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for some reason when I get regex to get the number i need it returns none.
But when I run it here http://regexr.com/38n3o it works
the regex was designed to get the last number of the ip so it can be removed
lanip=74.125.224.72
notorm=re.search("/([1-9])\w+$/g", lanip)
That is not how you define a regular expressions in Python. The correct way would be:
import re
lanip="74.125.224.72"
notorm=re.search("([1-9])\w+$", lanip)
print notorm
Output:
<_sre.SRE_Match object at 0x10131df30>
You were using a javascript regex style. To read more on correct python syntax read the documentation
If you want to match the last number of an IP use:
import re
lanip="74.125.224.72"
notorm=re.search("(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)", lanip)
print notorm.group(4)
Output:
72
Regex used from http://www.regular-expressions.info/examples.html
Your example did work in this scenario, but would match a lot of false positives.
What is lanip's type? That can't run.
It needs to be a string, i.e.
lanip = "74.125.224.72"
Also your RE syntax looks strange, make sure you've read the documentation on Python's RE syntax.
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I am trying to match the following pattern
sn,n+1
where n is an integer. Examples include
s1,2 s3,4
Right now I know how to match the following: sn,n
(for example s1,1) with regex. The syntax I use for this is s(\d+),\1
Is it possible to do something like the following? s(\d+),\1+1
More detail on my specific problem (these details aren't necessarily relevant to the solution! But I am including them anyway), I am using CST, an electromagnetic simulator that supports regex for sorting s-parameter data. With a high port count, it is cumbersome to manually select isolation between ports. So I want to use a regex in the above way.
Regex can not do arithmetic but python does. You can find all matching patterns in your string and filter them later with python. This might help:
Regex
import re
string= 's1,2 test s2,3 , test test s12,12'
pattern = 's\d+,\d+'
pattern_list = re.findall(pattern, string)
print(pattern_list)
['s1,2', 's2,3', 's12,12']
Filtering with Python
result_list = [i for i in pattern_list if int(i.split(',')[0].split('s')[1]) + 1 == int(i.split(',')[1]) ]
print(result_list)
['s1,2', 's2,3']
Basically, it finds all patterns by using regex then python checks the patterns that fits to sn,n+1
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I want to remove links in the format Reddit uses
comment = "Hello this is my [website](https://www.google.com)"
no_links = RemoveLinks(comment)
# no_links == "Hello this is my website"
I found a similar question about the same thing, but I don't know how to translate it to python.
I am not that familiar with regex so I would appreciate it if you explained what's happening.
You could do the following:
import re
pattern = re.compile('\[(.*?)\]\(.*?\)')
comment = "Hello this is my [website](https://www.google.com)"
print(pattern.sub(r'\1', comment))
The line:
pattern = re.compile('\[(.*?)\]\(.*?\)')
creates a regex pattern that will search for anything surrounded by square brackets, followed by anything surrounded by parenthesis, the '?' indicates that they should match as little text as possible (non-greedy).
The function sub(r'\1', comment) replaces a match by the first capturing group in this case the text inside the brackets.
For more information about regex I suggest you read this.
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How do I match the following pattern using re?
2016-02-13 02:00:00.0,3525,http://www.heatherllindsey.com/2016/02/my-husband-left-his-9-5-job-for-good-it.html,158,0,2584490
I used python's split() function to separate the attributes out but as the data is huge, the process is getting killed due to memory errors.
If you put the long version of string it would be better.
So how can you make it ? That is the answer:
import re
str = "2016-02-13 02:00:00.0,3525,http://www.heatherllindsey.com/2016/02/my-husband-left-his-9-5-job-for-good-it.html,158,0,2584490"
pattern = re.compile("(.*?),", re.DOTALL) #we use re.DOTALL to continue splitting after endlines.
result = pattern.findall(str) #we can't find the last statement (2584490) because of the pattern so we will apply second process
pattern = re.compile("(.*?)", re.DOTALL)
str2 = str[-50:-1]+str[-1] #we take last partition of string to find out last statement by using split() method
result.append(str2.split(",")[-1])
print result
It works...
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I have a content like this:
aid: "1168577519", cmt_id = 1168594403;
Now I want to get all number sequence：
1168577519
1168594403
by regex.
I have never meet regex problem, but this time I should use it to do some parse job.
Now I can just get sequence after "aid" and "cmt_id" respectively. I don't know how to merge them into one regex.
My current progress:
pattern = re.compile('(?<=aid: ").*?(?=",)')
print pattern.findall(s)
and
pattern = re.compile('(?<=cmt_id = ).*?(?=;)')
print pattern.findall(s)
There are many different approaches to designing a suitable regular expression which depend on the range of possible inputs you are likely to encounter.
The following would solve your exact question but could fail given different styled input. You need to provide more details, but this would be a start.
re_content = re.search("aid\: \"([0-9]*?)\",\W*cmt_id = ([0-9]*?);", input)
print re_content.groups()
This gives the following output:
('1168577519', '1168594403')
This example assumes that there might be other numbers in your input, and you are trying to extract just the aid and cmt_id values.
The simplest solution is to use re.findall
Example
>>> import re
>>> string = 'aid: "1168577519", cmt_id = 1168594403;'
>>> re.findall(r'\d+', string)
['1168577519', '1168594403']
>>>
\d+ matches one or more digits.
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I am not sure how I can extract the variables or groups I created in my regular expression. Specifically datetime and IP. I have read other postings and the documentation but I am getting a bit confused. I was wondering if someone could generate an example for me to follow. What I would like to do is to be able to extract datetime and IP for later use. Perhaps stored in a variable to be called on later
sample log:
log = 'Oct 7 13:24:36 192.168.10.2 2013: 10:07-13:24:35 httpproxy[15359]: id="0001"
httpproxy515139 = re.compile(r'(?P<datetime>\w\w\w\s+\d+\s+\d\d:\d\d:\d\d)\s+(?P<IP>d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}).*')
This sample should help you:
>>> import re
>>> sample = 'this is a sample text'
>>> third_word = re.compile(r'\S+ \S+ (?P<word>\S+) .*')
>>> ms = third_word.match(sample)
>>> ms.groupdict()
{'word': 'a'}
You need to access the groupdict() method of the returned match object.