PYTHON - URLLIB2 Catch socket.error - python

Right now I am using urllib to pull some data off a server. However, the server is a bit dodgy and tends to go down every now and then for a minute or so. To deal with, when my code encounters an error, it just waits two seconds and tries again:
def fin(group):
try:
data = urllib2.urlopen("cool website" + group)
return data.read()
except urllib2.HTTPError, err:
time.sleep(2)
fin(group) #calls itself again
except urllib2.URLError, err:
time.sleep(2)
fin(group)
That works fine if the website goes down or I lose my internet connection. However, last night I left the code running and got this error:
socket.error: [Errno 10053] An established connection was aborted by the software in your host machine
I am not quite sure how to catch that. After some searching I am thinking I may need to do this:
except httplib.HTTPException, err:
time.sleep(2)
fin(group)
But I am not certain. Would anyone be able to help me out?

Related

detect socket timeout when using "with" instead of "try"

Using python 3.6.8, I have the following code
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.settimeout(20)
s.connect(host, port)
As I understand it, using with as shown instead of a try except block better handles the error condition that occurs if opening the socket (s.connect()) fails. How so? In the code as shown, if s.connect() times out, will it print a message? My main question is, can I detect that it timed out, e.g. to run some code if a timeout occurs? I want to be able to do that from within the with block without using try. I read this example
with opened_w_error("/etc/passwd", "a") as (f, err):
if err:
print "IOError:", err
else:
f.write("guido::0:0::/:/bin/sh\n")
But that doesn't detect the type of error. I read this as well
try:
with ContextManager():
BLOCK
except InitError: # raised from __init__
...
except AcquireResourceError: # raised from __enter__
...
except ValueError: # raised from BLOCK
...
except ReleaseResourceError: # raised from __exit__
But I'm hoping there is a way to detect if it's a timeout error from within the with block.

try except not running except part

I have a short code that ftps a small file into a server.
session = ftplib.FTP("192.168.0.164", "admin", "admin")
file = open("path/test.txt", "rb")
try:
session.storbinary("STOR application/test.txt", file)
except:
print("failed")
else:
print("success!")
file.close()
In the above piece I changed the IP address to so it would fail (there is no 192.168.0.164 device) and it doesn't print failed like it's supposed to. In the terminal I get a
"connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond" error.
if I mistype the path, I also don't get a failed print on the terminal.
If I type in the correct IP the success part does work.
Am I using the try/except wrong?
UPDATE:
Current code looks like this:
file = open("path/test.txt", "rb")
try:
session = ftplib.FTP("192.168.0.161", "admin", "admin")
session.storbinary("STOR application/test.txt", file)
except:
print("Unable to reach host")
else:
print("success!")
session.quit()
finally:
print ("DONE!!")
file.close()
I figure the ftplib.all_errors will catch all errors (host unreachable, and file not found). It seems to catch the unable to reach host errors, but no file not found errors.
Am I using the try/except wrong?
Your syntax is correct, but Python is not actually reaching the try block at all.
When you call session = ftplib.FTP(host, ...) where host is unreachable, the code will stop in its tracks there. That's because FTP.__init__() greedily calls self.connect(). This will in turn call socket.create_connection(), which will not succeed for an unreachable host.
So, you'd need to modify to:
with open("path/test.txt", "rb") as file:
try:
session = ftplib.FTP("192.168.0.164", "admin", "admin")
session.storbinary("STOR application/test.txt", file)
except Exception as e:
print("failed")
print(e)
else:
print("success!")
finally:
session.quit()

