We Keep Coding

How to convert dict value into readable CSV file?

How to convert dict value into readable CSV file? I already tried to write it, but not success.
Original value:
[328900559584, 185455615753, 296889631456]
I want to make my file look like this:
328900559584
185455615753
296889631456
My code:
with open('cluster1.csv', 'w') as f:
[f.write('{0},{1}\n'.format(key, value)) for key, value in my_dict.items()]

Noting that you're using a list instead of a dict:
my_lines = [328900559584, 185455615753, 296889631456]
with open('cluster1.csv', 'w') as f:
for line in my_lines:
f.write(str(line) + '\n')

You can do it like this:
import os
list = [328900559584, 185455615753, 296889631456]
with open('cluster1.csv', 'w') as f:
[f.write(str(n) + os.linesep) for n in list]
Using os.linesep is a good idea, because that will use the right line separator for your system ("\n" or "\n\r" etc).

Getting Value error when reading file into a dictionary using python

I'm trying to read a file into a dictionary so that the key is the word and the value is the number of occurrences of the word. I have something that should work, but when I run it, it gives me a
ValueError: I/O operation on closed file.
This is what I have right now:
try:
f = open('fileText.txt', 'r+')
except:
f = open('fileText.txt', 'a')
def read_dictionary(fileName):
dict_word = {} #### creates empty dictionary
file = f.read()
file = file.replace('\n', ' ').rstrip()
words = file.split(' ')
f.close()
for x in words:
if x not in result:
dict_word[x] = 1
else:
dict_word[x] += 1
print(dict_word)
print read_dictionary(f)

It is because file was opened in write mode. Write mode is not readable.
Try this:
with open('fileText.txt', 'r') as f:
file = f.read()

Use a context manager to avoid manually keeping track of which files are open. Additionally, you had some mistakes involving using the wrong variable name. I've used a defaultdict below to simplify the code, but it isn't really necessary.
from collections import defaultdict
def read_dict(filename):
with open(filename) as f:
d = defaultdict(int)
words = f.read().split() #splits on both spaces and newlines by default
for word in words:
d[word] += 1
return d

Import dictionary from txt file

I have a function CalcPearson that needs 2 dictionaries as input. The dictionaries are in txt files in the following format:
(22, 0.4271125909116274)
(14, 0.4212051728881959)
(3, 0.4144765342960289)
(26, 0.41114433561925906)
(39, 0.41043882384484764)
.....
How can I import the data from the files as dictionaries? Do I need to modify them or there is a simple function for this?
I tried with this code:
inf = open('Route_cc.txt','r')
inf2 = open('Route_h2.txt','r')
d1 = eval(inf.read())
d2 = eval(inf2.read())
print(calcPearson(d1,d2))
inf.close()
But I got an invalid syntax error at the second row of the first file that the code opened so I think I need a particular syntax in the file.

If you're certain that you are looking for a dictionary, you can use something like this:
inf = open('Route_cc.txt', 'r')
content = inf.read().splitlines()
for line in range(content):
content[line] = content[line].strip('(').strip(')')
content[line] = content[line].split(', ')
inf_dict = dict(content)
Or more condensed:
inf = open('Route_cc.txt', 'r')
content = inf.read().splitlines()
inf_dict = dict(i.strip('(').strip(')').split(', ') for i in content)
Another option:
import re
inf = open('Route_cc.txt', 'r')
content = inf.read()
inf_dict = dict(i.split(', ') for i in re.findall("[^()\n-]+", content))
Note: Your original use of eval is unsafe and a poor practice.

