I'm basically trying to make a quine in python and first tried with f-strings, but I quickly realized that I first have to define the variables I want to format inside the string. I then learned about string templates and figured that would be the way to go. I am however not that experienced with it and could need some help. Any suggestions?
Here's the actual code:
from string import Template
s="from string import Template\ns=$s\nt=Template($s).substitute(s=$s)\nprint($s)"
t=Template(s).substitute(s=s)
print(s)
It gives me somewhat of the right result. The only problem is that it's not replacing the $s with the actual string. I've might just have misunderstood the whole concept with quines and the method of doing them but I feel this should work.
Output:
from string import Template
s=$s
t=Template($s).substitute(s=$s)
print($s)
I'm not sure how this would be done using string.Template, but you could use str.format as a straightforward replacement to f-strings that suits this task, as it allows you to delay the interpolation of the s variable:
s='s={0!r}\nprint(s.format(s))'
print(s.format(s))
Output:
s='s={0!r}\nprint(s.format(s))'
print(s.format(s))
The !r is used to get the repr of s, which wraps it in quotes, and escapes the newlines.
I've taken the advice from #Will Da Silva and included the repr() function in my method of doing it as seen below:
from string import Template
s='from string import Template\ns=$s\nt=Template(s)\nprint(t.substitute(s=repr(s)))'
t=Template(s)
print(t.substitute(s=repr(s)))
I think the problem was that it interpreted the string as code and in turn made a new line at every \n. But now when it keeps the quotation marks it just sees it as a string.
I want to be able to control vim/neovim on a per-key basis with python scripting. There is a function called feedkeys in the python vim module (vim.feedkeys) that is nearly what I want. However, I haven't been able to figure out how to send things like function keys, arrow keys, pgup, pgdown etc as it always takes my strings completely literally.
As per the documentation for vim's feedkeys (vimscript version, not python)
feedkeys("\<CR>") simulates pressing of the <Enter> key. But feedkeys('\<CR>') pushes 5 characters.
Things I've tried with the python counterpart that haven't worked (note, <CR> is just an example; I know I can use \n for that. Nonetheless, this should simulate an enter keypress):
vim.feedkeys("\<CR>")
vim.feedkeys("<CR>")
vim.feedkeys("\<CR\>")
vim.call("feedkeys", "\<CR>")
vim.call("feedkeys", '"\<CR>"')
All of these were interpreted literally. I want to do something like
vim.feedkeys("\<F5>") etc. Any ideas?
This isn't ideal, but it solves my issue well enough:
vim.command('call feedkeys("\<F5>")')
In case this is useful to anyone, I've written a general function that will handle the \<> escapes as well as double-quotes:
def fkeys(text):
firstsub = True
for sub in text.split('"'):
if firstsub:
firstsub = False
else:
vim.feedkeys('"')
vim.command(f'call feedkeys("{sub}")')
Sorry for being Captain Obvious, but it doesn't work, because Python is not VimScript.
See :h nvim_replace_termcodes() and :h nvim_feedkeys() for a complete example. In case of <CR>, simply byte value of 13 will do.
You don't, because the interpretation of something like "\<CR>" is a function of VimL string literals. In other words, feedkeys("\<CR>") is the same thing as (probably) feedkeys("\x0d") — the function doesn't see the difference, the interpretation happens at a source code level. Naturally, Python doesn't have the same feature in the same way.
If you don't want to figure out what the escape sequence is for F5 and code it into your Python script, perhaps you could use vim.eval() to eval a VimL expression, e.g. vim.eval(r'feedkeys("\<F5>")').
This my first question here so let me know if I'm doing something wrong.
I've just gotten into python, and I'm running into an issue with ampersands and upper(). That works just fine:
print("a&a".upper())
> A&A
However, when taking a string out from a list of strings, and then running .upper(), the above will turn to A & A. & has a semicolon following it, but I could not include it or the whole thing would have been replaced by an &. I'm not sure why this is happening sometimes and and not other times. I've even tried using str() to make sure that what was coming out of the list was a string.
You could just run the following:
["a&a"][0].upper().replace("&", "&")
The reason is most likely because Python is somehow doing a replacement of & but not & because of the case-sensitivity.
I'm scraping a set of originally pdf files, using Python. Having gotten them to text, I had a lot of trouble getting the line endings out. I couldn't figure out what the line separator was. The trouble is, I still don't know.
It's not a '\n', or, I don't think, '\r\n'. However, I've managed to isolate one of these special characters. I literally have it in memory, and by doing a call to my_str.replace(eol, ''), I can remove all of these characters from one of my files.
So my question is open-ended. I'm a bit lost when it comes to unicode and such. How can I identify this character in my files without resorting to something ridiculous, like serializing it and then reading it in? Is there a way I can refer to it as a code, perhaps? I can't get Python to yield what it actually IS. All I ever see if I print it, or call unicode(special_eol) is the character in its functional usage as a newline.
Please help! Thanks, and sorry if I'm missing something obvious.
