I have this date from Twitter:
created_at = "Wed Aug 29 17:12:58 +0000 2012"
I want to convert it to a time using something like:
time.mktime(created_at)
But I get this error:
TypeError: argument must be 9-item sequence, not str
What am I doing wrong?
You need to convert the incoming string to a Python time tuple using strptime before you can do anything with it.
This code will take the input string, convert it to a tuple and then converts that to a Unix-epoch time float using time.mktime:
import time
created_at = "Wed Aug 29 17:12:58 +0000 2012"
print time.mktime(time.strptime(created_at,"%a %b %d %H:%M:%S +0000 %Y"))
I don't if it too late, use arrow package instead could fewer imports and a lot less code.
pip install arrow
Then:
>>> arrow.Arrow.strptime("Wed Aug 29 17:12:58 +0000 2012", "%a %b %d %H:%M:%S %z %Y")
<Arrow [2012-08-29T17:00:58+00:00]>
>>> arrow.Arrow.strptime("Wed Aug 29 17:12:58 +0000 2012", "%a %b %d %H:%M:%S %z %Y").timestamp
1346259658
Read the documentation of time.mktime
It requires struct_time, or you can alternatively represent it using a 9-tuple.
The required entries are:
Year
Month
Date
Hour
Minute
Second
Day in week
Day in year
Daylight Savings Time
This is not the function you need, however. It seems that you want to use strptime instead.
According to the documentation:
Parse a string representing a time according to a format.
The return value is a struct_time as returned by gmtime() or localtime().
>>> import time
>>> time.strptime("30 Nov 00", "%d %b %y")
time.struct_time(tm_year=2000, tm_mon=11, tm_mday=30, tm_hour=0, tm_min=0,
tm_sec=0, tm_wday=3, tm_yday=335, tm_isdst=-1)
So, you can do:
time.strptime(created_at)
Related
When I pull events start times from Facebook Graph in comes in this form:
2017-09-26T18:00:00+0300
I'd like to convert it into readable format so I use this:
readable_event_date = dateutil.parser.parse(event_date).strftime('%a, %b %d %Y %H:%M:%S')
and it comes out like this:
Tue, 26 Sep 2017 18:00:00
Which is good but it loses the offset from UTC and I'd like it in AM PM format.
Thus, I would like it like this:
Tue, 26 Sep 2017 9:00 PM
To get into 12 hours format and keep offset from UTC for printing :
from dateutil.parser import parse
event_date = '2017-09-26T18:00:0+0300'
date = parse(event_date)
offset = date.tzinfo._offset
readable_event_date = (date + offset).strftime('%a, %b %d %Y %I:%M:%S %p')
print(readable_event_date)
Output:
'Tue, Sep 26 2017 09:00:00 PM'
It seems like what you want is this time, expressed in UTC, in the format '%a, %b %d %Y %I:%M:%S %p'. Luckily, all the information you need to do this is contained in the datetime object that you parsed, you just need to convert to UTC
Python 2.6+ or Python 3.3+:
The approach you've taken using dateutil will work for Python 2.6+ or Python 3.3.+ (and also works for a greater variety of datetime string formats):
from dateutil.parser import parse
# In Python 2.7, you need to use another one
from dateutil.tz import tzutc
UTC = tzutc()
dt_str = '2017-09-26T18:00:00+0300'
dt = parse(dt_str)
dt_utc = dt.astimezone(UTC) # Convert to UTC
print(dt_utc.strftime('%a, %b %d %Y %I:%M:%S %p'))
# Tue, Sep 26 2017 03:00:00 PM
One thing I notice is that the date you've provided, as far as I can tell, represents 3PM in UTC, not 9PM (as your example states). This is one reason you should use .astimezone(UTC) rather than some other approach.
If you want to include the time zone offset information, you can also use the %z parameter on the non-converted version of the datetime object.
print(dt.strftime('%a, %b %d %Y %I:%M:%S%z %p'))
# Tue, Sep 26 2017 06:00:00+0300 PM
This %z parameter may also be useful even if you are keeping it in UTC, because then you can at least be clear that the date the user is seeing is a UTC date.