Python socket programming - exception handling

I'm working on a basic socket client program in python and I'm not totally sure how to handle exceptions. This is what I did up to now:
TCP_IP = '..............'
TCP_PORT = 4950
MESSAGE = "o3"
BUFFER_SIZE = 2048
data = ""
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.settimeout(5.0)
try:
s.connect((TCP_IP, TCP_PORT))
except socket.error:
#write error code to file
s.close()
try:
s.sendall(MESSAGE)
except socket.error:
#write to file or whatever
s.close()
try:
data = s.recv(BUFFER_SIZE)
except socket.error:
#write to file or whatever
s.close()
finally:
s.close()
The code is working as I want, but I'm not sure if I should nest try/catch blocks or not? Should I put socket.socket into try/catch block too?
Second question, what will s.settimeout() do in my case? As far as I understood the documentation, it will throw an exception after 5 seconds, but for what? Just connect or will it do the same for sendall and recv?
Since you're doing exactly the same actions in all the exception blocks and catching the same socket.error exception, you could put s.connect, s.sendall and s.recv in the same try: block. Like so:
try:
s.connect((TCP_IP, TCP_PORT))
s.sendall(MESSAGE)
data = s.recv(BUFFER_SIZE)
except socket.error:
#write error code to file
finally:
s.close()
Note that since s.close is also in the finally section in your example, it will always get called, even after an exception has occurred. So you'd end up with another exception occurring when you try to close an already closed socket. By not putting it in the except block and only in finally, you can avoid that situation.
If you do intend to handle each error in a different way, then you can leave them separate as you already have. But make sure to break/return at the end of the exception block so that you don't try the next. It's done that way in the socket examples, by using a continue in the loop.
Nesting them would help if you wanted to do something different in the exception block. But if not you'd be repeating the except block every time. And if you wanted to do something different, when you exit the nested-trys, you wouldn't be certain of which level it has completed or raised an exception - would need to use flag values etc. to merely track that. So for your example of the same error handling code, at the very least, do something like this in your except block:
except socket.error as e:
socket_error_handler(e, s)
def socket_error_handler(exception, socket):
#write error code to file
etc.
Should I put socket.socket into try/catch block too?
They do that in the examples, linked above.
Apart from logging, you shouldn't really be doing the same exception handling at each stage. Probably need to handle those separately.
Part 2:
s.settimeout(5.0) sets the timeout for each socket operation, not just the first connect. Also implies that it's in blocking mode.

Create Socket Errors on Purpose / Python Script

I want to create socket errors (By doing things, obviously) but I've no idea how I should test if my script handles errors properly (If it dectes them.)
Currently, my code is this:
except socket.error as err:
print "Connection lost, waiting..."
time.sleep(5)
In theory, it should handle all the socket errors, print and then sleep (It's a part of a while loop.).
Any idea of how can I test it to see how it handles errors?
Use the raise statement:
try:
raise socket.error
except socket.error as err:
print "Connection lost, waiting..."
time.sleep(5)
Yet another example:
try:
raise AttributeError
except AttributeError:
print 'Sorry'
#Sorry
Also take a look at here and here

Checking a Python FTP connection

I have a FTP connection from which I am downloading many files and processing them in between. I'd like to be able to check that my FTP connection hasn't timed out in between. So the code looks something like:
conn = FTP(host='blah')
conn.connect()
for item in list_of_items:
myfile = open('filename', 'w')
conn.retrbinary('stuff", myfile)
### do some parsing ###
How can I check my FTP connection in case it timed out during the ### do some parsing ### line?
Send a NOOP command. This does nothing but check that the connection is still going and if you do it periodically it can keep the connection alive.
For example:
conn.voidcmd("NOOP")
If there is a problem with the connection then the FTP object will throw an exception. You can see from the documentation that exceptions are thrown if there is an error:
socket.error and IOError: These are raised by the socket connection and are most likely the ones you are interested in.
exception ftplib.error_reply: Exception raised when an unexpected reply is received from the server.
exception ftplib.error_temp: Exception raised when an error code signifying a temporary error (response codes in the range 400–499) is received.
exception ftplib.error_perm: Exception raised when an error code signifying a permanent error (response codes in the range 500–599) is received.
exception ftplib.error_proto: Exception raised when a reply is received from the server that does not fit the response specifications of the File Transfer Protocol, i.e. begin with a digit in the range 1–5.
Therefore you can use a try-catch block to detect the error and handle it accordingly.
For example this sample of code will catch an IOError, tell you about it and then retry the operation:
retry = True
while (retry):
try:
conn = FTP('blah')
conn.connect()
for item in list_of_items:
myfile = open('filename', 'w')
conn.retrbinary('stuff', myfile)
### do some parsing ###
retry = False
except IOError as e:
print "I/O error({0}): {1}".format(e.errno, e.strerror)
print "Retrying..."
retry = True

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