I'm reading xls file using xlrd. The problem is, when xlrd reading value like this "12/09/2012", i get result like this "xldate:41252.0". When I use xlrd.xldate_as_tuple, i get this result:
(2016, 12, 10, 0, 0, 0)
My code:
curr_row = -1
while curr_row < num_rows:
curr_row += 1
row = worksheet.row(curr_row)
for x in xrange(num_cols):
field_type = worksheet.cell_type(curr_row, x)
if field_type == 3: # this is date
field_value = worksheet.cell_value(curr_row, x)
print worksheet.cell(curr_row, x).value
print xlrd.xldate_as_tuple(field_value, 1)
Result:
41252.0
(2016, 12, 10, 0, 0, 0)
Both results are wrong for me. How can i get original cell value "12/09/2012" using xlrd ?
According to the docstring, you should pass your workbook's datemode to xldate_as_tuple as a second parameter:
from datetime import datetime
import xlrd
book = xlrd.open_workbook("test.xls")
sheet = book.sheet_by_index(0)
a1 = sheet.cell_value(rowx=0, colx=0)
print a1 # prints 41252.0
print xlrd.xldate_as_tuple(a1, 1) # prints (2016, 12, 10, 0, 0, 0)
a1_tuple = xlrd.xldate_as_tuple(a1, book.datemode)
print a1_tuple # prints (2012, 12, 9, 0, 0, 0)
a1_datetime = datetime(*a1_tuple)
print a1_datetime.strftime("%m/%d/%Y") # prints 12/09/2012
Related
everyone. Let me first paste the code.
c.execute("SELECT * FROM c20 WHERE Position = 'chain';")
data1 = c.fetchall()
c.execute("SELECT * FROM c20 WHERE Position = 'center';")
data2 = c.fetchall()
c.execute("SELECT * FROM c20 WHERE Position = 'Total';")
data3 = c.fetchall()
data1 = p_mod.list_multiply(data, copies_data)
data2 = p_mod.list_multiply(data2, copies_data)
data3 = p_mod.list_multiply(data3, copies_data)
meta_data = [data1, data2, data3]
n = 0
while n != 3:
for i in meta_data:
my_tree.insert(parent="", index="end", iid=n, text=f"{n + 1}", values=i)
n += 1
if n == 3:
my_tree.pack(pady=20)
root1.mainloop()
This is the code where I need to fetch queries regarding a requirement and the output required is as follows:
conn = sqlite3.connect("userdata.db")
>>> c = conn.cursor()
>>> c.execute("SELECT * FROM c20 WHERE Position = 'chain';")
<sqlite3.Cursor object at 0x00000221DA432F80>
>>> data1 = c.fetchall()
>>> data1
[('chain', 100, 350, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0)]
I have also used a remote function named p_mod.list_multiply().
The function looks like this:
def list_multiply(list_input, number):
new_list = []
list_input = list(list_input)[0]
list_input1 = list_input[1 : -1]
for i in list_input1:
data = int(i) * number
new_list.append(data)
if list_input[0] == 'chain':
new_list.insert(0, 'chain')
elif list_input[0] == 'center':
new_list.insert(0, 'center')
elif list_input[0] == 'Total':
new_list.insert(0, 'Total')
new_list = tuple(new_list)
return new_list
Now the problem arises...
Whenever I try to run the code with same outputs(data1, data2,...) using the function remotely from the main code,
it runs successfully, but whenever I am trying to run the script inside the main program it gives me an error.
Error is as follows:
PS D:\RM INCORPORATION\RM Software DEV Company Pvt\Jewellery App> & C:/Users/ONE/AppData/Local/Programs/Python/Python39/python.exe "d:/RM INCORPORATION/RM Software DEV Company Pvt/Jewellery App/contact.py"
h
Exception in Tkinter callback
Traceback (most recent call last):
File "C:\Users\ONE\AppData\Local\Programs\Python\Python39\lib\tkinter\__init__.py", line 1884, in __call__
return self.func(*args)
File "d:\RM INCORPORATION\RM Software DEV Company Pvt\Jewellery App\contact.py", line 53, in select
data1 = p_mod.list_multiply(data, copies_data)
File "d:\RM INCORPORATION\RM Software DEV Company Pvt\Jewellery App\p_mod.py", line 15, in list_multiply
data = int(i) * number
ValueError: invalid literal for int() with base 10: 'h'
Let me show you the output used with the function remotely, from the main code...
