Launching SimpleHTTPServer in background - python

I am trying to write a shell script that launches a server and then fires up a browser to view the served content
(cd app && python -m SimpleHTTPServer) &
open http://localhost:8000
Disclaimer: I'm new to bash scripting and I don't really know python.
It seems that when adding the & operator at the end of the line, the process doesn't stay alive long enough to remain functional.
What am I doing wrong?

The problem is (probably) not that the server doesn't stay alive long enough; it's that it doesn't start up fast enough. When the open command executes, the webserver hasn't started yet, so you get an error.
Try sleeping for a second or two before the open

Related

How can I keep my python-daemon process running or restart it on fail?

I have a python3.9 script I want to have running 24/7. In it, I use python-daemon to keep it running like so:
import daemon
with daemon.DaemonContext():
%%script%%
And it works fine but after a few hours or days, it just crashes randomly. I always start it with sudo but I can't seem to figure out where to find the log file of the daemon process for debugging. What can I do to ensure logging? How can I keep the script running or auto-restart it after crashing?
You can find the full code here.
If you really want to run a script 24/7 in background, the cleanest and easiest way to do it would surely be to create a systemd service.
There are already many descriptions of how to do that, for example here.
One of the advantages of systemd, in addition to being able to launch a service at startup, is to be able to restart it after failure.
Restart=on-failure
If all you want to do is automatically restart the program after a crash, the easiest method would probably be to use a bash script.
You can use the until loop, which is used to execute a given set of commands as long as the given condition evaluates to false.
#!/bin/bash
until python /path/to/script.py; do
echo "The program crashed at `date +%H:%M:%S`. Restarting the script..."
done
If the command returns a non zero exit-status, then the script is restarted.
I would start with familiarizing myself with those two questions:
How to make a Python script run like a service or daemon in Linux
Run a python script with supervisor
Looks like you need a supervisor that will make sure that your script/daemon is still running. You can take a look at supervisord.

How to run a python script on a remote server that it doesn't quit after I log off?

I've created a script for my school project that works with data. I'm quite new to working remotely on a server, so this might seem like a dumb question, but how do I execute my script named
stats.py
so that it continues executing even after I log off PuTTy? The script file is located on the server. It has to work with a lot of data, so I don't want to just try something and then few days later find out that it has exited right after I logged off.
Thank you for any help!
There are many ways you can run a python program after you disconnect from an SSH session.
1) Tmux or Screen
Tmux is a "terminal multiplexer" which enables a number of terminals to be accessed by a single one.
You start by sshing as you do, run it by typing tmux and executing it. Once you are done you can disconnect from putty and when you login back you can relog to the tmux session you left
Screen also does that you just type screen instead of tmux
2) nohup
"nohup is a POSIX command to ignore the HUP signal. The HUP signal is, by convention, the way a terminal warns dependent processes of logout."
You can run it by typing nohup <pythonprogram> &

Stopping Django's Server [duplicate]

So im using ruby on rails in windows (i hear you all spitting your coffee onto the screen), its only a short term thing. (using ubuntu at home) So i tried to fire up webrick this afternoon and i get the error message
TCPServer Error, only one usage of each socket address is normally permitted
So it seems as if port 3000 is still running from last week? My question is how do i kill the process from the Windows command line. normally i have to press ctrl and pause/break in windows as ctrl c is not working which is only killing the batch process it seems..
Any solutions welcomed
Edit
So it seems as if
tasklist
will give me the list of processes, but where do i find the process for running the webrick server?
ruby.exe is not listed as a running process
Try using netstat -a -o -n to determine the pid of the process running on port 3000. Then you should be able to use taskkill /pid #### to kill whatever process is running on that port.
Probably not the most graceful way to do it, but I think it should work.
EDIT
You'll probably have to also use the /F flag to force-kill the process. I just tried it on my local machine, and that worked fine.
Go into rails_project\tmp\pids and delete the .pid file in there.
run:
rails server

bash wait for first python file to start before continue

I have this bash:
#!/bin/sh
# launcher.sh
echo "Remote Control Server is starting up..."
sudo python RControlPanel.py &
wait &
sudo python startup.py &
wait
The first python file is a flask server which its necessary to start up first.
The second file is initialising the components on the raspberry pi, and turns on a couple of LEDs and stuff. The way the script is written requires the flask application first and then initialise the components.
Its seems that the flask application it takes longer to start up and the bash script continues to run the startup.py
Is it possible to make sure that the flask app is running and then carry on to the next script? I though wait at the end will work but it doesnt. I have even tried with sleep.
Update: Im not quite sure but, I think when flask app runs, is getting to an endless loop, and waits for requests, like a normal web server do. Maybe thats the problem why the solutions bellow wont work.
I suppose the Flask server opens some HTTP port? Let's say on port 8080, then you could poll the app like so:
while ! curl http://localhost:8080 -m1 -o/dev/null -s ; do
sleep 0.1
done
Options:
-m1 to allow at most 1 second for the HTTP request. If your firewall is configured to silently drop packets to closed ports, this should make it go faster.
-o/dev/null so the HTTP response body doesn't get printed.
-s to hide any errors, as they are expected.
Add -S if you still want to see the "Connection refused" messages scroll by until the server is up.
I came up with a solution which im using the Thomas answer.
I have created a sh file which is called webserver.sh:
echo "Remote Control Server is starting up..."
sudo python RControlPanel.py
Then a second file which is called components.sh:
while ! curl http://127.0.0.1:80 -m1 -o/dev/null -s ; do
sleep 0.1
echo "Web Server still loading" #This line is for testing purposes
done
sudo python startup.py
echo "Startup Initialazation done. System Ready!"
And the a thrid file launcher.sh:
./launcher.sh
./remoteServer.sh
The first file starts up the web server only. no other code needs to be executed in there because it will be skipped, cause the flask app is an endless loop and it will skip everything underneath it.
The second file at the biggening is using the Thomas code to check if the webserver is running. If it does not is keep looping until the webserver (Flask app) come alive, and then run the startup.py python script which is initialising the components.
The third file is just calling launcher.sh and remoteServer.sh. So I can run my whole project within a single file, no matter which one is gonna start first.
Just use:
sudo python RControlPanel.py && sudo python startup.py &
Double && ensures that the second command runs only after first returns exit status zero.

Pelican restarting you server

Hi I just started working with Pelican and it really suits my needs, I had tried to build blogs in Flask and other frameworks but I really just wanted something simple so I can post about math, and pelican just works.
My question is when I am testing on my machine, I start the server; however when I stop the server to make some edits to my test blogs, and then try to reload the server I get a socket already in use error. I am stopping my server by ctrl+z am I doing this correctly?
Use ctrl+c to terminate the process. ctrl+z will only send it's execution to the background.
On a separate note, since you are making changes and want to test them it would be more convenient to use $ make devserver instead of $ make serve. See docs.
For your development server, you can also use the script ./develop_server.sh that comes with the last versions of pelican (at least with the 3.5.0).
Build the blog and load a server with ./develop_server.sh start: it reloads each time you edit your blog (except the settings). Simply stop with ./develop_server.sh stop when you're finished.
When you press Ctrl + C or Ctrl + z, do not restart the HTTP server: it is running in the background, and that is the exact reason as why you are getting that error message.
To see that the server is running in the background after pressing the any of the key combinations above, try to edit and save any file: you will see right away in the terminal the re-generation process of your pages is active again.
You can start the HTTP server using this command: make devserver and stop by ./developer_server.sh stop

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