SQLAlchemy Many-to-many table with multiple foreign key entires - python

I'm new with sqlalchemy and I want to do this as simply as possible, yet correctly. I want to track domain use across multiple companies on a monthly basis, so I set up the following tables:
class Company(Base):
__tablename__ = 'company'
id = Column(Integer, primary_key = True)
name = Column('name', String)
class Domains(Base):
__tablename__ = 'domains'
id = Column(Integer, primary_key=True)
name = Column('name', String, unique=True)
class MonthlyUsage(Base):
'''
Track domain usage across all
companies on a monthly basis.
'''
__tablename__ = 'monthlyusage'
month = Column(DateTime)
company_id = Column(Integer, ForeignKey('company.id'))
domain_id = Column(Integer, ForeignKey('domains.id'))
# <...other columns snipped out...>
company = relationship('Company', backref='company_assoc')
domain = relationship('Domains', backref='domain_assoc')
This works fine, until I add usage details for the second month. Then I get duplicate key value errors:
*sqlalchemy.exc.IntegrityError: (IntegrityError) duplicate key value violates unique constraint "monthlyusage_pkey"*
Does this mean I have to split out the "monthlyusage" into a third table? That seems unnecessarily complicated, since all that needs to be unique is the month, company_id, and domain_id fields.
Any suggestions for my layout here, to keep it as simple as possible, yet still correct?
TIA!

Ok, I needed to add a primary key column to MonthlyUsage. The code below now works...
class MonthlyUsage(Base):
'''
Track domain usage across all
companies on a monthly basis.
'''
__tablename__ = 'monthlyusage'
month = Column(DateTime)
month_id = Column(Integer, primary_key=True)
company_id = Column(Integer, ForeignKey('company.id'), primary_key=True)
domain_id = Column(Integer, ForeignKey('domains.id'), primary_key=True)
# <...other columns snipped out...>
company = relationship('Company', backref='company_assoc')
domain = relationship('Domains', backref='domain_assoc')

Related

django query to get data

I am into a very confusing situation where I have one to many relation and I want to query data like I want all parent table data but want to get only data from child tables which fulfill condition of site_id = 100.
class Policy(Base):
"""table containing details for Policies"""
__tablename__ = "UmbrellaPolicy"
id = Column(Integer, primary_key=True)
policy_id = Column(Integer, nullable=False, index=True)
user_defined_name = Column(String(255), nullable=True)
and child is like this
class Site(Base):
__tablename__ = "Site"
id = Column(Integer, primary_key=True)
policy_id = Column(Integer, ForeignKey("Policy.id"))
site_id = Column(String(32), nullable=False, index=True)
policy = relationship("Policy", backref="sites")
You should be able to filter join relations like this
parents = Policy.objects.filter(site__site_id=100)
You can find more info about the Django query API here but its generally of the form where you reference the relation with classname__columnname there are many other ways to filter/query that you can reference in the docs

"has_many :through" construct in sqlalchemy

In rails we can simply define relationships with the has_many :through syntax in order to access 2nd, 3rd .. nth degree relations.
In SQLAlchemy however, this seems to be more difficult. I'm trying to avoid going down the route of writing joins, as I find them to be anti-patterns in trying to keep a clean code base.
My tables look like following:
class Message(db.Model):
__tablename__ = 'message'
id = db.Column(db.Integer, primary_key=True)
text = db.Column(db.String())
user_id = db.Column(db.ForeignKey("user.id"))
user = db.relationship('User', backref="messages")
class User(db.Model):
__tablename__ = 'user'
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String())
class Level(db.Model):
__tablename__ = 'level'
number = db.Column(db.Integer, nullable=False, primary_key=True)
name = db.Column(db.String(), nullable=False, primary_key=True)
users = db.relationship(
"User",
secondary="user_level",
backref="levels")
class UserLevel(db.Model):
__tablename__ = 'user_level'
user_id = db.Column(db.Integer, db.ForeignKey('user.id'), primary_key=True)
number = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(), primary_key=True)
__table_args__ = (
db.ForeignKeyConstraint(
['number', 'name'],
['level.number', 'level.name']
),
)
The idea is that a user can have multiple authorisation levels (e.g. a user can be at level 1, 3 and 6 at the same time). As the data I have does not contain unique sequence numbers for available levels, I had to resort to the use of composite keys to keep the data consistent with future updates.
To get all messages for a level I can currently do something like this:
users = Level.query[0].users
for user in users:
results.append(user.messages)
return results
This gives me all users on a level. But in order to get all messages for a certain level, I have to loop through these users and append them to a results list.
What I'd like to do is:
return Level.query[0].users.messages
This is more like the syntax I am used to from rails. How would one accomplish this in flask-SQLAlchemy?