PS D:\RM INCORPORATION\RM Software DEV Company Pvt\Jewellery App> & C:/Users/ONE/AppData/Local/Programs/Python/Python39/python.exe "d:/RM INCORPORATION/RM Software DEV Company Pvt/Jewellery App/p_mod.py"
('chain', 200, 700, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0) ('center', 222, 826, 82, 124, 98, 70, 756, 2, 2, 6, 8, 24, 24, 16, 0, 0) ('Total', 422, 1526, 82, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1878, 70)
Then what is the problem dude?
Eagerly waiting someone's reply
You have overwritten list_input by the following line in list_multiply():
list_input = list(list_input)[0]
Therefore, list_input will be a string after that.
Just remove this line will solve the issue.
Also the following line:
list_input1 = list_input[1 : -1]
will not copy the last item of list_input into list_input1.
It should be
list_input1 = list_input[1:]
list_multiply() can be simplified as below:
def list_multiply(list_input, number):
new_list = tuple(int(x)*number for x in list_input[1:])
return (list_input[0],) + new_list
I tried to update main dictionary with every new one in the loop, but every time it overwrite values inside the nested dictionary.
I mean I want smth like this:
{'Barbour': {1900: 73041, 1910: 895427, 1920: 1531624, 1930: 1617086, 1940: 1420561, 1950: 1853223,
1960: 3092728, 1970: 3505193, 1980: 3659797, 1990: 2575561, 2000: 743757, 2010: 1730711},
'Berkeley': {1900: 0, 1910: 0, 1920: 0, 1930: 0, 1940: 0, 1950: 0, 1960: 0, 1970: 0, 1980: 0, 1990:
0, 2000: 0, 2010: 0}}
(for all of the cities)
def read_file_contents_coal():
return ['Barbour,73041,895427,1531624,1617086,1420561,1853223,3092728,3505193,3659797,2575561,743757,1730711\n',
'Berkeley,0,0,0,0,0,0,0,0,0,0,0,0\n',
'Boone,0,50566,1477560,3045056,3804527,5851267,6278609,11607216,13842525,27618152,32446186,23277998\n',
'Braxton,0,114422,286955,123991,13751,38414,218087,0,459517,3256906,1196489,439662\n',
]
def process_file_contents():
lst = read_file_contents_coal()
dic = {}
coal_dic = {}
yearcoaldic = {}
ycdic = {}
for stringdata in lst:
city_data = stringdata.strip().split(',')
year = 1900
for j in range(1, 13):
ycdic = {year: int(city_data[j])}
year += 10
yearcoaldic.update(ycdic)
dic = {city_data[0]: yearcoaldic}
coal_dic.update(dic)
print(coal_dic)
return coal_dic
[EDIT]: the issue is that you have to move yearcoaldic to the first loop and always set it to en empty dictionary otherwise you will always overwrite your values as you have experienced.
def process_file_contents():
lst = read_file_contents_coal()
dic = {}
coal_dic = {}
ycdic = {}
for stringdata in lst:
yearcoaldic = {}
city_data = stringdata.strip().split(',')
year = 1900
for j in range(1, 13):
ycdic = {year: int(city_data[j])}
year += 10
yearcoaldic.update(ycdic)
# dic = {city_data[0]: yearcoaldic}
dic[city_data[0]] = yearcoaldic
# coal_dic.update(dic)
# print(coal_dic)
return dic
Hello I'm VERY new in python. I just have to do 1 thing with it.
When i print my string names, this is what comes up:
{'id': 1, 'xd_id': 2, 'name': 'nameea', 'description': 'somethingveryweird', 'again_id': 6, 'some_id': None, 'everything': False, 'is_ready': False, 'test_on': None, 'something': None, 'something': [], 'count_count': 28, 'other_count': 0, 'again_count': 0, 'new_count': 0, 'why_count': 0, 'custom_count': 0, 'custom2_count': 0, 'custom3_count': 0, 'custom4_count': 0, 'custom5_count': 0, 'custom_status6_count': 0, 'custom7_count': 0, 'lol_id': 7, 'wtf_id': None, 'numbers_on': 643346, 'something_by': 99, 'site': 'google.com'}
I would to get this info to excel with the left row being the "id": and the right being the 1. And all the info like this. for example. "site" on the left and "google.com" on the right. my current code adds all this info to the first row on the excel and i can't seem to find any tutorial for this. Thanks for all answers. My current code:
f = open('test.csv', 'w')
s = str(names)
f.write(s)
f.close()
if python is not going to be your key skill and only this task needs to be done, then here is the answer.
f = open('test.csv', 'w')
csvwt = csv.writer(f)
for x in names.items():
csvwt.writerow(x)
f.close()
if you want to write to an excel, then you have to do this,
workbook = xlsxwriter.Workbook('test.xlsx')
worksheet = workbook.add_worksheet()
row = 0
col = 0
for x in names.items():
worksheet.write(row, col, str(x[0]))
worksheet.write(row, col + 1, str(x[1]))
row += 1
workbook.close()
In a LibreOffice xlsx cell, the value is like this: 01/13/2016.
