We Keep Coding

When I open a text file, it only reads the last line

Say customPassFile.txt has two lines in it. First line is "123testing" and the second line is "testing321". If passwordCracking = "123testing", then the output would be that "123testing" was not found in the file (or something similar). If passwordCracking = "testing321", then the output would be that "testing321" was found in the file. I think that the for loop I have is only reading the last line of the text file. Any solutions to fix this?
import time
import linecache
def solution_one(passwordCracking):
print("Running Solution #1 # " + time.strftime("%Y-%m-%d %H:%M:%S",time.localtime()))
startingTimeSeconds = time.time()
currentLine = 1
attempt = 1
passwordFound = False
wordListFile = open("customPassFile.txt", encoding="utf8")
num_lines = sum(1 for line in open('customPassFile.txt'))
while(passwordFound == False):
for i, line in enumerate(wordListFile):
if(i == currentLine):
line = line
passwordChecking = line
if(passwordChecking == passwordCracking):
passwordFound = True
endingTimeSeconds = time.time()
overallTimeSeconds = endingTimeSeconds - startingTimeSeconds
print("~~~~~~~~~~~~~~~~~")
print("Password Found: {}".format(passwordChecking))
print("ATTEMPTS: {}".format(attempt))
print("TIME TO FIND: {} seconds".format(overallTimeSeconds))
wordListFile.close()
break
elif(currentLine == num_lines):
print("~~~~~~~~~~~~~~~~~")
print("Stopping Solution #1 # " + time.strftime("%Y-%m-%d %H:%M:%S", time.localtime()))
print("REASON: Password could not be cracked")
print("ATTEMPTS: {}".format(attempt))
break
else:
attempt = attempt + 1
currentLine = currentLine + 1
continue

The main problem with your code is that you open the file and you read it multiple times. The first time the file object position goes to the end and stays there. Next time you read the file nothing happens, since you are already at the end of the file.
Example
Sometimes an example is worth more than lots of words.
Take the file test_file.txt with the following lines:
line1
line2
Now open the file and read it twice:
f = open('./test_file.txt')
f.tell()
>>> 0
for l in f:
print(l, end='')
else:
print('nothing')
>>> line1
>>> line2
>>> nothing
f.tell()
>>> 12
for l in f:
print(l, end='')
else:
print('nothing')
>>> nothing
f.close()
The second time nothing happen, as the file object is already at the end.
Solution
Here you have two options:
you read the file only once and save all the lines in a list and then use the list in your code. It should be enough to replace
wordListFile = open("customPassFile.txt", encoding="utf8")
num_lines = sum(1 for line in open('customPassFile.txt'))
with
with open("customPassFile.txt", encoding="utf8") as f:
wordListFile = f.readlines()
num_lines = len(wordListFile)
you reset the file object position after you read the file using seek. It would be something along the line:
for i, line in enumerate(wordListFile):
if(i == currentLine):
line = line
wordListFile.seek(0)
I would go with option 1., unless you have memory constraint (e.g. the file is bigger than memory)
Notes
I have a few extra notes:
python starts counters with 0 (like c/c++) and not 1 (like fortran). So probably you want to set:
currentLine = 0
when you read a file, the new line character \n is not stripped, so you have to do it (with strip) or account for it when comparing strings (using e.g. startswith). As example:
passwordChecking == passwordCracking
will likely always return False as passwordChecking contains \n and passwordCracking very likely doesn't.
Disclamer
I haven't tried the code, nor my suggestions, so there might be other bugs lurking around.

**I will delete this answer after OP understands the problem in indentation of I understand his intention of his code.*
for i, line in enumerate(wordListFile):
if(i == currentLine):
line = line
passwordChecking = line
#rest of the code.
Here your code is outside of for loop so only last line is cached.
for i, line in enumerate(wordListFile):
if(i == currentLine):
line = line
passwordChecking = line
#rest of the code.

