Below is my django routing configuration:
# main module
urlpatterns = patterns('',
url(r'^api/', include('api.urls')),
)
# api module
urlpatterns = patterns('',
url(r'^$', views.index, name='index'),
url(r'^users/(?P<id>\d+)/?$', views.users, name='users')
)
I can access specific users (using ids) with http://localhost:8000/api/users/1/ but I can't access list of users: http://localhost:8000/api/users/:
Using the URLconf defined in duck_rip.urls, Django tried these URL patterns, in this order:
^api/ ^$ [name='index']
^api/ ^users/(?P<id>\d+) [name='users']
The current URL, api/users/, didn't match any of these.
Before this, I had my module urls like this:
url(r'^users/$', views.users, name='users')
and I had access to http://localhost:8000/api/users/. Can someone please explain me what is the error I make?
Just make id optional as:
url(r'^users/(?:(?P<id>\d+)/)?$', views.users, name='users')
And in view:
def users(request, id=None)
Related
This should be an easy enough problem to solve for you guys:
I just started working with Django, and I'm doing some routing. This is my urls.py in the root of the project:
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('dashboard.urls')),
]
This is the routing in my dashboard app:
urlpatterns = [
path('dashboard', views.index, name='index'),
path('', views.index, name='index'),
]
Now let's say I want my users to be redirected to /dashboard if they go to the root of the website. So I would use '' as a route in the urls.py in the root, and then have everyone sent to /dashboard from the urls.py in the dashboard app. But when I do this I get the following warning:
?: (urls.W002) Your URL pattern '/dashboard' [name='index'] has a route beginning with a '/'. Remove this slash as it is unnecessary. If this pattern is targeted in an include(), ensure the include() pattern has a trailing '/'.
So I tried to use '/' instead of '', but since a trailing / is automatically removed from an url, the url wouldn't match the pattern. Should I ignore/mute this warning or is there another way to go about it?
This is the code that worked perfectly but gave me a warning earlier:
urlpatterns = [
path('/dashboard', views.index, name='index'),
path('', views.index, name='index'),
]
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('dashboard.urls'))
]
You can use RedirectView to redirect from / to /dashboard/. Then use 'dashboard' when including the dashboard urls.
urlpatterns = [
path('admin/', admin.site.urls),
path('', RedirectView.as_view(pattern_name='dashboard:index')
path('dashboard/', include('dashboard.urls')),
]
You can then remove 'dashboard' from the path in dashboard/urls.py, as it is already in the include().
app_name = 'dashboard'
urlpatterns = [
path('', views.index, name='index'),
]
I've added app_name='dashboard' to match the namespace used above in pattern_name='dashboard:index'.
Note that Django projects usually use URLs with a trailing slash, e.g. /dashboard/ instead of dashboard.
If you really want to use URLs like /dashboard without a trailing slash, then the include should be
path('dashboard', include('dashboard.urls')),
If you do this, I suggest you set APPEND_SLASH to False in your settings.
You can try something like this:
from django.conf import settings
from django.conf.urls import include, url
from django.contrib import admin
from django.views.generic import RedirectView
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^contacts/', include('appname.contacts.urls')),
url(r'^comments/', include('appname.urls')),
url(r'^subscriptions/', include('appname.partner.urls')),
url(r'^', RedirectView.as_view(url="/admin/"))
]
This is what I've done in my project so whenever the user go to 127.0.0.1:8000 it redirects to /admin
Im trying to add this url to my app's urlpatterns (i.e. MyProject/MyApp/urls.py):
url(r'^login/$', auth_views.LoginView.as_view(), name='login')
I have this snippet in one of my templates:
Login
Normally, clicking on the link takes you to the login page successfully. However, when I try to add a namespace to my urls (app_name = my_namespace) and change the reverse to
Login
it fails when I click on the link and I get the error
Reverse for 'login' not found. 'login' is not a valid view function or
pattern name.
While all the other urls I reverse work with the namespace, it is just the login reverse that fails. Any idea why?
Edit:
MyProject/MyProject/urls.py:
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^clubinfo/', include('ClubInfo.urls')),
]
MyProject/MyApp/urls.py:
app_name = 'clubinfo'
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^register/$', views.register, name='register'),
url(r'^login/$', auth_views.LoginView.as_view(), name='login'),
]
A snippet of the template:
Home
Login
Register
I can click on Home and Register, not login
Edit 2: auth_views is from this import:
from django.contrib.auth import views as auth_views
I think this may have something to do with why the program is raising an error.
It turns out the problem was in my login.html file which Django renders in its LoginView. I didn't use the namespace in one of my reverses in that file.
in your project urls do this:
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^clubinfo/', include('ClubInfo.urls', namespace='clubinfo')),
]
now in clubinfo urls:
remove
app_name = 'clubinfo'
run de server again and try it should work that my way of doing
I find that your
app_name='clubinfo'
, but your urlpatterns is
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^clubinfo/', include('**ClubInfo**.urls')),
]
Okay... let's try to explain things clearly. I've used Python Django to create a dynamic webpage/web-app. After completing the website I have published it using DigitalOcean and have successfully attached my purchased domain name to the name server of DigitalOcean. When I access my website, ordinanceservices.com, i get an error 404; however, if I type ordinanceservices.com/home it works as it should and displays the home page. How, by editing the python files, can I have it to where ordinanceservices.com will display the home page as opposed to error 404? I feel like there's something that I am doing that is fundamentally wrong regarding my .urls structure and thus a rewrite/redirect in the nginx config should not be necessary.
