I am following this guide here tango with django and I am reading/copying as best from here tutorial part 3
But I cannot get different views to display different content. I am missing the explanation somewhere/somehow.
so this is my project urls.py
from django.conf.urls import patterns, include, url
# Uncomment the next two lines to enable the admin:
# from django.contrib import admin
# admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'Sayth.views.home', name='home'),
# url(r'^Sayth/', include('Sayth.foo.urls')),
# Uncomment the admin/doc line below to enable admin documentation:
# url(r'^admin/doc/', include('django.contrib.admindocs.urls')),
# Uncomment the next line to enable the admin:
# url(r'^admin/', include(admin.site.urls)),
url(r'^rango/', include('rango.urls')),
url(r'^rango/about/', include('rango.urls')),
)
This is my application urls.py
from django.conf.urls import patterns, url
from rango import views
urlpatterns = patterns('',
url(r'^$', views.index, name='index'),
url(r'^$', views.about, name='about'),
)
These are my views
# Create your views here.
from django.http import HttpResponse
def index(request):
return HttpResponse("Rango says Hello World! <a href='/rango/about'>About</a>" )
def about(request):
return HttpResponse("This is the about page. <a href='/rango/'>Index</a>")
Both my pages resolve but both show the index page, why?
The urls defined are not correct. The root urls.py should have only a pointer to the app, and the app's urls.py should resolve the different endpoints.
Try the following urls.py:
#Project urls.py
from django.conf.urls import patterns, include, url
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'Sayth.views.home', name='home'),
# url(r'^Sayth/', include('Sayth.foo.urls')),
# Uncomment the admin/doc line below to enable admin documentation:
# url(r'^admin/doc/', include('django.contrib.admindocs.urls')),
# Uncomment the next line to enable the admin:
# url(r'^admin/', include(admin.site.urls)),
url(r'^rango/', include('rango.urls')),
)
#rango/urls.py
from django.conf.urls import patterns, url
from rango import views
urlpatterns = patterns('',
url(r'^$', views.index, name='index'),
url(r'^about/$', views.about, name='about'),
)
As the first answer have mentioned, your project's urls.py only needs one pointer to the application urls.py.
Conceptually it is like this, anything matching '^rango/' should be passed onto the application urls.py, and then the applications handles the rest of the url.. either '/' or 'about/'
So in your applications urls.py, you then need to ensure that a mapping for each of these patterns exists.
In the tangowithdjango book, the about page is an exercise, left for the reader, but if you have future problems you can always inspect the code for the application, for example:
The project urls.py:
https://github.com/leifos/tango_with_django/blob/master/tango_with_django_project/tango_with_django_project/urls.py
The application urls.py:
https://github.com/leifos/tango_with_django/blob/master/tango_with_django_project/rango/urls.py
If you do not wish to create an urls.py on the app you can just do the url mapping like this:
urlpatterns = patterns('',
# ...
# most detailed urls comes first.
url(r'^rango/about/?$', 'rango.views.about', name='about'),
url(r'^rango/?$', 'rango.views.index', name='index'),
)
Related
I am trying to return different templates for different urls (having just one app), so basically I want to return:
One template for:http://127.0.0.1:8000/projects/
Another template for:http://127.0.0.1:8000/formpage/
I have the project urls.py:
from django.conf.urls import url,include
from django.contrib import admin
from appone import views
urlpatterns = [
url(r'^admin/', admin.site.urls),
#home page
url(r'^$', views.index, name='index'),
url(r'^projects/', include('appone.urls')),
url(r'^formpage/', include('appone.urls')),
]
And the app urls.py:
from django.conf.urls import url,include
from django.http import HttpResponse
from . import views
urlpatterns = [
url(r'^$', views.projs, name='proj'),
url(r'^$', views.form_view, name='form_view')
]
I have the views and templates , that are good, but I do not understand how can I return them based on the url, because for the moment I return the first view from app urls.py, for both urls.
Make separate view functions for both urls (projs and form_view).
Then in projects/urls.py
urlpatterns = [
...
url(r'^projects/', views.projs, name='proj'),
url(r'^formpage/', views.form_view, name='form_view')
...
]`
Or, if you want to have separate urls.py file
projects/urls.py:
urlpatterns = [
url(r'^admin/', admin.site.urls),
#home page
url(r'^$', views.index, name='index'),
url(r'^', include('appone.urls')),
]`
appone/urls.py
urlpatterns = [
url(r'^projects/', views.projs, name='proj'),
url(r'^formpage/', views.form_view, name='form_view')
]`
Do you really need the second urls page? You could just set your first urls.py as:
from django.conf.urls import url,include
from django.contrib import admin
from appone import views
urlpatterns = [
url(r'^admin/', admin.site.urls),
#home page
url(r'^$', views.index, name='index'),
url(r'^projects/', views.projs, name='proj'),
url(r'^formpage/', views.form_view, name='form_view'),
]
Okay... let's try to explain things clearly. I've used Python Django to create a dynamic webpage/web-app. After completing the website I have published it using DigitalOcean and have successfully attached my purchased domain name to the name server of DigitalOcean. When I access my website, ordinanceservices.com, i get an error 404; however, if I type ordinanceservices.com/home it works as it should and displays the home page. How, by editing the python files, can I have it to where ordinanceservices.com will display the home page as opposed to error 404? I feel like there's something that I am doing that is fundamentally wrong regarding my .urls structure and thus a rewrite/redirect in the nginx config should not be necessary.
Here is the specific error:
Page not found (404)
Request Method: GET
Request URL: http://ordinanceservices.com/
Using the URLconf defined in django_project.urls, Django tried these URL patterns, in this order:
^admin/
^ ^home/ [name='home']
^ ^contact/ [name='contact']
^ ^services/ [name='services']
The current URL, , didn't match any of these.