When I am creating a new xlsx file using python2, then that 01/13/2016 is converting to 42461.
python code :
sheet1.write(row,col,sheet.cell(row,col).value)
tab_matching = 0
for sheet_name in book.sheet_names():
temp_sheet_name = sheet_name.lower()
if temp_sheet_name == tab_name:
tab_matching = 1
sheet = book.sheet_by_name(sheet_name)
temp_sheet_name = file_prefix+part_file_name+"_"+file_type+".xlsx"
if os.path.exists(detail_path):
xlsx_file_name = detail_path+"/"+temp_sheet_name
else:
xlsx_file_name = dirname+"/"+temp_sheet_name
new_book = xlsxwriter.Workbook(xlsx_file_name)
sheet1 = new_book.add_worksheet()
for row in range(sheet.nrows):
for col in range(sheet.ncols):
sheet1.write(row,col,sheet.cell(row,col).value)
new_book.close()
Could you tell me why this is happening?
42461 is the underlying date value for 04/01/2016. To show the date instead of the number, specify a date format:
format1 = new_book.add_format({'num_format': 'mm/dd/yyyy'})
sheet1.write('B1', 42461, format1) # 04/01/2016
sheet1.write('B2', 42382, format1) # 01/13/2016
Documentation is at http://xlsxwriter.readthedocs.io/working_with_dates_and_time.html.
You could do this.
>>> import datetime
>>> today=datetime.datetime.now()
>>> today
datetime.datetime(2016, 8, 27, 1, 7, 1, 909049)
>>> value=today.strftime("%d/%m/%Y")
'27/08/2016'
>>> sheet1.write(row,col,sheet.cell(row,col).value)
The nvd3 line chart in the example below uses python list as data source. But how to plot multiline from a pandas dataframe without explicitly stating the columns i.e. like in pandas plot: df.plot() df could contain x columns.
from nvd3 import lineChart
# Open File for test
output_file = open('test_lineChart.html', 'w')
# ---------------------------------------
type = "lineChart"
chart = lineChart(name=type, x_is_date=False, x_axis_format="AM_PM")
xdata = list(range(0, 24))
ydata = [0, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 4, 3, 3, 5, 7, 5, 3, 16, 6, 9, 15, 4, 12]
ydata2 = [9, 8, 11, 8, 3, 7, 10, 8, 6, 6, 9, 6, 5, 4, 3, 10, 0, 6, 3, 1, 0, 0, 0, 1]
kwargs1 = {'color': 'black'}
kwargs2 = {'color': 'red'}
extra_serie = {"tooltip": {"y_start": "There is ", "y_end": " calls"}}
chart.add_serie(y=ydata, x=xdata, name='sine', extra=extra_serie, **kwargs1)
extra_serie = {"tooltip": {"y_start": "", "y_end": " min"}}
chart.add_serie(y=ydata2, x=xdata, name='cose', extra=extra_serie, **kwargs2)
chart.buildhtml()
output_file.write(chart.htmlcontent)
# close Html file
output_file.close()
How to plot from this dataframe using nvd3:
df = pd.DataFrame(data)
df = df.set_index('datetime')
fig, ax = plt.subplots()
df.plot(ax=ax, marker='o')
IIUC, the chart takes the data as list, so you would have to convert your index and column data to list like so (assuming your column names are col1 and col2 respectively:
def plot_nvd3(df, ydata='col1', ydata2='col2'):
# Open File for test
output_file = open('test_lineChart.html', 'w')
# ---------------------------------------
type = "lineChart"
chart = lineChart(name=type, x_is_date=False, x_axis_format="AM_PM")
xdata = df.index.tolist()
ydata = df[ydata].tolist()
ydata2 = df[ydata2].tolist()
kwargs1 = {'color': 'black'}
kwargs2 = {'color': 'red'}
extra_serie = {"tooltip": {"y_start": "There is ", "y_end": " calls"}}
chart.add_serie(y=ydata, x=xdata, name='sine', extra=extra_serie, **kwargs1)
extra_serie = {"tooltip": {"y_start": "", "y_end": " min"}}
chart.add_serie(y=ydata2, x=xdata, name='cose', extra=extra_serie, **kwargs2)
chart.buildhtml()
output_file.write(chart.htmlcontent)
# close Html file
output_file.close()
Usage would by:
plot_nvd3(df, 'col1', 'col2')
I have not checked how nvd3 works with DateTimeIndex, though, in case your df = df.set_index('datetime') results in one.