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How can I get the key value pair to create a dictionary from a nested dictionary?

I have a dictionary which looks as shown below. Now I need to get the key its corresponding path together so as to use it further to identify its slot number based on the key. How can I achieve that?
I tried an approach but it is giving me key error.

What you need can easily be implemented as:
>>> {key: value["mpath"] for key, value in multipath.items()}
{'/dev/sdh': '/dev/mapper/mpathk', '/dev/sdi': '/dev/mapper/mpathk',
'/dev/sdg': '/dev/mapper/mpathj', '/dev/sdf': '/dev/mapper/mpathj',
'/dev/sdd': '/dev/mapper/mpathi', '/dev/sde': '/dev/mapper/mpathi',
'/dev/sdb': '/dev/mapper/mpathh', '/dev/sdc': '/dev/mapper/mpathh',
'/dev/sdj': '/dev/mapper/mpathg', '/dev/sdk': '/dev/mapper/mpathg'}

Great one line answer by #Selcuk using dictionary comprehension.
An elaborated one along the same line would be:
mpath_dict = {}
for sd, mpath in multipath.items():
mpath_dict[sd] = mpath['mpath']
print(mpath_dict)
Since every value item of "mpath" dictionary is a dictionary itself, you can retrieve values from it as you would do it in a dictionary.

Convert json dict

I have pulled JSON data from a url. The result is a dictionary. How can I transform this dictionary so metric is a column, and the time is the index for each value
Thanks in advance
time------------------------AdrActCnt-----BlkCnt------BlkSizeByte
2021-01-28T00:00:00.000Z----1097896.0-----145.0-------190568423.0
2021-01-29T00:00:00.000Z----1208741.0-----152.0-------199725189.0
2021-01-29T00:00:00.000Z----1087755.0-----136.0-------177349536.0
Output:
{"metricData":{"metrics":["AdrActCnt","BlkCnt","BlkSizeByte"],"series":
[{"time":"2021-01-28T00:00:00Z","values"["1097896.0","145.0","190568423.0"]},
{"time":"2021-01-29T00:00:00Z","values":["1208741.0","152.0","199725189.0"]},
{"time":"2021-01-30T00:00:00Z","values":["1087755.0","136.0","177349536.0"]}

You may be looking for a dict comprehension, which is similar to a list comprehension, just creates a dictionary at the end:
liststuff = [{"time":"2021-01-28T00:00:00.000Z","values":["1097896.0","145.0","190568423.0"]},{"time":"2021-01-29T00:00:00.000Z","values":["1208741.0","152.0","199725189.0"]},{"time":"2021-01-30T00:00:00.000Z","values":["1087755.0","136.0","177349536.0"]}]
dictstuff = {item['time']:item['values'] for item in liststuff}
print(dictstuff)
{'2021-01-28T00:00:00.000Z': ['1097896.0', '145.0', '190568423.0'], '2021-01-29T00:00:00.000Z': ['1208741.0', '152.0', '199725189.0'], '2021-01-30T00:00:00.000Z': ['1087755.0', '136.0', '177349536.0']}
liststuff is your data, just needed [] wrapping (I assume that's a typo in the question, it's not valid JSON without the brackets). If you need help with parsing the string, use json.loads() (from the json module) to make it actual Python data:
import json
jsonstuff = '[{"time":"2021-01-28T00:00:00.000Z","values":["1097896.0","145.0","190568423.0"]},{"time":"2021-01-29T00:00:00.000Z","values":["1208741.0","152.0","199725189.0"]},{"time":"2021-01-30T00:00:00.000Z","values":["1087755.0","136.0","177349536.0"]}]'
liststuff = json.loads(jsonstuff)
(here jsonstuff is the string you've downloaded)

Retrieve values from both nested dictionaries within a list

i'm using an api call in python 3.7 which returns json data.
result = (someapicall)
the data returned appears to be in the form of two nested dictionaries within a list, i.e.
[{name:foo, firmware:boo}{name:foo, firmware:bar}]
i would like to retrieve the value of the key "name" from the first dictionary and also the value of key "firmware" from both dictionaries and store in a new dictionary in the following format.
{foo:(boo,bar)}
so far i've managed to retrieve the value of both the first "name" and the first "firmware" and store in a dictionary using the following.
dict1={}
for i in result:
dict1[(i["networkId"])] = (i['firmware'])
i've tried.
d7[(a["networkId"])] = (a['firmware'],(a['firmware']))
but as expected the above just seems to return the same firmware twice.
can anyone help achive the desired result above

you can use defaultdict to accumulate values in a list, like this:
from collections import defaultdict
result = [{'name':'foo', 'firmware':'boo'},{'name':'foo', 'firmware':'bar'}]
# create a dict with a default of empty list for non existing keys
dict1=defaultdict(list)
# iterate and add firmwares of same name to list
for i in result:
dict1[i['name']].append(i['firmware'])
# reformat to regular dict with tuples
final = {k:tuple(v) for k,v in dict1.items()}
print(final)
Output:
{'foo': ('boo', 'bar')}

Manipulating a list of dictionaries

I successfully imported from the web this json file, which looks like:
[{"h_mag":"19.7","i_deg":"9.65","moid_au":"0.035"},{"h_mag":"20.5","i_deg":"14.52","moid_au":"0.028"},
etc ...
I want to extract the values of the key moid_au, later compare moid_au with the key values of h_mag.
This works: print(data[1]['moid_au']), but if I try to ask all the elements of the list it won't, I tried: print(data[:]['moid_au']).
I tried iterators and a lambda function but still has not work yet, mostly because I'm new in data manipulation. It works when I have one dictionary, not with a list of dictionaries.
Thanks in advance for other tips. Some links were confusing.

