how to mock an exception call in python? - python

I have a code like this:
def extract(data):
if len(data) == 3:
a = 3
else:
component = data.split("-")
if len(component) == 3:
a,b,c = component
else:
raise globals.myException("data1", "Incorrect format", data)
return a,b,c
This is a simplified one. I want to mock the exception class globals.myException. I'm doing that:
def test_extract_data_throws_exception(self):
with patch('globals.myException') as mock:
mock.__init__("data1", "Incorrect format", "")
with self.assertRaises(myException):
self.assertEqual(extract(""), (""))
And I always get the error: "TypeError: exceptions must be old-style classes or derived from BaseException, not MagicMock"
EDIT: As #Aaron Digulla suggest, monkey patching is the correct solution. I post the solution to help others.
def test_extract_data_throws_exception(self):
#monkey patching
class ReplaceClass(myException):
def __init__(self, module, message, detail = u''):
pass
globals.myException = ReplaceClass
with self.assertRaises(myException:
self.assertEqual(extract(""), (""))

The reason is raise checks the type of the argument. It must be a string (a.k.a "old style exceptions") or derived from BaseException
Since a mock isn't either, raise refuses to use it.
In this specific case, you either have to raise the exception or use monkey patching (= overwrite the symbol globals.myException in your test and restore it afterwards).

Related

pytest for function as an argument

I was writing a test using pytest library where I need to test a method which takes another method as an argument.
class Certificate:
def upload(self, upload_fn: Callable):
try:
if self.file_name:
upload_fn(self.file_name)
return
raise ValueError("File name doesn't exist")
except Exception as e:
raise e
Now I created a dummy mock function which I am passing while calling upload method but I am not sure how do I make sure if the upload_fn is called.
I am trying to achieve something like this
def test_certificate_upload(certificate):
certificate.upload(some_mock_fn)
assert some_mock_fn.called_once() == True
EDIT: so currently I am testing it in the following way but I think there can be a better approach.
def mock_upload(f_name):
""just an empty mock method""
def mock_upload_raise_error(f_name):
raise Exception e
def test_certificate_upload_raise_exception(certificate):
with pytest.raises(Exception) as e:
certificate.generate(mock_generator_raise_error)
PS: limitation to this approach is we can't assert if the method was called or how many times the method was called or with what params the method was called.
Also, we have to create extra dummy mock methods for differnet scenarios.
You an mock :
def mock_get(self, *args):
return "Result I want"
#mock.patch(upload, side_effect=mock_get)
def test_certificate_upload(certificate):
certificate.upload(some_mock_fn)
assert function_name() == Return_data

Make python don't undo things after an error is raised in try block

I have a python class in which I open files and read out data. If some creteria are not met, I raise an error, but before that I specify the error by giving the object an attribute: self.Error = specification. But since the error raising undos everything in the try block I can't access it. This happens in the __init__ function, so the created object doesn't even exist..
Here's the necessary code:
class MyClass:
def __init__(self):
#do something
if this_or_that:
self.Error = specification
raise MyCostumError
try:
object = MyClass()
except MyCostumError:
print(object.Error)
I get: NameError: name 'object' is not defined
Just for clarification:
I have defined MyCostumError, the variable names are just for better understanding: I use good ones and they are defined and I need the clarification, because an Error can be raised in different lines.
So here's my question:
Is there something like try/except, but when an error is raised it does NOT undo everything. Or am I just stupid and there is a much easier method for a achieving this?
If you are raising an exception in the initializer, you should not rely on the object to be created to get some error information to the caller. This is where you should use the exception to pass that information:
class MyCustomError(Exception):
pass
class MyClass:
def __init__(self):
#do something
if this_or_that:
raise MyCustomError(specification) # put the spec in the exception itself
try:
object = MyClass()
except MyCustomError as e:
print(e) # the spec is in the exception object
You are trying to reference to an object that cannot exist. Let me explain:
If an error occurs when you try to initialise an object, that object will not be initialised. So if you try to acced to it when it is not initialised, you will get an error.
try:
object = MyClass() #initialising object successful, object existing.
except: #initialising failed, object does not exist.
print(object.Error) #nameError, since object was never created.
Try/except doesn't undo anything, just stops doing something if an error occurs.
Error raising doesn't undo anything. Have a look at the docs.
As your output states, the object is not defined, this is because when you raise an error in the __init__, it is seen as the initialosor of your class failing, and this does not return an object.
I think this is what you're looking for:
class MyClass:
def __init__(self):
# do initialisation stuff
def other_method(self):
# do something
if this_or_that:
self.Error = specification
raise MyCustomError(specification)
object = MyClass()
try:
object.other_method()
except MyCustomError as e:
print(e)
print(object.Error)
It's not a beautiful solution but it should work:
errorcode = None
class MyClass:
def __init__(self):
global errorcode
#do something
if this_or_that:
errorcode = specification
raise MyCostumError
try:
object = MyClass()
except MyCostumError:
print(errorcode)
Given your question I think the following should fit your use case well.
class MyClass:
def __init__(self):
# Do something
try:
if this_or_that:
self.Error = specification
raise MyCostumError
except MyCustomError as e:
# Handle your custom error however you like
object = MyClass()
In the above case you should be able to mitigate the risk of instantiation failing due to custom exception/error raising failing by handling this behaviour within MyClass.__init__ itself.
This is also a much cleaner solution in terms of keeping logic relating to instantiation of MyClass objects contained within the __init__ function of the class - i.e. you won't have to worry about wrapping instantiations of this class in try/except blocks each time they are present in your code.

