I'm running a script remotely on a cluster to generate a scatter plot. I wish to save the plot, but I don't want the plot to be display or a window to come up (as when you execute plt.show() ).
My saved plots are always empty. This is the code that I'm using (below). Any tips would be very helpful. Thanks!
fig = plt.figure()
ax = fig.add_subplot(111)
ax.set_xlim([-1,maxX+1])
ax.set_ylim([0,maxY+1])
ax.set_xlabel('Comparison number (n)', fontsize=18, fontweight='bold')
ax.set_ylabel('Normalized cross correlation score', fontsize=18, fontweight='bold')
ax.scatter(xaxis,yaxis)
plt.savefig('testfig.png')
In order to use avoid showing plot windows (i.e. to do off-screen rendering) you probably want to use a different matplotlib backend.
Before any matplotlib import statements, add
import matplotlib
matplotlib.use('Agg')
and subsequent calls to matplotlib will not show any plot windows.
If your plot file shows an empty axis, then the problem lies in the plotting arguments as calling plot with empty arguments creates an empty axis.
Related
I am trying to make a single scatterplot for my online course using matplotlib, but sometimes multiple plots are showing up on the screen.
Here is the code:
plt.figure()
plt.scatter(x[:2], y[:2], s=100, c='red', label='Tall students')
plt.scatter(x[2:], y[2:], s=100, c='blue', label='Short students')
plt.show()
My problem is that if I run the code twice I get two images like this:
If I run it again, I get only a single plot.
Is there any way to make sure I get only 1 plot here?
plt.clf() will clear the current figure. plt.cla() will clear all subplots.
I am new in python and I create pandas series in a for-loop. Each time I want to plot the series in a figure. I use ax = series.plot(title = str(i)+'.jpg') but all figures are plotted in same window. How can I plot them in different windows?
If you are using matplotlib, use
plt.figure()
for every new figure you want to plot.
You then show all figures with
plt.show()
also, you should check out what subplots does.
Jupyter notebook, using Python 3:
import matplotlib.pyplot as plt
import seaborn as sns
%matplotlib inline
sns.despine()
then
snstest1 = sns.regplot(x="foo", y="bar", data=my_data)
shows a plot with the unwanted border box (i.e., sns.despine() doesn't seem to have affected it).
but:
snstest2 = sns.lmplot(x="foo", y="bar", data=my_data)
shows a plot with the unwanted border box correctly removed.
The only documentation I can find that seems to bear directly on this is the following, from the api docs for regplot:
Understanding the difference between regplot() and lmplot() can be a
bit tricky. In fact, they are closely related, as lmplot() uses
regplot() internally and takes most of its parameters. However,
regplot() is an axes-level function, so it draws directly onto an axes
(either the currently active axes or the one provided by the ax
parameter), while lmplot() is a figure-level function and creates its
own figure, which is managed through a FacetGrid. This has a few
consequences, namely that regplot() can happily coexist in a figure
with other kinds of plots and will follow the global matplotlib color
cycle. In contrast, lmplot() needs to occupy an entire figure, and the
size and color cycle are controlled through function parameters,
ignoring the global defaults.
But I don't fully understand the difference between a "figure" and an "axis." The best guess I can make without knowing the underlying model here is that when these weird global-state-mutating functions built into Seaborn, like despine and (?) set_palette and such, are active, only "figures," not "axes," check that state before rendering? But if that's so, how would I get something that generates an "axis" to plot in accordance with what I've requested?
In short: Call sns.despine after your plotting function.
The longer version:
lmplot creates its own figure. But it does not need despine. It will do it automatically, even without calling sns.despine.
import matplotlib.pyplot as plt
import seaborn as sns
tips = sns.load_dataset("tips")
g = sns.lmplot(x="total_bill", y="tip", data=tips)
plt.show()
This is the reason the code from the question actually seems to work.
However, what is really happening is that if you call sns.despine before any figure is created, it will act on a newly created figure. The code from the question is hence creating two figures. One, which is empty, but also is "despined" and then one which is the lmplot figure and which is "despined" because every lmplot is despined by default.
