How can I click the link:
<a class="single_like_button btn3-wrap" onclick="openFbLWin_189932();">
<span> </span><div class="btn3">Share</div>
</a>
This is my code in Python, but it doesn't work. I use Selenium
......
elem = self.driver.find_elements_by_class_name("single_like_button btn3-wrap")[0].click();
......
find_elements_by_class_name() is apparently limited to a single class name.
You can use find_element_by_css_selector() instead and write:
self.driver.find_element_by_css_selector(
".single_like_button.btn3-wrap").click();
Related
I want to click this button in a website using selenium but I am not sure how to select it.
<a data-gfm-analytics-element="btn_showmore_browse" data-area="norma_category" class="button hollow expanded-mobile js-load-more-results" href="#" style="display: inline-block;">Show More</a>
I used this code to do it but it returns NoSuchElementException: Message: no such element
btn = driver.find_element(By.CLASS_NAME,'button hollow expanded-mobile js-load-more-results')
button hollow expanded-mobile js-load-more-results are actually 4 class names while By.CLASS_NAME receives single class name value. You can use CSS Selector or Xpath with multiple class names
btn = driver.find_element(By.CSS_SELECTOR,'a.button.hollow.expanded-mobile.js-load-more-results')
Also btn_showmore_browse seems to be unique value, so possibly this will work too:
btn = driver.find_element(By.CSS_SELECTOR,'a[data-gfm-analytics-element="btn_showmore_browse"]')
There are more possible options
so I'm currently using python to import data from an excel sheet and then take that information and use it to fill out a form on a webpage.
The problem I'm having is selecting a profile of the drop-down menu.
I've been using the Selenium library and I can actually select the element using find_element_by_xpath assuming, but that's assuming I know the data value, the data value is auto-generated for each new profile that's added so I can't use that as a reliable means.
Profile = Browser.find_element_by_xpath("/html/something/something/.....")
Profile.click()
time.sleep(0.75) #allowing time for link to be clickable
The_Guy = Browser.find_element_by-xpath("/html/something/something/...")
The_Guy.click()
This works only on known paths I would like to do something like this
Profile = Browser.find_element_by_xpath("/html/something/something/.....")
Profile.click()
time.sleep(0.75) #allowing time for link to be clickable
The_Guy = Browser.find_element_by_id("Caption.A")
The_Guy.click()
EXAMPLE OF HTML
<ul class ="list">
<li class = "option" data-value= XXXXX-XXXXX-XXXXX-XX-XXX>
::marker
Thor
</li>
<li class = "option" data-value= XXXXX-XXXXX-XXXXX-XX-XXX>
::marker
IronMan
</li>
<li class = "option" data-value= XXXXX-XXXXX-XXXXX-XX-XXX>
::marker
Caption.A
</li>
....
</ul>
What I'll like to be able to do is search via name (like Caption.A) and then step back to select the parent Li. Thanks in advance
Try using following xpath to find the li containing desired text and then click on it. Sample code:
driver.find_element(By.xpath("//li[contains(text(), 'Caption.A')]")).click()
Hope it helps :)
I'm trying to get Selenium to click on View All Companies button, but i'm not sure what am I doing wrong. It returns no element found
html code
<div class="screener-toggles">
<div class="buttons">
<span class="button selected" data-name="advanced-screener">Search by Screener<span data-name="advanced-screener" class="arrow selected"></span></span>
<span class="button" data-name="alpha-factors">Search by Alpha Factors<span data-name="alpha-factors" class="arrow"></span></span>
<span class="button" data-name="all-companies">View All Companies<span data-name="all-companies" class="arrow"></span></span>
</div>
</div>
python code I wrote
element1 = driver.find_elements_by_class_name('View All Companies')
element1.click()
# I have tried all-companies instead of View All Companies as well. But still doesn't work
Should I not be using find_elements_by_class_name?
Any advice on what I am doing wrong is greatly appreciated!
try xpath: "//span[contains(text(),'View All Companies')]"
View All Companies is text, not the class. Try looking by text with css_selector or xpath
element1 = find_element_by_css_selector('span:contains("View All Companies")')
element1 = find_element_by_xpath('//span[contains(text(), "View All Companies")]')
Or by the data-name attribute which contains all-companies
element1 = find_element_by_css_selector('span[data-name*="all-companies"]')
Yes, you should not use the find_elements_by_class_name instead of use find_element_by_class_name.
find_elements_by_class_name is used when your expecting your locator to return more than 1 element. for a specific element use only find_element_by_class_name.
Another thing is I am not able to see any class name as View All Companies in your HTML code. Please look into your HTML and select classname or other locator carefully
Hope it will help you
So I'm very new to python and selenium. I'm writting an scraper to take some balances and download a txt file. So far I've managed to grab the account balances but downloading the txt files have proven to be a difficult task.
