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Get WinWord version from Python program

in one simple Python program for testing users environment, I should also get version of installed Word (example: WinWord 16, 64-bit).
Any idea how to do that? I'm sure, that different GUIDs should exist, but where can I find them :-)
**** edit
I checked both suggestions, but it isn't enough. I have to get an information if Word is 32- or 64-bit. Until now, I have checked location of "winword.exe". For example: 1. location for 64-bit Office 15 c:\program files\microsoft office\office15\winword.exe 2. location for 32-bit Office 15 c:\program files (x86)\microsoft office\office15\winword.exe
I'm sure that M$ has list of GUIDs (used in registry) for latest versions of Word. But I can't find the list :-) With suggested solutions, I can't check 32- or 64- technology.

Searching shorcuts with architecture detection (32-bit or 64-bit)
I figured the additional information would be useful, but you can reduce it to just 32-bit and 64-bit.
import subprocess, os, struct
def getWordVersion():
directory = "C:\\ProgramData\\Microsoft\\Windows\\Start Menu\\Programs"
wordFile = ""
wordVersion = ""
def recursiveSearch(directory):
for root, dirs, filenames in os.walk(directory):
for dire in dirs:
result = recursiveSearch(root + "\\" + dire)
if result:
return result
for filename in filenames:
if filename.endswith(".lnk") and filename.startswith("Word "):
wordFile = root + "\\" + filename
wordVersion = filename[:-4]
return wordFile, wordVersion
return False
wordFile, wordVersion = recursiveSearch(directory)
lnkTarget = subprocess.check_output(["C:\\WINDOWS\\system32\\WindowsPowerShell\\v1.0\\powershell.exe",
"(New-Object -ComObject WScript.Shell).CreateShortcut('" + wordFile + "').TargetPath"],shell=True)
locationOfLnk = lnkTarget.strip()
IMAGE_FILE_MACHINE_I386=332
IMAGE_FILE_MACHINE_IA64=512
IMAGE_FILE_MACHINE_AMD64=34404
f=open(locationOfLnk, "rb")
f.seek(60)
s=f.read(4)
header_offset=struct.unpack("<L", s)[0]
f.seek(header_offset+4)
s=f.read(2)
machine=struct.unpack("<H", s)[0]
architecture = ""
if machine==IMAGE_FILE_MACHINE_I386:
architecture = "IA-32 (32-bit x86)"
elif machine==IMAGE_FILE_MACHINE_IA64:
architecture = "IA-64 (Itanium)"
elif machine==IMAGE_FILE_MACHINE_AMD64:
architecture = "AMD64 (64-bit x86)"
else:
architecture = "Unknown architecture"
f.close()
return wordVersion + " " + architecture
print(getWordVersion())
Registry Method
A method is to loop through all registry keys under Office and find the most recent one. Unfortunately, Microsoft decided it was a great idea to change the install directory in nearly every version. So, if you want to compile a complete list of all install locations, that'd work to (unless they installed it at a custom location).
Note: This is Python 3 code, if you need Python 2, then change winreg to _winreg.
import winreg
def getMicrosoftWordVersion():
key = winreg.OpenKey(winreg.HKEY_LOCAL_MACHINE, "SOFTWARE\\Microsoft\\Office", 0, winreg.KEY_READ)
versionNum = 0
i = 0
while True:
try:
subkey = winreg.EnumKey(key, i)
i+=1
if versionNum < float(subkey):
versionNum = float(subkey)
except: #relies on error handling WindowsError as e as well as type conversion when we run out of numbers
break
return versionNum
print(getMicrosoftWordVersion())

Another way is using OLE/ActiveX/COM technology. This is a some kind of high-level version of provided "registry method".
Assuming you're on Windows machine since this will not work on Linux in most cases:
#!/usr/bin/env python3
from win32com.client.dynamic import Dispatch
word = Dispatch('Word.Application')
print (word)
word_version = word.version
print (word_version)
Create virtualenv: $ python -m venv ve
Activate virtualenv: $ ve\Scripts\activate.bat
Install pypiwin32: (ve)$ pip install pypiwin32
Execute: (ve)$ python detect_msword_version.py
On my Windows machine output was:
Microsoft Word
16.0

python - Finding the user's "Downloads" folder

I already found this question that suggests to use os.path.expanduser(path) to get the user's home directory.
I would like to achieve the same with the "Downloads" folder. I know that this is possible in C#, yet I'm new to Python and don't know if this is possible here too, preferable platform-independent (Windows, Ubuntu).
I know that I just could do download_folder = os.path.expanduser("~")+"/Downloads/", yet (at least in Windows) it is possible to change the Default download folder.

