Sorting the order of entire columns in numpy - python

How can I sort this 3,20 ndarray by column? The np.sort() doesnt seem to do what I think it does. I want to turn this:
a
array([[0, 0, 0, 0, 1, 1, 1, 2, 2, 3, 0, 0, 0, 1, 1, 2, 0, 0, 1, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 2, 2, 2, 3],
[0, 1, 2, 3, 0, 1, 2, 0, 1, 0, 0, 1, 2, 0, 1, 0, 0, 1, 0, 0]])
into this:
a
array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 2, 2, 2, 3],
0, 0, 0, 0, 1, 1, 1, 2, 2, 3, 0, 0, 0, 1, 1, 2, 0, 0, 1, 0],
0, 1, 2, 3, 0, 1, 2, 0, 1, 0, 0, 1, 2, 0, 1, 0, 0, 1, 0, 0]])
Note: the columns are kept intact - see column a. They are sorted first by the first element in the column, then the second, then the third.
Thanks

Maybe you could use lexsort?
>>> arr[:,np.lexsort(arr[::-1])]
array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 2, 2, 2, 3],
[0, 0, 0, 0, 1, 1, 1, 2, 2, 3, 0, 0, 0, 1, 1, 2, 0, 0, 1, 0],
[0, 1, 2, 3, 0, 1, 2, 0, 1, 0, 0, 1, 2, 0, 1, 0, 0, 1, 0, 0]])

Make each line a tuple and use it as a sort criterion:
a = np.array([[0, 0, 0, 0, 1, 1, 1, 2, 2, 3, 0, 0, 0, 1, 1, 2, 0, 0, 1, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 2, 2, 2, 3],
[0, 1, 2, 3, 0, 1, 2, 0, 1, 0, 0, 1, 2, 0, 1, 0, 0, 1, 0, 0]])
np.array(sorted(a, key=tuple))
Out:
array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 2, 2, 2, 3],
[0, 0, 0, 0, 1, 1, 1, 2, 2, 3, 0, 0, 0, 1, 1, 2, 0, 0, 1, 0],
[0, 1, 2, 3, 0, 1, 2, 0, 1, 0, 0, 1, 2, 0, 1, 0, 0, 1, 0, 0]])

Related

Element wise sum of 5 out of 60 list

Consider I have a list with 60 list of 0 and 1s (there are 12~16 1s in series):
my_list=
[[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1],
[0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0],
[0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0],
[0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0],
[0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0],
[0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0],
[0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0],
[0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0],
[0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0],
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
The sum list that I aim to get is:
sum_list = [2,2,2,3,3,4,4,5,5,5,5,5,5,5,5,5,5,5,5,5,4,2,2,2,2]
I need to find the combinations of 01 lists that can give me the sum_list
for example:
[0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0]
+
[0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0]
+
.....
=
[2,2,2,3,3,4,4,5,5,5,5,5,5,5,5,5,5,5,5,5,4,2,2,2,2]
Since the max element is 5, I'm thinking to start with 5,
To select any 5 list out of 60 and add them elementwise, if there is no solution, try 6 out of 60.
I'm not sure how to do this list-element wise.
=============================================================
Based on solution Adrian provided I made a slight change, from combination to product, to include duplicates. Its still running, i'll see how it goes
Time_list = ["6:30","7:00","7:30","8:00","8:30","9:00","9:30","10:00","10:30","11:00","11:30","12:00","12:30","13:00","13:30","14:00","14:30","15:00","15:30","16:00","16:30","17:00","17:30","18:00","18:30"]
goal = [2,2,2,3,3,4,4,5,5,5,5,5,5,5,5,5,5,5,5,5,4,2,2,2,2]
my_list = []
a_list = [10,11,12,13,14,15,16]
slots = len(goal)
for j in a_list:
for i in range(slots+1):
if i<=(slots-(j)):
a_list = [0]*(slots-(j)-i)+[1]*(j)+ [0]*(i)
my_list.append(a_list)
print(len(my_list))
import itertools
from operator import add
test_range = len(my_list)
print(test_range)
for num_lists in [6,7]:
print("check combinations of "+str(num_lists)+" Lists.")
for index in itertools.product(range(0,test_range), repeat = num_lists):
#print(len(res))
#print(index)
res = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
for x in index:
res = list(map(add, res, my_list[x]))
#print(res)
if res == goal:
print("Goal found!")
for x in index:
print(my_list[x])
break
print("check combinations of "+str(num_lists)+" completed.")
you could try this brute-force approach. Needs some computing time to find a solution (maybe not solvable).
goal = [2,2,2,3,3,4,4,5,5,5,5,5,5,5,5,5,5,5,5,5,4,2,2,2,2]
from operator import add
for num_lists in [5,6,7]:
print("check combinations of "+str(num_lists)+" Lists.")
for index in itertools.combinations(range(0,60), num_lists):
res = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
for x in index:
res = list(map(add, res, my_list[x]))
if res == goal:
print("Goal found!")
for x in index:
print(my_list[x])
break
print("check combinations of "+str(num_lists)+" completed.")
Edit: I tried with this approch all combinations of 5, 6 and 7 lists. I found no solution for your goal. Maybe there is no solution.

