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NameError-- name 'logs' is not defined. Django-Python

from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^logs/', include(logs.urls)),
]
I have written this code in main/urls.py file
code in logs/urls.py is below:-
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$/', views.index, name='index'),
]
and i am accessing http://localhost:8000/logs
Error:- NameError name 'logs' is not defined

You need to import the module you are actually referencing before adding it to your URLs file.
Assuming logs is in your import path:
import logs

Usually you would use a string with include so that you don’t have to import the module;
url(r'^logs/', include('logs.urls')
Also, you should remove the slash from the end of your regex for the index view. The dollar marks the end of the string, so r'^$/' will never match.
url(r'^$', views.index, name='index'),

Please check the docs. It should help!
include() function takes a list/tuple of url(), path(), re_path() and includes them to django routing system.
It also requires app's name: you can define it in include(("enter here your app's name", app.urls))
or in an app itself, in urls.py at a modular level. app_name = 'enter here your apps'name '
But only include() isn't enough, you have to define it in path() or smth that is used for routing (e.g re_path(), url() (deprecated in django 2.0))
For full details: include() function.
So, the full poiting to app's urls look so:
from django.conf.urls import url, include
from . import views
from . import app
urlpatterns = [
url(r'^', include(("app", app.urls)), name='index'),
]
I recommend you to use path() and re_path() if you use Django 2.0 >
I noticed that you use regex incorrectly little bit
url(r'^$/', views.index, name='index'),
You type $ before /, it's incorrect, $ means the end of expression and must be used in the end of expression.
Unfortunately I can't tell you all the details in the post. You should read Django docs. Go through django tutorial for start.
I'm sure it will help!

Django urls.py: url doesn't work properly

I'm developing a webpage with Django.
I want to add/define an url for the application.
At this moment the url (dsvd/) doen't work properly. It shows only table data but no css and background.
here is the code for the main urls.py file.
from django.conf.urls import patterns, include, url
from django.conf import settings
from django.conf.urls.static import static
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'kleedkamer_overview.views.home', name='home'),
# url(r'^blog/', include('blog.urls')),
url(r'^admin/', include(admin.site.urls)),
url(r'^', include('kleedkamer_overview.urls')),
url(r'^dsvd/', 'kleedkamer_overview.views.indeling'),
)
and here the code inside the application urls.py file
from django.conf.urls import patterns, url
from kleedkamer_overview import views
urlpatterns = patterns ('',
url(r'^$',views.indeling, name='indeling'),
)
Is there anyone who can help me find the problem?
Greetz.

It looks like line is giving you trouble:
url(r'^dsvd/', 'kleedkamer_overview.views.indeling')
It seems like you are trying to map this URL to kleedkamer_overview.views.indeling but the URL regrex does not end with a '$'. Urls.py files that are mapped to other apps look like this:
url(r'^admin/', include(admin.site.urls))
Notice the include function call and that the regrex expression r'^admin/' does not end with a $
However mapping to a specific view is a bit different and it looks like this:
url(r'^$', 'kleedkamer_overview.views.home', name='home')
Notice that this time, where the include() function call would go you are instead telling Django which specific view you want to use and that the site regrex is r'^$' ending with a $.
Try changing this:
url(r'^dsvd/', 'kleedkamer_overview.views.indeling')
to this:
url(r'^dsvd/$', 'kleedkamer_overview.views.indeling')
Edit:
I saw your comments and while the urls.py is not the source of your problem, what I said is still valid because the urls.py was malformed. You should not even have the offending line there at all because you have already included the urls.py from kleedkamer_overview , there is no need to include it twice. It isn't DRY and it is just bad practice in general. This is why this still works despite being malformed because sites are looked for in order, in this case first it looks for /admin then / and does not reach /dsvd because it was already caught by / and your malformed url mapping is NEVER reached.

how to display a view in Django?