from pathlib import Path
downloads_path = str(Path.home() / "Downloads")

This fairly simple solution (expanded from this reddit post) worked for me
import os
def get_download_path():
"""Returns the default downloads path for linux or windows"""
if os.name == 'nt':
import winreg
sub_key = r'SOFTWARE\Microsoft\Windows\CurrentVersion\Explorer\Shell Folders'
downloads_guid = '{374DE290-123F-4565-9164-39C4925E467B}'
with winreg.OpenKey(winreg.HKEY_CURRENT_USER, sub_key) as key:
location = winreg.QueryValueEx(key, downloads_guid)[0]
return location
else:
return os.path.join(os.path.expanduser('~'), 'downloads')
The GUID can be obtained from Microsoft's KNOWNFOLDERID docs
This can be expanded to work more generically other directories

For python3+ mac or linux
from pathlib import Path
path_to_download_folder = str(os.path.join(Path.home(), "Downloads"))

Correctly locating Windows folders is somewhat of a chore in Python. According to answers covering Microsoft development technologies, such as this one, they should be obtained using the Vista Known Folder API. This API is not wrapped by the Python standard library (though there is an issue from 2008 requesting it), but one can use the ctypes module to access it anyway.
Adapting the above answer to use the folder id for downloads shown here and combining it with your existing Unix code should result in code that looks like this:
import os
if os.name == 'nt':
import ctypes
from ctypes import windll, wintypes
from uuid import UUID
# ctypes GUID copied from MSDN sample code
class GUID(ctypes.Structure):
_fields_ = [
("Data1", wintypes.DWORD),
("Data2", wintypes.WORD),
("Data3", wintypes.WORD),
("Data4", wintypes.BYTE * 8)
]
def __init__(self, uuidstr):
uuid = UUID(uuidstr)
ctypes.Structure.__init__(self)
self.Data1, self.Data2, self.Data3, \
self.Data4[0], self.Data4[1], rest = uuid.fields
for i in range(2, 8):
self.Data4[i] = rest>>(8-i-1)*8 & 0xff
SHGetKnownFolderPath = windll.shell32.SHGetKnownFolderPath
SHGetKnownFolderPath.argtypes = [
ctypes.POINTER(GUID), wintypes.DWORD,
wintypes.HANDLE, ctypes.POINTER(ctypes.c_wchar_p)
]
def _get_known_folder_path(uuidstr):
pathptr = ctypes.c_wchar_p()
guid = GUID(uuidstr)
if SHGetKnownFolderPath(ctypes.byref(guid), 0, 0, ctypes.byref(pathptr)):
raise ctypes.WinError()
return pathptr.value
FOLDERID_Download = '{374DE290-123F-4565-9164-39C4925E467B}'
def get_download_folder():
return _get_known_folder_path(FOLDERID_Download)
else:
def get_download_folder():
home = os.path.expanduser("~")
return os.path.join(home, "Downloads")
A more complete module for retrieving known folders from Python is available on github.

Some linux distributions localize the name of the Downloads folder. E.g. after changing my locale to zh_TW, the Downloads folder became /home/user/下載. The correct way on linux distributions (using xdg-utils from freedesktop.org) is to call xdg-user-dir:
import subprocess
# Copy windows part from other answers here
try:
folder = subprocess.run(["xdg-user-dir", "DOWNLOAD"],
capture_output=True, text=True).stdout.strip("\n")
except FileNotFoundError: # if the command is missing
import os.path
folder = os.path.expanduser("~/Downloads") # fallback
Note that the use of capture_output requires Python ≥3.7.
If you already use GLib or don't mind adding more dependencies, see also
these approaches using packages.

For python3 on windows try:
import os
folder = os.path.join(os.path.join(os.environ['USERPROFILE']), 'folder_name')
print(folder)

How to create symlinks in windows using Python?

