I am trying to parse several div blocks using Beautiful Soup using some html from a website. However, I cannot work out which function should be used to select these div blocks. I have tried the following:
import urllib2
from bs4 import BeautifulSoup
def getData():
html = urllib2.urlopen("http://www.racingpost.com/horses2/results/home.sd?r_date=2013-09-22", timeout=10).read().decode('UTF-8')
soup = BeautifulSoup(html)
print(soup.title)
print(soup.find_all('<div class="crBlock ">'))
getData()
I want to be able to select everything between <div class="crBlock "> and its correct end </div>. (Obviously there are other div tags but I want to select the block all the way down to the one that represents the end of this section of html.)
The correct use would be:
soup.find_all('div', class_="crBlock ")
By default, beautiful soup will return the entire tag, including contents. You can then do whatever you want to it if you store it in a variable. If you are only looking for one div, you can also use find() instead. For instance:
div = soup.find('div', class_="crBlock ")
print(div.find_all(text='foobar'))
Check out the documentation page for more info on all the filters you can use.
Related
Suppose we have the html code as follows:
html = '<div class="dt name">abc</div><div class="name">xyz</div>'
soup = BeautifulSoup(html, 'lxml')
I want to get the name xyz. Then, I write
soup.find('div',{'class':'name'})
However, it returns abc.
How to solve this problem?
The thing is that Beautiful Soup returns the first element that has the class name and div so the thing is that the first div has class name and class dt so it selects that div.
So, div helps but it still narrows down to 2 divs. Next, it returns a array so check the second div to use print(soup('div')[1].text). If you want to print all the divs use this code:
for i in range(len(soup('div')))
print(soup('div')[i].text)
And as pointed out in Ankur Sinha's answer, if you want to select all the divs that have only class name, then you have to use select, like this:
soup.select('div[class=name]')[0].get_text()
But if there are multiple divs that satisfy this property, use this:
for i in range(len(soup.select('div[class=name]'))):
print(soup.select('div[class=name]')[i].get_text())
Just to continue Ankur Sinha, when you use select or even just soup() it forms a array, because there can be multiple items so that's why I used len(), to figure out the length of the array. Then I ran a for loop on it and then printed the select function at i starting from 0.
When you do that, it rather would give a specific div instead of a array, and if it gave out a array, calling get_text() would produce errors because the array is NOT text.
This blog was helpful in doing what you would like, and that is to explicitly find a tag with specific class attribute:
from bs4 import BeautifulSoup
html = '<div class="dt name">abc</div><div class="name">xyz</div>'
soup = BeautifulSoup(html, 'html.parser')
soup.find(lambda tag: tag.name == 'div' and tag['class'] == ['name'])
Output:
<div class="name">xyz</div>
You can do it without lambda also using select to find exact class name like this:
soup.select("div[class = name]")
Will give:
[<div class="name">xyz</div>]
And if you want the value between tags:
soup.select("div[class=name]")[0].get_text()
Will give:
xyz
In case you have multiple div with class = 'name', then you can do:
for i in range(len(soup.select("div[class=name]"))):
print(soup.select("div[class=name]")[i].get_text())
Reference:
https://www.crummy.com/software/BeautifulSoup/bs4/doc/#css-selectors
This might work for you, note that it is contingent on the div being the second div item in the html.
import requests
from bs4 import BeautifulSoup
html = '<div class="dt name">abc</div><div class="name">xyz</div>'
soup = BeautifulSoup(html, features='lxml')
print(soup('div')[1].text)
I am trying to access the sequence on this webpage:
https://www.ncbi.nlm.nih.gov/protein/EGW15053.1?report=fasta
The sequence is stored under the div class="seq gbff". Each line is stored under
<span class='ff_line' id='gi_344258949_1"> *line 1 of sequence* </span>
When I try to search for the spans containing the sequence, beautiful soup returns None. Same problem when I try to look at the children or content of the div above the spans.