A regplot is instead created in an axes of a matplotlib figure. If no figure or axes is provided, it will create a new one. This means that sns.despine needs to know which axes to despine. If you call it before anything else, there will again be two figures: One, which is empty, but also is "despined" and then one which is the regplot figure. This figures axes are not "despined", because noone told them so.
So the idea is of course to call sns.despine after creating the plot. You may specify which figure or axes to despine as argument (sns.despine(ax=ax))
import matplotlib.pyplot as plt
import seaborn as sns
tips = sns.load_dataset("tips")
ax = sns.regplot(x="total_bill", y="tip", data=tips)
sns.despine(ax=ax)
plt.show()
but if you only have a single subplot that wouldn't even be necessary. Hence
tips = sns.load_dataset("tips")
sns.regplot(x="total_bill", y="tip", data=tips)
sns.despine()
will work equally well and produce
I would like to plot two or more graphs at once using python and matplotlib. I do not want to use subplot since it is actually two or more plots on the same drawing paper.
Is there any way to do it?
You can use multiple figures and plot some data in each of them. The easiest way of doing so is to call plt.figure() and use the pyplot statemachine.
import matplotlib.pyplot as plt
plt.figure() # creates a figure
plt.plot([1,2,3])
plt.figure() # creates a new figure
plt.plot([3,2,1])
plt.show() # opens a window for each of the figures
If for whatever reason after creating a second figure you want to plot to the first one, you need to 'activate' it via
plt.figure(1)
plt.plot([2,3,1]) # this is plotted to the first figure.
(Figure numbers start at 1)
I've got scatter plot with colorbar which I save as PNG image. I need the plot to be of a certain figsize but adding colorbar scales original plot.
import pylab as plt
plt.figure(figsize=FIGSIZE)
plt.scatter(X, Y, c=Z, s=marker_size, norm=LogNorm(), vmin=VMIN, vmax=VMAX, cmap=CMAP,rasterized=True,lw=0,)
CB = plt.colorbar(ticks=TICKS, format=FORMAT)
How could I save original plot (with figsize set as above) and colorbar as two separate images?
The obvious answer is "plot your colorbar separately". You need to create a new figure window and plot your colorbar there, in order to prevent your first figure from being distorted. Small example:
import matplotlib.pyplot as plt
import numpy as np # only for dummy data
X,Y = np.mgrid[-2:3,-2:3]
Z = np.random.rand(*X.shape)
FIGSIZE = (2,3)
plt.figure(figsize=FIGSIZE)
mpb = plt.pcolormesh(X,Y,Z,cmap='viridis')
# plot the original without a colorbar
plt.savefig('plot_nocbar.png')
# plot a colorbar into the original to see distortion
plt.colorbar()
plt.savefig('plot_withcbar.png')
# draw a new figure and replot the colorbar there
fig,ax = plt.subplots(figsize=FIGSIZE)
plt.colorbar(mpb,ax=ax)
ax.remove()
plt.savefig('plot_onlycbar.png')
# save the same figure with some approximate autocropping
plt.savefig('plot_onlycbar_tight.png',bbox_inches='tight')
Consider the following four figures that were produced (click to view properly):
The first is a saved version of the figure without a call to colormap. This is fine, this is what you want to preserve. The second figure shows what happens if we call colorbar without any extra fuss: it takes some space from the original figure, and this is what you want to prevent.
You have to open a new figure (and axes) using plt.subplots, with the size of your original figure. This way you can be sure that the produced colorbar will be the same size as if it was drawn in your original figure. In the above setup I let matplotlib determine the size of the colorbar itself; but then afterward we need to delete the auxiliary axes that would pollute the resulting plot. (The other option would be to create a single axes in the new figure manually, with the expected size of the colorbar. I suspect this is not a feasible course of action.)
Now, as you can see in the third plot, the empty space left after the deleted axes is clearly visible in the resulting plot (but the size of the colorbar is perfect, correspondingly). You can either cut this white space off manually in post-production, or use something that autocrops your colorbar image.
I also included a version of the plot wherein matplotlib itself crops most of the figure: the bbox_inches='tight' keyword argument to savefig does exactly this. The upside is that the resulting image file only contains the colorbar (as seen above in the fourth image), but the size of the resulting colorbar will be slightly different from your original. Depending on your specific needs, you'll need to experiment with the available methods to come up with a solution that's most convenient for you.