Python Replace String in File in With clause

I am trying to replace a string in a file.
Below code is simply modifying certain substrings within the bigger string from the file. Any ideas on how I can actually replace line with current_line in the filename?
from sys import *
import os
import re
import datetime
import fileinput
script, filename = argv
userhome = os.path.expanduser('~')
username = os.path.split(userhome)[-1]
print "\n"
print "User: " + username
today = datetime.date.today().strftime("%Y/%m/%d")
time = datetime.datetime.now().strftime("%H:%M:%S")
print "Date: " + str(today)
print "Current time: " + str(time)
print "Filename: %s\n" % filename
def replace_string():
found = False
with open(filename, 'r+') as f:
for line in f:
if re.search("CVS Header", line):
print line
####################################################################################
# Below logic: #
# if length of revision number is 4 characters (e.g. 1.15) then increment by 0.01 #
# else if it is 3 characters (e.g. 1.5) then increment by 0.1 #
####################################################################################
if len(line.split("$Revision: ")[1].split()[0]) == 4:
new_line = str.replace(line, line.split("$Revision: ")[1].split()[0], str(float(line.split("$Revision: ")[1].split()[0]) + 0.01))
elif len(line.split("$Revision: ")[1].split()[0]) == 3:
new_line = str.replace(line, line.split("$Revision: ")[1].split()[0], str(float(line.split("$Revision: ")[1].split()[0]) + 0.1))
###
###
newer_line = str.replace(new_line, line.split("$Author: ")[1].split()[0], username)
newest_line = str.replace(newer_line, line.split("$Date: ")[1].split()[0], today)
current_line = str.replace(newest_line, line.split("$Date: ")[1].split()[1], time)
print current_line
found = True
if not found:
print "No CVS Header exists in %s" % filename
if __name__ == "__main__":
replace_string()
I tried adding something like..
f.write(f.replace(line, current_line))
but this just clears all the contents out of the file and leaves it blank so obviously that is incorrect.

The fileinput provides a way to edit a file in place. If you use the inplace parameter the file is moved to a backup file and standard output is directed to the input file.
import fileinput
def clause(line):
return len(line) < 5
for line in fileinput.input('file.txt', inplace=1):
if clause(line):
print '+ ' + line[:-1]
fileinput.close()
Trying to apply this idea to your example, it could be something like this:
def replace_string():
found = False
for line in fileinput.input(filename, inplace=1): # <-
if re.search("CVS Header", line):
#print line
####################################################################################
# Below logic: #
# if length of revision number is 4 characters (e.g. 1.15) then increment by 0.01 #
# else if it is 3 characters (e.g. 1.5) then increment by 0.1 #
####################################################################################
if len(line.split("$Revision: ")[1].split()[0]) == 4:
new_line = str.replace(line, line.split("$Revision: ")[1].split()[0], str(float(line.split("$Revision: ")[1].split()[0]) + 0.01))
elif len(line.split("$Revision: ")[1].split()[0]) == 3:
new_line = str.replace(line, line.split("$Revision: ")[1].split()[0], str(float(line.split("$Revision: ")[1].split()[0]) + 0.1))
###
###
newer_line = str.replace(new_line, line.split("$Author: ")[1].split()[0], username)
newest_line = str.replace(newer_line, line.split("$Date: ")[1].split()[0], today)
current_line = str.replace(newest_line, line.split("$Date: ")[1].split()[1], time)
print current_line[:-1] # <-
found = True
else:
print line[:-1] # <- keep original line otherwise
fileinput.close() # <-
if not found:
print "No CVS Header exists in %s" % filename

The solution proposed by user2040251 is the correct way, and the way used but all text editors I know. The reason is that in case of a major problem when writing the file, you keep the previous version unmodified until the new version is ready.
But of course if you want you can edit in place, if you accept the risk of completely losing the file in case of crash - it can be acceptable for a file under version control since you can always get previous commited version.
The principle is then a read before write, ensuring that you never write something that you have not still read.
At the simplest level, you load everything in memory with readlines, replace the line rewind the file the the correct position (or to the beginning) and write it back.
Edit : here is a simple implementation when all lines can be loaded in memory :
fd = open(filename, "r+")
lines = fd.readlines()
for i, line in enumerate(lines):
# test if line if the searched line
if found :
lines[i] = replacement_line
break
fd.seek(0)
fd.writelines()
It could be done even for a big file using readlines(16384) for example instead of readlines() to read by chunks of little more than 16K, and always reading one chunk before writing previous, but it is really much more complicated and anyway you should use a backup file when processing big files.