I am trying to create symlinks using Python on Windows 8. I found This Post and this is part of my script.
import os
link_dst = unicode(os.path.join(style_path, album_path))
link_src = unicode(album_path)
kdll = ctypes.windll.LoadLibrary("kernel32.dll")
kdll.CreateSymbolicLinkW(link_dst, link_src, 1)
Firstly, It can create symlinks only when it is executed through administrator cmd. Why is that happening?
Secondly, When I am trying to open those symlinks from windows explorer I get This Error:
...Directory is not accessible. The Name Of The File Cannot Be Resolved By The System.
Is there a better way of creating symlinks using Python? If not, How can I solve this?
EDIT
This is the for loop in album_linker:
def album_Linker(album_path, album_Genre, album_Style):
genre_basedir = "E:\Music\#02.Genre"
artist_basedir = "E:\Music\#03.Artist"
release_data_basedir = "E:\Music\#04.ReleaseDate"
for genre in os.listdir(genre_basedir):
genre_path = os.path.join(genre_basedir, "_" + album_Genre)
if not os.path.isdir(genre_path):
os.mkdir(genre_path)
album_Style_list = album_Style.split(', ')
print album_Style_list
for style in album_Style_list:
style_path = os.path.join(genre_path, "_" + style)
if not os.path.isdir(style_path):
os.mkdir(style_path)
album_path_list = album_path.split("_")
print album_path_list
#link_dst = unicode(os.path.join(style_path, album_path_list[2] + "_" + album_path_list[1] + "_" + album_path_list[0]))
link_dst = unicode(os.path.join(style_path, album_path))
link_src = unicode(album_path)
kdll = ctypes.windll.LoadLibrary("kernel32.dll")
kdll.CreateSymbolicLinkW(link_dst, link_src, 1)
It takes album_Genre and album_Style And then It creates directories under E:\Music\#02.Genre . It also takes album_path from the main body of the script. This album_path is the path of directory which i want to create the symlink under E:\Music\#02.Genre\Genre\Style . So album_path is a variable taken from another for loop in the main body of the script
for label in os.listdir(basedir):
label_path = os.path.join(basedir, label)
for album in os.listdir(label_path):
album_path = os.path.join(label_path, album)
if not os.path.isdir(album_path):
# Not A Directory
continue
else:
# Is A Directory
os.mkdir(os.path.join(album_path + ".copy"))
# Let Us Count
j = 1
z = 0
# Change Directory
os.chdir(album_path)

Firstly, It can create symlinks only when it is executed through administrator cmd.
Users need "Create symbolic links" rights to create a symlink. By default, normal users don't have it but administrator does. One way to change that is with the security policy editor. Open a command prompt as administrator, run secpol.msc and then go to Security Settings\Local Policies\User Rights Assignment\Create symbolic links to make the change.
Secondly, When I am trying to open those symlinks from windows explorer I get This Error:
You aren't escaping the backslashes in the file name. Just by adding an "r" to the front for a raw string, the file name changes. You are setting a non-existant file name and so explorer can't find it.
>>> link_dst1 = "E:\Music\#02.Genre_Electronic_Bass Music\1-800Dinosaur-1-800-001_[JamesBlake-Voyeur(Dub)AndHolyGhost]_2013-05-00"
>>> link_dst2 = r"E:\Music\#02.Genre_Electronic_Bass Music\1-800Dinosaur-1-800-001_[JamesBlake-Voyeur(Dub)AndHolyGhost]_2013-05-00"
>>> link_dst1 == link_dst2
False
>>> print link_dst1
E:\Music\#02.Genre_Electronic_Bass Music☺-800Dinosaur-1-800-001_[JamesBlake-Voyeur(Dub)AndHolyGhost]_2013-05-00

os.symlink works out of the box since python 3.8 on windows, as long as Developer Mode is turned on.

If you're just trying to create a link to a directory, you could also create a "Junction", no admin privileges required:
import os
import _winapi
src_dir = "C:/Users/joe/Desktop/my_existing_folder"
dst_dir = "C:/Users/joe/Desktop/generated_link"
src_dir = os.path.normpath(os.path.realpath(src_dir))
dst_dir = os.path.normpath(os.path.realpath(dst_dir))
if not os.path.exists(dst_dir):
os.makedirs(os.path.dirname(dst_dir), exist_ok=True)
_winapi.CreateJunction(src_dir, dst_dir)

