Visualizing data with matplotlib - python

In Matlab, you can use drawnow to view a calculation's result while it's in progress. I have tried a similar syntax in Python, both with matplotlib and mayavi.
I know it's possible to animate in one dimension with ion and set_data. However, animating in two dimensions (via imshow) is useful and I couldn't find an easy way to do that.
I know it's possible to animate using a function call but that's not as useful for algorithm development (since you can't use IPython's %run and query your program).
In matplotlib, I can use
N = 16
first_image = arange(N*N).reshape(N,N)
myobj = imshow(first_image)
for i in arange(N*N):
first_image.flat[i] = 0
myobj.set_data(first_image)
draw()
to animate an image but this script doesn't respond to <Cntrl-C> -- it hangs and disables future animations (on this machine). Despite this SO answer, different ways of invoking this animation process does not work. How do I view 2D data as it's being calculated?

EDIT: I have since made a package called python-drawnow to implement the following answer.
You just want to visualize the data from some complicated computation and not smoothly animate an image, correct? Then you can just define some simple functions:
def drawnow(draw_fig, wait_secs=1):
"""
draw_fig: (callable, no args by use of python's global scope) your
function to draw the figure. it should include the figure() call --
just like you'd normally do it. However, you must leave out the
show().
wait_secs : optional, how many seconds to wait. note that if this is 0
and your computation is fast, you don't really see the plot update.
does not work in ipy-qt. only works in the ipython shell.
"""
close()
draw_fig()
draw()
time.sleep(wait_secs)
def drawnow_init():
ion()
An example of this:
def draw_fig():
figure()
imshow(z, interpolation='nearest')
#show()
N = 16
x = linspace(-1, 1, num=N)
x, y = meshgrid(x, x)
z = x**2 + y**2
drawnow_init()
for i in arange(2*N):
z.flat[i] = 0
drawnow(draw_fig)
Notice this requires that the variables you're plotting be global. This shouldn't be a problem since it seems that the variables you want to visualize are global.
This method responds fine to cntrl-c and is visible even during fast computations (through wait_secs.

Related

Put additional data on existing figure

I'm solving the optimization problem by different methods (for study).
The idea is written bellow:
instance = class_with_diff_methods()
instance.create_some_func()
instance.optimization_method_one()
instance.create_data_for_plot()
instance.display()
instance.optimization_method_two()
instance.create_data_for_plot()
instance.display()
So I wanted to add the new data iteratively, without saving and I implemented my idea this way:
`
import matplotlib.pyplot as plt
def display(self):
if not self.__plot_exists:
self.figure = plt.figure()
plt.scatter( self.data[0], self.data[1])
plt.plot( self.data[0], self.appdata)
self.figure.show()
self.__plot_exists = True
else:
plt.plot( self.data[0], self.appdata)
plt.show( block=False)`
This works, but the problem is that I don't really understand, why I even need (it necessary) using "self.figure" in the first part of the code and why I should use "plt.show()" instead of just "self.figure.show" at the last line.
I would be grateful for links, that will help me clearly understand how this works.
The plt.show() method is native from matplotlib, it is what launches the GUI. Check out their documentation if you would like to know about these types of things:
https://matplotlib.org/contents.html

Sympy plot _backend.ax appears as a list object, won't let me set xlabel

I'm trying to use sympy to plot an implicitly defined function in python, and have found the built-in plotting functionality to be sorely lacking. The source code recommends using _backend to directly modify the matplotlib axis and figure objects. Here's an abbreviated version of my code:
import matplotlib
from sympy import symbols, exp, plot_implicit, Eq
V,I = symbols('V I')
#define implicit equation to plot
eq1 = Eq(exp(I+V)-I,0)
#plot equation
p1 = plot_implicit(eq1, V,I)
#use _backend.ax to set xlabel and title of plot
axis = p1._backend.ax
axis.set_xlabel('Voltage (V)')
axis.set_title('ooga')
p1._backend.fig.savefig('test.png')
p1.show()
But when I run it, I get the following output:
plot generated without specified axis label and title
AttributeError: 'list' object has no attribute 'set_xlabel'
Why isn't this working? I don't understand why my axis object is being saved as a list. (Also, I find it rather odd that I get any plot output at all, as this would seem to imply the plot is being generated before I call p1.show())
Edit:
I've resolved the issue by following JohanC's recommendation to use move_sympyplot_to_axes from this post. Unfortunately I was unable to get ._backend working as intended, but this solution works well enough for my purposes.

