This question already has answers here:
open() gives FileNotFoundError / IOError: '[Errno 2] No such file or directory'
(8 answers)
Closed 7 months ago.
I'm trying to write a simple program to read a file and search for a word then print how many times that word is found in the file. Every time I type in "test.rtf" (which is the name of my document) I get this error:
Traceback (most recent call last):
File "/Users/AshleyStallings/Documents/School Work/Computer Programming/Side Projects/How many? (Python).py", line 9, in <module>
fileScan= open(fileName, 'r') #Opens file
FileNotFoundError: [Errno 2] No such file or directory: 'test.rtf'
In class last semester, I remember my professor saying you have to save the file in a specific place? I'm not sure if he really said that though, but I'm running apple OSx if that helps.
Here's the important part of my code:
fileName= input("Please enter the name of the file you'd like to use.")
fileScan= open(fileName, 'r') #Opens file
If the user does not pass the full path to the file (on Unix type systems this means a path that starts with a slash), the path is interpreted relatively to the current working directory. The current working directory usually is the directory in which you started the program. In your case, the file test.rtf must be in the same directory in which you execute the program.
You are obviously performing programming tasks in Python under Mac OS. There, I recommend to work in the terminal (on the command line), i.e. start the terminal, cd to the directory where your input file is located and start the Python script there using the command
$ python script.py
In order to make this work, the directory containing the python executable must be in the PATH, a so-called environment variable that contains directories that are automatically used for searching executables when you enter a command. You should make use of this, because it simplifies daily work greatly. That way, you can simply cd to the directory containing your Python script file and run it.
In any case, if your Python script file and your data input file are not in the same directory, you always have to specify either a relative path between them or you have to use an absolute path for one of them.
Is test.rtf located in the same directory you're in when you run this?
If not, you'll need to provide the full path to that file.
Suppose it's located in
/Users/AshleyStallings/Documents/School Work/Computer Programming/Side Projects/data
In that case you'd enter
data/test.rtf
as your file name
Or it could be in
/Users/AshleyStallings/Documents/School Work/Computer Programming/some_other_folder
In that case you'd enter
../some_other_folder/test.rtf
As noted above the problem is in specifying the path to your file.
The default path in OS X is your home directory (/Users/macbook represented by ~ in terminal ...you can change or rename the home directory with the advanced options in System Preferences > Users & Groups).
Or you can specify the path from the drive to your file in the filename:
path = "/Users/macbook/Documents/MyPython/"
myFile = path + fileName
You can also catch the File Not Found Error and give another response using try:
try:
with open(filename) as f:
sequences = pick_lines(f)
except FileNotFoundError:
print("File not found. Check the path variable and filename")
exit()
A good start would be validating the input. In other words, you can make sure that the user has indeed typed a correct path for a real existing file, like this:
import os
fileName = input("Please enter the name of the file you'd like to use.")
while not os.path.isfile(fileName):
fileName = input("Whoops! No such file! Please enter the name of the file you'd like to use.")
This is with a little help from the built in module os, That is a part of the Standard Python Library.
You might need to change your path by:
import os
path=os.chdir(str('Here_should_be_the_path_to_your_file')) #This command changes directory
This is what worked for me at least! Hope it works for you too!
Difficult to give code examples in the comments.
To read the words in the file, you can read the contents of the file, which gets you a string - this is what you were doing before, with the read() method - and then use split() to get the individual words.
Split breaks up a String on the delimiter provided, or on whitespace by default. For example,
"the quick brown fox".split()
produces
['the', 'quick', 'brown', 'fox']
Similarly,
fileScan.read().split()
will give you an array of Strings.
Hope that helps!
First check what's your file format(e.g: .txt, .json, .csv etc ),
If your file present in PWD , then just give the name of the file along with the file format inside either single('')or double("") quote and the appropriate operation mode as your requirement
e.g:
with open('test.txt','r') as f: data=f.readlines() for i in data: print(i)
If your file present in other directory, then just give the full path name where is your file is present and file name along with file format of the file inside either single('')or double("") quote and the appropriate operation mode as your requirement.