How to create a shortcut in startmenu using setuptools windows installer

I want to create a start menu or Desktop shortcut for my Python windows installer package. I am trying to follow https://docs.python.org/3.4/distutils/builtdist.html#the-postinstallation-script
Here is my script;
import sys
from os.path import dirname, join, expanduser
pyw_executable = sys.executable.replace('python.exe','pythonw.exe')
script_file = join(dirname(pyw_executable), 'Scripts', 'tklsystem-script.py')
w_dir = expanduser(join('~','lsf_files'))
print(sys.argv)
if sys.argv[1] == '-install':
print('Creating Shortcut')
create_shortcut(
target=pyw_executable,
description='A program to work with L-System Equations',
filename='L-System Tool',
arguments=script_file,
workdir=wdir
)
I also specified this script in scripts setup option, as indicated by aforementioned docs.
Here is the command I use to create my installer;
python setup.py bdist_wininst --install-script tklsystem-post-install.py
After I install my package using created windows installer, I can't find where my shorcut is created, nor I can confirm whether my script run or not?
How can I make setuptools generated windows installer to create desktop or start menu shortcuts?

Like others have commented here and elsewhere the support functions don't seem to work at all (at least not with setuptools). After a good day's worth of searching through various resources I found a way to create at least the Desktop shortcut. I'm sharing my solution (basically an amalgam of code I found here and here). I should add that my case is slightly different from yasar's, because it creates a shortcut to an installed package (i.e. an .exe file in Python's Scripts directory) instead of a script.
In short, I added a post_install function to my setup.py, and then used the Python extensions for Windows to create the shortcut. The location of the Desktop folder is read from the Windows registry (there are other methods for this, but they can be unreliable if the Desktop is at a non-standard location).
#!/usr/bin/env python
import os
import sys
import sysconfig
if sys.platform == 'win32':
from win32com.client import Dispatch
import winreg
def get_reg(name,path):
# Read variable from Windows Registry
# From https://stackoverflow.com/a/35286642
try:
registry_key = winreg.OpenKey(winreg.HKEY_CURRENT_USER, path, 0,
winreg.KEY_READ)
value, regtype = winreg.QueryValueEx(registry_key, name)
winreg.CloseKey(registry_key)
return value
except WindowsError:
return None
def post_install():
# Creates a Desktop shortcut to the installed software
# Package name
packageName = 'mypackage'
# Scripts directory (location of launcher script)
scriptsDir = sysconfig.get_path('scripts')
# Target of shortcut
target = os.path.join(scriptsDir, packageName + '.exe')
# Name of link file
linkName = packageName + '.lnk'
# Read location of Windows desktop folder from registry
regName = 'Desktop'
regPath = r'Software\Microsoft\Windows\CurrentVersion\Explorer\User Shell Folders'
desktopFolder = os.path.normpath(get_reg(regName,regPath))
# Path to location of link file
pathLink = os.path.join(desktopFolder, linkName)
shell = Dispatch('WScript.Shell')
shortcut = shell.CreateShortCut(pathLink)
shortcut.Targetpath = target
shortcut.WorkingDirectory = scriptsDir
shortcut.IconLocation = target
shortcut.save()
setup(name='mypackage',
...,
...)
if sys.argv[1] == 'install' and sys.platform == 'win32':
post_install()
Here's a link to a full setup script in which I used this:
https://github.com/KBNLresearch/iromlab/blob/master/setup.py

If you want to confirm whether the script is running or not, you can print to a file instead of the console. Looks like text you print to console in the post-install script won't show up.
Try this:
import sys
from os.path import expanduser, join
pyw_executable = join(sys.prefix, "pythonw.exe")
shortcut_filename = "L-System Toolsss.lnk"
working_dir = expanduser(join('~','lsf_files'))
script_path = join(sys.prefix, "Scripts", "tklsystem-script.py")
if sys.argv[1] == '-install':
# Log output to a file (for test)
f = open(r"C:\test.txt",'w')
print('Creating Shortcut', file=f)
# Get paths to the desktop and start menu
desktop_path = get_special_folder_path("CSIDL_COMMON_DESKTOPDIRECTORY")
startmenu_path = get_special_folder_path("CSIDL_COMMON_STARTMENU")
# Create shortcuts.
for path in [desktop_path, startmenu_path]:
create_shortcut(pyw_executable,
"A program to work with L-System Equations",
join(path, shortcut_filename),
script_path,
working_dir)