How to count 0's & 1's in a matrix using python?

I have a matrix as shown below ,
matrix([[0, 0, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 1,
1, 0, 1, 1, 0, 1, 0, 0, 1],
[0, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 1, 0, 0,
1, 1, 0, 0, 0, 1, 0, 0, 1],
[0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0,
1, 1, 0, 0, 1, 0, 0, 0, 0],
[1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1,
0, 1, 0, 0, 0, 1, 1, 0, 0],
[1, 1, 1, 0, 1, 0, 0, 0, 0, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 0,
1, 0, 0, 0, 0, 1, 1, 0, 1],
[0, 0, 1, 1, 0, 0, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 0, 0,
0, 1, 0, 1, 0, 1, 0, 0, 0],
[0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 1, 1, 0, 1, 1, 1, 1, 0, 0, 1, 1,
0, 1, 1, 1, 1, 0, 0, 1, 0],
[0, 0, 1, 1, 1, 0, 1, 0, 1, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1,
1, 0, 1, 0, 1, 0, 0, 0, 0],
[1, 1, 1, 1, 1, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 0, 1, 0,
1, 0, 0, 1, 0, 0, 1, 1, 1],
[1, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 1, 0, 1, 1, 0, 1, 0]])
I want to count the 0's and 1's in that matrix.
The code i tried is ,
def countZeroes(mat):
# start from bottom-left
# corner of the matrix
N = 10;
row = N-1;
col = 0;
# stores number of
# zeroes in the matrix
count = 0;
while (col < N):
# move up until
# you find a 0
while (mat[row][col]):
# if zero is not found
# in current column, we
# are done
if (row < 0):
return count;
row = row - 1;
# add 0s present in
# current column to result
count = count + (row + 1);
# move right to
# next column
col = col + 1;
return count;
The above code is to count 0's.
Could you help me in solving this problem?
I would request you to provide me an answer using loops.
Thanks!
Looks like we don't care at all about the positions of the various 0s and 1s - so, we're not counting on a per-row or per-column basis, then.
matrix = [[0, 0, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 1,
1, 0, 1, 1, 0, 1, 0, 0, 1],
[0, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 1, 0, 0,
1, 1, 0, 0, 0, 1, 0, 0, 1],
[0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0,
1, 1, 0, 0, 1, 0, 0, 0, 0],
[1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1,
0, 1, 0, 0, 0, 1, 1, 0, 0],
[1, 1, 1, 0, 1, 0, 0, 0, 0, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 0,
1, 0, 0, 0, 0, 1, 1, 0, 1],
[0, 0, 1, 1, 0, 0, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 0, 0,
0, 1, 0, 1, 0, 1, 0, 0, 0],
[0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 1, 1, 0, 1, 1, 1, 1, 0, 0, 1, 1,
0, 1, 1, 1, 1, 0, 0, 1, 0],
[0, 0, 1, 1, 1, 0, 1, 0, 1, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1,
1, 0, 1, 0, 1, 0, 0, 0, 0],
[1, 1, 1, 1, 1, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 0, 1, 0,
1, 0, 0, 1, 0, 0, 1, 1, 1],
[1, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 1, 0, 1, 1, 0, 1, 0]]
The pythonic solution would be to use a comprehension inside a call to the built-in sum() to just count the number of 1s, then subtract that from the size of the matrix:
matrix_height = len(matrix)
matrix_width = len(matrix[0])
num_ones = sum(cell for row in matrix for cell in row)
num_zeroes = (matrix_height * matrix_width) - num_ones
# num_zeroes = 155
However, we can also just use two nested for loops to count the number of zeroes that way:
num_zeroes = 0
for row in matrix:
for cell in row:
if cell == 0:
num_zeroes += 1
# num_zeroes = 155
You can see that the comprehension I demonstrated before is essentially just these two for loops, but in a single line.
You can use sum() and map() to obtain the number of ones. Then subtract that number from the total number of elements to obtain the number of zeroes:
ones = sum(map(sum,matrix))
zeros = sum(map(len,matrix))-ones

