So I am a beginner in coding and I started learning Python a while back! Recently I was writing my own code. It's a translator project from english to pyg latin (Just a made up language adding 'ay' to the word. Now this is my code:
original = raw_input('Name any english word?')
if len(original) > 0 and original.isalpha(): #Testing if variable has characters and not numbers
word = original.lower()
first = word[0]
if first == 'a' or first == 'e' or first == 'i' or first == 'o' or first == 'u':
new_word = word + pyg #Word translated to pyg latin
print new_word
else:
new_word = word[1:] + word[0] + pyg
print new_word
else:
print "empty" #No word active
Problem is I keep getting a EOF error in my 3rd line? What is the problem and what is an EOF error?
The code needs a bit more than some indent fixes, but I'll forgive. This works for me on OSx and PC.
original = raw_input('Name any english word?\n')
PYG = 'ay'
VOWELS = 'aeiou'
if len(original) > 0 and original.isalpha(): #Testing if variable has characters and not numbers
word = original.lower()
first = word[0]
if first in VOWELS:
new_word = ''.join([word, PYG]) #Word translated to pyg latin
print new_word
else:
new_word = ''.join([word[1:], word[0], PYG])
print new_word
else:
print 'Empty'
Using in and ''.join() is easier and more pythonic. '\n' just produces a newline before the input query.
As for your strange error... I expect your Mac was just throwing up something for one of the various problems with the code. EOF means "End of File." raw_input can throw the error but none of the calls you made should produce it normally. Alternatively, it could be because you are unintentionally using an older version of python that comes with your Mac and cannot accommodate some of those calls in the same way.
Anyway, not important. The code should work now.
Related
Hi i made a pyglatin code:
pyg = 'ay'
original = input("Enter a word:")
if len(original) > 0 and original.isalpha():
word = original.lower()
first = word[0]
new_word = word + first + pyg
new_word = new_word[1:len(new_word)]
print(new_word)
else:
print("empty")
and it works perfectly but i need s.th else.
for example if user entered
"rm !"
then the output should be:
"mray !"
i dont punctuation marks like ! , . # to change.
can anyone help?
I have a assignment where I need to
sometimes it might be useful to convert text from lowerCamelCase to snake_case. The main trick is to find the correct place where to insert an underscore. Let's make a rule that it's right before a capital letter of the next word. If the first letter is capitalized, convert it to lowercase and don't forget to insert an underscore before it.
I wrote my code and for some reason it doesn't return anything, it's completely empty, my ide says I have no errors
word = input()
new_word = ''
for char in word:
if char.isupper():
new_word.join('_' + char.lower())
else:
new_word.join(char)
print(new_word)
The assignment runs multiple tests with different words, and here they are
Sample Input 1:
python
Sample Output 1:
python
Sample Input 2:
parselTongue
Sample Output 2:
parsel_tongue
I legitimately don't see any reason why it's not printing, any ideas why
It's because the 1st test case is all lower case.
new_word will be empty because loop's inner condition won't execute at all.
Here's the correct and cleaner code I wrote
word = input()
counter = 0
new_word = ""
for char in word:
if not(char.islower()) and counter > 0:
new_word = new_word + '_' + char.lower()
else:
new_word = new_word + char.lower()
counter += 1
print(new_word)
You are almost there. You have to concatenate the characters to new_word and not join.
This is Concatenation. char gets appended to new_word:
new_word += char
join() will just concatenate and return the strings passed to it. But it is not saved to new_word.
Use concatenation instead of join in your code.
word = input('Input: ')
new_word = ''
for char in word:
if char.isupper():
new_word += '_' + char.lower()
else:
new_word += char
print(f'Output: {new_word}')
Input: python
Output: python
Input: parselTongue
Output: parsel_tongue
As your title says "list comprehension", here is an approach that utilizes a comprehension:
snake_word = ''.join(f'_{c.lower()}' if c.isupper() else c for c in word)
This question already has answers here:
python pig latin converter
(2 answers)
Closed 6 years ago.
I have a python code to translate a one worded string to pyglatin and is as follows:
pyg = 'ay'
original = raw_input('Enter a word:')
if len(original)>0 and original.isalpha():
word = original.lower()
first = word[0]
rest = word[1:]
new_word = rest+first+pyg
print new_word
However, I'm stumped on how to translate an entire sentence to Pyglatin. The problem I'm working on has these following conditions: for words that begin with consonants, all initial consonants are moved to the end of the word and 'ay' is appended. For words that begin with a vowel, the initial vowel remains, but 'way' is added to the end of the word.
As an example, the string 'How are you today?' would be 'owhay areway uoyay odaytay?'
Read in a sentence. Break it into individual words (split method). Translate each word to Pig Latin. Concatenate the translations.
Does that get you moving?
Try this. Use split and put it into an empty string.
original = raw_input("Enter Sentence: ")
conversion = ""
for word in original.split():
if len(word)>0 and word.isalpha():
word = word.lower()
first = word[0]
rest = word[1:]
pyg = "ay"
pygword = rest+first+pyg
conversion += pygword + " "
print conversion
Here is my try, but if you are not doing it yourself at least try to understand it. (You are free to ask of course)
This has basic ability to deal with special characters like the "?"
def pygword(word):
vowels = 'aeiou'
if word[0] in vowels:
return word + 'way'
else:
while word[0] not in vowels:
word = word[1:]+word[0]
return word + "ay"
def pygsentence(sentence):
final = ''
for word in sentence.lower().split(): #split the sentence
#words should only end in symols in correct grammar
if word[-1] in '.,;:!?':
symbol = word[-1]
word = word[:-1]
else:
symbol = ''
if word.isalpha(): #check if word is alphanumerically
final += pygword(word)+symbol+' '
else:
return "There is a strange thing in one of your words."
return final[:-1] #remove last unecessary space
There may be faster, more robust, simpler, better understandable ways to do this, but this how I would start.
