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Reverse for 'surveydetails' not found. 'surveydetails' is not a valid view function or pattern name

I've been stuck on this for a while, can't seem to fix the error. I've checked the code a hundred times but obviously there is something I'm missing. I have installed my app also.
Can anybody see what I'm missing?
views.py
def survey_details(request, id=None):
context = {}
surveys = Survey.objects.get(id=id)
context['survey'] = survey
return render(request, 'surveydetails.html', context)
feedback.urls.py
path('details/<int:id>', views.survey_details, name="surveydetails"),
surveys.html
{% extends 'main.html' %}
{% block content%}
<h1>Surveys</h1>
<h2>list of {{title}} </h2>
{% if surveys %}
<ul>
{% for survey in surveys %}
<li>
{{ survey.title }}
</li>
{% endfor %}
</ul>
{% else %}
<p>There are no surveys.</p>
{% endif %}
{% endblock %}
surveydetails.html
{% extends 'main.html' %}
{% block content%}
<h1>Surveys</h1>
<h2>Detail page</h2>
<h3>{{question.title}}</h3>
<p>Details page of {{question.title}}</p>
{% endblock %}

Here you are not passing the survey id.
{% for survey in surveys %}
<li>
{{ survey.title }}
</li>
{% endfor %}

Django pagination - for loop in all pages

I have a list of objects that I would like to display in an ul/li. For that I do the code below:
<ul id="myUL">
{% for l in lpps %}
<li id="lpps">{{ l.codeACL }} {{ l.libelle }}</li>
{% endfor %}
</ul>
The problem is that in my view, I ask to display only 15 objects per page.
But I want to ignore this and display all the objects on all the pages.
Is there something like for l in lpps.page(all)...?

django have forloop.counter ,
you can use that like
<ul id="myUL">
{% for l in lpps %}
{% if forloop.counter == 15 %}{% break %}{% endif %}
<li id="lpps">{{ l.codeACL }} {{ l.libelle }}</li>
{% endfor %}
</ul>

Django template loop

debug is answering me that there is any if without endif tag.
{% for j in content.numpaginas %}
{% if j == content.actpag %}
<li class="active blue-grey"></li>
{% else %}
<li class="waves-effect"></li>
{% endif %}
{% endfor }

replace = with ==
{% if j == content.actpag %}

Django also have {% ifequal foo bar %} tag.
See here.

Error in the template with Django : can I make arithmetic in if statement

I would like to make a pagination with Bootstrap : a new page every 10 new field in data.
file.html
{% for d in data %}
{% if forloop.first %}
<ul class="pagination">
{% endif %}
{% if (forloop.counter % 10) == 0 %}
<li>{{ forloop.counter % 10 }}</li>
{% endif %}
{% if forloop.last %}
</ul>
{% endif %}
{% endfor %}
output I would like that => Bootstrap pagination
But Django give me an error for this :
{% if (forloop.counter % 10) == 0 %}
TemplateSyntaxError :/
I don't know how to do except create my own filter or add a filter, but i would like to know first if i can do in the template first.
PS: I use Django 1.5 and I can't upgrade it.
Edit:
Finally I use this condition:
{% if forloop.counter|divisibleby:'10' and forloop.counter|divisibleby:'5' and forloop.counter|divisibleby:'2' %}
Like that I know when I have a 10 multiple.

The modulus (%) operator is not available in django templates. However, you can use the divisibleby (https://docs.djangoproject.com/en/1.5/ref/templates/builtins/#divisibleby) template filter, something like
{% if forloop.counter|divisibleby:"2" %}

Use the paginator, your QuerySet are not evaluated for the hole table, just the number you need to build the page, and it offers properties that you can use in the template like (page_range, next_page_number, has_next, etc.)
here is the code withe BootStrap 2 and django.core.paginator:
<div class="pagination pagination-centered">
<ul>
{% if MYDATAENTIRES.has_previous %}
<li>
{% trans "Précédent" %}
</li>
{% endif %}
{% for i in MYDATAENTIRES.paginator.page_range %}
<li {% ifequal MYDATAENTIRES.number i %} {{ 'class="disabled"' }} {% endifequal %}>
<a href="?page={{ i }}">
{{ i }}
</a>
</li>
{% endfor %}
{% if MYDATAENTIRES.has_next %}
<li>
{% trans "Suivant" %}
</li>
{% endif %}
</ul>
</div>

Pagination problem with Django haystack

i'm using django-haystack with simple engine, the search is fine, but the pagination is not working. This is the code of my search results template
{% if query %}
<br>
<div id="contenido_pagina">
{% for result in page.object_list %}
{% if result.object.get_model == '[Video] ' %}
{% if result.object.publicar %}
<div class="salida_search">
{{result.object.get_model}}{{result.object.nombre}}<br>
<div class="resumen_search">
{{result.object.sinopsis|safe|truncatewords:"30"}}
</div>
<div class="link_search">
{{result.object.anio}}
</div>
</div>
{% endif %}
{% else %}
<div class="salida_search">
{{result.object.get_model}}{{result.object.titulo}}<br>
<div class="resumen_search">
{% if result.object.contenido %}
{{result.object.contenido|safe|truncatewords:"30"}}
{% else %}
{{result.object.sinopsis|safe|truncatewords:"30"}}
{% endif %}
</div>
<div class="link_search">
{{result.object.fecha|date:"d M Y"}}
</div>
</div>
{% endif %}
{% empty %}
<div>La busqueda <span class="highlighted">{{query}}</span> no obtuvo ningun resultado</div>
{% endfor %}
{% if page.has_previous or page.has_next %}
<div>
{% if page.has_previous %}{% endif %}« Anterior{% if page.has_previous %}{% endif %}
|
{% if page.has_next %}{% endif %}Siguiente »{% if page.has_next %}{% endif %}
</div>
{% endif %}
</div>
<br>
{% else %}
{# Show some example queries to run, maybe query syntax, something else? #}
{% endif %}
when i go to the next page i see the same objects that first page. What i am doing wrong??

I had this issue as well. From debugging the code it looks like it's an issue with the paginator and the searchqueryset. Unfortunately i didn't have more time to devote to it and ended up moving on to whoosh for development environment.

Just encountered this. Seems as though it's a known limitation of the simple backend.
https://github.com/toastdriven/django-haystack/issues/320