Maybe a stupid question but how do I remove a sublist from list in django template
I have something like this:
{% for j in sub_com|slice:"1" %}
{% for k in j|slice:"3" %}
<li> {{k}} </li>
{% endfor %}
{# remove sublist from list here #}
{% endfor %}
You can probably use templateContext.pop here.
{% for j in sub_com|slice:"1" %}
{% for k in j|slice:"3" %}
<li> {{k}} </li>
{% endfor %}
{{ j.pop.0 }}
{% endfor %}
Related
I have a list of objects that I would like to display in an ul/li. For that I do the code below:
<ul id="myUL">
{% for l in lpps %}
<li id="lpps">{{ l.codeACL }} {{ l.libelle }}</li>
{% endfor %}
</ul>
The problem is that in my view, I ask to display only 15 objects per page.
But I want to ignore this and display all the objects on all the pages.
Is there something like for l in lpps.page(all)...?
django have forloop.counter ,
you can use that like
<ul id="myUL">
{% for l in lpps %}
{% if forloop.counter == 15 %}{% break %}{% endif %}
<li id="lpps">{{ l.codeACL }} {{ l.libelle }}</li>
{% endfor %}
</ul>
What does Django return with using {{ fieldset.fields }}? How can I make it a string?
In my template, I have this:
{% for fieldset in adminform %}
<li> {{ fieldset.fields }} </li>
{% if "nanoadded" in fieldset.fields %}
<li> nanoadded is here </li>
{% else %}
<li> nanoadded is NOT here </li>
{% endif %}
{% endfor %}
Here is what is returned:
[('arri', 'aconcentration', 'acat', 'anotes', 'agtlt', 'id'), ('nanoadded', 'response', 'select_charc')]
nanoadded is NOT here
So I am assuming that the fieldset.fields is not returning a string (even though it looks like a string). How can a make Django see the contents of fieldset.fields as a string? Thanks for you assistance!
It looks like the fields property returns a list that contains two tuples, so you might want to run it through a for loop to check each tuple for the membership of the string 'nanoadded'
Perhaps like this:
{% for fieldset in adminform %}
{% for field in fieldset.fields %}
<li> {{ field }} </li>
{% if "nanoadded" in field %}
<li> nanoadded is here </li>
{% else %}
<li> nanoadded is NOT here </li>
{% endif %}
{% endfor %}
{% endfor %}
I would like to make a pagination with Bootstrap : a new page every 10 new field in data.
file.html
{% for d in data %}
{% if forloop.first %}
<ul class="pagination">
{% endif %}
{% if (forloop.counter % 10) == 0 %}
<li>{{ forloop.counter % 10 }}</li>
{% endif %}
{% if forloop.last %}
</ul>
{% endif %}
{% endfor %}
output I would like that => Bootstrap pagination
But Django give me an error for this :
{% if (forloop.counter % 10) == 0 %}
TemplateSyntaxError :/
I don't know how to do except create my own filter or add a filter, but i would like to know first if i can do in the template first.
PS: I use Django 1.5 and I can't upgrade it.
Edit:
Finally I use this condition:
{% if forloop.counter|divisibleby:'10' and forloop.counter|divisibleby:'5' and forloop.counter|divisibleby:'2' %}
Like that I know when I have a 10 multiple.
The modulus (%) operator is not available in django templates. However, you can use the divisibleby (https://docs.djangoproject.com/en/1.5/ref/templates/builtins/#divisibleby) template filter, something like
{% if forloop.counter|divisibleby:"2" %}
Use the paginator, your QuerySet are not evaluated for the hole table, just the number you need to build the page, and it offers properties that you can use in the template like (page_range, next_page_number, has_next, etc.)
here is the code withe BootStrap 2 and django.core.paginator:
<div class="pagination pagination-centered">
<ul>
{% if MYDATAENTIRES.has_previous %}
<li>
{% trans "Précédent" %}
</li>
{% endif %}
{% for i in MYDATAENTIRES.paginator.page_range %}
<li {% ifequal MYDATAENTIRES.number i %} {{ 'class="disabled"' }} {% endifequal %}>
<a href="?page={{ i }}">
{{ i }}
</a>
</li>
{% endfor %}
{% if MYDATAENTIRES.has_next %}
<li>
{% trans "Suivant" %}
</li>
{% endif %}
</ul>
</div>
I have a nested list. I need to iterate through a list and keep it in for loop as shown below.
{% for alpha in list %}
<div id="{{ loop.index }}">
<div class='sidebar-one'>
{% for beta in list[0][2:] %} #I want to iterate through list[0][2:] till list[n][2:]
<p> {{ beta[0][0] }} </p>
{% endfor %}
</div>
</div>
{% endfor %}
I tried range but no luck.
{% for n in range(1,n) %}
{% for line in check[{{n}}][2:] %}
{% endfor %}
it threw error:
TemplateSyntaxError: expected token ':', got '}'
It's just like Python:
{% for n in range(n) %}
{% for line in check[n][2:] %}
<p> {{ beta[0][0] }} </p>
{% endfor %}
{% endfor %}
You can use the "length" property:
{% for n in range(yourList| length) %}
<p class="someclass">{{n + 1}}.</p>
<a class="someclass2"
href="{{ url_for( 'yourFunction', Int = yourList[n].iterable)}}">
{{yourList[n].iterable}}</a><br>
{% endfor %}
Length is similar to len(yourlist) that we have in python.
views:
....
d = Data.objects.filter(is_accepted=True)
....
templates:
{% for item in d %}
{% for picture in item.photo_set.all %}
<img class="image" src="{{ picture.photo.url}}">
{% endfor %}
{% endfor %}
How to get only first photo? ({{ picture.photo.url}})
You can index with the dot notation:
{{ item.photo_set.all.0.photo.url }}
You need to use forloop.first. Have a look at the docs.
{% for item in d %}
{% for picture in item.photo_set.all %}
{% if forloop.first %}
<img class="image" src="{{ picture.photo.url}}">
{% endif %}
{% endfor %}
{% endfor %}
First, a sharp knife.
Second, a slice