At least with Python 3.6.5, 32bit on Windows, setuptools does work for this. But based on the accepted answer, by trial and error I found some issues that may have caused your script to fail to do what you wanted.
create_shortcut does not accept keyword arguments, only positional, so its usage in your code is invalid
You must add a .lnk extension for Windows to recognise the shortcut
I found sys.executable will be the name of the installer executable, not the python executable
As mentioned, you can't see stdout or stderr so you might want to log to a text file. I would suggest also redirecting sys.stdout and sys.stderr to the log file.
(Maybe not relevant) as mentioned in this question there appears to be a bug with the version string generated by bdist_wininst. I used the hexediting hack from an answer there to work around this. The location in the answer is not the same, you have to find the -32 yourself.
Full example script:
import sys
import os
import datetime
global datadir
datadir = os.path.join(get_special_folder_path("CSIDL_APPDATA"), "mymodule")
def main(argv):
if "-install" in argv:
desktop = get_special_folder_path("CSIDL_DESKTOPDIRECTORY")
print("Desktop path: %s" % repr(desktop))
if not os.path.exists(datadir):
os.makedirs(datadir)
dir_created(datadir)
print("Created data directory: %s" % repr(datadir))
else:
print("Data directory already existed at %s" % repr(datadir))
shortcut = os.path.join(desktop, "MyModule.lnk")
if os.path.exists(shortcut):
print("Remove existing shortcut at %s" % repr(shortcut))
os.unlink(shortcut)
print("Creating shortcut at %s...\n" % shortcut)
create_shortcut(
r'C:\Python36\python.exe',
"MyModuleScript",
shortcut,
"",
datadir)
file_created(shortcut)
print("Successfull!")
elif "-remove" in sys.argv:
print("Removing...")
pass
if __name__ == "__main__":
logfile = r'C:\mymodule_install.log' # Fallback location
if os.path.exists(datadir):
logfile = os.path.join(datadir, "install.log")
elif os.environ.get("TEMP") and os.path.exists(os.environ.get("TEMP"),""):
logfile = os.path.join(os.environ.get("TEMP"), "mymodule_install.log")
with open(logfile, 'a+') as f:
f.write("Opened\r\n")
f.write("Ran %s %s at %s" % (sys.executable, " ".join(sys.argv), datetime.datetime.now().isoformat()))
sys.stdout = f
sys.stderr = f
try:
main(sys.argv)
except Exception as e:
raise
f.close()
sys.exit(0)

UPD: on an off chance that the client machine has pywin32 installed, we try in-process creation first. Somewhat cleaner that way.
Here is another take. This assumes the package is called myapp, and that also becomes the executable that you want a shortcut to. Substitute your own package name and your own shortcut text.
Uses a Windows Scripting Host COM class - in process if possible, inside a Powershell command line as a subprocess if not. Tested on Python 3.6+.
from setuptools import setup
from setuptools.command.install import install
import platform, sys, os, site
from os import path, environ
def create_shortcut_under(root, exepath):
# Root is an env variable name -
# either ALLUSERSPROFILE for the all users' Start menu,
# or APPDATA for the current user specific one
profile = environ[root]
linkpath = path.join(profile, "Microsoft", "Windows", "Start Menu", "Programs", "My Python app.lnk")
try:
from win32com.client import Dispatch
from pywintypes import com_error
try:
sh = Dispatch('WScript.Shell')
link = sh.CreateShortcut(linkpath)
link.TargetPath = exepath
link.Save()
return True
except com_error:
return False
except ImportError:
import subprocess
s = "$s=(New-Object -COM WScript.Shell).CreateShortcut('" + linkpath + "');$s.TargetPath='" + exepath + "';$s.Save()"
return subprocess.call(['powershell', s], stdout = subprocess.DEVNULL, stderr = subprocess.DEVNULL) == 0
def create_shortcut(inst):
try:
exepath = path.join(path.dirname(sys.executable), "Scripts", "myapp.exe")
if not path.exists(exepath):
# Support for "pip install --user"
exepath = path.join(path.dirname(site.getusersitepackages()), "Scripts", "myapp.exe")
# If can't modify the global menu, fall back to the
# current user's one
if not create_shortcut_under('ALLUSERSPROFILE', exepath):
create_shortcut_under('APPDATA', exepath)
except:
pass
class my_install(install):
def run(self):
install.run(self)
if platform.system() == 'Windows':
create_shortcut(self)
#...
setup(
#...
cmdclass={'install': my_install},
entry_points={"gui_scripts": ["myapp = myapp.__main__:main"]},

Python: Getting AppData folder in a cross-platform way

I'd like a code snippet that gets the proper directory for app data (config files, etc) on all platforms (Win/Mac/Linux at least). For example: %APPDATA%/ on Windows.