How to manipulate figures while a script is running in Python?

Introduction
As I am coming from matlab, I am used to an interactive interface where a script can update figures while it is running. During the processing each figure can be re-sized or even closed. This probably means that each figure is running in its own thread which is obviously not the case with matplotlib.
IPython can imitate the Matlab behavior using the magic command %pylab or %matplotlib which does something that I don't understand yet and which is the very point of my question.
My goal is then to allow standalone Python scripts to work as Matlab does (or as IPython with %matplotlib does). In other words, I would like this script to be executed from the command line. I am expecting a new figure that pop-up every 3 seconds. During the execution I would be able to zoom, resize or even close the figure.
#!/usr/bin/python
import matplotlib.pyplot as plt
import time
def do_some_work():
time.sleep(3)
for i in range(10):
plt.plot([1,2,3,4])
plt.show() # this is way too boilerplate, I'd like to avoid it too.
do_some_work()
What alternative to %matplotlib I can use to manipulate figures while a script is running in Python (not IPython)?
What solutions I've already investigated?
I currently found 3 way to get a plot show.
1. %pylab / %matplotlib
As tom said, the use of %pylab should be avoided to prevent the namespace to be polluted.
>>> %pylab
>>> plot([1,2,3,4])
This solution is sweet, the plot is non-blocking, there is no need for an additionnal show(), I can still add a grid with grid() afterwards and I can close, resize or zoom on my figure with no additional issues.
Unfortunately the %matplotlib command is only available on IPython.
2. from pylab import * or from matplotlib.pyplot import plt
>>> from pylab import *
>>> plot([1,2,3,4])
Things are quite different here. I need to add the command show() to display my figure which is blocking. I cannot do anything but closing the figure to execute the next command such as grid() which will have no effect since the figure is now closed...
** 3. from pylab import * or from matplotlib.pyplot import plt + ion()**
Some suggestions recommend to use the ion() command as follow:
>>> from pylab import *
>>> ion()
>>> plot([1,2,3,4])
>>> draw()
>>> pause(0.0001)
Unfortunately, even if the plot shows, I cannot close the figure manually. I will need to execute close() on the terminal which is not very convenient. Moreover the need for two additional commands such as draw(); pause(0.0001) is not what I am expecting.
Summary
With %pylab, everything is wonderful, but I cannot use it outside of IPython
With from pylab import * followed by a plot, I get a blocking behavior and all the power of IPython is wasted.
from pylab import * followed by ion offers a nice alternative to the previous one, but I have to use the weird pause(0.0001) command that leads to a window that I cannot close manually (I know that the pause is not needed with some backends. I am using WxAgg which is the only one that works well on Cygwin x64.
This question advices to use matplotlib.interactive(True). Unfortunately it does not work and gives the same behavior as ion() does.
Change your do_some_work function to the following and it should work.
def do_some_work():
plt.pause(3)
For interactive backends plt.pause(3) starts the event loop for 3 seconds so that it can process your resize events. Note that the documentation says that it is an experimental function and that for complex animations you should use the animation module.
The, %pylab and %matplotlib magic commands also start an event loop, which is why user interaction with the plots is possible. Alternatively, you can start the event loop with %gui wx, and turn it off with %gui. You can use the IPython.lib.guisupport.is_event_loop_running_wx() function to test if it is running.
The reason for using ion() or ioff() is very well explained in the 'What is interactive mode' page. In principle, user interaction is possible without IPython. However, I could not get the interactive-example from that page to work with the Qt4Agg backend, only with the MacOSX backend (on my Mac). I didn't try with the WX backend.
Edit
I did manage to get the interactive-example to work with the Qt4Agg backend by using PyQt4 instead of PySide (so by setting backend.qt4 : PyQt4 in my ~/.config/matplotlibrc file). I think the example doesn't work with all backends. I submitted an issue here.
Edit 2
I'm afraid I can't think of a way of manipulating the figure while a long calculation is running, without using threads. As you mentioned: Matplotlib doesn't start a thread, and neither does IPython. The %pylab and %matplotlib commands alternate between processing commands from the read-eval-print loop and letting the GUI processing events for a short time. They do this sequentially.
In fact, I'm unable to reproduce your behavior, even with the %matplotlib or %pylab magic. (Just to be clear: in ipython I first call %matplotlib and then %run yourscript.py). The %matplotlib magic puts Matplotlib in interactive-mode, which makes the plt.show() call non-blocking so that the do_some_work function is executed immediately. However, during the time.sleep(3) call, the figure is unresponsive (this becomes even more apparent if I increase the sleeping period). I don't understand how this can work at your end.
Unless I'm wrong you'll have to break up your calculation in smaller parts and use plt.pause (or even better, the animation module) to update the figures.
My advice would be to keep using IPython, since it manages the GUI event loop for you (that's what pylab/pylot does).
I tried interactive plotting in a normal interpreter and it worked the way it is expected, even without calling ion() (Debian unstable, Python 3.4.3+, Matplotlib 1.4.2-3.1). If I recall it right, it's a fairly new feature in Matplotlib.
Alternatively, you can also use Matplotlib's animation capabilities to update a plot periodically:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.animation as animation
import time
plt.ion()
tt = np.linspace(0, 1, 200)
freq = 1 # parameter for sine
t0 = time.time() # for measuring ellapsed time
fig, ax = plt.subplots()
def draw_func(i):
""" This function gets called repeated times """
global freq # needed because freq is changed in this function
xx = np.sin(2*np.pi*freq*tt)/freq
ax.set_title("Passed Time: %.1f s, " % (time.time()-t0) +
"Parameter i=%d" % i)
ax.plot(tt, xx, label="$f=%d$ Hz" % freq)
ax.legend()
freq += 1
# call draw_func every 3 seconds 1 + 4 times (first time is initialization):
ani = animation.FuncAnimation(fig, draw_func, np.arange(4), interval=3000,
repeat=False)
# plt.show()
Checkout matplotlib.animation.FuncAnimation for details. You'll find further examples in the examples section.