If it showing unicode error just put either r before quote of file path or else put '/' instead of ''
with open(r'C:\Users\soman\Desktop\test.txt','r') as f: data=f.readlines() for i in data: print(i)
The mistake I did was
my code :
x = open('python.txt')
print(x)
But the problem was in file directory ,I saved it as python.txt instead of just python .
So my file path was
->C:\Users\noob\Desktop\Python\Course 2\python.txt.txt
That is why it was giving a error.
Name your file without .txt it will run.
Related
I am quite new to working with Python files, and having a small issue. I am simply trying to print the name of a text file and its 'mode'.
Here is my code:
f = open('test.txt','r')
print(f.name)
print(f.mode)
f.close()
I have a saved a text file called 'test.txt' in the same directory as where I wrote the above code.
However, when I run the code, I get the following file not found error:
FileNotFoundError: [Errno 2] No such file or directory: 'test.txt'
Any ideas what is causing this?
I have also tried to replace the first argument above with the path of the test.txt file, but I get the same error?
open (on pretty much any operating system) doesn't care where your program lies, but from which directory you are running it. (This is not specific to python, but how file operations work, and what a current working directory is.)
So, this is expected. You need to run python from the directory that test.txt is in.
I have also tried to replace the first argument above with the path of the test.txt file, but I get the same error?
In that case, you must have mistyped the path. Make sure there's no special characters (like backslashes) that python interprets specially in there, or use the raw string format r'...' instead of just '...'.
It depend from where the python command is launched for instance :
let suppose we have this 2 files :
dir1/dir2/code.py <- your code
dir1/dir2/test.txt
if you run your python commande from the dir1 directory it will not work because it will search for dir1/test.txt
you need to run the python commande from the same directory(dir2 in the example).
This question already has answers here:
open() gives FileNotFoundError / IOError: '[Errno 2] No such file or directory'
(8 answers)
Closed 7 months ago.
I'm trying to write a simple program to read a file and search for a word then print how many times that word is found in the file. Every time I type in "test.rtf" (which is the name of my document) I get this error:
Traceback (most recent call last):
File "/Users/AshleyStallings/Documents/School Work/Computer Programming/Side Projects/How many? (Python).py", line 9, in <module>
fileScan= open(fileName, 'r') #Opens file
FileNotFoundError: [Errno 2] No such file or directory: 'test.rtf'
In class last semester, I remember my professor saying you have to save the file in a specific place? I'm not sure if he really said that though, but I'm running apple OSx if that helps.
Here's the important part of my code:
fileName= input("Please enter the name of the file you'd like to use.")
fileScan= open(fileName, 'r') #Opens file
If the user does not pass the full path to the file (on Unix type systems this means a path that starts with a slash), the path is interpreted relatively to the current working directory. The current working directory usually is the directory in which you started the program. In your case, the file test.rtf must be in the same directory in which you execute the program.
You are obviously performing programming tasks in Python under Mac OS. There, I recommend to work in the terminal (on the command line), i.e. start the terminal, cd to the directory where your input file is located and start the Python script there using the command
$ python script.py
In order to make this work, the directory containing the python executable must be in the PATH, a so-called environment variable that contains directories that are automatically used for searching executables when you enter a command. You should make use of this, because it simplifies daily work greatly. That way, you can simply cd to the directory containing your Python script file and run it.
In any case, if your Python script file and your data input file are not in the same directory, you always have to specify either a relative path between them or you have to use an absolute path for one of them.
Is test.rtf located in the same directory you're in when you run this?
If not, you'll need to provide the full path to that file.
Suppose it's located in
/Users/AshleyStallings/Documents/School Work/Computer Programming/Side Projects/data
In that case you'd enter
data/test.rtf
as your file name
Or it could be in
/Users/AshleyStallings/Documents/School Work/Computer Programming/some_other_folder
In that case you'd enter
../some_other_folder/test.rtf
As noted above the problem is in specifying the path to your file.
The default path in OS X is your home directory (/Users/macbook represented by ~ in terminal ...you can change or rename the home directory with the advanced options in System Preferences > Users & Groups).