To determine what specific character that is, you can use str.encode('unicode_escape') or repr() to get (in Python 2) a ASCII-printable representation of the character:
>>> print u'☃'.encode('unicode_escape')
\u2603
>>> print repr(u'☃')
u'\u2603'
I'm trying to find a way to print a string in raw form from a variable. For instance, if I add an environment variable to Windows for a path, which might look like 'C:\\Windows\Users\alexb\', I know I can do:
print(r'C:\\Windows\Users\alexb\')
But I cant put an r in front of a variable.... for instance:
test = 'C:\\Windows\Users\alexb\'
print(rtest)
Clearly would just try to print rtest.
I also know there's
test = 'C:\\Windows\Users\alexb\'
print(repr(test))
But this returns 'C:\\Windows\\Users\x07lexb'
as does
test = 'C:\\Windows\Users\alexb\'
print(test.encode('string-escape'))
So I'm wondering if there's any elegant way to make a variable holding that path print RAW, still using test? It would be nice if it was just
print(raw(test))
But its not
I had a similar problem and stumbled upon this question, and know thanks to Nick Olson-Harris' answer that the solution lies with changing the string.
Two ways of solving it:
Get the path you want using native python functions, e.g.:
test = os.getcwd() # In case the path in question is your current directory
print(repr(test))
This makes it platform independent and it now works with .encode. If this is an option for you, it's the more elegant solution.
If your string is not a path, define it in a way compatible with python strings, in this case by escaping your backslashes:
test = 'C:\\Windows\\Users\\alexb\\'
print(repr(test))
In general, to make a raw string out of a string variable, I use this:
string = "C:\\Windows\Users\alexb"
raw_string = r"{}".format(string)
output:
'C:\\\\Windows\\Users\\alexb'
You can't turn an existing string "raw". The r prefix on literals is understood by the parser; it tells it to ignore escape sequences in the string. However, once a string literal has been parsed, there's no difference between a raw string and a "regular" one. If you have a string that contains a newline, for instance, there's no way to tell at runtime whether that newline came from the escape sequence \n, from a literal newline in a triple-quoted string (perhaps even a raw one!), from calling chr(10), by reading it from a file, or whatever else you might be able to come up with. The actual string object constructed from any of those methods looks the same.
I know i'm too late for the answer but for people reading this I found a much easier way for doing it
myVariable = 'This string is supposed to be raw \'
print(r'%s' %myVariable)
try this. Based on what type of output you want. sometime you may not need single quote around printed string.
test = "qweqwe\n1212as\t121\\2asas"
print(repr(test)) # output: 'qweqwe\n1212as\t121\\2asas'
print( repr(test).strip("'")) # output: qweqwe\n1212as\t121\\2asas
Get rid of the escape characters before storing or manipulating the raw string:
You could change any backslashes of the path '\' to forward slashes '/' before storing them in a variable. The forward slashes don't need to be escaped:
>>> mypath = os.getcwd().replace('\\','/')
>>> os.path.exists(mypath)
True
>>>
Just simply use r'string'. Hope this will help you as I see you haven't got your expected answer yet:
test = 'C:\\Windows\Users\alexb\'
rawtest = r'%s' %test
I have my variable assigned to big complex pattern string for using with re module and it is concatenated with few other strings and in the end I want to print it then copy and check on regex101.com.
But when I print it in the interactive mode I get double slash - '\\w'
as #Jimmynoarms said:
The Solution for python 3x:
print(r'%s' % your_variable_pattern_str)
Your particular string won't work as typed because of the escape characters at the end \", won't allow it to close on the quotation.
Maybe I'm just wrong on that one because I'm still very new to python so if so please correct me but, changing it slightly to adjust for that, the repr() function will do the job of reproducing any string stored in a variable as a raw string.
You can do it two ways:
>>>print("C:\\Windows\Users\alexb\\")
C:\Windows\Users\alexb\
>>>print(r"C:\\Windows\Users\alexb\\")
C:\\Windows\Users\alexb\\
Store it in a variable:
test = "C:\\Windows\Users\alexb\\"
Use repr():
>>>print(repr(test))
'C:\\Windows\Users\alexb\\'
or string replacement with %r
print("%r" %test)
'C:\\Windows\Users\alexb\\'
The string will be reproduced with single quotes though so you would need to strip those off afterwards.
To turn a variable to raw str, just use
rf"{var}"
r is raw and f is f-str; put them together and boom it works.
Replace back-slash with forward-slash using one of the below:
re.sub(r"\", "/", x)
re.sub(r"\", "/", x)
This does the trick
>>> repr(string)[1:-1]
Here is the proof
>>> repr("\n")[1:-1] == r"\n"
True
And it can be easily extrapolated into a function if need be
>>> raw = lambda string: repr(string)[1:-1]
>>> raw("\n")
'\\n'
i wrote a small function.. but works for me
def conv(strng):
k=strng
k=k.replace('\a','\\a')
k=k.replace('\b','\\b')
k=k.replace('\f','\\f')
k=k.replace('\n','\\n')
k=k.replace('\r','\\r')
k=k.replace('\t','\\t')
k=k.replace('\v','\\v')
return k
Here is a straightforward solution.
address = 'C:\Windows\Users\local'
directory ="r'"+ address +"'"
print(directory)
"r'C:\\Windows\\Users\\local'"