You can create another file and write the output to it. After that, you can just remove the original file and rename the new file.

Pick parts from a txt file and copy to another file with python

I'm in trouble here. I need to read a file. Txt file that contains a sequence of records, check the records that I want to copy them to a new file.
The file content is like this (this is just an example, the original file has more than 30 000 lines):
AAAAA|12|120 #begin file
00000|46|150 #begin register
03000|TO|460
99999|35|436 #end register
00000|46|316 #begin register
03000|SP|467
99999|33|130 #end register
00000|46|778 #begin register
03000|TO|478
99999|33|457 #end register
ZZZZZ|15|111 #end file
The records that begin with 03000 and have the characters 'TO' must be written to a new file. Based on the example, the file should look like this:
AAAAA|12|120 #begin file
00000|46|150 #begin register
03000|TO|460
99999|35|436 #end register
00000|46|778 #begin register
03000|TO|478
99999|33|457 #end register
ZZZZZ|15|111 #end file
Code:
file = open("file.txt",'r')
newFile = open("newFile.txt","w")
content = file.read()
file.close()
# here I need to check if the record exists 03000 characters 'TO', if it exists, copy the recordset 00000-99999 for the new file.
I did multiple searches and found nothing to help me.
Thank you!

with open("file.txt",'r') as inFile, open("newFile.txt","w") as outFile:
outFile.writelines(line for line in inFile
if line.startswith("03000") and "TO" in line)
If you need the previous and the next line, then you have to iterate inFile in triads. First define:
def gen_triad(lines, prev=None):
after = current = next(lines)
for after in lines:
yield prev, current, after
prev, current = current, after
And then do like before:
outFile.writelines(''.join(triad) for triad in gen_triad(inFile)
if triad[1].startswith("03000") and "TO" in triad[1])

import re
pat = ('^00000\|\d+\|\d+.*\n'
'^03000\|TO\|\d+.*\n'
'^99999\|\d+\|\d+.*\n'
'|'
'^AAAAA\|\d+\|\d+.*\n'
'|'
'^ZZZZZ\|\d+\|\d+.*')
rag = re.compile(pat,re.MULTILINE)
with open('fifi.txt','r') as f,\
open('newfifi.txt','w') as g:
g.write(''.join(rag.findall(f.read())))
For files with additional lines between lines beginning with 00000, 03000 and 99999, I didn't find simpler code than this one:
import re
pat = ('(^00000\|\d+\|\d+.*\n'
'(?:.*\n)+?'
'^99999\|\d+\|\d+.*\n)'
'|'
'(^AAAAA\|\d+\|\d+.*\n'
'|'
'^ZZZZZ\|\d+\|\d+.*)')
rag = re.compile(pat,re.MULTILINE)
pit = ('^00000\|.+?^03000\|TO\|\d+.+?^99999\|')
rig = re.compile(pit,re.DOTALL|re.MULTILINE)
def yi(text):
for g1,g2 in rag.findall(text):
if g2:
yield g2
elif rig.match(g1):
yield g1
with open('fifi.txt','r') as f,\
open('newfifi.txt','w') as g:
g.write(''.join(yi(f.read())))

file = open("file.txt",'r')
newFile = open("newFile.txt","w")
content = file.readlines()
file.close()
newFile.writelines(filter(lambda x:x.startswith("03000") and "TO" in x,content))