Python 3.2+ only:
Given that you know the exact format of the input string, in Python 3.2+, you can achieve this same thing without pulling in dateutil, and it will almost certainly be faster (which may or may not be a concern for you).In your case here is how to rewrite the code so that it works with just the standard library:
from datetime import datetime, timezone
UTC = timezone.utc
dt_str = '2017-09-26T18:00:00+0300'
dt = datetime.strptime(dt_str, '%Y-%m-%dT%H:%M:%S%z')
dt_utc = dt.astimezone(UTC)
print(dt_utc.strftime('%a, %b %d %Y %I:%M:%S %p'))
# Tue, Sep 26 2017 03:00:00 PM
print(dt.strftime('%a, %b %d %Y %I:%M:%S%z %p'))
# Tue, Sep 26 2017 06:00:00+0300 PM
I have found a question at this link that almost answers what I need but not quite. What I need to know, how using this method could I convert a string of the format u'Saturday, Feb 27 2016' into a Python date variable in the format 27/02/2016?
Thanks
You have to first remove the weekday name (it's not much use anyway) and parse the rest:
datetime.datetime.strptime('Saturday, Feb 27 2016'.split(', ', 1)[1], '%b %d %Y').date()
Alternatively, use dateutil:
dateutil.parser.parse('Saturday, Feb 27 2016').date()
EDIT
My mistake, you don't need to remove the Weekday (I'd missed it in the list of options):
datetime.datetime.strptime('Saturday, Feb 27 2016', '%A, %b %d %Y').date()
You don't have to remove anything, you can parse it as is and use strftime to get the format you want:
from datetime import datetime
s = u'Saturday, Feb 27 2016'
dt = datetime.strptime(s,"%A, %b %d %Y")
print(dt)
print(dt.strftime("%d/%m/%Y"))
2016-02-27 00:00:00
27/02/2016
%A Locale’s full weekday name.
%b Locale’s abbreviated month name.
%d Day of the month as a decimal number [01,31].
%Y Year with century as a decimal number.
The full listing of directives are here
I'm pulling the date value from gmail and trying to perform some functions on it. First I simply want to display it, but I can't even do that. See my code and error below.
from datetime import datetime
timeString = 'Sat, 2 Aug 2014 09:29:31 -0700'
myTime = datetime.strptime(timeString, '%m-%d-%Y %I:%M %p')
Here's the error I get. Do you think its the -0700 that's getting in the way?
ValueError: time data 'Sat, 2 Aug 2014 09:29:31 -0700' does not match format '%m-%d-%Y %I:%M %p'
As the error message suggests, you need to put the same format as your date string is in, I've not tried it, but something like this should work:
myTime = datetime.strptime(timeString, '%a, %d %b %Y %I:%M:%S %z')
Check here for complete details.
How do I format a date in python to look like this: weekday:month:day(number):HH:MM:SS(military):EST/CST/PST:YYYY? I am familiar with strftime(), but I am unsure how I would handle the HH:MM:SS and EST/CST/PST.
example of how I am trying to get the date to look:
Sun Mar 10 15:53:00 EST 2013
from time import gmtime, strftime
print strftime("%a %b %d %H:%M:%S %Z %Y", gmtime())
This will produce
Fri Mar 22 21:10:56 Eastern Standard Time 2013
You'll have to settle for the long name of the timezone unless you want to use pytz. I suppose it's worth noting that timezone abbreviations aren't unique.
Use strftime to output a formatted string representation:
print time.strftime("%a %b %d %H:%M:%S %Z %Y")
A list of the format codes can be found here
I have these date strings:
Fri Oct 7 16:00:09 CEST 2011
I want to convert them to UTC. I have tried with this implementation:
def LocalToUtc(localtime):
return datetime.strptime(localtime, "%a %m %d %H:%M:%S %Z %Y").isoformat() + 'Z'
But I get a ValueError:
ValueError: time data 'Fri Oct 7 16:00:09 CEST 2011' does not match format '%a %m %d %H:%M:%S %Z %Y'
Any ideas?
Use the parsedatetime library.
There are two problems here:
You're using "%m" instead of "%b"
The standard lib can't parse "CEST", it understands only very few time zone names.
See also here: What possible values does datetime.strptime() accept for %Z?