Django 1.5: Display foreignkey values in both admin models - python

I'm not sure that my title really made sense. Basically (from the code below), when I access the admin screen, I want a project to display with its client and a client to display all attached projects. Is there any way to do this?
class Client(models.Model):
title = models.CharField(max_length=250, null=True)
#project = models.ManyToManyField(Project)
#status = models.CharField(max_length=250)
class Project(models.Model):
project_choices = (
('L1', 'Lead'),
('C1', 'Confirmed'),
('P1', 'In Progress'),
('P1', 'Paid'),
)
title = models.CharField(verbose_name='Project Title', max_length=250, null=True)
client = models.ForeignKey(Client)
project_status = models.CharField(max_length=2,
choices=project_choices,
default='P1')
def __unicode__(self):
return self.title

I would suggest setting up a custom ModelAdmin and using the list_display to indicate which fields you want to show in the admin. It is fairly customizable, and you can add callables that could display exactly the info you indicate. An example ModelAdmin for the Client Model is below.
# project/app/admin.py
# Callable to add to ModelAdmin List Display
def show_client_projects(obj):
project_list = [p.title for p in obj.project_set.all()]
return ', '.join(project_list)
show_client_projects.short_description = 'Client Projects'
# Custom ModelAdmin
class ClientAdmin(admin.ModelAdmin):
list_display = ('title', 'show_client_projects')

You will need to create ModelAdmin classes for your models to define columns to display in the built-in Django admin:
https://docs.djangoproject.com/en/dev/ref/contrib/admin/
This is particularly relevant:
ManyToManyField fields aren’t supported, because that would entail executing a separate SQL statement for each row in the table. If you want to do this nonetheless, give your model a custom method, and add that method’s name to list_display. (See below for more on custom methods in list_display.)
So, you can create a method for your Client which loads up the Client's projects, and include that in the list_display.
Something like this should put you on the right track:
# In your models.py...
from django.contrib import admin
class Client(models.Model):
title = models.CharField(max_length=250, null=True)
def projects(self):
return Project.objects.filter(client=self)
class ClientAdmin(models.ModelAdmin):
list_display = ('title','projects',)
admin.site.register(Client,ClientAdmin)

Related

Show fields passing through a ManyToMany field django admin

I'm working on a project developed in Python 2.7 and Django 1.11.
I'm trying to show in admin page two fields passing through a ManyToMany field.
Here the models:
class ModelZero(Model):
# some fields
mtm_field = models.ManyToManyField(to="ModelOne", through="ModelTwo")
class ModelOne(Model):
# some fields
field_1_1 = models.CharField(unique=True, max_length=200)
field_1_2 = models.BooleanField(default=True)
class ModelTwo(Model):
# some fields
field_2_1 = models.ForeignKey('ModelOne', on_delete=models.CASCADE)
field_2_2 = models.BooleanField(default=True)
In the ModelZero admin page I want to show some fields from the ModelZero itself plus field_2_1 and field_2_2 from ModelTwo.
More in detail, the field_2_1 should be present using a custom widget.
Please note that ModelZeroAdmin is an inline ones.
Here the admin page:
class ModelZeroAdmin(DynamicRawIDMixin, admin.TabularInline):
model = ModelZero
fields = ('some', 'fields', 'field_2_2')
form = forms.ModelZeroForm
def field_2_2(self, obj):
return obj.mtm_field.through.field_2_2
Here the form:
class ModelZeroForm(ModelForm):
class Meta:
widgets = {
"mtm_field.through.field_2_1": dal.autocomplete.ModelSelect2Multiple(
url="my-autocomplete-url"
)
}
In this way i have two errors:
it's not possible add custom fields (field_2_2) in the fields tuple
custom widget is not showed
Is there a way to achieve this goal using this models structure?
I don't have experience with older Django version, but if I am not mistaken the syntax for a related field in admin interface would be something like :mtm_field__field_2_2.