This seems to work. The other answers seem to only be writing out records that contain '03000|TO|' but you have to write out the record before and after that as well.
import sys
# ---------------------------------------------------------------
# ---------------------------------------------------------------
# import file
file_name = sys.argv[1]
file_path = 'C:\\DATA_SAVE\\pick_parts\\' + file_name
file = open(file_path,"r")
# ---------------------------------------------------------------
# create output files
output_file_path = 'C:\\DATA_SAVE\\pick_parts\\' + file_name + '.out'
output_file = open(output_file_path,"w")
# create output files
# ---------------------------------------------------------------
# process file
temp = ''
temp_out = ''
good_write = False
bad_write = False
for line in file:
if line[:5] == 'AAAAA':
temp_out += line
elif line[:5] == 'ZZZZZ':
temp_out += line
elif good_write:
temp += line
temp_out += temp
temp = ''
good_write = False
elif bad_write:
bad_write = False
temp = ''
elif line[:5] == '03000':
if line[6:8] != 'TO':
temp = ''
bad_write = True
else:
good_write = True
temp += line
temp_out += temp
temp = ''
else:
temp += line
output_file.write(temp_out)
output_file.close()
file.close()
Output:
AAAAA|12|120 #begin file
00000|46|150 #begin register
03000|TO|460
99999|35|436 #end register
00000|46|778 #begin register
03000|TO|478
99999|33|457 #end register
ZZZZZ|15|111 #end file

Does it have to be python? These shell commands would do the same thing in a pinch.
head -1 inputfile.txt > outputfile.txt
grep -C 1 "03000|TO" inputfile.txt >> outputfile.txt
tail -1 inputfile.txt >> outputfile.txt

# Whenever I have to parse text files I prefer to use regular expressions
# You can also customize the matching criteria if you want to
import re
what_is_being_searched = re.compile("^03000.*TO")
# don't use "file" as a variable name since it is (was?) a builtin
# function
with open("file.txt", "r") as source_file, open("newFile.txt", "w") as destination_file:
for this_line in source_file:
if what_is_being_searched.match(this_line):
destination_file.write(this_line)
and for those who prefer a more compact representation:
import re
with open("file.txt", "r") as source_file, open("newFile.txt", "w") as destination_file:
destination_file.writelines(this_line for this_line in source_file
if re.match("^03000.*TO", this_line))

code:
fileName = '1'
fil = open(fileName,'r')
import string
##step 1: parse the file.
parsedFile = []
for i in fil:
##tuple1 = (1,2,3)
firstPipe = i.find('|')
secondPipe = i.find('|',firstPipe+1)
tuple1 = (i[:firstPipe],\
i[firstPipe+1:secondPipe],\
i[secondPipe+1:i.find('\n')])
parsedFile.append(tuple1)
fil.close()
##search criterias:
searchFirst = '03000'
searchString = 'TO' ##can be changed if and when required
##step 2: used the parsed contents to write the new file
filout = open('newFile','w')
stringToWrite = parsedFile[0][0] + '|' + parsedFile[0][1] + '|' + parsedFile[0][2] + '\n'
filout.write(stringToWrite) ##to write the first entry
for i in range(1,len(parsedFile)):
if parsedFile[i][1] == searchString and parsedFile[i][0] == searchFirst:
for j in range(-1,2,1):
stringToWrite = parsedFile[i+j][0] + '|' + parsedFile[i+j][1] + '|' + parsedFile[i+j][2] + '\n'
filout.write(stringToWrite)
stringToWrite = parsedFile[-1][0] + '|' + parsedFile[-1][1] + '|' + parsedFile[-1][2] + '\n'
filout.write(stringToWrite) ##to write the first entry
filout.close()
I know that this solution may be a bit long. But it is quite easy to understand. And it seems an intuitive way to do it. And I have already checked this with the Data that you have provided and it works perfectly.
Please tell me if you need some more explanation on the code. I will definitely add the same.

