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I would like to do 2 char into a short.
I want to do that (c syntax):
short var = (msg[4:5]<<8) | (msg[5:6])
algo:
ord(msg[4:5) = 105 -> 0b1101001
ord(msg[5:6) = 135 -> 0b10000111
var = 0b1101001 <<8 eq 0b1101001 00000000 eq 0x6900
var |= 0b10000111 eq 0b1101001 10000111 eq 0x6987
var = 27015
So i want as result the a numeric value
If you have any solution...
Thanks
(ord(msg[4])<<8) + ord(msg[5])
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I used integergroup in charm-crypto as building block, and used encode_as_group_element() and decode_from_group_element() to conversion element between int and Integer element mod N, but I can't get right result.
For example,
a = 15651 mod 62939
print(a)
b = decode_from_group_element(a, group)
print(b)
c = encode_as_group_element(b, group)
print(c)
>>>>15651 mod 62939
>>>>34
>>>>62648 mod 62939
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# no periods, spaces or puctuation marks
punctuation_not_wanted = [".","!", " " "/"]
for punctuation_not_wanted in s:
if punctuation_not_wanted in s:
return false
You can compare them as sets. If they have same symbols, their intersection (&) will have this same symbols and will converts to True for if statement.
if set(punctuation_not_wanted) & set(s):
return False
all([(c not in s) for c in punctuation_not_wanted])
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I have a list of acc nos:
list1 = ['1234','3456','2345','5543','1344','5679','6433','3243','0089']
Output I need is a string:
print(output): '1234','3456','2345','5543','1344','5679','6433','3243','0089'
You can join all the values with ',' and then adding a ' before and after the string like this:
"'{0}'".format("','".join(list1))
>>> list1 = ['1234','3456','2345','5543','1344','5679','6433','3243','0089']
>>> print(','.join(["'{0}'".format(s) for s in list1]))
'1234','3456','2345','5543','1344','5679','6433','3243','0089'
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How to convert this field from database
to
or to
[EDIT]The question was updated and the below was answered based on the original question.
if you fix your input var1 then you can do something like this:
var1 = '{"text":"tool","pos":"\\xd1\\x81\\xd1\\x83\\xd1\\x89\\xd0\\xb5\\xd1\\x81\\xd1\\x82\\xd0\\xb2\\xd0\\xb8\\xd1\\x82\\xd0\\xb5\\xd0\\xbb\\xd1\\x8c\\xd0\\xbd\\xd0\\xbe\\xd0\\xb5"}'
md = {}
for e in var1[1:-1].split(','):
md[e.split(':')[0][1:-1]] = e.split(':')[1][1:-1]
md['pos'] = (bytes.fromhex(''.join([h for h in md['pos'].split('\\x')]))).decode('utf-8')
print(md)
output:
{'text': 'tool', 'pos': 'существительное'}
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How would I create a script it in python late the values from the recursive sequence:
$x_1 = \sqrt{2}$, $x_{n+1} = \sqrt{2x_n}$ http://www.sciweavers.org/upload/Tex2Img_1392861864/render.png
X = [sqrt(2)]
for i in range(1,10):
X.append(sqrt(2*X[i-1]))
Here is a slow solution. Assuming n is >=1
import math
def recursive(n):
if n = 1:
math.sqrt(2)
return math.sqrt(2*recursive(n-1))