Or you can specify the path from the drive to your file in the filename:
path = "/Users/macbook/Documents/MyPython/"
myFile = path + fileName
You can also catch the File Not Found Error and give another response using try:
try:
with open(filename) as f:
sequences = pick_lines(f)
except FileNotFoundError:
print("File not found. Check the path variable and filename")
exit()
A good start would be validating the input. In other words, you can make sure that the user has indeed typed a correct path for a real existing file, like this:
import os
fileName = input("Please enter the name of the file you'd like to use.")
while not os.path.isfile(fileName):
fileName = input("Whoops! No such file! Please enter the name of the file you'd like to use.")
This is with a little help from the built in module os, That is a part of the Standard Python Library.
You might need to change your path by:
import os
path=os.chdir(str('Here_should_be_the_path_to_your_file')) #This command changes directory
This is what worked for me at least! Hope it works for you too!
Difficult to give code examples in the comments.
To read the words in the file, you can read the contents of the file, which gets you a string - this is what you were doing before, with the read() method - and then use split() to get the individual words.
Split breaks up a String on the delimiter provided, or on whitespace by default. For example,
"the quick brown fox".split()
produces
['the', 'quick', 'brown', 'fox']
Similarly,
fileScan.read().split()
will give you an array of Strings.
Hope that helps!
First check what's your file format(e.g: .txt, .json, .csv etc ),
If your file present in PWD , then just give the name of the file along with the file format inside either single('')or double("") quote and the appropriate operation mode as your requirement
e.g:
with open('test.txt','r') as f: data=f.readlines() for i in data: print(i)
If your file present in other directory, then just give the full path name where is your file is present and file name along with file format of the file inside either single('')or double("") quote and the appropriate operation mode as your requirement.
If it showing unicode error just put either r before quote of file path or else put '/' instead of ''
with open(r'C:\Users\soman\Desktop\test.txt','r') as f: data=f.readlines() for i in data: print(i)
The mistake I did was
my code :
x = open('python.txt')
print(x)
But the problem was in file directory ,I saved it as python.txt instead of just python .
So my file path was
->C:\Users\noob\Desktop\Python\Course 2\python.txt.txt
That is why it was giving a error.
Name your file without .txt it will run.
I'm trying to build a file transfer system with python3 sockets. I have the connection and sending down but my issue right now is that the file being sent has to be in the same directory as the program, and when you receive the file, it just puts the file into the same directory as the program. How can I get a user to input the location of the file to be sent and select the location of the file to be sent to?
I assume you're opening files with:
open("filename","r")
If you do not provide an absolute path, the open function will always default to a relative path. So, if I wanted to open a file such as /mnt/storage/dnd/5th_edition.txt, I would have to use:
open("/mnt/storage/dnd/4p5_edition","r")
And if I wanted to copy this file to /mnt/storage/trash/ I would have to use the absolute path as well:
open("/mnt/storage/trash/4p5_edition","w")
If instead, I decided to use this:
open("mnt/storage/trash/4p5_edition","w")
Then I would get an IOError if there wasn't a directory named mnt with the directories storage/trash in my present folder. If those folders did exist in my present folder, then it would end up in /whatever/the/path/is/to/my/current/directory/mnt/storage/trash/4p5_edition, rather than /mnt/storage/trash/4p5_edition.
since you said that the file will be placed in the same path where the program is, the following code might work
import os
filename = "name.txt"
f = open(os.path.join(os.path.dirname(__file__),filename))
Its pretty simple just get the path from user
subpath = raw_input("File path = ")
print subpath
file=open(subpath+str(file_name),'w+')
file.write(content)
file.close()
I think thats all you need let me know if you need something else.
like you say, the file should be in the same folder of the project so you have to replace it, or to define a function that return the right file path into your open() function, It's a way that you can use to reduce the time of searching a solution to your problem brother.
It should be something like :
import os
filename = "the_full_path_of_the_fil/name.txt"
f = open(os.path.join(os.path.dirname(__file__),filename))
then you can use the value of the f variable as a path to the directory of where the file is in.
I have a very elementary question, but I've tried searching past posts and can't seem to find anything that can help. I'm learning about file i/o in Python. All the tutorials I've seen thus far seem to skip a step and just assume that a file has already been created, and just being by saying something like handleName = open('text.txt', 'r'), but this leaves 2 questions unanswered for me:
Do I have to create the file manually and name it? I'm using a Mac, so would I have to go to Applications, open up TextEdit, create and save the file or would I be able to do that through some command in IDLE?