Why does python keep crashing when plotting with matplotlib?

I am running a python code that simulates and predicts conditions inside a rapid compression machine (such as temperature, pressure, chemical species, etc.). The code is set up so that it calculates the time evolution of all these parameters (which are saved in numpy arrays) and then outputs them to a function, which creates and saves plots of these parameters against time.
These arrays are very large, and the function creates about 14 plots using matplotlib. The function will get to about the 7th plot (sometimes more, sometimes less), when I get an error reading "python.exe has stopped working". Not sure if it's a memory issue because the plots are so big or what's going on.
I have tried both (as you'll see in my sample code) plt.figure.clf() and plt.close(). I've even tried doing a time.sleep inbetween plots. The following is an example snippet of my function that does the plotting (not the real code, just an example necessary to illustrate my problem).
I am using Windows, Python 2.7, and Matplotlib 1.4.2
def graph_parameters(time, a, b, c, d, e): #a,b,c,d,e are my parameters
delay = 10
plt.figure(1)
plt.figure(facecolor="white")
plt.plot(time, a)
plt.ylabel('a')
plt.xlabel('Time(s)')
plt.savefig('fig1.png')
plt.figure(1).clf()
plt.close('all')
time.sleep(delay)
plt.figure(2)
plt.figure(facecolor="white")
plt.plot(time, b)
plt.ylabel('b')
plt.xlabel('Time(s)')
plt.savefig('fig2.png')
plt.figure(2).clf()
plt.close('all')
time.sleep(delay)
etc.
Thanks in advance.
I'm not completely sure, but I think it was a memory issue. I found a way (from another stackoverflow entry) to delete variables I don't need. Per my example above, if I only want to keep 'time_' and parameters 'a_','b_','c_','d_' and 'e_', I run the following at the end of my main code:
graph_array = np.array([time_, a_, b_, c_, d_, e_])
#Delete variables that aren't going to be plotted in order to free up memory
attributes = sys.modules[__name__]
for name in dir():
if name[0]!='_' and np.all( name!= np.array(['graph_array', 'attributes','np', 'gc', 'graph_parameters']) ):
delattr(attributes, name)
gc.collect()
graph_parameters(*graph_array)
Basically what the for loop does is keep private and magical function names and names of specified variables, and deletes all other names. I got this idea from the answer to the following link. How do I clear all variables in the middle of a Python script?
I watched my task manager as the code ran, and there was a significant drop in memory usage (~1,600,000 K to ~100,000 K) by Python right before plots began being saved, indicating that this method did free up memory. Also, no crash.