I tip (Beasley and Joran elyase) very interesting, but it only allows to get the contents of the line 03000. I would like to get the contents of the lines 00000 to line 99999.
I even managed to do here, but I am not satisfied, I wanted to make a more cleaner.
See how I did:
file = open(url,'r')
newFile = open("newFile.txt",'w')
lines = file.readlines()
file.close()
i = 0
lineTemp = []
for line in lines:
lineTemp.append(line)
if line[0:5] == '03000':
state = line[21:23]
if line[0:5] == '99999':
if state == 'TO':
newFile.writelines(lineTemp)
else:
linhaTemp = []
i = i+1
newFile.close()
Suggestions...
Thanks to all!

Cutting character values according to value from file

This is the which i am doing
import csv
output = open('output.txt' , 'wb')
# this functions return the min for num.txt
def get_min(num):
return int(open('%s.txt' % num, 'r+').readlines()[0])
# temporary variables
last_line = ''
input_list = []
#iterate over input.txt in sort the input in a list of tuples
for i, line in enumerate(open('input.txt', 'r+').readlines()):
if i%2 == 0:
last_line = line
else:
input_list.append((last_line, line))
filtered = [(header, data[:get_min(header[-2])] + '\n' ) for (header, data) in input_list]
[output.write(''.join(data)) for data in filtered]
output.close()
In this code input.txt is something like this
>012|013|0|3|M
AFDSFASDFASDFA
>005|5|67|0|6
ACCTCTGACC
>029|032|4|5|S
GGCAGGGAGCAGGCCTGTA
and num.txt is something like this
M 4
P 10
I want that in above input.txt check the amount of value from the num.txt by looking at its last column which is same like in num.txt and cut its character according to that values
I think the error in my code is that it only accept the integer text file , where it should also accept file which contain alphabets

The totally revised version, after a long chat with the OP;
import os
import re
# Fetch all hashes and counts
file_c = open('num.txt')
file_c = file_c.read()
lines = re.findall(r'\w+\.txt \d+', file_c)
numbers = {}
for line in lines:
line_split = line.split('.txt ')
hash_name = line_split[0]
count = line_split[1]
numbers[hash_name] = count
#print(numbers)
# The input file
file_i = open('input.txt')
file_i = file_i.read()
for hash_name, count in numbers.iteritems():
regex = '(' + hash_name.strip() + ')'
result = re.findall(r'>.*\|(' + regex + ')(.*?)>', file_i, re.S)
if len(result) > 0:
data_original = result[0][2]
stripped_data = result[0][2][int(count):]
file_i = file_i.replace(data_original, '\n' + stripped_data)
#print(data_original)
#print(stripped_data)
#print(file_i)
# Write the input file to new input_new.txt
f = open('input_new.txt', 'wt')
f.write(file_i)

You can do it like so;
import re
min_count = 4 # this variable will contain that count integer from where to start removing
str_to_match = 'EOG6CC67M' # this variable will contain the filename you read
input = '' # The file input (input.txt) will go in here
counter = 0
def callback_f(e):
global min_count
global counter
counter += 1
# Check your input
print(str(counter) + ' >>> ' + e.group())
# Only replace the value with nothing (remove it) after a certain count
if counter > min_count:
return '' # replace with nothing
result = re.sub(r''+str_to_match, callback_f, input)
With this tactic you can keep count with a global counter and there's no need to do hard line-loops with complex structures.
Update
More detailed version with file access;
import os
import re
def callback_f(e):
global counter
counter += 1
# Check your input
print(str(counter) + ' >>> ' + e.group())
# Fetch all hash-file names and their content (count)
num_files = os.listdir('./num_files')
numbers = {}
for file in num_files:
if file[0] != '.':
file_c = open('./num_files/' + file)
file_c = file_c.read()
numbers[file.split('.')[0]] = file_c
# Now the CSV files
csv_files = os.listdir('./csv_files')
for file in csv_files:
if file[0] != '.':
for hash_name, min_count in numbers.iteritems():
file_c = open('./csv_files/' + file)
file_c = file_c.read()
counter = 0
result = re.sub(r''+hash_name, callback_f, file_c)
# Write the replaced content back to the file here
Considered directory/file structure;
+ Projects
+ Project_folder
+ csv_files
- input1.csv
- input2.csv
~ etc.
+ num_files
- EOG6CC67M.txt
- EOG62JQZP.txt
~ etc.
- python_file.py
The CSV files contain the big chunks of text you state in your original question.
The Num files contain the hash-files with an Integer in them
What happens in this script;
Collect all Hash files (in a dictionary) and it's inner count number
Loop through all CSV files
Subloop through the collected numbers for each CSV file
Replace/remove (based on what you do in callback_f()) hashes after a certain count
Write the output back (it's the last comment in the script, would contain the file.write() functionality)