removing the first 0 bit value

i want to get the binary value from a string, but why if i print the binary value and save it into an array there is always 0 bit get inserted automatically, i know that its from the bitwise operation inside the loop, how can i delete it and get the actual binary value from a string?
this is the code
def padding():
a = "Testing"
byte_a = a.encode('utf-8')
print(byte_a)
print(bin(byte_a[0]))
print(bin(byte_a[1]))
print(bin(byte_a[2]))
i = 0
x = []
#byte_a.append(1)
while True:
x.insert(i, ((byte_a[i//8]>>(7-(i%8)))&1))
print(x)
i+=1
and here is the output:
b'Testing'
0b1010100
0b1100101
0b1110011
[0]
[0, 1]
[0, 1, 0]
[0, 1, 0, 1]
[0, 1, 0, 1, 0]
[0, 1, 0, 1, 0, 1]
[0, 1, 0, 1, 0, 1, 0]
[0, 1, 0, 1, 0, 1, 0, 0]
[0, 1, 0, 1, 0, 1, 0, 0, 0]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1, 1]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1, 1, 1]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1, 1, 1, 0]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1, 1, 1, 0, 0]
[0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1, 1, 1, 0, 0, 1]
...
as you can see the array had the first value of 0 for every binary.
thanks guys

Append rows in array

I am making a Draughts game in python, I made an array 10 by 10 and I need to append values within the entire row so that is eventually looks like this;
(
[0, 1, 0, 1, 0, 1, 0, 1, 0, 1],
[1, 0, 1, 0, 1, 0, 1, 0, 1, 0],
[0, 1, 0, 1, 0, 1, 0, 1, 0, 1],
[1, 0, 1, 0, 1, 0, 1, 0, 1, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 2, 0, 2, 0, 2, 0, 2, 0, 2],
[2, 0, 2, 0, 2, 0, 2, 0, 2, 0],
[0, 2, 0, 2, 0, 2, 0, 2, 0, 2],
[2, 0, 2, 0, 2, 0, 2, 0, 2, 0],
)
Here is my attempt at it so far, I know it's incorrect;
__author__ = 'Matt'
import array
Board_Array = array(10, 10)
pieces = ['Empty', 'White_Piece', 'Black_Piece', 'Upgraded_White_Piece', 'Upgraded_Black_Piece']
list(enumerate(pieces))
if Board_Array.array_equals == [1, 0]:
for i in range(10):
if (i%2) == 0:
array.pop([i])
array.insert(i,1)
You could use a nested list comprehension:
In [173]: [[((i+j) % 2)*k for i in range(10)] for k in (1,1,0,2,2)
for j in (0,1)]
Out[173]:
[[0, 1, 0, 1, 0, 1, 0, 1, 0, 1],
[1, 0, 1, 0, 1, 0, 1, 0, 1, 0],
[0, 1, 0, 1, 0, 1, 0, 1, 0, 1],
[1, 0, 1, 0, 1, 0, 1, 0, 1, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 2, 0, 2, 0, 2, 0, 2, 0, 2],
[2, 0, 2, 0, 2, 0, 2, 0, 2, 0],
[0, 2, 0, 2, 0, 2, 0, 2, 0, 2],
[2, 0, 2, 0, 2, 0, 2, 0, 2, 0]]
This is equivalent to
result = []
for k in (1,1,0,2,2):
for j in (0,1):
row = []
for i in range(10):
row.append(((i+j) % 2)*k)
result.append(row)

numpy.genfromtxt: delimiter=',' fails to split string

I don't understand why numpy.genfromtxt doesn't split the following string correctly using delimiter="," while it works for most of the other strings in my chunk.
chunk[12968]
Out[143]: '2901869281,3279442095,2012-12-15T23:00:00.003Z,Sacramento,CA,R#3817874,United States,38.583,-121.498,11, 8, 6, 5, 1, 0, 2, 3, 3, 5, 3, 3, 2, 2, 6, 6, 1, 2, 3, 0, 1, 1, 0, 0, 2, 2, 2, 2, 1, 0, 0, 2, 1, 0, 1, 1, 2, 0, 3, 1, 1, 1, 1, 0, 0, 4, 0, 0, 0, 1, 3, 1, 0, 2, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 2, 0, 9, 0, 0, 0, 2, 3, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0,130\n'
I would expect an array of shape (110,) but get the following
genfromtxt([chunk[12968]],delimiter=",",dtype=np.int64)
Out[142]:
array([2901869281, 3279442095, -1, -1, -1,
-1], dtype=int64)
Note that I am using izip_longest from itertools to read a large *csv by chunks this way:
with open('events.csv','r') as:
for chunk in izip_longest(*[f] *50000):
...
Thanks for help.
The comments argument to genfromtxt() defaults to '#', so everything past the # in your input is getting ignored:
2901869281,3279442095,2012-12-15T23:00:00.003Z,Sacramento,CA,R#3817874,United States,...
^ start of comment

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