How to update matplotlib plot in while loop? [duplicate]

what I am trying to do is having a script compute something, prepare a plot and show the already obtained results as a pylab.figure - in python 2 (specifically python 2.7) with a stable matplotlib (which is 1.1.1).
In python 3 (python 3.2.3 with a matplotlib git build ... version 1.2.x), this works fine. As a simple example (simulating a lengthy computation by time.sleep()) consider
import pylab
import time
import random
dat=[0,1]
pylab.plot(dat)
pylab.ion()
pylab.draw()
for i in range (18):
dat.append(random.uniform(0,1))
pylab.plot(dat)
pylab.draw()
time.sleep(1)
In python 2 (version 2.7.3 vith matplotlib 1.1.1), the code runs cleanly without errors but does not show the figure. A little trial and error with the python2 interpreter seemed to suggest to replace pylab.draw() with pylab.show(); doing this once is apparently sufficient (not, as with draw calling it after every change/addition to the plot). Hence:
import pylab
import time
import random
dat=[0,1]
pylab.plot(dat)
pylab.ion()
pylab.show()
for i in range (18):
dat.append(random.uniform(0,1))
pylab.plot(dat)
#pylab.draw()
time.sleep(1)
However, this doesn't work either. Again, it runs cleanly but does not show the figure. It seems to do so only when waiting for user input. It is not clear to me why this is, but the plot is finally shown when a raw_input() is added to the loop
import pylab
import time
import random
dat=[0,1]
pylab.plot(dat)
pylab.ion()
pylab.show()
for i in range (18):
dat.append(random.uniform(0,1))
pylab.plot(dat)
#pylab.draw()
time.sleep(1)
raw_input()
With this, the script will of course wait for user input while showing the plot and will not continue computing the data before the user hits enter. This was, of course, not the intention.
This may be caused by different versions of matplotlib (1.1.1 and 1.2.x) or by different python versions (2.7.3 and 3.2.3).
Is there any way to accomplish with python 2 with a stable (1.1.1) matplotlib what the above script (the first one) does in python 3, matplotlib 1.2.x:
- computing data (which takes a while, in the above example simulated by time.sleep()) in a loop or iterated function and
- (while still computing) showing what has already been computed in previous iterations
- and not bothering the user to continually hit enter for the computation to continue
Thanks; I'd appreciate any help...
You want the pause function to give the gui framework a chance to re-draw the screen:
import pylab
import time
import random
import matplotlib.pyplot as plt
dat=[0,1]
fig = plt.figure()
ax = fig.add_subplot(111)
Ln, = ax.plot(dat)
ax.set_xlim([0,20])
plt.ion()
plt.show()
for i in range (18):
dat.append(random.uniform(0,1))
Ln.set_ydata(dat)
Ln.set_xdata(range(len(dat)))
plt.pause(1)
print 'done with loop'
You don't need to create a new Line2D object every pass through, you can just update the data in the existing one.
Documentation:
pause(interval)
Pause for *interval* seconds.
If there is an active figure it will be updated and displayed,
and the gui event loop will run during the pause.
If there is no active figure, or if a non-interactive backend
is in use, this executes time.sleep(interval).
This can be used for crude animation. For more complex
animation, see :mod:`matplotlib.animation`.
This function is experimental; its behavior may be changed
or extended in a future release.
A really over-kill method to is to use the matplotlib.animate module. On the flip side, it gives you a nice way to save the data if you want (ripped from my answer to Python- 1 second plots continous presentation).
example, api, tutorial
Some backends (in my experience "Qt4Agg") require the pause function, as #tcaswell suggested.
Other backends (in my experience "TkAgg") seem to just update on draw() without requiring a pause. So another solution is to switch your backend, for example with matplotlib.use('TkAgg').

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