Here is the code:
import requests
import re
from bs4 import BeautifulSoup
# Create a variable with the url
url = 'https://www.ncbi.nlm.nih.gov/protein/EGW15053.1?report=fasta'
# Use requests to get the contents
r = requests.get(url)
# Get the text of the contents
html_content = r.text
# Convert the html content into a beautiful soup object
soup = BeautifulSoup(html_content, 'html.parser')
div = soup.find_all('div', attrs={'class', 'seq gbff'})
for each in div.children:
print(each)
soup.find_all('span', aatrs={'class', 'ff_line'})
Neither method works and I'd greatly appreciate any help :D
This page uses JavaScript to load data
With DevTools in Chrome/Firefox I found this url and there are all <span>
https://www.ncbi.nlm.nih.gov/sviewer/viewer.fcgi?id=344258949&db=protein&report=fasta&extrafeat=0&fmt_mask=0&retmode=html&withmarkup=on&tool=portal&log$=seqview&maxdownloadsize=1000000
Now hard part. You have to find this url in HTML because different pages will use different arguments in url. Or you have to compare few urls and find schema so you could generate this url manually.
EDIT: if in url you change retmode=html to retmode=xml then you get it as XML. If you use retmode=text then you get it as text without HTML tags. retmode=json doesn't works.
I'm playing around with parsing an html page using css selectors
import requests
import webbrowser
from bs4 import BeautifulSoup
page = requests.get('http://www.marketwatch.com', headers={'User-Agent': 'Mozilla/5.0'})
soup = BeautifulSoup(page.content, 'html.parser')
I'm having trouble selecting a list tag with a class when using the select method. However, I have no trouble when using the find_all method
soup.find_all('ul', class_= "latestNews j-scrollElement")
This returns the output I desire, but for some reason I can't do the same using
css selectors. I want to know what I'm doing wrong.
Here is my attempt:
soup.select("ul .latestNews j-scrollElement")
which is returning an empty list.
I can't figure out what I'm doing wrong with the select method.
Thank you.
From the documentation:
If you want to search for tags that match two or more CSS classes, you
should use a CSS selector:
css_soup.select("p.strikeout.body")
In your case, you'd call it like this:
In [1588]: soup.select("ul.latestNews.j-scrollElement")
Out[1588]:
[<ul class="latestNews j-scrollElement" data-track-code="MW_Header_Latest News|MW_Header_Latest News_Facebook|MW_Header_Latest News_Twitter" data-track-query=".latestNews__headline a|a.icon--facebook|a.icon--twitter">
.
.
.
I need to extract some articles from the Piography website.
so from this page http://www.biography.com/people I need all the sublinks.
for example:
/people/ryan-seacrest-21095899
/people/edgar-allan-poe-9443160
but I have two problems:
1- when I am trying to a find all < a >. I couldn't find the href that I need.
import urllib2
from BeautifulSoup import BeautifulSoup
url = "http://www.biography.com/people"
text = urllib2.urlopen(url).read()
soup = BeautifulSoup(text)
divs = soup.findAll('a')
for div in divs:
print(div)
2- There are a "see more" button. so how I can take all the links for all the people in the website. not just that appear in the first page?
On site what you show, use angular and part of content generate with JS. BeautifulSoup not execute JS. You need to use http://selenium-python.readthedocs.io/ or another like instrument. Or you may pry in ajax need for you GET(or may be POST) method, and give data through him.
The page is: http://item.taobao.com/item.htm?id=13015989524
you can see its source code.
In its source code the following code exists
<a href="http://item.taobao.com/item.htm?id=13015989524" target="_blank">
But when I use BeautifulSoup to read the source code and execute the following
soup.findAll('a', href="http://item.taobao.com/item.htm?id=13015989524")
It returns [] empty. What does it return '[]'?
As far as I can see, the <a> tag you are trying to find is inside a <textarea> tag. BS does not parse the contents of <textarea> as HTML, and rightly so since <textarea> should not contain HTML. In short, that page is doing something sketchy.
If you really need to get that, you might "cheat" and parse the contents of <textarea> again and search within them:
import urllib
from BeautifulSoup import BeautifulSoup as BS
soup = BS(urllib.urlopen("http://item.taobao.com/item.htm?id=13015989524"))
a = []
for textarea in soup.findAll("textarea"):
textsoup = BS(textarea.text) # parse the contents as html
a.extend(textsoup.findAll("a", attrs={"href":"http://item.taobao.com/item.htm?id=13015989524"}))
for tag in a:
print tag
# outputs
# <a href="http://item.taobao.com/item.htm?id=13015989524" target="_blank"><img ...
# <a href="http://item.taobao.com/item.htm?id=13015989524" title="901 ...
Use a dictionary to store the attribute:
soup.findAll('a', {
'href': "http://item.taobao.com/item.htm?id=13015989524"
})