I'm totally new to Django, and I'm trying to understand how does it work (I'm more used to PHP and Spring frameworks.
I have a project called testrun and inside it an app called graphs, so my views.py looks like:
#!/usr/bin/python
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello, World. You're at the graphs index.")
then, in graphs/urls.py:
from django.conf.urls import patterns, url, include
from graphs import views
urlpatterns = patterns(
url(r'^$', views.index, name='index'),
)
finally, at testrun/urls.py:
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'testrun.views.home', name='home'),
# url(r'^blog/', include('blog.urls')),
url(r'^graphs/', include('graphs.urls')),
url(r'^admin/', include(admin.site.urls)),
)
However, when I try to access http://127.0.0.1:8000/graphs/ I get:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/graphs/
Using the URLconf defined in testrun.urls, Django tried these URL patterns, in this order:
^admin/
The current URL, graphs/, didn't match any of these.
You're seeing this error because you have DEBUG = True in your Django settings file. Change that to False, and Django will display a standard 404 page.
What am I doing wrong that I can't get that simple message to be displayed in the browser?

To expand on my comment, the first argument to patterns() function is
a prefix to apply to each view function
You can find more information here:
https://docs.djangoproject.com/en/dev/topics/http/urls/#syntax-of-the-urlpatterns-variable
Therefore in graphs/urls.py you need to fix the patterns call like so:
urlpatterns = patterns('', # <-- note the `'',`
url(r'^$', views.index, name='index'),
)

Django Invalid Syntax Error

I am at my wits. I am trying to set up Django admin but I am having a hard time. I have followed the Django book and checked several times but get an invalid syntax (urls.py, line 23).
from django.conf.urls.defaults import *
from mysite.views import hello, current_datetime, hours_ahead
# Uncomment the next two lines to enable the admin:
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
(r'^hello/$', hello),
(r'^time/$', current_datetime),
(r'^time/plus/(\d{1,2})/$', hours_ahead),
(r'^admin/', include(admin.site.urls),
)
Any insight would be appreciated - thanks!

You are missing a closing parens on line 22:
(r'^admin/', include(admin.site.urls)),
When you get a SyntaxError in Python, check that your parenthesis are balanced on the lines preceding it.

What's wrong with this url?

I have a root urls.py and an app urls.py. In my root I have this:
from django.conf.urls.defaults import *
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
(r'^$', include('realestate.properties.urls')),
(r'^admin/', include(admin.site.urls)),
)
In my app urls I have the following
from django.conf.urls.defaults import *
urlpatterns = patterns('realestate.properties.views',
url(r'^$', 'property_list', {'template_name': 'properties/property_list.html'}, name='property_list'),
url(r'^(?P<slug>[-\w]+)/$', 'property_detail', { 'template': 'property_detail.html' }, name='property_details'),
)
now in my template I have a link to the details view, which looks like this:
{% url property_details property.slug %}
Everytime I render this page i get the error:
*Caught NoReverseMatch while rendering: Reverse for 'property_details' with arguments '(u'111-front-st',)' and keyword arguments '{}' not found.*
No matter what I do, I get that error. I tried capturing just the id and nothing is working, i am not sure why, I have used url's many times before so I am really confused if I am missing something obvious. Any see anything wrong here?
Thanks
Jeff

I think you need to drop the $ from your urlconf, where you include the app's urls. Probably you can remove the ^ too.
urlpatterns = patterns('',
(r'^', include('realestate.properties.urls')),
(r'^admin/', include(admin.site.urls)),
)
http://docs.djangoproject.com/en/1.2/topics/http/urls/#including-other-urlconfs
Note that the regular expressions in
this example don't have a $
(end-of-string match character) but do
include a trailing slash. Whenever
Django encounters include(), it chops
off whatever part of the URL matched
up to that point and sends the
remaining string to the included
URLconf for further processing.

Do something like this:
from django.conf.urls.defaults import *
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
(r'^$', 'realestate.properties.views.property_list'),
(r'^properties/', include('realestate.properties.urls')),
(r'^admin/', include(admin.site.urls)),
)
Otherwise (like sugested by Reiners post) you will make the first regular expression a "catch all" and /admin will never match.
You can also place the admin regular expression before your "catch all" re, but what happens if you have a slug like 'admin'? That is why I would advice against a url scheme with /<slug>/ at the first level. Instead, use /<object-type>/<slug>/, that will make room for other things in the future.