Python nonnumeric port exception - python

I try to send post request with json body with urllib2:
request = urllib2.Request('http://localhost:8090/api/', jdata, {'Content-Type': 'application/json'})
f = urllib2.urlopen(request)
But get exception:
File "/usr/lib/python2.7/urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 407, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 520, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 439, in error
result = self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 379, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 626, in http_error_302
return self.parent.open(new, timeout=req.timeout)
File "/usr/lib/python2.7/urllib2.py", line 401, in open
response = self._open(req, data)
File "/usr/lib/python2.7/urllib2.py", line 419, in _open
'_open', req)
File "/usr/lib/python2.7/urllib2.py", line 379, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 1211, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "/usr/lib/python2.7/urllib2.py", line 1150, in do_open
h = http_class(host, timeout=req.timeout) # will parse host:port
File "/usr/lib/python2.7/httplib.py", line 693, in __init__
self._set_hostport(host, port)
File "/usr/lib/python2.7/httplib.py", line 721, in _set_hostport
raise InvalidURL("nonnumeric port: '%s'" % host[i+1:])
httplib.InvalidURL: nonnumeric port: '8090��>��hbWb�ba'
How can i fix it?
Thank you.

It seems that the urllib2 functions doesn't parse right your request. Why don't you try curl?
import pycurl
c = pycurl.Curl()
c.setopt(c.URL, 'http://myfavpizzaplace.com/order')
c.setopt(c.POSTFIELDS, 'pizza=Quattro+Stagioni&extra=cheese')
c.setopt(c.VERBOSE, True)
c.perform()
example from http://www.angryobjects.com/2011/10/15/http-with-python-pycurl-by-example/

Related

urllib2 httplib.BadStatusLine

I am using with python urllib2 to a connect HTTP server. Sometimes I get the response: httplib.BadStatusLine: ''.
My code :
response = None
try:
request = urllib2.Request(http_url,params)
response = urllib2.urlopen(request,timeout=5000)
return str(response.read())
except urllib2.HTTPError :
return ""
except urllib2.URLError:
return ""
response error :
File "/usr/lib64/python2.7/urllib2.py", line 154, in urlopen
return opener.open(url, data, timeout)
File "/usr/lib64/python2.7/urllib2.py", line 431, in open
response = self._open(req, data)
File "/usr/lib64/python2.7/urllib2.py", line 449, in _open
'_open', req)
File "/usr/lib64/python2.7/urllib2.py", line 409, in _call_chain
result = func(*args)
File "/usr/lib64/python2.7/urllib2.py", line 1244, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "/usr/lib64/python2.7/urllib2.py", line 1217, in do_open
r = h.getresponse(buffering=True)
File "/usr/lib64/python2.7/httplib.py", line 1051, in getresponse
response.begin()
File "/usr/lib64/python2.7/httplib.py", line 415, in begin
version, status, reason = self._read_status()
File "/usr/lib64/python2.7/httplib.py", line 379, in _read_status
raise BadStatusLine(line)
httplib.BadStatusLine: ''
I don't to know how to fix this bug? And I don't to know why I get an error response.

urlopen error [Errno 111] Connection refused in a very simple script

I already checked if proxy settings were enabled, reset winsock, uninstall firewall and antivirus, and I still get the same error message, but if I type the url in Firefox or IE it works just fine. Thanks for any help
Here is the script:
import urllib2
import ssl
gcontext = ssl._create_unverified_context()
url = 'https://192.168.1.1:8000/cgi-bin/login.html'
html = urllib2.urlopen(url=url,context=gcontext).read()
print html
and here is the traceback:
File "get_url.py", line 6, in <module>
f = urllib2.urlopen("https://192.168.1.1:8000/cgi-bin/login.html",context=gcontext, timeout=3000)
File "/usr/lib/python2.7/urllib2.py", line 154, in urlopen
return opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 435, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 548, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 467, in error
result = self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 407, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 654, in http_error_302
return self.parent.open(new, timeout=req.timeout)
File "/usr/lib/python2.7/urllib2.py", line 429, in open
response = self._open(req, data)
File "/usr/lib/python2.7/urllib2.py", line 447, in _open
'_open', req)
File "/usr/lib/python2.7/urllib2.py", line 407, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 1241, in https_open
context=self._context)
File "/usr/lib/python2.7/urllib2.py", line 1198, in do_open
raise URLError(err)
urllib2.URLError: <urlopen error [Errno 111] Connection refused>

Why am I getting these errors and how to fix them?

When I run this script I get a ton of errors.
import urllib, urllib2
proxy = urllib2.ProxyHandler({
'http': '127.0.0.1',
'https': '127.0.0.1'
})
opener = urllib2.build_opener(proxy)
urllib2.install_opener(opener)
# this way both http and https requests go through the proxy
urllib2.urlopen('http://www.google.com')
urllib2.urlopen('https://www.google.com')
I don't really understand what these errors are, hence why I am asking. Here they are:
Traceback (most recent call last):
File "C:\Python27\Craig.py", line 10, in <module>
urllib2.urlopen('http://www.google.com')
File "C:\Python27\lib\urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python27\lib\urllib2.py", line 410, in open
response = meth(req, response)
File "C:\Python27\lib\urllib2.py", line 523, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python27\lib\urllib2.py", line 448, in error
return self._call_chain(*args)
File "C:\Python27\lib\urllib2.py", line 382, in _call_chain
result = func(*args)
File "C:\Python27\lib\urllib2.py", line 531, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 501: Not Implemented
Update:
After I added the ports I got these errors:
Traceback (most recent call last):
File "C:\Python27\Craig.py", line 10, in <module>
urllib2.urlopen('http://www.google.com')
File "C:\Python27\lib\urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python27\lib\urllib2.py", line 404, in open
response = self._open(req, data)
File "C:\Python27\lib\urllib2.py", line 422, in _open
'_open', req)
File "C:\Python27\lib\urllib2.py", line 382, in _call_chain
result = func(*args)
File "C:\Python27\lib\urllib2.py", line 1214, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "C:\Python27\lib\urllib2.py", line 1184, in do_open
raise URLError(err)
urllib2.URLError: <urlopen error [Errno 10061] No connection could be made because the target machine actively refused it>
Are you running a local proxy?
If you are, it's probably not running on port 80. The default port is 3128.
proxy = urllib2.ProxyHandler({
'http': 'http://127.0.0.1:3128/',
'https': 'http://127.0.0.1:3128/'
})