Since you've mentioned that your dictionaries are in txt files, you'll have to tokenize your input by splitting into key/value pairs.
Read the file, line by line.
Remove the leading and trailing braces.
Split the stripped line using a comma as a delimiter.
Add each line to your dictionary.
I've written this code, and tested it for the sample input you have given. Have a look.
import collections
def addToDictionary(dict, key, value):
if key in dict:
print("Key already exists")
else:
dict[key] = value
def displayDictionary(dict):
dict = collections.OrderedDict(sorted(dict.items()))
for k, v in dict.items():
print(k, v)
filename = "dictionary1.txt"
f = open(filename, 'r')
dict1 = {}
for line in f:
line = line.lstrip('(')
line = line.rstrip(')\n')
tokenizedLine = line.split(', ')
addToDictionary(dict1, tokenizedLine[0], tokenizedLine[1])
displayDictionary(dict1)

Don't use eval it is dangerous (see the dangers of eval). Instead, use ast.literal_eval.
You can't create a dictionary directly from an input as you have given it. You have to go through the lines, one by one, convert them into a zip object and add it to a dictionary.
This process is shown below.
Code:
import ast
inf = open('Route_cc.txt','r')
d1 = {}
for line in inf:
zipi = ast.literal_eval(line)
d1[zipi[0]] = zipi[1]
inf2 = open('Route_h2.txt','r')
d2 = {}
for line1 in inf2:
zipi1 = ast.literal_eval(line1)
d2[zipi1[0]] = zipi1[1]
print(calcPearson(d1, d2))
inf.close()
inf2.close()

How to save a dictionary to a file?

I have problem with changing a dict value and saving the dict to a text file (the format must be same), I only want to change the member_phone field.
My text file is the following format:
memberID:member_name:member_email:member_phone
and I split the text file with:
mdict={}
for line in file:
x=line.split(':')
a=x[0]
b=x[1]
c=x[2]
d=x[3]
e=b+':'+c+':'+d
mdict[a]=e
When I try change the member_phone stored in d, the value has changed not flow by the key,
def change(mdict,b,c,d,e):
a=input('ID')
if a in mdict:
d= str(input('phone'))
mdict[a]=b+':'+c+':'+d
else:
print('not')
and how to save the dict to a text file with same format?

Python has the pickle module just for this kind of thing.
These functions are all that you need for saving and loading almost any object:
import pickle
with open('saved_dictionary.pkl', 'wb') as f:
pickle.dump(dictionary, f)
with open('saved_dictionary.pkl', 'rb') as f:
loaded_dict = pickle.load(f)
In order to save collections of Python there is the shelve module.

Pickle is probably the best option, but in case anyone wonders how to save and load a dictionary to a file using NumPy:
import numpy as np
# Save
dictionary = {'hello':'world'}
np.save('my_file.npy', dictionary)
# Load
read_dictionary = np.load('my_file.npy',allow_pickle='TRUE').item()
print(read_dictionary['hello']) # displays "world"
FYI: NPY file viewer

We can also use the json module in the case when dictionaries or some other data can be easily mapped to JSON format.
import json
# Serialize data into file:
json.dump( data, open( "file_name.json", 'w' ) )
# Read data from file:
data = json.load( open( "file_name.json" ) )
This solution brings many benefits, eg works for Python 2.x and Python 3.x in an unchanged form and in addition, data saved in JSON format can be easily transferred between many different platforms or programs. This data are also human-readable.

Save and load dict to file:
def save_dict_to_file(dic):
f = open('dict.txt','w')
f.write(str(dic))
f.close()
def load_dict_from_file():
f = open('dict.txt','r')
data=f.read()
f.close()
return eval(data)

As Pickle has some security concerns and is slow (source), I would go for JSON, as it is fast, built-in, human-readable, and interchangeable:
import json
data = {'another_dict': {'a': 0, 'b': 1}, 'a_list': [0, 1, 2, 3]}
# e.g. file = './data.json'
with open(file, 'w') as f:
json.dump(data, f)
Reading is similar easy:
with open(file, 'r') as f:
data = json.load(f)
This is similar to this answer, but implements the file handling correctly.
If the performance improvement is still not enough, I highly recommend orjson, fast, correct JSON library for Python build upon Rust.

I'm not sure what your first question is, but if you want to save a dictionary to file you should use the json library. Look up the documentation of the loads and puts functions.

