i am having this weird url reaction.
this is my views.py
def user_edit(request):
user = User.objects.get(id=request.GET.get('userid'))
return render_to_response("editprofile.html",{'user':user},context_instance=RequestContext(request))
and this is my form.
<form action="/update_userprofile/?userid={{user.id}}" ...
my urls.py
url(r'^update_userprofile/','home.views.update_userprofile')
but once i send the form, i am getting error:
Internal Server Error: /update_userprofile/on
where is that on coming from? i dont understand what happens here.
thanks a lot .
OK I try your codes. You did not put in your question what method did you use. So I try the GET and the output User matching query does not exist. I try the POST and it works now.
<form action="/update_userprofile/?userid={{user.id}}" method="POST">
Even though you have user id define in your url, you can still get the value from the method POST.
UPDATE:
You code is fine, just change the method into method=POST in your form
Related
I have a Post model that requires a certain category before being added to the database, and I want the category to be generated automatically. Clicking the addPost button takes you to a different page and so the category will be determined by taking a part of the previous page URL.
Is there a way to get the previous page URL as a string?
I have added my AddPost button here.
<aside class="addPost">
<article>
<form action="/Forum/addPost">
<input type="submit" name="submit" value="Add Post"/>
</form>
</article>
</aside>
You can do that by using request.META['HTTP_REFERER'], but it will exist if only your tab previous page was from your website, else there will be no HTTP_REFERER in META dict. So be careful and make sure that you are using .get() notation instead.
# Returns None if user came from another website
request.META.get('HTTP_REFERER')
Note: I gave this answer when Django 1.10 was an actual release. I'm not working with Django anymore, so I can't tell if this applies to Django 2
You can get the referring URL by using request.META.HTTP_REFERER
More info here: https://docs.djangoproject.com/en/dev/ref/request-response/#django.http.HttpRequest.META
I can't answer #tryingtolearn comment, but for future people, you can use request.META['HTTP_REFERER']
Instead of adding it to your context, then passing it to the template, you can place it in your template directly with:
Return
A much more reliable method would be to explicitly pass the category in the URL of the Add Post button.
You can get the previous url in "views.py" as shown below:
# "views.py"
from django.shortcuts import render
def test(request):
pre_url = request.META.get('HTTP_REFERER') # Here
return render(request, 'test/index.html')
You can also get the previous url in Django Template as shown below:
# "index.html"
{{ request.META.HTTP_REFERER }}
I'm having issues with correctly sending and receiving a variable with a GET request. I cannot find any information online either. From the HTML form below, you can see I'm sending the value of 'question' but I'm also receiving 'topic' from a radio button in the form (though the code is for that is not below).
I want to send 'topic' using POST but use GET for 'question'. I'm aware that the form method is POST though I'm not sure how to cater for both POST and GET.
HTML Form:
<form method="POST" action="{{ url_for('topic', question=1) }}">
My second issue is that I'm unsure how to receive 'topic' AND 'question' from the form. I've managed to receive 'topic' as seen below but I'm not quite sure how to receive 'question'. Preferably it would be better for the URL to be like so:
www.website.com/topic/SomeTopic?question=1
For the code below, I found online that request.args[] is used for receiving GET requests though I'm not sure if it is correct.
Flask:
#app.route('/topic/<topic>', methods=['POST', 'GET'])
def questions(topic):
question = request.args['questions']
return render_template('page.html')
The question is
How do I send two variables from a form using GET and POST for different variables at the same time.
How would I go about receiving both variables?
The short answer to your question is that you can't send both GET and POST using the same form.
But if you want your url to look like you specified:
www.website.com/topic/SomeTopic?question=1
then you're almost there. First you will need to already know the name of the topic as you have to specify that in your call to url_for() for the questions url.
<form method="GET" action="{{ url_for('questions', topic_name="cars") }}">
# Your url will be generated as www.website.com/topic/cars
flask
# Note that I changed the variable name here so you can see how
# its related to what's passed into url_for
#app.route('/topic/<topic_name>')
def questions(topic_name):
question = request.args['question']
return render_template('page.html')
Now when you submit your form, your input will be sent as a GET, an asumming you have an input field with the name question you'll be able to get the value of that field.
I have a Post model that requires a certain category before being added to the database, and I want the category to be generated automatically. Clicking the addPost button takes you to a different page and so the category will be determined by taking a part of the previous page URL.
Is there a way to get the previous page URL as a string?
I have added my AddPost button here.
<aside class="addPost">
<article>
<form action="/Forum/addPost">
<input type="submit" name="submit" value="Add Post"/>
</form>
</article>
</aside>
You can do that by using request.META['HTTP_REFERER'], but it will exist if only your tab previous page was from your website, else there will be no HTTP_REFERER in META dict. So be careful and make sure that you are using .get() notation instead.
# Returns None if user came from another website
request.META.get('HTTP_REFERER')
Note: I gave this answer when Django 1.10 was an actual release. I'm not working with Django anymore, so I can't tell if this applies to Django 2
You can get the referring URL by using request.META.HTTP_REFERER
More info here: https://docs.djangoproject.com/en/dev/ref/request-response/#django.http.HttpRequest.META
I can't answer #tryingtolearn comment, but for future people, you can use request.META['HTTP_REFERER']
Instead of adding it to your context, then passing it to the template, you can place it in your template directly with:
Return
A much more reliable method would be to explicitly pass the category in the URL of the Add Post button.
You can get the previous url in "views.py" as shown below:
# "views.py"
from django.shortcuts import render
def test(request):
pre_url = request.META.get('HTTP_REFERER') # Here
return render(request, 'test/index.html')
You can also get the previous url in Django Template as shown below:
# "index.html"
{{ request.META.HTTP_REFERER }}
I have the form which i am showing by normal view. Then i am send the GET parameters to djnago ChangeList view like django does for lookups like this
student/?region__id__exact=1&status__exact=Published
now is there any way to remove that from the URL in the address bar.
I don't users to see what i am doing
The whole point of GET is that they are retrieved from the URL itself, removing them from the URL removes them entirely.
If you want them 'hidden' you will need to use POST.
The HTTP GET method of form submission passes the information from template to views through URL. If you want to "hide" information from URL use POST instead. In your form do like this:
<form action="/view_name/" method="post">
and in views:
request.POST['name']
I'm trying to send a HTML form input from a page to a python script. This is just for testing purposes so ignore the poor code. Basically I don't know how to define the action= part to reference the search() function in the python script. I just need to get the basic functionality working. I'm using web2py as the framework which is probably relevant:
Controller: default.py
def index():
return dict()
def search():
import urllib
q=request.vars.q
result1 = urllib.urlopen('http://www.google.com/search?q=%s' % q)
return dict(result1=result1)
default/search.html:
{{extend 'layout.html'}}
<form method=get action=???>
<input name=q>
<input type=submit value=search>
</form>
It looks like the form itself is served via the search() function, so you can just set action="", and it will submit back to the search() function. Also, you should put quotes around your HTML attribute values, and you should add some logic to check whether there is anything in request.vars.q, because when the page first loads with an empty form, there is no query to process.
What you are doing there is correct for GET requests. For POST requests you need to pass the fields as the data parameter.
urllib.urlopen('http://www.google.com/search', data=urllib.urlencode({'q':'FOO'}))
does the search as a POST request for example.
See here for more info.