Specific Queryset for Input on Django ModelAdmin Change Form

I've got a 'Registration' object in place that users can create on the front end without issue.
It looks like this:
class Registration(models.Model):
person = models.ForeignKey(Person, on_delete=models.PROTECT)
course_detail = models.ForeignKey(CourseDetail, on_delete=models.PROTECT)
camp_shirt = models.ForeignKey(CampShirt, on_delete=models.PROTECT)
comments = models.CharField(max_length=200, blank=True, null=True)
created_at = models.DateTimeField(auto_now_add=True)
updated_at = models.DateTimeField(auto_now=True)
def __str__(self):
return "%s" % (self.course_detail.course.camp)
When I am in the admin and click on a given Registration - it takes a while to load because there are thousands and thousands of Person objects.
For ease of use - there will never be a time when we would need to edit the 'person' associated with a given registration, so I would like to make the 'person' dropdown only show the selected user in the person queryset when editing from the django admin.
So when I go to http://myapp.com/admin/registration/23/change I want the form to only display the currently selected person as the only option in the dropdown.
My admin model looks like this:
class RegistrationAdmin(admin.ModelAdmin):
list_display = ("person", "course_detail")
class Meta:
# I think this is what I do in order to override the default admin form? Not sure.
form = RegistrationAdminForm
My RegistrationAdminForm looks like this:
class RegistrationAdminForm(forms.ModelForm):
# course_detail, person, camp_shirt, comments
person = forms.ModelChoiceField(queryset=Person.objects.filter(
id=registration.person.id)
)
def __init__(self, registration, *args, **kwargs):
super(RegistrationAdminForm, self).__init__(*args, **kwargs)
self.fields['person'].queryset = Person.objects.filter(
id=registration.person.id
)
class Meta:
model = Registration
fields = '__all__'
Main Question : How do I change the admin form so that a specific queryset is returned for one of the fields in the django admin?
If the person field will never be changed you can add the person field to readonly_fields, a select with all Person objects will not be rendered.
class RegistrationAdmin(admin.ModelAdmin):
list_display = ("person", "course_detail")
readonly_fields = ("person", )
Then you do not need your custom form. FYI when you want to add a custom form to a ModelAdmin you do not put it in Meta, you define it on the form itself
class MyModelAdmin(admin.ModelAdmin):
form = MyModelForm

manytomany field not working django-cms

I am using django-cms
many to many field is working fine when i add plugins or update but
after publish page i didn't get any data where i add many to many field.
models are look like this
#python_2_unicode_compatible
class ClientLogo(CMSPlugin):
client_logo = models.ManyToManyField(LogoPluginModel, blank=True)
class LogoPluginModel(CMSPlugin):
title = models.CharField(max_length=100)
here field 'client_logo' will be disapper when i publish djagno-cms page
The relations need to be explicitly copied through the copy_relations method (see django-cms models manual). It's also advantageous to add a related_name property to the ManyToManyField, especially when a model contains multiple sets of foreign keys or ManyToManyFields.
#python_2_unicode_compatible
class ClientLogo(CMSPlugin):
client_logo = models.ManyToManyField(
LogoPluginModel,
blank=True,
related_name='client_logos',
)
class LogoPluginModel(CMSPlugin):
title = models.CharField(max_length=100)
def copy_relations(self, oldinstance):
self.client_logos.all().delete()
for logo in oldinstance.client_logos.all():
logo.pk = None
logo.showroom = self
logo.save()