Test yields me:
In[1]: pygsentence("How are you today? I am fine, thank you very much good sir!")
Out[1]: 'owhay areway ouyay odaytay? iway amway inefay, ankthay ouyay eryvay uchmay oodgay irsay!'
Your code does not obey the vowel/consonant rule, so I did my own converter for single words.
Just realized that it won't be able to deal with apastrophes in the middle of words (we don't really have theese in german ;) ) so there is a little task left for you.
edit: I did not know in which order you wanted the consonants apended, since that became not clear from your example. So i made an alternative pygword function:
def pygword2(word):
vowels = 'aeiou'
if word[0] in vowels:
return word + 'way'
else:
startcons = ''
while word[0] not in vowels:
startcons = word[0] +startcons
word = word[1:]
word = word+startcons
return word + "ay"
See the differnece:
In[48]: pygword("street")
Out[48]: 'eetstray'
In[49]: pygword2("street")
Out[49]: 'eetrtsay'
I'm doing part of the 'PigLatin translation' program.
Here is the part I'm doing writing right now.
input_str = input("Input a word: ")
consonant_check = 0
while input_str[int(consonant_check)] != 'a' or 'e' or 'i' or 'u':
output_str = input_str[:int(consonant_check)] + input_str[0,int(consonant_check)] + 'ay'
consonant_check = int(consonant_check) + 1
else:
print(output_str)
This part is supposed to check if the word input begins with a consonant. If it does, the program could remove all consonants from the beginning of the word and append them to the end of the word. Then append "ay" to the end of the word.
By collecting information online I had some clues about how to make it happen but I think there are still something wrong with my code.
I would approach it similar to what you intended, resulting in the code below.
In short, check the first character of a string. If it's not a vowel (not in ['a','e','i','o','u']), move the character to the end of the string. Keep doing that until you hit a vowel (so 'string' becomes 'trings' then 'ringst' then 'ingstr' before breaking the loop). Once you finally hit a vowel, you leave the loop, and print the modified string + 'ay'. If the first character is a vowel, you leave the loop and print the string + 'ay'.
There's no need to set a consonant check - you're always checking the first character (0). And there's no need to have two variables - just keep modifying and replacing the original string.
word_string = input("Input a word: ")
while word_string[0] not in ['a','e','i','o','u']:
word_string = word_string[1:] + word_string[0:1]
else:
print(word_string + 'ay')
This isn't a direct answer to your question, but my solution to the pig-latin problem. When learning python, I found that looking at completed examples helped a great deal.
word = "snake"
import string
# Create a list of vowels an consonants
vowels = ['a','e','i','o','u','y']
vowels += [v.upper() for v in vowels]
consonants = [x for x in string.ascii_letters if x not in vowels]
if word[0] in consonants:
# Find the first vowel
idx = min([word.find(v) for v in vowels if word.find(v)>0])
# Split the word at this point and add 'ay'
word = word[idx:] + word[:idx] + 'ay'
print(word)
# Returns "akesnay"
I think your logic is overall a little messed up. I would suggest tackling the problem like this.
1.) Check to see if the first letter is a consonant, if not, do nothing, if so, go to step 2
2.) Find all of the consonants in the word and store them in a list
3.) If it is, remove the vowels from the word, and then append all of the consonant onto the end, followed by 'ay'.
There are infinite ways to actually implement this and I think it would be a good exercise for you to try to implement it yourself, but let me know if you need any more help.
Here is my code for the pig latin translator. It works both on Code academy and in linux terminal.
pyg = 'ay'
new_word = pyg
original = raw_input('Enter a word: ')
if len(original) > 0 and original.isalpha():
original.lower()
word = original
first = original[0]
if first == 'a' or first =='e' or first == 'i' or first =='o' or first == 'u':
print 'vowel'
elif first != 'a' or first !='e' or first !='o' or first !='i' or first !='u':
print word.lower()[1:] + first +new_word
else:
print 'empty'
Code academy gives following result;
Oops, try again! Your word started with a consonant, but “ay' was printed instead of “ogday”. Make sure the correct value #is stored in “new_word”.
"ay" is not printed but "ogday' is printed.
Does anyone know how to fix this? I cannot continue with Codeacademy as without solving this.
You can do something like this for example. You are in the right track just use what you have learned in the Code academy up to this task.
consonants = "bcdfghjklmnpqrstvxz"
original = raw_input('Enter a word: ')
if len(original) > 0 and original.isalpha():
if original.lower()[0] in 'aeiou':
print original.lower() + 'ay'
else:
keep_first_consonants = ''
count = 0
for letter in original.lower():
if letter in consonants:
keep_first_consonants = keep_first_consonants + letter
count += 1
else:
break
total_characters = len(original.lower())
print original.lower()[count:total_characters] + keep_first_consonants + 'ay'
else:
print 'Accept only letters'
The codeacademy lesson checker seems to check the variable new_word when you hit run
So you just need to use new_word for both your print varibles
This code works:
pyg = 'ay'
original = raw_input('Enter a word:')
if len(original) > 0 and original.isalpha():
word = original.lower()
first = word[0]
if first == "a" or first == "e" or first == "i" or first == "o" or first == "u":
new_word = original + pyg
print new_word
else:
newer_word = word[1:]
new_word = newer_word + first + pyg
print new_word