I would suggest saving your data using the JSON format instead of pickle format as JSON's files are human-readable which makes your debugging easier since your data is small. JSON files are also used by other programs to read and write data. You can read more about it here
You'll need to install the JSON module, you can do so with pip:
pip install json
# To save the dictionary into a file:
json.dump( data, open( "myfile.json", 'w' ) )
This creates a json file with the name myfile.
# To read data from file:
data = json.load( open( "myfile.json" ) )
This reads and stores the myfile.json data in a data object.

For a dictionary of strings such as the one you're dealing with, it could be done using only Python's built-in text processing capabilities.
(Note this wouldn't work if the values are something else.)
with open('members.txt') as file:
mdict={}
for line in file:
a, b, c, d = line.strip().split(':')
mdict[a] = b + ':' + c + ':' + d
a = input('ID: ')
if a not in mdict:
print('ID {} not found'.format(a))
else:
b, c, d = mdict[a].split(':')
d = input('phone: ')
mdict[a] = b + ':' + c + ':' + d # update entry
with open('members.txt', 'w') as file: # rewrite file
for id, values in mdict.items():
file.write(':'.join([id] + values.split(':')) + '\n')

I like using the pretty print module to store the dict in a very user-friendly readable form:
import pprint
def store_dict(fname, dic):
with open(fname, "w") as f:
f.write(pprint.pformat(dic, indent=4, sort_dicts=False))
# note some of the defaults are: indent=1, sort_dicts=True
Then, when recovering, read in the text file and eval() it to turn the string back into a dict:
def load_file(fname):
try:
with open(fname, "r") as f:
dic = eval(f.read())
except:
dic = {}
return dic

Unless you really want to keep the dictionary, I think the best solution is to use the csv Python module to read the file.
Then, you get rows of data and you can change member_phone or whatever you want ;
finally, you can use the csv module again to save the file in the same format
as you opened it.
Code for reading:
import csv
with open("my_input_file.txt", "r") as f:
reader = csv.reader(f, delimiter=":")
lines = list(reader)
Code for writing:
with open("my_output_file.txt", "w") as f:
writer = csv.writer(f, delimiter=":")
writer.writerows(lines)
Of course, you need to adapt your change() function:
def change(lines):
a = input('ID')
for line in lines:
if line[0] == a:
d=str(input("phone"))
line[3]=d
break
else:
print "not"

I haven't timed it but I bet h5 is faster than pickle; the filesize with compression is almost certainly smaller.
import deepdish as dd
dd.io.save(filename, {'dict1': dict1, 'dict2': dict2}, compression=('blosc', 9))

file_name = open("data.json", "w")
json.dump(test_response, file_name)
file_name.close()
or use context manager, which is better:
with open("data.json", "w") as file_name:
json.dump(test_response, file_name)

Writing a dict to txt file and reading it back?

I am trying to write a dictionary to a txt file. Then read the dict values by typing the keys with raw_input. I feel like I am just missing one step but I have been looking for a while now.
I get this error
File "name.py", line 24, in reading
print whip[name]
TypeError: string indices must be integers, not str
My code:
#!/usr/bin/env python
from sys import exit
class Person(object):
def __init__(self):
self.name = ""
self.address = ""
self.phone = ""
self.age = ""
self.whip = {}
def writing(self):
self.whip[p.name] = p.age, p.address, p.phone
target = open('deed.txt', 'a')
target.write(str(self.whip))
print self.whip
def reading(self):
self.whip = open('deed.txt', 'r').read()
name = raw_input("> ")
if name in self.whip:
print self.whip[name]
p = Person()
while True:
print "Type:\n\t*read to read data base\n\t*write to write to data base\n\t*exit to exit"
action = raw_input("\n> ")
if "write" in action:
p.name = raw_input("Name?\n> ")
p.phone = raw_input("Phone Number?\n> ")
p.age = raw_input("Age?\n> ")
p.address = raw_input("Address?\n>")
p.writing()
elif "read" in action:
p.reading()
elif "exit" in action:
exit(0)