Here is the specific error:
Page not found (404)
Request Method: GET
Request URL: http://ordinanceservices.com/
Using the URLconf defined in django_project.urls, Django tried these URL patterns, in this order:
^admin/
^ ^home/ [name='home']
^ ^contact/ [name='contact']
^ ^services/ [name='services']
The current URL, , didn't match any of these.
I somewhat understand what is happening here though I do not know how to fix this. Next I will provide my .urls files for each folder that contains such:
/django_project urls.py
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls)),
url(r'^', include('company.urls')),
)
/company urls.py
from django.conf.urls import url, include
from . import views
urlpatterns = [
url(r'^home/', views.home, name='home'),
url(r'^contact/', views.contact, name='contact'),
url(r'^services/', views.services, name='services'),
]
/company views.py
from django.shortcuts import render
def home(request):
return render(request, 'company/home.html')
def contact(request):
return render(request, 'company/contact.html')
def services(request):
return render(request, 'company/services.html')
What I am aiming to do, without needing to redirect the main URL using the nginx config files to do so, is to edit my urls and views structure of my Python files to ensure that the normal URL, ordinanceservices.com, will actually display a page; preferably the home page of my webpage.
I have a hunch that it has to do with the fact that I do not have a views.index for the r'^admin/' to reach to. I am not certain but I have been trying to figure this out for hours. Does anyone have a clue what I can do to fix this?
You haven't defined anything at the root url. Add one more line to your company urls.py so it becomes
//company urls.py
from django.conf.urls import url, include
from . import views
urlpatterns = [
url(r'^$', views.home, name='home'),
url(r'^home/', views.home, name='home'),
url(r'^contact/', views.contact, name='contact'),
url(r'^services/', views.services, name='services'),
]
First of all, check if you have added www.yourdomain.com or yourdomain.com to ALLOWED_HOST = ['www.yourdomain.com','yourdomain.com'] in your settings.py
and then in your company/urls.py do this
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.home, name='home'),
url(r'^contact/$', views.contact, name='contact'),
url(r'^services/$', views.services, name='services'),
]
and in your main urls.py add this code
from django.conf.urls import url,include
from django.contrib import admin
admin.autodiscover()
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^', include('company.urls')),
]
New to Python, just starting up with a Issue reporting app which involves an API module.
My Urls.py file:
urlpatterns = patterns('',
url(r'^api/', include('api.urls')),
)
My api.urls file
urlpatterns = patterns('api.v1',
# Examples:
# url(r'^$', 'newproject.views.home', name='home'),
# url(r'^blog/', include('blog.urls')),
# authentication / session managemen
url(r'^auth/profile/me/$', 'account', name='my-account'),
url(r'^auth/profile/$', 'new_account', name='new-account'),
url(r'^auth/session/(?P<key>[a-z0-9]{64})/$', 'session', name='existing-session'),
url(r'^auth/session/$', 'new_session', name='new-session'),
....
My Web Page 404 Error
Using the URLconf defined in newproject.urls, Django tried these URL patterns, in this order:
^api/
The current URL, , didn't match any of these.
I might be overlooking a mistake I made...
Help Please?
Using Django 1.9.7
replace url(r'^api/', include('api.urls')),
with url(r'', include('api.urls')),
I'm totally new to Django, and I'm trying to understand how does it work (I'm more used to PHP and Spring frameworks.
I have a project called testrun and inside it an app called graphs, so my views.py looks like:
#!/usr/bin/python
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello, World. You're at the graphs index.")
then, in graphs/urls.py:
from django.conf.urls import patterns, url, include
from graphs import views
urlpatterns = patterns(
url(r'^$', views.index, name='index'),
)
finally, at testrun/urls.py:
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'testrun.views.home', name='home'),
# url(r'^blog/', include('blog.urls')),
url(r'^graphs/', include('graphs.urls')),
url(r'^admin/', include(admin.site.urls)),
)
However, when I try to access http://127.0.0.1:8000/graphs/ I get:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/graphs/
Using the URLconf defined in testrun.urls, Django tried these URL patterns, in this order:
^admin/
The current URL, graphs/, didn't match any of these.
You're seeing this error because you have DEBUG = True in your Django settings file. Change that to False, and Django will display a standard 404 page.
What am I doing wrong that I can't get that simple message to be displayed in the browser?
To expand on my comment, the first argument to patterns() function is
a prefix to apply to each view function
You can find more information here:
https://docs.djangoproject.com/en/dev/topics/http/urls/#syntax-of-the-urlpatterns-variable
Therefore in graphs/urls.py you need to fix the patterns call like so:
urlpatterns = patterns('', # <-- note the `'',`
url(r'^$', views.index, name='index'),
)