I'm having issues with Python finding an available Executable on my Linux machine. My default PATH includes this Executable (svnlook) but when I run the python script the below function fails to find executable. Any ideas on how to fix this?
def command_output(cmd):
child = subprocess.Popen(cmd.split(), stdout=subprocess.PIPE)
output = child.communicate()[0]
return output, child.returncode
def get_author():
cmd = "svnlook author %s %s %s" % (svn_opt, svn_txn, svn_repo)
author, return_code = command_output(cmd)
return author.strip()
Error:
Traceback (most recent call last):
File "/home/user/app/csvn/data/repositories/repo/hooks/pre-commit", line 82, in <module>
author = get_author()
File "/home/user/app/csvn/data/repositories/repo/hooks/pre-commit", line 53, in get_author
author, return_code = command_output(cmd)
File "/home/user/app/csvn/data/repositories/repo/hooks/pre-commit", line 36, in command_output
child = subprocess.Popen(cmd.split(), stdout=subprocess.PIPE)
File "/home/user/app/activepython-2.7.2.5_x86_64/lib/python2.7/subprocess.py", line 679, in __init__
errread, errwrite)
File "/home/user/app/activepython-2.7.2.5_x86_64/lib/python2.7/subprocess.py", line 1228, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
Error: [Errno 2] No such file or directory
You probably want to provide the full path to the executable, e.g. /usr/bin/svnlook or /usr/local/bin/svnlook instead of just svnlook.
See this answer to a related question for details.
Try running it from the console. Make sure the permissions/executability is correct. Try os.system().
Related
While coding an os extension with the “subprocesses” package, the FileNotFoundError seems to be re-occuring.
My code:
perm = “filename1 filename2”
subprocess.run(‘ren’, perm)
This returns the error:
Traceback (most recent call last):
File "main.py", line 46, in <module>
listeningfunc()
File "main.py", line 37, in listeningfunc
mv(listening.split(' ', 1)[1])
File "main.py", line 16, in mv
subprocess.run(['ren', perm])#, cwd=(os.getcwd()), stdout=subprocess.PIPE, stderr=subprocess.PIPE, shell=True)
File "/nix/store/2vm88xw7513h9pyjyafw32cps51b0ia1-python3-3.8.12/lib/python3.8/subprocess.py", line 493, in run
with Popen(*popenargs, **kwargs) as process:
File "/nix/store/2vm88xw7513h9pyjyafw32cps51b0ia1-python3-3.8.12/lib/python3.8/subprocess.py", line 858, in __init__
self._execute_child(args, executable, preexec_fn, close_fds,
File "/nix/store/2vm88xw7513h9pyjyafw32cps51b0ia1-python3-3.8.12/lib/python3.8/subprocess.py", line 1704, in _execute_child
raise child_exception_type(errno_num, err_msg, err_filename)
FileNotFoundError: [Errno 2] No such file or directory: 'ren‘
I tried using
subprocess.run([’ren’, perm], cwd=(os.getcwd()), stdout=subprocess.PIPE, stderr=subprocess.PIPE, shell=True)
which seemed to resolve the issue (removes the error) but the function does not run. Can anyone help me with this? I’ve noticed that the package os also has similar issues.
Using OS package does not result in an error, but results in:
sh: 1: ren: not found
That's because ren is a cmd built-in. Several options:
perm = “filename1 filename2”
subprocess.run(‘ren’, perm, shell=True)
or prepend with cmd /c
perm = “filename1 filename2”
subprocess.run(['cmd','/c',‘ren’, "filename1","filename2"])
or way better: use native os functions as it's not worth to call ren when you can call os.rename
os.rename("filename1","filename2")
another way with shutil
shutil.move('filename1','filename2')
In my program I call the command:
command_two = 'sfit4Layer0.py -bv5 -fs'
subprocess.call(command_two.split(), shell=False)
I am using PyCharm and I get the error message:
Traceback (most recent call last):
File "part2test.py", line 5, in <module>
subprocess.call(command_two.split(), shell=False) #writes the summary file
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 522, in call
return Popen(*popenargs, **kwargs).wait()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 710, in __init__
errread, errwrite)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 1335, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
When walking through my program, it never gets to the program I want it to sfit4Layer0.py, it is getting stuck in subprocess but I am not sure why. Changing the shell=True doesn't do anything helpful either - I don't get these error messages but it does not execute my code properly. Any suggestions would be helpful.
My bash profile:
PATH="~/bin:/usr/bin:${PATH}"
export PATH PYTHONPATH="/Users/nataliekille/Documents/sfit4/pbin/Layer0:/Users/nataliekille/Documents/sfit4/pbin/Layer1:/Users/nataliekille/Documents/sfit4/pbin/ModLib:/Users/nataliekille/Documents/sfit4/SpectralDB"
export PYTHONPATH
PATH=${PATH}:${PYTHONPATH}
export PATH
You've missed an important part of the subprocess documentation. "If passing a single string [at the command, rather than a list of strings], either shell must be True (see below) or else the string must simply name the program to be executed without specifying any arguments."