Python - Implementing Custom exceptions

I have a project that I need to run and have no idea how to implement custom exceptions. It mostly does complicated scientific functions, to be vague.
Mostly it will be raising exceptions if something is not set. I've been given this as a starting example from runnables.
# Define a class inherit from an exception type
class CustomError(Exception):
def __init__(self, arg):
# Set some exception infomation
self.msg = arg
try:
# Raise an exception with argument
raise CustomError('This is a CustomError')
except CustomError, arg:
# Catch the custom exception
print 'Error: ', arg.msg
I have no idea how this is meant to work or how I am meant to implement my code. It's not very explicit.
To give an idea of a basic exception that needs created.
In a function:
if self.humidities is None:
print "ERROR: Humidities have not been set..."
return
Apparently this needs to raise/throw an exception instead.
A ValueError looks suitable for your humidities example.
if self.humidities is None:
raise ValueError('Humidities value required')
If you want to be specific:
class HumiditiesError(Exception):
pass
def set_humidities(humidities):
if humidities is None:
raise HumiditiesError('Value required')
try:
set_humidities(None)
except HumiditiesError as e:
print 'Humidities error:', e.message
This defines a subclass of Exception named HumiditiesError. The default behavior seems sufficient for your example, so the body of the class is empty (pass) as no additional nor modified functionality is required.
N.B. Python 2 assumed. In Python 3 you would access elements of the e.args tuple.

Exceptions that reflect error codes of a remote service

I'm working with an external service which reports errors by code.
I have the list of error codes and the associated messages. Say, the following categories exist: authentication error, server error.
What is the smartest way to implement these errors in Python so I can always lookup an error by code and get the corresponding exception object?
Here's my straightforward approach:
class AuthError(Exception):
pass
class ServerError(Exception):
pass
map = {
1: AuthError,
2: ServerError
}
def raise_code(code, message):
""" Raise an exception by code """
raise map[code](message)
Would like to see better solutions :)
Your method is correct, except that map should be renamed something else (e.g. ERROR_MAP) so it does not shadow the builtin of the same name.
You might also consider making the function return the exception rather than raising it:
def error(code, message):
""" Return an exception by code """
return ERROR_MAP[code](message)
def foo():
raise error(code, message)
By placing the raise statement inside foo, you'd raise the error closer to where the error occurred and there would be one or two less lines to trace through if the stack trace is printed.
Another approach is to create a polymorphic base class which, being instantiated, actually produces a subclass that has the matching code.
This is implemented by traversing __subclasses__() of the parent class and comparing the error code to the one defined in the class. If found, use that class instead.
Example:
class CodeError(Exception):
""" Base class """
code = None # Error code
def __new__(cls, code, *args):
# Pick the appropriate class
for E in cls.__subclasses__():
if E.code == code:
C = E
break
else:
C = cls # fall back
return super(CodeError, cls).__new__(C, code, *args)
def __init__(self, code, message):
super(CodeError, self).__init__(message)
# Subclasses with error codes
class AuthError(CodeError):
code = 1
class ServerError(CodeError):
code = 2
CodeError(1, 'Wrong password') #-> AuthError
CodeError(2, 'Failed') #-> ServerError
With this approach, it's trivial to associate error message presets, and even map one class to multiple codes with a dict.