This is a sample of the html
<td>
<div id="expoDato_msdd" class="dd noImprimible" style="width: 135px">
<div id="expoDato_title123" class="ddTitle">
<span id="expoDato_arrow" class="arrow" style="background-position: 0pt 0pt"></span>
<span id="expoDato_titletext" class="textTitle">Exportar Datos</span>
</div>
<div id="expoDato_child" class="ddChild" style="width: 133px; z-index: 50">
<a class="enabled" href="/CCOLEmpresasCartolaHistoricaWEB/exportarDatos.do;jsessionid=9817239879882871987129837882222R?tipoExportacion=txt">txt</a>
<a class="enabled" href="/CCOLEmpresasCartolaHistoricaWEB/exportarDatos.do;jsessionid=9817239879882871987129837882222R?tipoExportacion=pdf">PDF</a>
<a class="enabled" href="/CCOLEmpresasCartolaHistoricaWEB/exportarDatos.do;jsessionid=9817239879882871987129837882222R?tipoExportacion=excel">Excel</a>
<a class="modal" href="#info_formatos">Información Formatos</a>
</div>
</div>
I need to click on the fisrt "a" class=enabled. But i just can't manage to get there by xpath, class or whatever really. Here is the last thing i tried.
#Descarga de Archivos
ddmenu2 = driver.find_element_by_id("expoDato_child")
ddmenu2.find_element_by_css_selector("txt").click()
This is more of the stuff i've already tryed
#TXT = driver.select
#TXT.send_keys(Keys.RETURN)
#ddmenu2 = driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div/form/table/tbody/tr[2]/td/div[2]/table/tbody/tr/td[4]/div/div[2]")
#Descarga = ddmenu2.find_element_by_visible_text("txt")
#Descarga.send_keys(Keys.RETURN)
Please i would apreciate your help.
Ps:English is not my native language, so i'm sorry for any confusion.
EDIT:
This was the approach that worked, I'll try your other suggetions to make a more neat code. Also it will only work if the mouse pointer is over the browser windows, it doesn't matter where.
ddmenu2a = driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div/form/table/tbody/tr[2]/td/div[2]/table/tbody/tr/td[4]/div/div[1]").click()
ddmenu2b = driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div/form/table/tbody/tr[2]/td/div[2]/table/tbody/tr/td[4]/div/div[2]")
ddmenu2c = driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div/form/table/tbody/tr[2]/td/div[2]/table/tbody/tr/td[4]/div/div[2]/a[1]").click()
Pretty much brute force, but im getting to like python scripting.
Or simply use CSS to match on the href:
driver.find_element_by_css_selector("div#expoDato_child a.enabled[href*='txt']")
You can get all anchor elements like this:
a_list = driver.find_elements_by_tag_name('a')
this will return a list of elements. you can click on each element:
for a in a_list:
a.click()
driver.back()
or try xpath for each anchor element:
a1 = driver.find_element_by_xpath('//a[#class="enabled"][1]')
a2 = driver.find_element_by_xpath('//a[#class="enabled"][2]')
a3 = driver.find_element_by_xpath('//a[#class="enabled"][3]')
Please let me know if this was helpful
you can directly reach the elements by xpath via text:
driver.find_element_by_xpath("//*[#id='expoDato_child' and contains(., 'txt')]").click()
driver.find_element_by_xpath("//*[#id='expoDato_child' and contains(., 'PDF')]").click()
...
If there is a public link for the page in question that would be helpful.
However, generally, I can think of two methods for this:
If you can discover the direct link you can extract the link text and use pythons' urllib and download the file directly.
or
Use use Seleniums' click function and have it click on the link in the page.
A quick search resulted thusly:
downloading-file-using-selenium
I am testing a website that has buttons that are not discernible by element or id. However, I am able to identify it by xpath or css class. How do you click on a button using one of those two attributes. I'm able to assert the button is there using get_element_by_xpath; however, I seem unable to use the click_element, click_link, or click_button using id_or_elem. What statement would you use to click on a button like this?
Edit:
The test code looks like this: (webpage name removed on purpose)
class TestMyTest(cases.SSTTestCase):
def test_mytestcase_home_page(self):
go_to('http://www.mywebpage.com')
assert_title_contains('Page Name')
assert_element(tag='a', text='Log in')
click_element(id_or_elem='page_nav')
assert_title_contains('Login')
assert_element(id='tbLUser')
write_textfield('tbLUser','username')
assert_element(id='tbLPass')
write_textfield('tbLPass','badpassword')
assert_element(css_class='btn-login1')
get_element_by_xpath('//*[#id="login_box"]/div/a/img')
The code I'm trying to test from:
<div class="btn-login1">
<a href="javascript:void(0)" onclick=javascript:return Validate(document.theLoginForm,'/mypage/mywebpage.asp');" onmouseout="MM_swapImgRestore();" onmouseover="MM_swapImage('lg5_login','','/assets/page4/lg5_login_f2.png',1);">
<img name="lg5_login" src="http://www.mywebpage.com/login/lg5_login.png" border="0" alt="Log in Now">
</a>
</div>
If this answer is helpful to someone else. We we able to solve the issue with the following solutions.
click_element(get_element_by_xpath('your xpath'), wait=True)
click_link(get_element_by_xpath('your xpath'), wait=True)
click_button(get_element_by_xpath('your xpath'), wait=True)
Parameters: id_or_elem The identifier of the element, or its element object.
All of the click actions should support id or element