So the kernel is compaining because there is not executable with the name 'sfit4Layer0.py -bv5 -fs'. Should work if you replace the string with (for example) 'sfit4Layer0.py -bv5 -fs'.split(), or ['sfit4Layer0.py', '-bv5', '-fs'].
I am trying to execute a program with python using subprocess
The format our professor gave us was subprocess(path/executableProgram)
File: OS377.py
I am doing it as subprocess(['/home/Joseph/OS377.py']) but I am getting errors
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python3.2/subprocess.py", line 471, in call
return Popen(*popenargs, **kwargs).wait()
File "/usr/lib/python3.2/subprocess.py", line 745, in __init__
restore_signals, start_new_session)
File "/usr/lib/python3.2/subprocess.py", line 1361, in _execute_child
raise child_exception_type(errno_num, err_msg)
OSError: [Errno 8] Exec format error
I need to execute a file using this format but am unsure how to go about it
Code:
def RUN(file):
pid = os.fork() #pid is non-zero in the parent process and 0 in the child
if pid: #parent
os.waitpid(pid,0)
elif pid == 0: #child
print("path is : ")
child(file)
def child(file):
#path = os.path.abspath(file)
#print(path)
subprocess.call(os.path.abspath('OS377.py'))
subprocess.call(['python', os.path.abspath('OS377.py')].
The file you're calling, a python script, may not be marked as executable (chmod u+x file.py). Alternatively, you should probably be executing it with $ python file.py - which is calling the python interpreter and passing it the name of your script as the first argument. So you should put it as subprocess.call(['python', '/home/Joe/file.py'].
Btw, did you mean subprocess.call() instead of just subprocess()?
i have a code running on python 2.7.3 (windows) and i try to run it on python 2.7.8(windows) and get the following error:
main : INFO ** Starting Main **
Traceback (most recent call last):
File "C:\wamp\www\prenderer\src\main.py", line 82, in <module>
nuke_process = launch_nuke()
File "C:\wamp\www\prenderer\src\main.py", line 31, in launch_nuke
query = subprocess.Popen(r"query process", stdout=subprocess.PIPE)
File "F:\python27\lib\subprocess.py", line 710, in __init__
errread, errwrite)
File "F:\python27\lib\subprocess.py", line 958, in _execute_child
startupinfo)
WindowsError: [Error 2] The system cannot find the file specified
>>>
what is wrong?
Pass shell=True argument:
query = subprocess.Popen(r"query process", stdout=subprocess.PIPE, shell=True)
or pass the command line argument as a list:
query = subprocess.Popen(["query", "process"], stdout=subprocess.PIPE)
Otherwise query process is recognized as a program instead of query.
how can I open an java file in python?, i've search over the net and found this:
import os.path, subprocess
from subprocess import STDOUT, PIPE
def compile_java (java_file):
subprocess.check_call(['javac', java_file])
def execute_java (java_file):
cmd=['java', java_file]
proc=subprocess.Popen(cmd, stdout = PIPE, stderr = STDOUT)
input = subprocess.Popen(cmd, stdin = PIPE)
print(proc.stdout.read())
compile_java("CsMain.java")
execute_java("CsMain")
but then I got this error:
Traceback (most recent call last):
File "C:\Python33\lib\subprocess.py", line 1106, in _execute_child
startupinfo)
FileNotFoundError: [WinError 2] The system cannot find the file specified
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:\casestudy\opener.py", line 13, in <module>
compile_java("CsMain.java")
File "C:\casestudy\opener.py", line 5, in compile_java
subprocess.check_call(['javac', java_file])
File "C:\Python33\lib\subprocess.py", line 539, in check_call
retcode = call(*popenargs, **kwargs)
File "C:\Python33\lib\subprocess.py", line 520, in call
with Popen(*popenargs, **kwargs) as p:
File "C:\Python33\lib\subprocess.py", line 820, in __init__
restore_signals, start_new_session)
File "C:\Python33\lib\subprocess.py", line 1112, in _execute_child
raise WindowsError(*e.args)
FileNotFoundError: [WinError 2] The system cannot find the file specified
>>>
the python file and java file is in the same folder, and I am using Python 3.3.2, how can I resolve this? or do you guys have another way on doing this?, any answer is appreciated thanks!
I think it isn't recognizing the javac command. Try manually running the command and if javac isn't a recognized command, register it in your PATH variable and try again.
Or you could just try typing the full pathname to the Java directory for javac and java.
you need to add path to your java file name. like this:
compile_java("C:\\path\to\this\CsMain.java")