I tried manually creating a file (as described above), but then when I tried entering openfile = open('test_readline', 'r'), I got the error: IOError: [Errno 2] No such file or directory: 'abc'
Regarding the error, I'm assuming I have to declare the path, but how do I do so in Python?
openfile = open('test_readline', 'w')
^^
Opening in write mode will create the file if it doesn't already exist. Now you can write into it and close the file pointer and it will be saved.
To be able to read from any file, the file must exist.Right? Now look here, file I/O has the syntax as shown below:
fp = open('file_name', mode) # fp is a file object
The second argument, i.e mode describes the way in which file will be used. w mode will open any existing file(if it exists) with the name as given in first argument. Otherwise it creates a new file with the same name. Beside, if you are on Windows and want to open a file in binary mode then append b to the mode. Eg. to open file to write in binary mode, use wb. Make a note that if you try to open any existing file in w (writing) mode then the existing file with the same name will be erased. If you want to write to the existing file without getting the old data erased, then use the a mode.It adds the new data at the end of the previous one.
fw = open('file_name','w')
fa = open('file_name','a') # append mode
To know in detail you can refer the doc at
Python File I/O.
I hope this helps!
Python will automatically use the default path.
import os
default_path = os.getcwd() ## Returns the default path
new_path = "C:\\project\\" ## Path directory
os.chdir(path) ## Changes the current directory
Once you change the path, the files you write and read will be in C:\project. If you try and read a project else where, the program will fail.
os.chdir is how you declare or set a path in python.
Do I have to create the file manually and name it?
Do you mean as a user, must you use existing tools to create a file, then return to Python to work on it? No. Python has all the tools necessary to create a file. As already explained by vks in their answer, you must open the file using a mode that will create the file if it doesn't exist. You've chosen read ('r') mode, which will (correctly) throw an error if there is no file to read at the location you've specified, which brings us to...
I'm assuming I have to declare the path, but how do I do so in Python?
If you do not (if you say, e.g., "filename.txt"), Python will look in its current working directory. By default, this is the current working directory of the shell when you invoke the Python interpreter. This is almost always true unless some program has changed it, which is unusual. To specify the path, you can either hardcode it like you're doing to the filename:
open('/full/path/to/filename.txt')
or you can build it using the os.path module.
Example:
I created an empty directory and opened the Python interpreter in it.
>>> with open('test.txt'): pass
...
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IOError: [Errno 2] No such file or directory: 'test.txt'
>>> with open('test.txt', 'w'): pass
...
>>>
As noted, read mode (the default) gives an error because there is no file. Write mode creates a file for us with nothing in it. Now we can see the file in the directory, and opening with read mode works:
>>> os.listdir(os.getcwd())
['test.txt']
>>> with open('test.txt'): pass
...
>>> # ^ No IOError because it exists now
Now I create a subdirectory called 'subdir' and move the text file in there. I did this on the command line but could have just as easily done it in Python:
>>> with open('test.txt'): pass
...
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IOError: [Errno 2] No such file or directory: 'test.txt'
>>> with open('subdir/test.txt'): pass
...
Now we have to specify the relative path (at least) to open the file, just like on the command line. Here I "hardcoded" it but it can just as easily be "built up" using the os module:
>>> with open(os.path.join(os.getcwd(), 'subdir', 'test.txt')): pass
(That is just one way it could be done, as an example.)
I am having issues reading in a file. I prompt the user to load a file and then use the input as an argument in a function which simply attempts to load the given filename and print each line.
I am receiving an IOError: No such file or directory: 'filename.txt'
filename = raw_input("Filename to load: ")
print load_records(students, filename)
def load_records(students, filename):
#loads student records from a file
records = []
in_file = open(filename, "r")
for line in in_file:
print line
I suspect that I am not accessing the correct directory.
Given the error, I will conclude that you typed nothing but filename.txt when prompted. This will cause Python to search for a file named filename.txt in the current directory. So if your command prompt's current directory is C:\dev, this is equivalent to C:\dev\filename.txt (the absolute path). You should either change the current directory to the directory containing filename.txt or specific the absolute path when prompted. The latter would probably be simpler as it wouldn't be as likely to mess up Python's ability to find your other modules.