Have you tried the json module? JSON format is very similar to python dictionary. And it's human readable/writable:
>>> import json
>>> d = {"one":1, "two":2}
>>> json.dump(d, open("text.txt",'w'))
This code dumps to a text file
$ cat text.txt
{"two": 2, "one": 1}
Also you can load from a JSON file:
>>> d2 = json.load(open("text.txt"))
>>> print d2
{u'two': 2, u'one': 1}

Your code is almost right! You are right, you are just missing one step. When you read in the file, you are reading it as a string; but you want to turn the string back into a dictionary.
The error message you saw was because self.whip was a string, not a dictionary. So you need to convert the string to a dictionary.
Example
Here is the simplest way: feed the string into eval(). Like so:
def reading(self):
s = open('deed.txt', 'r').read()
self.whip = eval(s)
You can do it in one line, but I think it looks messy this way:
def reading(self):
self.whip = eval(open('deed.txt', 'r').read())
But eval() is sometimes not recommended. The problem is that eval() will evaluate any string, and if someone tricked you into running a really tricky string, something bad might happen. In this case, you are just running eval() on your own file, so it should be okay.
But because eval() is useful, someone made an alternative to it that is safer. This is called literal_eval and you get it from a Python module called ast.
import ast
def reading(self):
s = open('deed.txt', 'r').read()
self.whip = ast.literal_eval(s)
ast.literal_eval() will only evaluate strings that turn into the basic Python types, so there is no way that a tricky string can do something bad on your computer.
EDIT
Actually, best practice in Python is to use a with statement to make sure the file gets properly closed. Rewriting the above to use a with statement:
import ast
def reading(self):
with open('deed.txt', 'r') as f:
s = f.read()
self.whip = ast.literal_eval(s)
In the most popular Python, known as "CPython", you usually don't need the with statement as the built-in "garbage collection" features will figure out that you are done with the file and will close it for you. But other Python implementations, like "Jython" (Python for the Java VM) or "PyPy" (a really cool experimental system with just-in-time code optimization) might not figure out to close the file for you. It's good to get in the habit of using with, and I think it makes the code pretty easy to understand.

To store Python objects in files, use the pickle module:
import pickle
a = {
'a': 1,
'b': 2
}
with open('file.txt', 'wb') as handle:
pickle.dump(a, handle)
with open('file.txt', 'rb') as handle:
b = pickle.loads(handle.read())
print a == b # True
Notice that I never set b = a, but instead pickled a to a file and then unpickled it into b.
As for your error:
self.whip = open('deed.txt', 'r').read()
self.whip was a dictionary object. deed.txt contains text, so when you load the contents of deed.txt into self.whip, self.whip becomes the string representation of itself.
You'd probably want to evaluate the string back into a Python object:
self.whip = eval(open('deed.txt', 'r').read())
Notice how eval sounds like evil. That's intentional. Use the pickle module instead.

Hi there is a way to write and read the dictionary to file you can turn your dictionary to JSON format and read and write quickly just do this :
To write your date:
import json
your_dictionary = {"some_date" : "date"}
f = open('destFile.txt', 'w+')
f.write(json.dumps(your_dictionary))
and to read your data:
import json
f = open('destFile.txt', 'r')
your_dictionary = json.loads(f.read())

I created my own functions which work really nicely:
def writeDict(dict, filename, sep):
with open(filename, "a") as f:
for i in dict.keys():
f.write(i + " " + sep.join([str(x) for x in dict[i]]) + "\n")
It will store the keyname first, followed by all values. Note that in this case my dict contains integers so that's why it converts to int. This is most likely the part you need to change for your situation.
def readDict(filename, sep):
with open(filename, "r") as f:
dict = {}
for line in f:
values = line.split(sep)
dict[values[0]] = {int(x) for x in values[1:len(values)]}
return(dict)

You can iterate through the key-value pair and write it into file
pair = {'name': name,'location': location}
with open('F:\\twitter.json', 'a') as f:
f.writelines('{}:{}'.format(k,v) for k, v in pair.items())
f.write('\n')