can calling pythons urllib2.info() cause an exception?

I'm getting a couple of exceptions popping up from time to time but can't think of the cause.
Here's a snippet:
try:
r = urllib2.urlopen(url)
except urllib2.URLError, e:
if hasattr(e, 'code'):
# unauthorized
print('UA: %s' % url)
elif hasattr(e, 'reason'):
print('TO: %s' % url)
# timeout
else:
i = r.info()
try:
server = i['server']
except:
pass
else:
if not 'authenticate' in server:
print('NA: %s' % url)
I'm thinking perhaps that r.info() is causing an exception but not sure why it would as the r = urllib2.urlopen(url) is covered with the try.
The errors are:
Traceback (most recent call last):
File "C:\Python27\lib\threading.py", line 551, in __bootstrap_inner
self.run()
File "C:\Users\anthony\Scripts\checker.py", line 35, in run
r = urllib2.urlopen(url)
File "C:\Python27\lib\urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python27\lib\urllib2.py", line 400, in open
response = self._open(req, data)
File "C:\Python27\lib\urllib2.py", line 418, in _open
'_open', req)
File "C:\Python27\lib\urllib2.py", line 378, in _call_chain
result = func(*args)
File "C:\Python27\lib\urllib2.py", line 1207, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "C:\Python27\lib\urllib2.py", line 1180, in do_open
r = h.getresponse(buffering=True)
File "C:\Python27\lib\httplib.py", line 1030, in getresponse
response.begin()
File "C:\Python27\lib\httplib.py", line 407, in begin
version, status, reason = self._read_status()
File "C:\Python27\lib\httplib.py", line 371, in _read_status
raise BadStatusLine(line)
BadStatusLine: ''
and
File "C:\Python27\lib\urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python27\lib\urllib2.py", line 400, in open
response = self._open(req, data)
File "C:\Python27\lib\urllib2.py", line 418, in _open
'_open', req)
File "C:\Python27\lib\urllib2.py", line 378, in _call_chain
result = func(*args)
File "C:\Python27\lib\urllib2.py", line 1207, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "C:\Python27\lib\urllib2.py", line 1180, in do_open
r = h.getresponse(buffering=True)
File "C:\Python27\lib\httplib.py", line 1030, in getresponse
response.begin()
File "C:\Python27\lib\httplib.py", line 407, in begin
version, status, reason = self._read_status()
File "C:\Python27\lib\httplib.py", line 365, in _read_status
line = self.fp.readline()
File "C:\Python27\lib\socket.py", line 447, in readline
data = self._sock.recv(self._rbufsize)
error: [Errno 10054] An existing connection was forcibly closed by the remote host
I've read a bit of information on the [Errno 10054] but have no idea how to prevent it.
Any help would be appriciated.
I'm thinking perhaps that r.info() is causing an exception but not
sure why it would as the r = urllib2.urlopen(url) is covered with the
try.
Nope. The first exception has nothing to do with r.info() - exception is raised on urllib2.urlopen(url), as you may see in the traceback.
BadStatusLine exception is defined in httplib and your except urllib2.URLError simply doesn't catch it. You should probably improve your exception handling logic like:
except (httplib.HTTPException, urllib2.URLError) as err:
...

How to get around error 304 in urllib2, Python

For the openers, opener = urllib2.build_opener(), if I try to add an header:
request.add_header('if-modified-since',request.headers.get('last-nodified'))
I get the error code:
Traceback (most recent call last):
File "<pyshell#19>", line 1, in <module>
feeddata = opener.open(request)
File "C:\Python27\lib\urllib2.py", line 391, in open
response = self._open(req, data)
File "C:\Python27\lib\urllib2.py", line 409, in _open
'_open', req)
File "C:\Python27\lib\urllib2.py", line 369, in _call_chain
result = func(*args)
File "C:\Python27\lib\urllib2.py", line 1173, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "C:\Python27\lib\urllib2.py", line 1142, in do_open
h.request(req.get_method(), req.get_selector(), req.data, headers)
File "C:\Python27\lib\httplib.py", line 946, in request
self._send_request(method, url, body, headers)
File "C:\Python27\lib\httplib.py", line 986, in _send_request
self.putheader(hdr, value)
File "C:\Python27\lib\httplib.py", line 924, in putheader
str = '%s: %s' % (header, '\r\n\t'.join(values))
TypeError: sequence item 0: expected string, NoneType found
How do you get around this?
I tried building a class from urllib2.BaseHandler and it doesn't work.
Your traceback says: expected string, NoneType found from which I deduce that you've stored a None value as a header. Did you really write 'last-nodified'? The header you mean was probably 'last-modified', but even then you should check that it existed and not re-use it as a header if request.headers.get() returns None.

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