
from django.db.models.signals import post_save
#receiver(post_save, sender=Person)
def set_person_id(sender, instance, created, **kwargs):
if created:
instance.person_id = "%07d" % instance.id
instance.save()

Yes, self.id will be Nonein some cases, and then the assignment will fail.
However you cannot just the assignment and the call to super, as suggested in the comments, because then you wouldn't be persisting the assignment to the database layer.
You need to check whether the model has an id and then proceed differently:
def save(self, *args, **kwargs):
if not self.id: # Upon instance creation
super(Person, self).save(*args, **kwargs) # Acquire an ID
self.person_id = "%07d" % self.id # Set the person_id
return super(Person, self).save(*args, **kwargs)
This issues two save operations to the database. You will want to wrap them in a transaction to make sure your database receives these two fields simultaneously.
from django.db import IntegrityError, transaction
class Person(models.Model):
target = models.OneToOneField(Target)
person = models.OneToOneField(User)
gender = models.CharField(max_length=1)
gender_name = models.CharField(max_length=100)
person_id = models.CharField(max_length=100)
def create_person_id(self):
if not self.id: # Upon instance creation
super(Person, self).save(*args, **kwargs) # Acquire an ID
self.person_id = "%07d" % self.id
def save(self, *args, **kwargs):
try:
with transaction.atomic():
self.create_person_id
return super(Person, self).save(*args,**kwargs)
except IntegrityError:
raise # or deal with the error

I agree that signals might be the better option, if not, try using pk instead of id.
class Person(models.Model):
# [ . . . ]
def save(self, *args, **kwargs):
self.person_id = "%07d" % self.pk
super(Person, self).save(*args, **kwargs)

Django. Override save for model

Before saving model I'm re-size a picture. But how can I check if new picture added or just description updated, so I can skip rescaling every time the model is saved?
class Model(model.Model):
image=models.ImageField(upload_to='folder')
thumb=models.ImageField(upload_to='folder')
description=models.CharField()
def save(self, *args, **kwargs):
if self.image:
small=rescale_image(self.image,width=100,height=100)
self.image_small=SimpleUploadedFile(name,small_pic)
super(Model, self).save(*args, **kwargs)
I want to rescale only if new image loaded or image updated, but not when description updated.

Some thoughts:
class Model(model.Model):
_image=models.ImageField(upload_to='folder')
thumb=models.ImageField(upload_to='folder')
description=models.CharField()
def set_image(self, val):
self._image = val
self._image_changed = True
# Or put whole logic in here
small = rescale_image(self.image,width=100,height=100)
self.image_small=SimpleUploadedFile(name,small_pic)
def get_image(self):
return self._image
image = property(get_image, set_image)
# this is not needed if small_image is created at set_image
def save(self, *args, **kwargs):
if getattr(self, '_image_changed', True):
small=rescale_image(self.image,width=100,height=100)
self.image_small=SimpleUploadedFile(name,small_pic)
super(Model, self).save(*args, **kwargs)
Not sure if it would play nice with all pseudo-auto django tools (Example: ModelForm, contrib.admin etc).

Check the model's pk field. If it is None, then it is a new object.
class Model(model.Model):
image=models.ImageField(upload_to='folder')
thumb=models.ImageField(upload_to='folder')
description=models.CharField()
def save(self, *args, **kwargs):
if 'form' in kwargs:
form=kwargs['form']
else:
form=None
if self.pk is None and form is not None and 'image' in form.changed_data:
small=rescale_image(self.image,width=100,height=100)
self.image_small=SimpleUploadedFile(name,small_pic)
super(Model, self).save(*args, **kwargs)
Edit: I've added a check for 'image' in form.changed_data. This assumes that you're using the admin site to update your images. You'll also have to override the default save_model method as indicated below.
class ModelAdmin(admin.ModelAdmin):
def save_model(self, request, obj, form, change):
obj.save(form=form)

You may supply extra argument for confirming a new image is posted.
Something like:
def save(self, new_image=False, *args, **kwargs):
if new_image:
small=rescale_image(self.image,width=100,height=100)
self.image_small=SimpleUploadedFile(name,small_pic)
super(Model, self).save(*args, **kwargs)
or pass request variable
def save(self, request=False, *args, **kwargs):
if request and request.FILES.get('image',False):
small=rescale_image(self.image,width=100,height=100)
self.image_small=SimpleUploadedFile(name,small_pic)
super(Model, self).save(*args, **kwargs)
I think these wont break your save when called simply.
You may put this in your admin.py so that this work with admin site too (for second of above solutions):
class ModelAdmin(admin.ModelAdmin):
....
def save_model(self, request, obj, form, change):
instance = form.save(commit=False)
instance.save(request=request)
return instance

Query the database for an existing record with the same PK. Compare the file sizes and checksums of the new and existing images to see if they're the same.

What I did to achieve the goal was to make this..
# I added an extra_command argument that defaults to blank
def save(self, extra_command="", *args, **kwargs):
and below the save() method is this..
# override the save method to create an image thumbnail
if self.image and extra_command != "skip creating photo thumbnail":
# your logic here
so when i edit some fields but not editing the image, I put this..
Model.save("skip creating photo thumbnail")
you can replace the "skip creating photo thumbnail" with "im just editing the description" or a more formal text.
Hope this one helps!

In new version it is like this:
def validate(self, attrs):
has_unknown_fields = set(self.initial_data) - set(self.fields.keys())
if has_unknown_fields:
raise serializers.ValidationError("Do not send extra fields")
return attrs

I have found one another simple way to store the data into the database
models.py
class LinkModel(models.Model):
link = models.CharField(max_length=500)
shortLink = models.CharField(max_length=30,unique=True)
In database I have only 2 variables
views.py
class HomeView(TemplateView):
def post(self,request, *args, **kwargs):
form = LinkForm(request.POST)
if form.is_valid():
text = form.cleaned_data['link'] # text for link
dbobj = LinkModel()
dbobj.link = text
self.no = self.gen.generateShortLink() # no for shortLink
dbobj.shortLink = str(self.no)
dbobj.save() # Saving from views.py
In this I have created the instance of model in views.py only and putting/saving data into 2 variables from views only.