How do I instantiate a specific subclass based on arguments passed to __init__?

I'm wrapping a remote XML-based API from python 2.7. The API throws errors by sending along a <statusCode> element as well as a <statusDescription> element. Right now, I catch this condition and raise a single exception type. Something like:
class ApiError(Exception):
pass
def process_response(response):
if not response.success:
raise ApiError(response.statusDescription)
This works fine, except I now want to handle errors in a more sophisticated fashion. Since I have the statusCode element, I would like to raise a specific subclass of ApiError based on the statusCode. Effectively, I want my wrapper to be extended like this:
class ApiError(Exception):
def __init__(self, description, code):
# How do I change self to be a different type?
if code == 123:
return NotFoundError(description, code)
elif code == 456:
return NotWorkingError(description, code)
class NotFoundError(ApiError):
pass
class NotWorkingError(ApiError):
pass
def process_response(response):
if not response.success:
raise ApiError(response.statusDescription, response.statusCode)
def uses_the_api():
try:
response = call_remote_api()
except NotFoundError, e:
handle_not_found(e)
except NotWorkingError, e:
handle_not_working(e)
The machinery for tying specific statusCode's to specific subclasses is straightforward. But what I want is for that to be buried inside of ApiError somewhere. Specifically, I don't want to change process_response except to pass in the value statusCode.
I've looked at metaclasses, but not sure they help the situation, since __new__ gets write-time arguments, not run-time arguments. Similarly unhelpful is hacking around __init__ since it isn't intended to return an instance. So, how do I instantiate a specific subclass based on arguments passed to __init__?
A factory function is going to be much easier to understand. Use a dictionary to map codes to exception classes:
exceptions = {
123: NotFoundError,
456: NotWorkingError,
# ...
}
def exceptionFactory(description, code):
return exceptions[code](description, code)
Create a function that will yield requested error class basing on description.
Something like this:
def get_valid_exception(description, code):
if code == 123:
return NotFoundError(description, code)
elif code == 456:
return NotWorkingError(description, code)
Depending on your requirements and future changes, you could create exceptions with different arguments or do anything else, without affecting code that uses this function.
Then in your code you can use it like this:
def process_response(response):
if not response.success:
raise get_valid_exception(response.statusDescription, response.statusCode)
You could create a series of subclasses and use the base class' __new__ as a factory for the children. However, that's probably overkill here; you could just create a simple factory method or class. If you wanted to get fancy in another direction though, you could create a metaclass for the base class that would automatically add your subclasses to a factory when they are created. Something like:
class ApiErrorRegistry(type):
code_map = {}
def __new__(cls, name, bases, attrs):
try:
mapped_code = attrs.pop('__code__')
except KeyError:
if name != 'ApiError':
raise TypeError('ApiError subclasses must define a __code__.')
mapped_code = None
new_class = super(ApiErrorRegistry, cls).__new__(cls, name, bases, attrs)
if mapped_code is not None:
ApiErrorRegistry.code_map[mapped_code] = new_class
return new_class
def build_api_error(description, code):
try:
return ApiErrorRegistry.code_map[code](description, code)
except KeyError:
raise ValueError('No error for code %s registered.' % code)
class ApiError(Exception):
__metaclass__ = ApiErrorRegistry
class NotFoundError(ApiError):
__code__ = 123
class NotWorkingError(ApiError):
__code__ = 456
def process_response(response):
if not response.success:
raise build_api_error(response.statusDescription, response.statusCode)
def uses_the_api():
try:
response = call_remote_api()
except ApiError as e:
handle_error(e)

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