Searching a file for matches between two values and outputting search hits in Python

I am (attempting) to write a program that searches through a hex file for instances of a hex string between two values, eg. Between D4135B and D414AC, incrementing between the first value until the second is reached- D4135B, D4135C, D4135D etc etc.
I have managed to get it to increment etc, but it’s the search part I am having trouble with.
This is the code I have so far, it's been cobbled together from other places and I need to make it somehow output all search hits into the output file (file_out)
I have exceeded the limit of my Python understanding and I'm sure there's probably a much easier way of doing this. I would be very grateful for any help.
def search_process(hx): # searching for two binary strings
global FLAG
while threeByteHexPlusOne != threeByteHex2: #Keep incrementing until second value reached
If Flag:
if hx.find(threeByteHex2) != -1:
FLAG = False #If threeByteHex = ThreeByteHexPlusOne, end search
Print (“Reached the end of the search”,hx.find(threeByteHexPlusOne))
Else:
If hx.find(threeByteHexPlusOne) != -1:
FLAG = True
Return -1 #If no results found
if __name__ == '__main__':
try:
file_in = open(FILE_IN, "r") #opening input file
file_out = open(FILE_OUT, 'w') #opening output file
hx_read = file_in.read #read from input file
tmp = ''
found = ''
while hx_read: #reading from file till file is empty
hx_read = tmp + hx_read
pos = search_process(hx_read)
while pos != -1:
hex_read = hx_read[pos:]
if FLAG:
found = found + hx_read
pos = search_process(hx_read)
tmp = bytes_read[]
hx_read = file_in.read
file_out.write(found) #writing to output file
except IOError:
print('FILE NOT FOUND!!! Check your filename or directory/PATH')

Here's a program that looks through a hex string from a file 3 bytes at a time and if the 3-byte hex string is between the given hex bounds, it writes it to another file. It makes use of generators to make getting the bytes from the hex string a little cleaner.
import base64
import sys
_usage_string = 'Usage: python {} <input_file> <output_file>'.format(sys.argv[0])
def _to_base_10_int(value):
return int(value, 16)
def get_bytes(hex_str):
# Two characters equals one byte
for i in range(0, len(hex_str), 2):
yield hex_str[i:i+2]
def get_three_byte_hexes(hex_str):
bytes = get_bytes(hex_str)
while True:
try:
three_byte_hex = next(bytes) + next(bytes) + next(bytes)
except StopIteration:
break
yield three_byte_hex
def find_hexes_in_range(hex_str, lower_bound_hex, upper_bound_hex):
lower_bound = _to_base_10_int(lower_bound_hex)
upper_bound = _to_base_10_int(upper_bound_hex)
found = []
for three_byte_hex in get_three_byte_hexes(hex_str):
hex_value = _to_base_10_int(three_byte_hex)
if lower_bound <= hex_value < upper_bound:
found.append(three_byte_hex)
return found
if __name__ == "__main__":
try:
assert(len(sys.argv) == 3)
except AssertionError:
print _usage_string
sys.exit(2)
file_contents = open(sys.argv[1], 'rb').read()
hex_str = base64.decodestring(file_contents).encode('hex')
found = find_hexes_in_range(hex_str, 'D4135B', 'D414AC')
print('Found:')
print(found)
if found:
with open(sys.argv[2], 'wb') as fout:
for _hex in found:
fout.write(_hex)
Check out some more info on generators here