Django: allow user to add fields to model

I am just starting with Django and want to create a model for an application.
I find Djangos feature to
- automatically define validations and html widget types for forms according to the field type defined in the model and
- define a choice set for the field right in the model
very usefull and I want to make best use of it. Also, I want to make best use of the admin interface.
However, what if I want to allow the user of the application to add fields to the model? For example, consider a simple adress book. I want the user to be able to define additional atributes for all of his contacts in the admin settings, i.e. add a fax number field, so that a fax number can be added to all contacts.
from a relational DB perspective, I would have a table with atributes (PK: atr_ID, atr_name, atr_type) and an N:N relation between atributes and contacts with foreign keys from atributes and contacts - i.e. it would result in 3 tables in the DB. right?
but that way I cannot define the field types directly in the Django model. Now what is best practice here? How can I make use of Djangos functionality AND allow the user to add aditional/custom fields via the admin interface?
Thank you! :)
Best
Teconomix
i would suggest storing json as a string in the database, that way it can be as extendable as you want and the field list can go very long.
Edit:
If you are using other damn backends you can use Django-jsonfield. If you are using Postgres then it has a native jsonfield support for enhanced querying, etc.
Edit 2:
Using django mongodb connector can also help.
I've used this approach, first seen in django-payslip, to allow for extendable fields. This provides a structure for adding fields to models, from which you can allow users to add/edit through standard view procedures (no admin hacking necessary). This should be enough to get you started, and taking a look at django-payslip's source code (see the views) also provides view Mixins and forms as an example of how to render to users.
class YourModel(models.Model):
extra_fields = models.ManyToManyField(
'your_app.ExtraField',
verbose_name=_('Extra fields'),
blank=True, null=True,
)
class ExtraFieldType(models.Model):
"""
Model to create custom information holders.
:name: Name of the attribute.
:description: Description of the attribute.
:model: Can be set in order to allow the use of only one model.
:fixed_values: Can transform related exta fields into choices.
"""
name = models.CharField(
max_length=100,
verbose_name=_('Name'),
)
description = models.CharField(
max_length=100,
blank=True, null=True,
verbose_name=_('Description'),
)
model = models.CharField(
max_length=10,
choices=(
('YourModel', 'YourModel'),
('AnotherModel', 'AnotherModel'), # which models do you want to add extra fields to?
),
verbose_name=_('Model'),
blank=True, null=True,
)
fixed_values = models.BooleanField(
default=False,
verbose_name=_('Fixed values'),
)
class Meta:
ordering = ['name', ]
def __unicode__(self):
return '{0}'.format(self.name)
class ExtraField(models.Model):
"""
Model to create custom fields.
:field_type: Connection to the field type.
:value: Current value of this extra field.
"""
field_type = models.ForeignKey(
'your_app.ExtraFieldType',
verbose_name=_('Field type'),
related_name='extra_fields',
help_text=_('Only field types with fixed values can be chosen to add'
' global values.'),
)
value = models.CharField(
max_length=200,
verbose_name=_('Value'),
)
class Meta:
ordering = ['field_type__name', ]
def __unicode__(self):
return '{0} ({1}) - {2}'.format(
self.field_type, self.field_type.get_model_display() or 'general',
self.value)
You can use InlineModelAdmin objects. It should be something like:
#models.py
from django.db import models
class Person(models.Model):
name = models.CharField(max_length=100)
class ContactType(models.Model):
name = models.CharField(max_length=100)
class Contact(models.Model):
person = models.ForeignKey(Person, on_delete=models.CASCADE)
contact_type = models.ForeignKey(ContactType, on_delete=models.CASCADE)
value = models.CharField(max_length=100)
#admin.py
from django.contrib import admin
class ContactInline(admin.TabularInline):
model = Contact
class PersonAdmin(admin.ModelAdmin):
inlines = [
ContactInline,
]
By the way... stackoverflow questions should contain some code. You should try to do something before asking a question.

Django Admin: Ordering of ForeignKey and ManyToManyField relations referencing User

I have an application that makes use of Django's UserProfile to extend the built-in Django User model. Looks a bit like:
class UserProfile(models.Model):
user = models.ForeignKey(User, unique=True)
# Local Stuff
image_url_s = models.CharField(max_length=128, blank=True)
image_url_m = models.CharField(max_length=128, blank=True)
# Admin
class Admin: pass
I have added a new class to my model:
class Team(models.Model):
name = models.CharField(max_length=128)
manager = models.ForeignKey(User, related_name='manager')
members = models.ManyToManyField(User, blank=True)
And it is registered into the Admin:
class TeamAdmin(admin.ModelAdmin):
list_display = ('name', 'manager')
admin.site.register(Team, TeamAdmin)
Alas, in the admin inteface, when I go to select a manager from the drop-down box, or set team members via the multi-select field, they are ordered by the User numeric ID. For the life of me, I can not figure out how to get these sorted.
I have a similar class with:
class Meta:
ordering = ['name']
That works great! But I don't "own" the User class, and when I try this trick in UserAdmin:
class Meta:
ordering = ['username']
I get:
django.core.management.base.CommandError: One or more models did not validate:
events.userprofile: "ordering" refers to "username", a field that doesn't exist.
user.username doesn't work either. I could specify, like image_url_s if I wanted to . . . how can I tell the admin to sort my lists of users by username? Thanks!
This
class Meta:
ordering = ['username']
should be
ordering = ['user__username']
if it's in your UserProfile admin class. That'll stop the exception, but I don't think it helps you.
Ordering the User model as you describe is quite tricky, but see http://code.djangoproject.com/ticket/6089#comment:8 for a solution.
One way would be to define a custom form to use for your Team model in the admin, and override the manager field to use a queryset with the correct ordering:
from django import forms
class TeamForm(forms.ModelForm):
manager = forms.ModelChoiceField(queryset=User.objects.order_by('username'))
class Meta:
model = Team
class TeamAdmin(admin.ModelAdmin):
list_display = ('name', 'manager')
form = TeamForm
This might be dangerous for some reason, but this can be done in one line in your project's models.py file:
User._meta.ordering=["username"]
For me, the only working solution was to use Proxy Model. As stated in the documentation, you can create own proxy models for even built-in models and customize anything like in regular models:
class OrderedUser(User):
class Meta:
proxy = True
ordering = ["username"]
def __str__(self):
return '%s %s' % (self.first_name, self.last_name)
After that, in your model just change Foreign Key to:
user = models.OneToOneField(OrderedUser, unique=True)
or even more suitable
user = models.OneToOneField(OrderedUser, unique = True, parent_link = True)

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