If you don't mind using the appdirs module, it should solve your problem. (cost = you either need to install the module or include it directly in your Python application.)

Qt's QStandardPaths documentation lists paths like this.
Using Python 3.8
import sys
import pathlib
def get_datadir() -> pathlib.Path:
"""
Returns a parent directory path
where persistent application data can be stored.
# linux: ~/.local/share
# macOS: ~/Library/Application Support
# windows: C:/Users/<USER>/AppData/Roaming
"""
home = pathlib.Path.home()
if sys.platform == "win32":
return home / "AppData/Roaming"
elif sys.platform == "linux":
return home / ".local/share"
elif sys.platform == "darwin":
return home / "Library/Application Support"
# create your program's directory
my_datadir = get_datadir() / "program-name"
try:
my_datadir.mkdir(parents=True)
except FileExistsError:
pass
The Python documentation recommends the sys.platform.startswith('linux') "idiom" for compatibility with older versions of Python that returned things like "linux2" or "linux3".

You can use the following function to get user data dir, tested in linux and w10 (returning AppData/Local dir) it's adapted from the appdirs package:
import sys
from pathlib import Path
from os import getenv
def get_user_data_dir(appname):
if sys.platform == "win32":
import winreg
key = winreg.OpenKey(
winreg.HKEY_CURRENT_USER,
r"Software\Microsoft\Windows\CurrentVersion\Explorer\Shell Folders"
)
dir_,_ = winreg.QueryValueEx(key, "Local AppData")
ans = Path(dir_).resolve(strict=False)
elif sys.platform == 'darwin':
ans = Path('~/Library/Application Support/').expanduser()
else:
ans=Path(getenv('XDG_DATA_HOME', "~/.local/share")).expanduser()
return ans.joinpath(appname)

I recommend researching the locations of 'appdata' in the operating systems that you want to use this program on. Once you know the locations you could simple use if statements to detect the os and do_something().
import sys
if sys.platform == "platform_value":
do_something()
elif sys.platform == "platform_value":
do_something()
System: platform_value
Linux (2.x and 3.x): 'linux2'
Windows: 'win32'
Windows/Cygwin: 'cygwin'
Mac OS X: 'darwin'
OS/2: 'os2'
OS/2 EMX: 'os2emx'
RiscOS: 'riscos'
AtheOS: 'atheos'
List is from the official Python docs. (Search for 'sys.platform')

You can use module called appdata:
pip install appdata
from appdata import AppDataPaths
app_paths = AppDataPaths()
app_paths.app_data_path # cross-platform path to AppData folder
Original question - How can I get the path to the %APPDATA% directory in Python?
Original answer - https://stackoverflow.com/a/70411576/9543830

I came across a similar problem and I wanted to dynamically resolve all of the Windows % paths without knowing about them prior. You can use os.path.expandvars to resolve the paths dynamically. Something like this:
from os import path
appdatapath = '%APPDATA%\MyApp'
if '%' in appdatapath:
appdatapath = path.expandvars(appdatapath)
print(appdatapath)
The line at the end will print: C:\Users\\{user}\AppData\Roaming\MyApp
This works for windows however I have not tested on Linux. So long as the paths are defined by the environment than expandvars should be able to find it. You can read more about expand vars here.

If you are after the config directory here is a solution that defaults to ~/.config unless a platform specific (sys.platform) entry is available in the method's local platforms: dict
from sys import platform
from os.path import expandvars, join
def platform_config_directory() -> str:
'''
Platform config directory
Entries available in local platforms dict use the current
"best practice" location for config directories.
Default: $HOME/.config (XDG Base Directory Specification)
https://specifications.freedesktop.org/basedir-spec/basedir-spec-latest.html
'''
home: str = expandvars('$HOME')
platforms: dict = {
"win32": expandvars('%AppData%'),
"darwin": join(home, 'Library', 'Application Support'),
}
if platform in platforms:
return platforms[platform]
return join(home, '.config')
This works on windows, mac and linux, however allows for easier expansion given the need.