Sounds like you are using lambda wrong because you need map as well:
c = [{"h_mag":"19.7","i_deg":"9.65","moid_au":"0.035"},{"h_mag":"20.5","i_deg":"14.52","moid_au":"0.028"}]
list(map(lambda rec: rec.get('moid_au'), c))
['0.035', '0.028']
Each lambda grabs a record from your list and you map your function to that.

Using print(data[:]['moid_au']) equals to print(data['moid_au']), and you can see that it won't work, as data has no key named 'moid_au'.
Try working with a loop:
for item in data:
print(item['moid_au'])

using your approach to iterate over the whole array to get all the instances of a key,this method might work for you
a = [data[i]['moid_au']for i in range(len(data))]
print(a)

In which exact way do you want to compare them?
Would it be useful getting the values in a way like this?
list_of_dicts = [{"h_mag":"19.7","i_deg":"9.65","moid_au":"0.035"}, {"h_mag":"20.5","i_deg":"14.52","moid_au":"0.028"}]
mod_au_values = [d["moid_au"] for d in list_of_dicts]
h_mag_values = [d["h_mag"] for d in list_of_dicts]

for key, value in my_list.items ():
print key
print value
for value in my_list.values ():
print value
for key in my_list.keys():
print key

Converting dict values into a set while preserving the dict

I have a dict like this:
(100002: 'APPLE', 100004: 'BANANA', 100005: 'CARROT')
I am trying to make my dict have ints for the keys (as it does now) but have sets for the values (rather than strings as it is now.) My goal is to be able to read from a .csv file with one column for the key (an int which is the item id number) and then columns for things like size, shape, and color. I want to add this information into my dict so that only the information for keys already in dict are added.
My goal dict might look like this:
(100002: set(['APPLE','MEDIUM','ROUND','RED']), 100004: set(['Banana','MEDIUM','LONG','YELLOW']), 100005: set(['CARROT','MEDIUM','LONG','ORANGE'])
Starting with my dict of just key + string for item name, I tried code like this to read the extra information in from a .csv file:
infile = open('FileWithTheData.csv', 'r')
for line in infile.readlines():
spl_line = line.split(',')
if int(spl_line[0]) in MyDict.keys():
MyDict[int(spl_line[0])].update(spl_line[1:])
Unfortunately this errors out saying AttributeError: 'str' object has no attribute 'update'. My attempts to change my dictionary's values into sets so that I can then .update them have yielded things like this: (100002: set(['A','P','L','E']), 100004: set(['B','A','N']), 100005: set(['C','A','R','O','T']))
I want to convert the values to a set so that the string that is currently the value will be the first string in the set rather than breaking up the string into letters and making a set of those letters.
I also tried making the values a set when I create the dict by zipping two lists together but it didn't seem to make any difference. Something like this
MyDict = dict(zip(listofkeys, set(listofnames)))
still makes the whole listofnames list into a set but it doesn't achieve my goal of making each value in MyDict into a set with the corresponding string from listofnames as the first string in the set.
How can I make the values in MyDict into a set so that I can add additional strings to that set without turning the string that is currently the value in the dict into a set of individual letters?
EDIT:
I currently make MyDict by using one function to generate a list of item ids (which are the keys) and another function which looks up those item ids to generate a list of corresponding item names (using a two column .csv file as the data source) and then I zip them together.
ANSWER:
Using the suggestions here I came up with this solution. I found that the section that has set()).update can easily be changed to list()).append to yield a list rather than a set (so that the order is preserved.) I also found it easier to update by .csv data input files by adding the column containing names to the FileWithTheData.csv so that I didn't have to mess with making the dict, converting the values to sets, and then adding in more data. My code for this section now looks like this:
MyDict = {}
infile = open('FileWithTheData.csv', 'r')
for line in infile.readlines():
spl_line = line.split(',')
if int(spl_line[0]) in itemidlist: #note that this is the list I was formerly zipping together with a corresponding list of names to make my dict
MyDict.setdefault(int(spl_line[0]), list()).append(spl_line[1:])
print MyDict

Your error is because originally your MyDict variable maps an integer to a string. When you are trying to update it you are treating the value like a set, when it is a string.
You can use a defaultdict for this:
combined_dict = defaultdict(set)
# first add all the values from MyDict
for key, value in MyDict.iteritems():
combined_dict[int(key)].add(value)
# then add the values from the file
infile = open('FileWithTheData.csv', 'r')
for line in infile.readlines():
spl_line = line.split(',')
combined_dict[int(sp_line[0])].update(spl_line[1:])

Your issue is with how you are initializing MyDict, try changing it to the following:
MyDict = dict(zip(listofkeys, [set([name]) for name in listofnames]))
Here is a quick example of the difference:
>>> listofkeys = [100002, 100004, 100005]
>>> listofnames = ['APPLE', 'BANANA', 'CARROT']
>>> dict(zip(listofkeys, set(listofnames)))
{100002: 'CARROT', 100004: 'APPLE', 100005: 'BANANA'}
>>> dict(zip(listofkeys, [set([name]) for name in listofnames]))
{100002: set(['APPLE']), 100004: set(['BANANA']), 100005: set(['CARROT'])}
set(listofnames) is just going to turn your list into a set, and the only effect that might have is to reorder the values as seen above. You actually want to take each string value in your list, and convert it to a one-element set, which is what the list comprehension does.
After you make this change, your current code should work fine, although you can just do the contains check directly on the dictionary instead of explicitly checking the keys (key in MyDict is the same as key in MyDict.keys()).