Item and Category database relationship

So I would like to have users add an item and an arbitrary category. Right now I use if statements to make sure that if the category has been created already, not to add it again. Is there a better way to make use of SQLAlchemy relationships so that I could skip some of the logic I had to write to ensure that the categories are unique?
Here are the model's I used:
class Category(Base):
__tablename__ = 'category'
id = Column(Integer, primary_key=True)
name = Column(String(250), nullable=False)
class Item(Base):
__tablename__ = 'item'
id = Column(Integer, primary_key=True)
name = Column(String(250), nullable=False)
description = Column(String)
category_id = Column(Integer, ForeignKey('category.id'))
category = relationship(Category)
date_created = Column(DateTime)
date_updated = Column(DateTime)
user_id = Column(Integer, ForeignKey('user.id'))
user = relationship(User)
Here is an example of how I would edit an item:
if new_category_name != category.name:
if db_session.query(Category).\
filter_by(name=new_category_name).count() == 0:
new_category = Category(name=new_category_name)
else:
new_category = db_session.query(Category)\
.filter_by(name=new_category_name).one()
is_last_of_category = db_session.query(Item)\
.filter_by(category_id=item.category_id).count() == 1
if is_last_of_category:
db_session.delete(category)
item.category = new_category
db_session.commit()
Any other suggestions you are willing to make I am happy to listen to.
Use the unique constraint,
Quoting from sqlalchemy's docs
unique – When True, indicates that this column contains a unique
constraint, or if index is True as well, indicates that the Index
should be created with the unique flag. To specify multiple columns in
the constraint/index or to specify an explicit name, use the
UniqueConstraint or Index constructs explicitly.
Example from sqlalchemy documentation:
from sqlalchemy import UniqueConstraint
meta = MetaData()
mytable = Table('mytable', meta,
# per-column anonymous unique constraint
Column('col1', Integer, unique=True),
Column('col2', Integer),
Column('col3', Integer),
# explicit/composite unique constraint. 'name' is optional.
UniqueConstraint('col2', 'col3', name='uix_1')
)

