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Division in python [duplicate]

This question already has answers here:
How can I force division to be floating point? Division keeps rounding down to 0?
(11 answers)
Closed 4 years ago.
Going through the python doc and doing the following operation:
ravi#user-ThinkCentre-M90:~$ python
Python 2.7.6 (default, Oct 26 2016, 20:30:19)
[GCC 4.8.4] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> 17/3
5
>>>
Why the output is not a float num?

you should use 17/3.0
It is a different place of python2 and python3.

try dividing it this way:
17/3.0

String/unicode references in Python embedded dictionaries [duplicate]

This question already has answers here:
Why does comparing strings using either '==' or 'is' sometimes produce a different result?
(15 answers)
Python string interning
(2 answers)
Closed 5 years ago.
I have a question about the Python 2.7.5-Python 2.7.13. It may be
about semantics or it may be a genuine Python bug. I'm not entirely
sure which. Here is the simplest code I can construct with the
issue
Python 2.7.13 |Enthought, Inc. (x86_64)| (default, Mar 2 2017, 08:20:50)
[GCC 4.2.1 Compatible Apple LLVM 6.0 (clang-600.0.57)] on darwin
>>> dd = {'foo': {'yy':u'Tannenbaum'}}
>>> dd['foo']['yy'] is u'Tannenbaum'
False
>>> dd['foo']['yy'] == u'Tannenbaum'
True
Note: If 'Tannebaum' is changed from unicode to a string the outcome changes. Both of the final tests are true. The question is: Why do the two final tests differ in the unicode case? My understanding is that since unicode and strings are both immutables the "is" and "==" tests should never differ in value. But I get this behavior in both Python 2.7.13 and the old 2.7.5 that came installed on my Mac. Am I relying on something I shouldn't rely on? Is the moral that I should never use "is" for string equality? But what is the principle that tells me that?
Postscript: I have access to a Python 3.6.2 on another machine, and lo and behold, I cannot reproduce this anomaly.
Python 3.6.2 (default, Jul 30 2017, 12:03:06)
[GCC 4.8.5 20150623 (Red Hat 4.8.5-11)] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> dd = {'foo': {'yy':u'Tannenbaum'}}
>>> dd['foo']['yy'] is u'Tannenbaum'
True
>>> dd['foo']['yy'] == u'Tannenbaum'
True

Python Syntax Error On The 5 In 3.5.1 [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 6 years ago.
Improve this question
When I try to run a python module it highlights the 5 in:
Python 3.**5**.1 (v3.5.1:37a07cee5969, Dec 6 2015, 01:38:48) [MSC v.1900 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> print ("Hello")
and says it's "invalid syntax". I've seen other sites to try to fix it, but it gets very confusing. What am I doing wrong and why is it highlighting the 5 in 3.5.1?

You're trying to execute the introductory text the interpreter prints out when you start it as if it were actual, valid Python code. It's not clear why. To recreate:
$ python3 -c "Python 3.5.1 (v3.5.1:37a07cee5969, Dec 6 2015, 01:38:48)"
File "<string>", line 1
Python 3.5.1 (v3.5.1:37a07cee5969, Dec 6 2015, 01:38:48)
^
SyntaxError: invalid syntax
Here's how it's supposed to look:
$ python3 # I only typed this
Python 3.5.2 (default, Jun 29 2016, 13:43:58)
[GCC 4.2.1 Compatible Apple LLVM 7.3.0 (clang-703.0.31)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> print ("Hello") # and this
Hello
In this second, working case, I start the interpreter, which prints out a welcome message to tell me which version I'm running, and then start typing valid commands at the interpreter prompt.

Python sys.maxint, sys.maxunicode on Linux and windows

On 64-bit Debian Linux 6:
Python 2.6.6 (r266:84292, Dec 26 2010, 22:31:48)
[GCC 4.4.5] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.maxint
9223372036854775807
>>> sys.maxunicode
1114111
On 64-bit Windows 7:
Python 2.7.1 (r271:86832, Nov 27 2010, 17:19:03) [MSC v.1500 64 bit (AMD64)] on
win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.maxint
2147483647
>>> sys.maxunicode
65535
Both Operating Systems are 64-bit. They have sys.maxunicode, according to wikipedia There are 1,114,112 code points in unicode. Is sys.maxunicode on Windows wrong?
And why do they have different sys.maxint?

I don't know what your question is, but sys.maxunicode is not wrong on Windows.
See the docs:
sys.maxunicode
An integer giving the largest supported code point for a Unicode character. The value of this depends on the configuration option that
specifies whether Unicode characters are stored as UCS-2 or UCS-4.
Python on Windows uses UCS-2, so the largest code point is 65,535 (and the supplementary-plane characters are encoded by 2*16 bit "surrogate pairs").
About sys.maxint, this shows at which point Python 2 switches from "simple integers" (123) to "long integers" (12345678987654321L). Obviously Python for Windows uses 32 bits, and Python for Linux uses 64 bits. Since Python 3, this has become irrelevant because the simple and long integer types have been merged into one. Therefore, sys.maxint is gone from Python 3.

Regarding the difference is sys.maxint, see What is the bit size of long on 64-bit Windows?. Python uses the long type internally to store a small integer on Python 2.x.

Python2.4 and 2.6 behaves differently for os.path.getmtime() on Windows

Getting two different modification time when calculated from different Python versions on Windows XP.
Python2.4
C:\Copy of elisp>c:\python24\python
Python 2.4.4 (#71, Oct 18 2006, 08:34:43) [MSC v.1310 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import os
>>> os.path.getmtime("auto-complete-emacs-lisp.el")
1251684178
>>> ^Z
Python2.6
C:\Copy of elisp>C:\Python26\python
Python 2.6.4 (r264:75708, Oct 26 2009, 08:23:19) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import os
>>> os.path.getmtime("auto-complete-emacs-lisp.el")
1251687778.0
>>>
There is a difference of 3600 seconds reported by Python2.6 and Python2.4.
What is the reason of this strange behavior?

It's a bug in Microsoft's implementation of the C standard library. Python 2.4 used to use the stdlib fstat call to get file information, and hence could end up an hour out in locales that use DST.
In Python 2.5 and later, os.stat calls the direct Win32-only API to get file information when running on Windows, resulting in the correct output. See this thread for more.

There is a difference of 3600 seconds ...
This should be the kicker. It's a timezone problem, pure and simple.
Now all you have to do is find out why 2.4 and 2.6 are using different timezone information :-)