I somewhat understand what is happening here though I do not know how to fix this. Next I will provide my .urls files for each folder that contains such:
/django_project urls.py
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls)),
url(r'^', include('company.urls')),
)
/company urls.py
from django.conf.urls import url, include
from . import views
urlpatterns = [
url(r'^home/', views.home, name='home'),
url(r'^contact/', views.contact, name='contact'),
url(r'^services/', views.services, name='services'),
]
/company views.py
from django.shortcuts import render
def home(request):
return render(request, 'company/home.html')
def contact(request):
return render(request, 'company/contact.html')
def services(request):
return render(request, 'company/services.html')
What I am aiming to do, without needing to redirect the main URL using the nginx config files to do so, is to edit my urls and views structure of my Python files to ensure that the normal URL, ordinanceservices.com, will actually display a page; preferably the home page of my webpage.
I have a hunch that it has to do with the fact that I do not have a views.index for the r'^admin/' to reach to. I am not certain but I have been trying to figure this out for hours. Does anyone have a clue what I can do to fix this?
You haven't defined anything at the root url. Add one more line to your company urls.py so it becomes
//company urls.py
from django.conf.urls import url, include
from . import views
urlpatterns = [
url(r'^$', views.home, name='home'),
url(r'^home/', views.home, name='home'),
url(r'^contact/', views.contact, name='contact'),
url(r'^services/', views.services, name='services'),
]
First of all, check if you have added www.yourdomain.com or yourdomain.com to ALLOWED_HOST = ['www.yourdomain.com','yourdomain.com'] in your settings.py
and then in your company/urls.py do this
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.home, name='home'),
url(r'^contact/$', views.contact, name='contact'),
url(r'^services/$', views.services, name='services'),
]
and in your main urls.py add this code
from django.conf.urls import url,include
from django.contrib import admin
admin.autodiscover()
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^', include('company.urls')),
]
I'm trying out Python Django. With eclipse pyDev. But I'm unable to simply get my first url to display.
This urls.py is from the Cr package.
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.index, name='index')
]
This urlspy is from the Crowd package.
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'Crowd/', include('Cr.urls'))
]
So what I've understood from this the Crowd package is the "main" webservice(?), and by using include I can whenever the regular expression matches Crowd, will pass it on to the other urls.py(Cr). But the debugger passes:
Using the URLconf defined in Crowd.urls, Django tried these URL patterns, in this order:
^admin/
The current URL, crowd, didn't match any of these.
my views.py file
from django.shortcuts import HttpResponse
def index(request):
return HttpResponse('<h1>Hello World!</h1>')
I tried to access it with http://127.0.0.1:8000/Crowd
Below is an image of the project folder.
Can we see your settings.py file? There is a place in there where you define your project's url file. I'm assuming it's right now either not there or it's pointing to the wrong place, because Django can't find your urls.py file.
For example, in my settings.py file for one of my projects, I have:
ROOT_URLCONF = 'Freya.urls'
Where "Freya" is my project name
Just for reference, not that I know this will solve your problem, this is what (part of) my urls.py file looks like for one of my projects:
from django.conf.urls import patterns, url
import views
urlpatterns = patterns(
'',
url(r'^$', views.index, name='index'),
url(r'^login/$', views.login, name='login'),
url(r'^logout/$', views.logout, name='logout'),
)
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'Crowd/', include('Cr.urls'))
]
just use this urls.py file
I just started playing with Django, I love it! I followed the tutorial from the Django documentation, but have the following question:
I only have one app (polls), currently I always have localhost/polls/{urlname}
Is there a way to remove the polls keyword? So people that go to localhost automatically go to my app polls? At the moment, I have this wildcard
url(r'.*$', RedirectView.as_view(url='polls/', permanent=False), name='index'),
But this still keeps polls in the url. This is my complete urls.py file:
from django.conf.urls import patterns, include, url
from django.contrib import admin
urlpatterns = patterns('',
url(r'^polls/', include('polls.urls', namespace="polls")),
url(r'^admin/', include(admin.site.urls)),
url(r'.*$', RedirectView.as_view(url='polls/', permanent=False), name='index'),
)
Thanks in advance!
Just remove the polls/ prefix in the regex of the "include" url:
urlpatterns = patterns('',
url(r'^', include('polls.urls', namespace="polls")),
...
)
I'm totally new to Django, and I'm trying to understand how does it work (I'm more used to PHP and Spring frameworks.
I have a project called testrun and inside it an app called graphs, so my views.py looks like:
#!/usr/bin/python
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello, World. You're at the graphs index.")
then, in graphs/urls.py:
from django.conf.urls import patterns, url, include
from graphs import views
urlpatterns = patterns(
url(r'^$', views.index, name='index'),
)
finally, at testrun/urls.py:
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'testrun.views.home', name='home'),
# url(r'^blog/', include('blog.urls')),
url(r'^graphs/', include('graphs.urls')),
url(r'^admin/', include(admin.site.urls)),
)
However, when I try to access http://127.0.0.1:8000/graphs/ I get:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/graphs/
Using the URLconf defined in testrun.urls, Django tried these URL patterns, in this order:
^admin/
The current URL, graphs/, didn't match any of these.
You're seeing this error because you have DEBUG = True in your Django settings file. Change that to False, and Django will display a standard 404 page.
What am I doing wrong that I can't get that simple message to be displayed in the browser?
To expand on my comment, the first argument to patterns() function is
a prefix to apply to each view function
You can find more information here:
https://docs.djangoproject.com/en/dev/topics/http/urls/#syntax-of-the-urlpatterns-variable
Therefore in graphs/urls.py you need to fix the patterns call like so:
urlpatterns = patterns('', # <-- note the `'',`
url(r'^$', views.index, name='index'),
)