SqlAlchemy Table and Query Issues

Still wrapping my head around SqlAlchemy and have run into a few issues. Not sure if it is because I am creating the relationships incorrectly, querying incorrect, or both.
The general idea is...
one-to-many from location to user (a location can have many users but users can only have one location).
many-to-many between group and user (a user can be a member of many groups and a group can have many members).
Same as #2 above for desc and user.
My tables are created as follows:
Base = declarative_base()
class Location(Base):
__tablename__ = 'location'
id = Column(Integer, primary_key=True)
name = Column(String)
group_user_association_table = Table('group_user_association_table', Base.metadata,
Column('group_id', Integer, ForeignKey('group.id')),
Column('user_id', Integer, ForeignKey('user.id')))
class Group(Base):
__tablename__ = 'group'
id = Column(Integer, primary_key=True)
name = Column(String)
users = relationship('User', secondary=group_user_association_table, backref='group')
desc_user_association_table = Table('desc_user_association', Base.metadata,
Column('desc_id', Integer, ForeignKey('desc.id')),
Column('user_id', Integer, ForeignKey('user.id')))
class Desc(Base):
__tablename__ = 'desc'
id = Column(Integer, primary_key=True)
name = Column(String)
users = relationship('User', secondary=desc_user_association_table, backref='desc')
class User(Base):
__tablename__ = 'user'
id = Column(Integer, primary_key=True)
user_name = Column(String)
location_id = Column(Integer, ForeignKey('location.id'))
groups = Column(String, ForeignKey('group.id'))
descs = Column(String, ForeignKey('desc.id'))
location = relationship('Location', backref='user')
Here are some examples as to how I am creating the data (all being scraped from the web):
location = Location(id=city[1], name=city[0]) #city = ('name', id)
profile = User()
profile.id = int(str(span2class[0].a['href'][7:]))
profile.user_name = str(span2class[0].a.img['alt'])
profile.location_id = location.id
g = Group(id=gid, name=str(group.contents[0])) # add the group to the Group table
self.db_session.add(g)
# Now add the gid to a list that will be added to the profile that eventually gets added to the user table
profile.groups.append(str(gid)) # stick the gid into the list
profile.groups = ','.join(profile.groups) # convert list to csv string
# Repeat basically same thing above for desc
self.db_session.add(profile)
self.db_session.commit()
As far as queries go, I've got some of the basic ones working such as:
for instance in db_session.query(User).all():
print instance.id, instance.user_name
But when it comes to performing a join to get (for example) group.id and group.name for a specific user.id... nothing I've tried has worked. I am guessing that the form would be something like the following:
db_session.query(User, Group).join('users').filter(User.id==42)
but that didn't work.
Joins works from left to right, so you should join on the relationship from User to Group:
db_session.query(User, Group).join(User.group).filter(User.id == 42)
But this return you a list of tuples (<User>, <Group>), so if the user belongs to 2 or more groups, you will receive 2 or more rows.
If you really want to load both the user and its groups in one (SQL) query, a better way would be to load a user, but configure query to preload groups:
u = (session.query(User)
.options(joinedload(User.group))
.get(42)
)
print("User = {}".format(u))
for g in u.group:
print(" Group = {}".format(g))

SqlAlchemy can't determine join condition

I have 2 tables defined:
class TCableSet(Base):
__tablename__ = 'tCableSet'
ixCableSet = Column(Integer, primary_key=True)
decCableSetOne = Column(Numeric(8, 2))
decCableSetTwo = Column(Numeric(8, 2))
decCableSetThree = Column(Numeric(8, 2))
class TStepVoltage(Base):
__tablename__ = 'tStepVoltage'
ixStepVoltage = Column(Integer, primary_key=True)
ixSubReport = Column(Integer, ForeignKey('tSubReport.ixSubReport'), nullable=False)
iVoltage = Column(Integer)
ixPhaseA = Column(Integer, ForeignKey('tCableSet.ixCableSet'), nullable=False)
ixPhaseB = Column(Integer, ForeignKey('tCableSet.ixCableSet'), nullable=False)
ixPhaseC = Column(Integer, ForeignKey('tCableSet.ixCableSet'), nullable=False)
sub_report = relationship('TSubReport',
backref=backref('step_voltage'))
I understand why I am getting this error but can't figure out a proper way (yet).
When the table gets saved, I store the values in the tCableSet table and then use the id as a foreign key in my tStepVoltage table. The problem I have is when I go to retrieve the data, I want to be able to get the values(tCableSet row) along with the rest of my tStepVoltage table via a relationship, however I'm not sure how to go about this since I don't have a field in my tCableSet that can directly be linked via relationship to my tStepVoltage. I basically just needed the tCableSet for normalization
Since you have more than one foreign key that points to the same table, you have to tell SQLAlchemy which foreign key to use.
For example:
sub_report_a = relationship('TSubReport',
backref=backref('step_voltage'),
foreign_keys=[ixPhaseA])

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